I have this code in order to make a RPN calculator,but im trying to read from the console entering the expression in reverse polish notation,Also I think it will be better to use fgets() instead of scanf since the person can entere something like this 3 2 1 + x
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <ctype.h>
[Code].....
been working on this code til my eyes bled, can not get second operand to work, if i enter 1 2 3 + - it will only return 5 from the addition operand.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
[Code].....
I have my Reverse Polish calculator compiling and everything but for the assignment I need to handle a few exceptions that I can't seem to get. First off I'm trying to make the program exit if the user enters only "0" but since the input i'm using is string, I cant figure out how to code
"If the first node is 0 and the next node = NULL, return true"
Here is my code:
#include<iomanip>
#include<iostream>
#include<stdlib.h>
#include<stdio.h>
#include<string>
#include<sstream>
using namespace std;
class Stack {
[Code] .....
Write a program to convert the time from 24-hour notation to 12-hour notation and vice versa. Your program must be menu driven, giving the user the choice of converting the time between the two notations. Furthermore, your program must contain at least the following function: a function to convert the time from 24-hour notation to 12-hour notation, a function to convert the time from 12-hour notation to 24-hour notation, a function to display the choices, function(s) to get the input, and function(s) to display the results. (For 12-hour time notation, your program must display AM or PM.)
Answer:
#include <iostream>
#include <iomanip>
#include <cmath>
[Code]....
It is showing error because may be I was not able to put that if statement inside any function. find out the error sand complete the program with corrected code.
l need to write a program which writes out its command line arguments in reverse order one per line. The output from the program should look like this:
% a.out Two roads diverged in a yellow wood
wood
yellow
a
in
diverged
roads
Two
works fine without the for loop.... if i use for loop...it doesnt give the output...
Code: #include<iostream>
#include<conio.h>
#include<fstream>
[Code]....
Lets say I have my name "Kevin".
What would the program be so it reads "niveK"?
How to write the program for that?
Need to correct the errors. i've done so far.
#include<iostream>
#include<fstream>
#include<cstdlib>
#include<iomanip>
using namespace std;
int main() {
ifstream fin; char ch; int size=0;
[Code]...
1. Construct a class diagram that can be used to represent food items. A type of food can be classified as basic or prepared. Basic food items can be further classified as meat, fruit, veg or Grain. The services provide by the class should be the ability to enter data for new food, to change data for food and to display existing data about food.
using this class definition write a main program to include a simple menu that offers the following choices:
1. Add food
2. Modify Food
3. Delete Food
4. Exit this menu
2. Read a list of numbers from a file and then print them out in reverse order. State whether the list is palindromic or not.
Write a program that reads from total.dat file and displays its contents to the console. The program should allow the user to add new entries to the file.
So far this is what I've got and I'm not sure if I even started right.
#include <iostream>
#include <fstream>
using namespace std;
int main () {
ifstream dataIn;
ofstream dataOut;
dataIn.open("total.dat");
cout << dataIn;
return 0;
}
I have a file named "A6.txt" inside it has this code:
April Joe, 1, SUPER DUPER ULTRA SECRET, 02031982|
Matthews Jocob, 2, TOP SECRET, 11031992|
Garfield Kitty, 3, SECRET, 04041942|
Lake Bill, 4, MEH, 12031968|
Jones Betty, 5, WATCHLIST, 06031974|
Goodman Betty, 6, BANE OF SOCIETY, 05021952|
Very Simple, all it has is "Name, ID, Access, Date of Birth" (DOB needs to be formatted like 00/00/0000 if possible)
Output should Look like :
Client #1:
Name: April Joe
Access: SUPER DUPER ULTRA SECRET
DoB: 02/03/1982
I have been struggling to read a certificate in windows store from C++ DLL, but its not happening. from console application I can but when same code built as a DLL and tried to access from a separate console application. I think its not going to windows store to read the cert.
pCertContext = CertFindCertificateInStore((HCERTSTORE)*pCertStore, X509_ASN_ENCODING | PKCS_7_ASN_ENCODING, 0, CERT_FIND_ISSUER_OF, operator PCCERT_CONTEXT(), pCertContext);
int Error = GetLastError();
if (Error == 0)
LINFO << "
Signtuare is valid
";
else
LINFO << std::hex << Error << '
' << "GetLastErrorStdStr=
" << GetLastErrorStdStr();
it returns 80092004 GetLastErrorStdStr= C a n n o t f i n d o b j e c.
I have been trying to read a comma separated .txt file into an array and print it to console in C++. The txt file consists of two columns of double type data. For some reason the program runs, but gives blank output in the console. I want to know if I am doing something wrong. So far this is what I have:
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main() {
int i=0;
double x[10];
double y[10];
string line;
[Code] .....
I'm new to programming and i'm trying to do a certain task. I want to use a for loop to read certain data from a txt file and print them to a console. I'm trying to read student names and their grades.
Something like
3 // 3 represents the number of students.
