why does the following code output "0.000000" instead of "1.000000"?
Code:
#include <stdio.h>
int main(void) {
int x=3, y=2;
printf("3/2 is %f
", x/y);
return 0;
}
the code was compiled and run using gcc 4.4.7 and glibc 2.17 on linux kernal 2.6.32 running on a PC with an intel i5-2500k cpu(sandy bridge)
I am looking for a math/big num library, that allows me to convert 32/64/80 bot float numbers to string and vice versa.
Precision & accuracy is of importance here, and since this is an IEEE standard, i have high hopes that there are libraries for this out there, which would save me the hassle of trying to implement this myself...
I want a code that can convert floating/double value into string/char array(char arr[]) and also it can be run on Boreland C++ 5.02
Here I've a code but it doesn't show all the numbers. Instead, it's showing in exponential form which I don't want!!
int main() {
char* str = new char[30];
float flt = 2.4567F;
sprintf(str, "%.4g", flt );
cout<<str<<endl; //Exponential form even after 6 digits without decimal
return 0;
}
So, I'm supposed to do : Create a function with unlimited number of arguments, which forms a dynamic string based on the following form (%d, %s, %f, %lf, %c), with the following prototype:
char*create(char*form, ...);
The function is supposed to have the following output:
create("Peter is %d years old and is in %s-%c class.",7,"second",'A');
-> Peter is 7 years old and is in 7-A class.
create("His GPA is %lf.",4.96);
-> His GPA is 4.96.
create("His favourite subject is math!");
-> His favourite subject is math!
I've managed to do the following :
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <stdarg.h>
char *create(char *form, ...) {
char *res =(char*)calloc(1,1),*pos_int,*pos_float,*pos_str,pos_char,*pos_long;
[Code] ....
The part with %d and %s string was not that hard, but now I'm supposed to convert %f and %lf to string, I've tried using sprintf but I've had no luck so far, another problem is the fact that I've gotta use lists to complete the task. I've been trying to convert float to string for the past 2 hours, but I'm drawing a blank now.
this is my code
#include<stdio.h>
main()
{
[Code]....
N=1st number M=2nd number(accrding to my prof we will name it N and M
ctr= increment of factorial of N, ctr2= increment of factorial of (N-M)
the problem is when i got the factorial of N / factorial of (N-M) i need to get the last non zero digit. so i use mod if it has zero in it. but mod can be only used with an int value. and when i change it to int value, the value of fact1 which is a float change
This program is basically working. I'm very knew to C++, so basically I need instructions as if you were explaining this to your grandma. I need this to loop but how to incorporate one. Basic code (while loops). Here is what I've done so far.
#include <iostream>
using namespace std;
int main () {
int i, c, k;
cout << "Please enter a number to convert: ";
cin >> i;
[Code] ....
ive written a simple code but throws an error in C#, why is this happen.
bool inputValue = Convert.ToBoolean(Console.ReadLine());
Console.WriteLine(inputvalue);
Console.ReadLine();
I have a float values I'd like to round off to the nearest integer value.
That is to say, if the float value is 44.234533, the integer value should be 44. If the float value is 44.682101, the integer value should be 45.
How do I do this?
I would like to convert a float or double variable into unsigned char variable and back.
float number_float = 23.453f;
unsigned char* number_char = (unsigned char*)malloc(sizeof(float));
number_char = reinterpret_cast<unsigned char*> (&number_float);
float* number_float_0 = reinterpret_cast<float*>(&number_char);
I am not getting the same value back.. why?
I am trying to convert uint32_t or unit16_t to chars in little endian. When I was reading the char s from binary file I used memcpy so I did not need to convert them, but now I try this:
Code:
static void write2Bytes(unsigned char ** pDestStr, uint16_t* item) {
(*pDestStr)[0] = ((uint16_t) item & 0x00ff);
(*pDestStr)[1] = ((uint16_t) item & 0xff00) >> 8;
*pDestStr+=2;
[code]...
In the last function I try either to cast to uint_32_t or unsigned char but in both case I got wrong values. The original binary string read from left: 0x36000003 (it is number corresponding to 48Mbytes).
And the result when casting to unsigned char is T000000 and T(>00 for uint_32. So what's wrong? I need to get some string with will be corresponding to 0x36000003. does this kind of convertion take a lot of compute performance when I one would use it offten (like when one would do convesions for bitmaps).
I need to read a float number and show the rest of his division by an integer, but i'm having the following error message:
Quote
error: invalid operands of types 'float' and 'int' to binary 'operator%'
i am writing a program that requires me to write am input a float and an integer and save it to a txt file. When i try to compile my code i get an error "assignment from incompatible data type". ?
int *intconstant;
float *floatconstant;
int *value;
struct FILE *infileptr, *outfileptr;
infileptr = fopen("/home/brinkmann.brendon/assign14data.txt", "r");
outfileptr = fopen("/home/brinkmann.brendon/assign14report.txt", "w");
[Code]...
