my code is working as expected except a slight error, i have to find min max and median values of an inputed array terminated by 0, the problem im having is with calculating the minimum, where when i enter 0 to terminate the program it uses 0 as the minimum value. my code is as follows
public static void FindAverages()
{
try
{
[Code]....
Finally got a programme partially working, why the values are not showing? Is this down to incorrect formula or i havent declared the values etc?
Code:
#include <stdio.h>
#include <math.h>
float timeconstant(float R, float C);
float R;
float C;
float time_c;
[Code] ....
I am trying to calculate the largest and smallest values using functions. I keep getting this (pointer-to) error
#include <iostream>
#include <conio.h>
using namespace std;
void getValues(int [], int);
void displayValues(const int[], int);
int largest(const int[],int);
int smallest(const int[],int);
void displayLargestSmallest(int,int);
[code]....
I have two doubts in the following code,the doubts are marked..PLs note that the following code is correct .This is a program to read 2d array using pointer ()i.e Dynamic array ,to calculate its rowsum and column sum and display this array along row sum and column sum.
#include<iostream.h>
#include<conio.h>
void main() {
clrscr();
int *Val,*Rsum,*Csum;
int MaxR,MaxC,i,j;
[Code] .....
Now this issue is about calculating the average of numbers and displaying it in the out put.
The following numbers is what I have read in from a file. There are 7 lines all the same format, just different values of course.
132475.889.392.3
435686.383.498.3
The output will need to look like:
Student #Test1Test2Test3Average
132475.889.392.385.8
435686.383.498.389.3
My program thus far is: (omitted code to shorten post and remove irrelevant information.
I don't know if it is because I have been working on other things and forgot how to proceed with the calculations and display, but I am just stuck. I'm not sure how to have the program read the numbers from columns 2 through 5 and then divide by 3. As you can see in my DisplayAverages() method I should have the ConsoleWrite and WriteLines done properly.
static void Main()
{
double[,] scoresArray = new double[7,4];
LoadFile();
ReadData(scoresArray);
[Code]....
Should read columns 2-4 and then display the average in column 5.
Goal: Write a program that compares the values stored in the first array to the user inputted values in the second array.
In order to fix this error: [URL]...
I had to change my array initialization to one with a star in front of it:
char a1[]={"a","d","b","b","c","b","a","b","c","d","a","c","d","b","d","c","c","a","d","b"};
to:
char *a1[]={"a","d","b","b","c","b","a","b","c","d","a","c","d","b","d","c","c","a","d","b"};
I also changed my 2nd array to one with a star in front of it: char *a2[20];
What does this mean exactly? Putting a star in front of an array?
Also, I am now getting an "unhandled exception" when I try to get input for my 2nd array:
cin>>a2[i];
I need to calculate how often each letter appears in a text file from a function that is called from main() with an array of pointers to char and how many pointers there are in the array. The code i have so far is:
#include<stdio.h>
#include<string.h>
#include<ctype.h>
#include<stdlib.h>
[Code]....
I get no errors and it runs but it gives me the wrong output. I know my array is correct because when i print it in main() it is correct but each letter is incorrectly counted. When i give it the input .txt file of:
This is one line of a string
This is another
This is the third one
Wow heres another one
It counts a as 8
b as 1
c as 3
etc.
I have hand traced it and cant figure out why it isnt giving me correct values
I got this program to create an array of playing cards and assign the values and suits and shuffle the array. I'm at the point where I need to output the cards but I need to burn the first card by making it output "**" instead of the card. my cards[] is a constant so I can's assign the first card as such.
void showCards(const int cards[], int numCards, bool hideFirstCard) {
if (cards[0]) {
hideFirstCard=true;
cards[0] = '**';
} for(int a = 0; a <= numCards; a++) {
cout >> showCard(cards[a]);
} }
But it can the other way around
Code:
static_Array= dynamic_Array;
dynamic_Array = static_Array;
The second statement works and i'm able to print out both arrays with equal values but with the first
[code] static_Array = dynamic_Array;I get incompatible types in assignment of 'int*' to 'int [7]' is the error I get [/code]
I wanted to print the values of a array from a function by passing the array as well as the number of elements to be read. For a single dimensional array, this is how i have written it. It's pretty straight forward. I want to read 5 elements from the 5th element in the array.
Code:
#include<stdio.h>
void display(int array[],int size) {
int i;
[Code]....
With this code I want to print the five elements from the element present in [0][4].
But shows an error that
Code:
D:BennetCodeblocks CLearning CSingleDimentionalArray.c||In function 'main':|
D:BennetCodeblocks CLearning CSingleDimentionalArray.c|18|warning: passing argument 1 of 'display' from incompatible pointer type [enabled by default]|
D:BennetCodeblocks CLearning CSingleDimentionalArray.c|2|note: expected 'int (*)[10]' but argument is of type 'int *'|
||=== Build finished: 0 error(s), 1 warning(s) (0 minute(s), 0 second(s)) ===|
I know when you pass a array as an argument it gets decomposed into a pointer, but with a multi-dimensional array this is not the case. how this works for mult- dimensional array's?