George 97
Sarah 70
Maya 88
The data may vary but it's always in this format.
Is there a simple notation to check if a value is within a plus or minus range?
E.g.
//I read a value A. delay(50); //Read value again -calling this value B delay(50);
//Read value again -calling this value C delay(50); //Read value again -calling this value D delay(50);
//Read value again -calling this value E
Check IF first value A is within 5 of the value B and within 5 of value C, etc.
I can think of a few round about ways of doing this but is there any simple "equals to plus or minus" notation? (what I actually want to do is to check a lot more values than this and it will get very complicated with any of my solutions)....
I just wrote code that is a program for a relativity calculator. However many of my outputs (because the values tend to be large) end up in scientific notation. Although useful, its not great for the laymen, or nice looking.
How can I change it so that output is not in scientific notation? here is the code:
// This program/converter is designed to find the desired 'real' values using Einstein's theory of relativity
#include<iostream>
#include<math.h>
#include<stdlib.h>
[Code]....
My program suppose calculate postfix expression.
Ex. 5 4 + 3 10 * + the answer is 39 because if I change it to infix, it's (5 + 4) + (3 * 10)
I need to use vector to compute the value. Here is what I think. First, I save leftmost from the string. If it is a number, I push. If that is a operation, I pop twice and push the result. By doing it until the string is emptied, the vector will only contain the final answer. And here is my code
#include <iostream>
#include <vector>
#include <string>
using namespace std;
int main(){
vector<int> stack;
string input;
[Code] .....
When I put 1 1 + or 2 2 +, it showing me a correct answer, but when I put the above example which is 5 4 + 3 10 * +, it shows 30 instead of 39.
I'm trying to make an infix to postfix notation calculator. The difficult thing is th stack class is custom. It's not to hard to understand, I don't know if the fact that it is that way will not allow me to receive support. The difference is that the pop functions is as such:
stack<char> conversion;
char temp;
conversion.pop(temp);//It receives a parameter and puts the popped element in there.
conversion.peek(temp);//Places the top element in said parameter
not only that... but these are boolean functions. they return true if the operation was completed. So they can be used as conditions.
#include<iostream>
#include<string>
#include<stdio.h>
#include"stack.h"
using namespace std;
int main(void) {
Stack<char> conversion;
string infix,inter,temps;
[Code] .....
The error is that i am mismanaging parenthesis handling and i can't seem to grasp where and how.
An example input is:(35+7)-(9-2)
that input gives me:35 7 + 9 2 ) -
but another input such as :(35+7)/7
outputs as: 35 7 + 7 /. Totally fine.
double number = 10000000;
int range;//the length of the string result
string result;//holds the number in a string
ostringstream convert; //stream used for the conversion
convert << number;
result = convert.str();
range = result.length();
I'm trying to convert a double to a string and when the number goes to ten million it goes to scientific notation and it shows it in the string. How do I stop it from do that?
I have to develop script in C to print the alphabets in given notation.
Please check the attachment.
I was trying 2 write a program that would calculate the sum notation of 1/(i^2) with the starting number to be 1 and goes up to the nth term. For instance if the user inputed 3 then the sum would look like 1+1/4+1/9. I somehow made a code but it gets weird numbers which some include negative numbers... when I input a number that is above 5.
#include <stdio.h>
#include <math.h>
int main(int argc, const char * argv[]) {
int n;
register int i=1;
float b;//For part 1
[Code] ....
For some reason I can't edit printf("%f",/>/>; when I post it as the topic so ignore that part cuz Ik its supposed to be written as printf("%f",/>;
how i solve this..?
View 1 Replies View RelatedMy code compiled well(After long Messing up with my head). But, i still not satisfied of my output as i expected. My code ought to sort the object of person comparing their salary. But, its not.
Code:
#include <iostream>
#include <string>
using namespace std;
class person {
protected :
string name;
float salary;
[Code] ....
It doesn't sort the object of class person rather than it prints out the stored value as it is.
I was having problems changing the value of my head node I passed it as an argument as head which would be the address. The parameter was defined as struct node *head. like this
bool deleteNode(struct node *head, struct node *delptr)
I tried manipultaing pointer values to change head node value but it did not work. I saw some code online which used pointer to pointers(in code below) to change head node value it worked I dont fully understand why. Would like better understanding of why.
Would also like to know why the argument call needed &head instead of just head.
remove = deleteNode(&head,found); opposed to remove = deleteNode(head,found);
#include "stdafx.h"
#include<iostream>
struct node{
[Code].....
I need to write a code in c++ , to input decimal number and the output to be number in Scientific notation with 32 bits .
View 1 Replies View RelatedHow can I reverse/toggle bit like 1 to 0 and conversely, 0 to 1?
For instance: 01000100 ('D' 68) to 10111011 ('╗' 187).
Is there any way easier and more simple than:
1. Convert char/string to binary.
2. Toggle bits.
3. Convert binary back to char/string.