I'm reading lines from a text file in C++ which contains integer + string + float number(like 3,67 with comma) + string in this order. I need the float number to sort the lines but I couldn't manage to separate the data into the types I can use so far. I tried different kind of functions and the best I could do was such a code;
void main (){
ifstream records;
records.open("records.txt");
int id;
string line;
char name[100];
float gpa;
[Code] ....
This fails at reading the floating number which has comma in it and then last string is read as string starting with the comma and rest of the number. An output example is:
698 John 3 ,67
It doesn't read last string on the line as well. I understand that part but simply I need another read but what I want exactly is to separate one line using "tab" as a seperator into proper data types and then using the numbers as integers, and the grades as floating numbers. How Can I do this?
I'm expected to write a c program for this question :
Using these header files
#include <stdio.h>
#include <conio.h>
Question : Write a program that will prompt the user to enter an integer value and a character code to indicate whether they want to do a Kilogram to Pounds conversion (A) or a Pounds to Kilogram (B) conversion. Note that 1 kg = 2.2 pounds. The program should then do the necessary conversion indicated by the code and display the newly converted value to the screen.
I can do the folowing:
float var1 ;
var1 = 9.12345 ;
printf("%.2f",var1) ;
the output will be 9.12. What if I wanted to save that as another separate float with displaying it on screen?
#include <iostream>
#include <string.h>
#include <sstream>
[Code]....
I am trying to assign the integer value to unsigned char array. But it is not storing the integer values. It prints the ascii values. Here the code snippet
Code: uchar uc[100];
for(i=0;i<100;i++)
{
uc[i] = i;
}
The values which are stored in uc[] is ascii values.I need the integer values to be stored in uc[]. I tried to do it with sprintf. but the output is not as expected. if I print the uc[i] it should diplay the value as 0,1,2....99.
changing a 9 digit integer into a new 9 digit integer through simple mathematical operations. For example, I need to change 123456789 into the new digit 456123789. Sometimes I need to change a 9 digit integer into an 8 digit integer. An example is 789062456 into 62789456. I can ONLY use simple mathematical operations (addition, subtraction, multiplication, division and modulo).
View 4 Replies View RelatedComplete the function myitohex so that its converts 8-byte integer to string based hexadecimals.
Ex: printf("0x%s",myitohex(64,hex)); should printout "0x40" on the screen
char *myitohex(uint8_t i, char *result){
???
return result;
}
I wrote:
#include <stdio.h>
#include <stdint.h>
char *myitohex(uint8_t i, char *result){
*result = i + '0';
[Code] ....
0xp gets printed out which is wrong. I think *result = i + '0'; is wrong. What changes should i do on this row ?
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int displayMenu ();
void addRecords ();
void zip ();
void city ();
[Code] ...
I want to convert time from est to utc. Is there any function for this.
View 3 Replies View RelatedI am having trouble in creating a program (named "up.c") that should do the following:
- if you run the command ("up") with no arguments, it should read input from stdin and display it on stdout, converting lowercase letters to uppercase.
- if you run the command with one or more files (as arguments to the "up" command), your program should read input from each file and display it on stdout, again converting lowercase letters to uppercase.
I'm trying to create a single program that can do both of these, and handle errors gracefully. I've found that some codes work to convert the letters, but they seem overly simple and aren't giving me what I'm looking for in my program.
I have this project, How do I ever Convert a .Pdf file to .txt file using C++.
View 5 Replies View RelatedI'm writing a small pice of code that takes numbers and convert it to string. So that's what I got
int main() {
char letter;
char letter1;
char letter2;
cin >> letter;
cin >>letter1;
int sum = letter * 128 + letter1;
[Code] ....
Then it asks the user to enter a letter, say 'w' , which it's value is 119
Then enter another letter, say 'o' which value is 111
then it do the equation, which is take the value of the first letter multiple it by 128 then add it to the value of the second letter.
How can I make it does this process in a For loop, or any kind of loop??
Then I have the second part which is the other way around. That is when the user enter a numbers then the code convert these numbers to a string.
251394404 - "d"
1964018 - "rd"
15343 - "ord"
119 - "word"
so what's happening here is the it divide each time by 128. But I can't do that in a code.
I have a question on conversion between char & string. I have cut & pasted the part of the code from my C++ code and my function "decryptPwd" uses C style code with "char" etc.
I need to pass a string (mypwd) somehow to this function after conversion & then compare it to another string (newmypwd).
I tried - "decryptPwd(mypwd.c_str())==newmypwd.c_str()" but it did not work.
..
#include <string>
..
char* decryptPwd(char hash[64]);
main () {
string mypwd;
string newmypwd;
if (decryptPwd(mypwd)==newmypwd)
[Code] ...
Converting an IP address to a binary number? As in the entire thing 123.45.555.49 to it's binary equivalent.
View 14 Replies View Related
