C :: Stack Conversion From Infix To Prefix
Sep 16, 2013
Code:
#include<stdio.h>
#include<conio.h>
#include<string.h>
#include<ctype.h>
#define MAX 50
[Code] ....
[URL] .....
My output should look like this ..
Enter an expression in infix form: (9+6)/(2*4)^15
Specify output expression type,1) Prefix 2)Postfix
The Prefix expression is: /+96^*2415
----------------------------------------------
Enter an expression in infix form: (9+6)/(2*4)^15
Specify output expression type,1) Prefix 2)Postfix
The Postfix expression is:96+24*15^/
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Mar 8, 2013
I am Getting following errors I don't know why.I have mentioned the lines (in comments) where these errors are occurring.
__________________________________________________
warning C4018: '<' : signed/unsigned mismatch
error C2064: term does not evaluate to a function taking 0 arguments
error C2064: term does not evaluate to a function taking 0 arguments
__________________________________________________ _
Code:
/////////////////////////////////////////////////
//libraries
/////////////////////////////////////////////////
#include <iostream>
#include <string>
using namespace std;
[Code] .....
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Mar 27, 2014
I keep getting the same error messages every time on Visual Studio. I don't know where the error is originating. Basically I'm trying to convert an infix expression (A+B-C) to a postfix expression (AB+C-) using stacks.
#include <iostream>
#include <fstream>
#include <string>
#include <stack>
#include "Expression.h"
#include "stackType.h"
using namespace std;
int main() {
string fileName;
string infixExpression, postfixExpression;
[Code] .....
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Feb 4, 2014
Array based stack class. So i am having a problem, i do not understand how to convert an infix notation into a postfix notation from a txt file. The infix expressions are stored in a text file. for example inside the text file is
6+9
2+7*8
(1+5)*3
5+(6-2)*((2-8)
at the moment my header file is
#ifndef STACKS_H
#define STACKS_H
#include <iostream>
using namespace std;
const int STACKS_CAPACITY = 128;
typedef int StacksElement;
[Code] ....
but how to make it convert the into postfix...
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Apr 12, 2015
I am trying to convert from infix to postfix, and then evaluating the postfix expression to get the final answer. I am having a severe problem though, because for somereason the conversion is not working at all. For example, when I input the first infix expression:
24 + 33 * ( 7 - 5 ) + 8 / 3 it ouputs 24 33 7 5 - 5 ) + 8 / 3( 7 - 5 ) + 8 / 3* ( 7 - 5 ) + 8 / 3+ 33 * ( 7 - 5 ) + 8 / 3 8 3/ 3+ 8 / 3
Which is obviously very wrong. I am not really sure where the problem is though.
Below I have included all of the code needed. I also had to create my own stack class, so I will include it too .
#include "stacks.h"
#include <iostream>
using namespace std;
bool IsOperand(char C) {
if(C >= '0' && C <= '9') return true;
if(C >= 'a' && C <= 'z') return true;
[Code] .....
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Sep 25, 2013
I trying to write a code for a calculator using stack is how to convert an operation from infix to postfix . Here is my attempt I created a header file.
#ifndef STACK_H
#define STACK_H
#include <iostream>
using namespace std;
template<class T>
struct node {
T item;
[Code] .....
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Apr 25, 2013
first code,
Code:
int aRRay[] = {2,4,8,-2,-1,100};
int *ptr;
int loop;
ptr = &aRRay[0];
}
[code].....
first code result, " aRRay[] " and " ptr + loop " are in the same result
second code result, " aRRay[] " and "ptr + loop " are in the same result too,
third code result, " aRRay[] " and "ptr + loop " are in the same result Except "aRRay[4] = -1 with ptr + 4 = 100 " and "aRRay[5] = 100 with ptr + 5 = 14"
Question:Why the third code had a different result ? Its only because of the increment ++ptr or the round brackets on the *(++ptr) ?