My program takes the values from one array and searches for their index position in another array (linear search algorithm). This is an example of the issue im having(its not part of the actual code below)
a[]={1,2,3,4,5,6}
Arr[]={1,2,2,3,4,5}
If it finds 1 in arr, it returns 0, which is fine but if it finds 2 in arr it return 1 and 1 instead of 1 and 2.
for (int q=0; q=size2;q++) {
int rs=secfunc(array1;size1;array2[q])
if(rs>=0) {
cout<<rs << "";
[Code] .....
use 2D array in function and change the array values. I do not know if I can use array by calling from a function. I have 6 row 6 column array, I used it inside a function and for the another function I just need to change 4. row 4. column and I do not want to type array to just change one part. I do not know if there is another way or not
View 7 Replies View RelatedHow can I Figure out and store the sum of EACH COLUMN in the 2D array values in a 1D array? And to the same for the average?
View 1 Replies View RelatedIts output is not correct
#‎include <stdio.h>
void main() {
int n,i,j,option;
int evensum=0;
int oddsum=0;
[Code] ....
I tried sorting arr2 from lowest to highest value, but it only gives me 4 values and then the rest are zero.
Code:
#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
cout << fixed << setprecision(1);
[code].....
I have this simple program below:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct {
unsigned long long int address;
float current;
unsigned char pressure_units;
} sensor;
[Code]...
As you can see, it has stored the last struct in all three indexes of the array. Why?
How would i go about making a program that asks the user how many elements they want in the array and then what those numbers would be.
View 4 Replies View Relatedusing Win 7 64 bit enterprise, sp1.
I'm getting unwanted values assigned to a 2D array. I'm working on a tic tac toe program as a method of building my array skills. It's just text/ascii based command prompt output, in case you are wondering.
I have a 3x3 array for the actual grid values (to determine if there is a blank, an X or an O) based on x,y position as determined by GetAsyncKeyState to use arrows for square selection.
these x,y values I use to determine the array slot, square[xX][xY]
the xX and xY values range from 0-2 respectively depending on the game square the cursor is currently in.
The problem is, some of the array values get assigned to multiple array slots, and some don't get assigned at all, although 6 of the 9 squares function correctly. It is always the same squares. (I've tried it on multiple PC's and get the same error). I reset the array to 0's when the program starts.
I have a debugging output of this array's values that show on the screen so I can keep an eye on what it is doing.
Intended operation is to select a square and assign a value of 1 indicating an X. For example, select the center square and hit the enter key it will place an X in the center square and assign a value of 1 to square[1][1].
My debugging output shows square[1][1]=1 as shown by this line of code from below
curPos(31,4); cout<<"square["<<xX<<"]["<<xY<<"]="<<square[xX][xY];
if I hit the up arrow, xY changes to 0, xX remains 1, and the cursor moves up one. If I hit enter, it will place an X in the upper center square.
Debugging output shows square[0][1]=1, but my grid tracking the values square[][] will change to square [0][0]=1, square [0][1]=1, and square[0][2]=1. function square[xX][xY]=1 get's exercised only once that I can see, yet 3 elements in the array get assigned the value of 1. square[0][0] when selected gets no value assigned.
Here is the code in question: I think the offend variables are the xX and xY, and this is the only location in the entire code where they appear, aside from declaring them.
for (a=0; a<3; a++){//reset square[][] to 0
for (b=0; b<3; b++)
square[a][b]=0;
}
drawboard();//draw large # gameboard
[Code] ...
If I have an array of two columns that have the same values and I want to change only the third column how can I go about doing this. The values of the third column will change based on the values in one of the columns which I plug into a math equation. Also how come I can't show a double value in the array?
#include <iostream>
#include <math.h>
#include<iomanip>
#include <vector>
using namespace std;
[code]...
If we have array like
int numbers [] = {3,4,8,9,6,3,2,58,6,3,2,5};
how can we fast do smth like 3*4*8*9*6*3*2*58*6*3*2*5
also numbers[0]*numbers[1]*numbers[2] etc
all must be in one loop....
how can i change the array value and display the updated value. for example this is the output beginning of the program
-----------------------------------------------------
Part Description Number of parts in the bin
----------------------------------------------------
valve 10
Bearing 5
Bushing 21
Coupling 7
[Code].....
I have an array as such and need to multiply all the values of it by each other and put that as a variable.
//for example
int array1[100]
//assume i have already input the values of each element properly up to, say, element 4
//I need to now multiply all of those values together. I think I need the size of the array to control what it multiplies (I know how to find size) ....
Problem: My code works perfectly and I only need to solve one issue. When I am calculating the average, how do I exclude the min and max values from the array?
My code:
#include <iostream>
using namespace std;
int main(){
float a[9];
int x;
int sum = 0;
for (x=0; x<9; x++) {
[code]....
I'm very new to programming and this assignment (actually my Final Project, entry level!) has already been submitted.I noticed to late that when I output my max and min values, they are not linked to string comp. The assignment is suppose to have me outputting both the Highest and Lowest company name attached to their revenue after it displays all 10 companies, etc. I completely missed that part of the assignment.
Code:
for ( int i = 0; i < 10; i++ ) {
if(rev[i]<min){
min=rev[i],comp[i];
}
Would link the 2 part of the array to max, apparently I completely screwed up there . Below is the full project.
#include <iostream>
#include <iomanip>
#include <string>
using namespace std;
int main() {
const int array = 10;
string comp[array];
[Code] .....
How i can find two equal int in array with O(n) time complexityand O(1) place complexity?
View 8 Replies View RelatedI am using pointer to display values of an array but its output is not correct example 23424,0, -323423 etc... whats the problem with my code:
Code:
#include<stdio.h>
#include<conio.h>
int main() {
clrscr();
int arr[10][10],rows,cols;
int* ptr;
[Code] ....