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Feb 4, 2014
I am writing the overloading operator function (prefix ++) according to my book.. but it doesnt work !!!!!!
But if i write:
void operator++() {
++x;
}
It works !!!!!
Here is my code according to the book that doesnt work as it should:
#include <iostream>
using namespace std;
class things {
int x,y,z;
[Code] ....
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Jan 17, 2014
I have some functions inlined using the inline function prefix. If the function is called from outside the file (so a seperate psp-gcc -O3 ... filename.c filename.o compile command, when only the function is changed), will the other files be updated too? (I'm using the pspsdk toolchain).
Example:
max.c
inline byte max(byte a, byte b) {
return a>b?a:b;
} use1.c
void use1() {
if (max(1,2)==0)
[Code] ....
If I compile this, next change the max function and recompile using make (the compiler only takes the changed max.c->max.o file, next links them together) will use1.c&use2.c be updated with the new max.c function?
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May 2, 2013
The objective is to build a month class that hold data on the number of the month and the name of the month. Using constructors and overloads, set it up to where you can input either the month or the name and it will output the results for both the month number and name.
Here is the code I have so far:
#include<iostream>
#include<string>
using namespace std;
class Month{
private: string name;
int monthNumber;
[Code] ....
It is almost fully compiled if I go by the error list. The only problems I see to be having are with the prefix and postfix overloads.
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Oct 26, 2012
I have an assignment which includes overriding the prefix and postfix operators, and my teacher has provided what the output from the program should be. I've written the code and it's nearly perfect, except for one tiny error I can't seem to get right.
This is (most of) the code from the header--I left out a few of the parts that aren't relevant to my question:
Code:
using namespace std;
#include<string>
#include<iostream>
class NumDays {
private:
int hours;
[Code] ....
The two problem lines are supposed to be outputting 12 and 1.5, respectively, but are instead showing 13 and 1.625. I know that hours is being changed to 12 at the end of the overriden prefix operation in the line above them, so I don't understand why it returns to 13 again. What I need to change?
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Sep 14, 2014
I'm trying to make an infix to postfix notation calculator. The difficult thing is th stack class is custom. It's not to hard to understand, I don't know if the fact that it is that way will not allow me to receive support. The difference is that the pop functions is as such:
stack<char> conversion;
char temp;
conversion.pop(temp);//It receives a parameter and puts the popped element in there.
conversion.peek(temp);//Places the top element in said parameter
not only that... but these are boolean functions. they return true if the operation was completed. So they can be used as conditions.
#include<iostream>
#include<string>
#include<stdio.h>
#include"stack.h"
using namespace std;
int main(void) {
Stack<char> conversion;
string infix,inter,temps;
[Code] .....
The error is that i am mismanaging parenthesis handling and i can't seem to grasp where and how.
An example input is:(35+7)-(9-2)
that input gives me:35 7 + 9 2 ) -
but another input such as :(35+7)/7
outputs as: 35 7 + 7 /. Totally fine.
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Oct 1, 2013
Program which convert expression from PostFiz to Infix and also wants to evaluate them....
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Nov 21, 2014
So I have been working my way through this assignment and I'm just stuck now. I cannot get this work properly It just tells me I'm trying to return a local variable when attempting to return postfix in the to_postfix function. It is line 97 that wont compile. Also I cannot change anything in runner.c.
Calculator.c
Code:
1 #include <stdio.h>
2 #include <stdlib.h>
3 #include <ctype.h>
4 #include <string.h>
5 #include "stack.h"
[Code] .....
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Dec 3, 2014
Also, can't use namespace std for this.
#include<iostream>
#include<stack>
#include<fstream>
#include<iomanip>
#include<queue>
#include<cassert>
[Code] ....
/* It will read in a infix expression from a text file.check if the parentheses in the input expression are balanced.convert the infix expression into a postfix expression and evaluate the expression.*/
int main() {
string expression;
string postfixExpression;
double result;
testBalanced();
[Code] ....
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Feb 6, 2014
So i solved my earlier problem but now how do i make it read from the text file that i have and output the postfix notations? Because right now it is only outputting what is currently in the text file for example
6+9
2+7*8
(1+5)*3
5+(6-2)*((2-8)
Header file is
#ifndef STACKS_H
#define STACKS_H
#include <iostream>
using namespace std;
const int STACKS_CAPACITY = 128;
typedef int StacksElement;
[Code]...
test client cpp is
#include <iostream>
using namespace std;
#include "Stacks.h"
#include <fstream>
#include <string>
#include <cassert>
#include <cctype>
[Code]...
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May 24, 2014
I need to convert from an infix expression to postfix using stacks!
#ifndef EXPRESSIONMANAGER_H_
#define EXPRESSIONMANAGER_H_
#include <iostream>
#include <stack>
#include <string>
#include <sstream>
using namespace std;
class ExpressionManager : public ExpressionManagerInterface{
[code]....
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Apr 25, 2014
I have the following problem on my C++ Program and I am not sure why it is not working. I am creating a infix to postfix program through an inherited class which I am not sure it is working.
#include <iostream>
#include <stack>
using namespace std;
int in_stack_Priority(char a){
if(a == '*' || a == '/')
return 2;
[Code] .....
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Sep 28, 2014
I was given a task to convert infix to post fix using both linked lists and stacks in the code so this is what i have written but the problem is it is giving me same error at three different places "missing function header(old style format?)
#include <iostream>
#include <string>
using namespace std;
const int size = 100;
class stack{
private: // Declare a structure for the list
[Code] ....
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Apr 9, 2014
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int displayMenu ();
void addRecords ();
void zip ();
void city ();
[Code] ...
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Apr 1, 2013
I want to convert time from est to utc. Is there any function for this.
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Feb 14, 2012
I am looking for a math/big num library, that allows me to convert 32/64/80 bot float numbers to string and vice versa.
Precision & accuracy is of importance here, and since this is an IEEE standard, i have high hopes that there are libraries for this out there, which would save me the hassle of trying to implement this myself...
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Oct 15, 2014
I am having trouble in creating a program (named "up.c") that should do the following:
- if you run the command ("up") with no arguments, it should read input from stdin and display it on stdout, converting lowercase letters to uppercase.
- if you run the command with one or more files (as arguments to the "up" command), your program should read input from each file and display it on stdout, again converting lowercase letters to uppercase.
I'm trying to create a single program that can do both of these, and handle errors gracefully. I've found that some codes work to convert the letters, but they seem overly simple and aren't giving me what I'm looking for in my program.
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Oct 14, 2013
why does the following code output "0.000000" instead of "1.000000"?
Code:
#include <stdio.h>
int main(void) {
int x=3, y=2;
printf("3/2 is %f
", x/y);
return 0;
}
the code was compiled and run using gcc 4.4.7 and glibc 2.17 on linux kernal 2.6.32 running on a PC with an intel i5-2500k cpu(sandy bridge)
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Feb 25, 2013
I have this project, How do I ever Convert a .Pdf file to .txt file using C++.
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May 22, 2014
I'm writing a small pice of code that takes numbers and convert it to string. So that's what I got
int main() {
char letter;
char letter1;
char letter2;
cin >> letter;
cin >>letter1;
int sum = letter * 128 + letter1;
[Code] ....
Then it asks the user to enter a letter, say 'w' , which it's value is 119
Then enter another letter, say 'o' which value is 111
then it do the equation, which is take the value of the first letter multiple it by 128 then add it to the value of the second letter.
How can I make it does this process in a For loop, or any kind of loop??
Then I have the second part which is the other way around. That is when the user enter a numbers then the code convert these numbers to a string.
251394404 - "d"
1964018 - "rd"
15343 - "ord"
119 - "word"
so what's happening here is the it divide each time by 128. But I can't do that in a code.
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