double number = 10000000;
int range;//the length of the string result
string result;//holds the number in a string
ostringstream convert; //stream used for the conversion
convert << number;
result = convert.str();
range = result.length();
I'm trying to convert a double to a string and when the number goes to ten million it goes to scientific notation and it shows it in the string. How do I stop it from do that?
I just wrote code that is a program for a relativity calculator. However many of my outputs (because the values tend to be large) end up in scientific notation. Although useful, its not great for the laymen, or nice looking.
How can I change it so that output is not in scientific notation? here is the code:
// This program/converter is designed to find the desired 'real' values using Einstein's theory of relativity
#include<iostream>
#include<math.h>
#include<stdlib.h>
[Code]....
how i solve this..?
View 1 Replies View RelatedI need to write a code in c++ , to input decimal number and the output to be number in Scientific notation with 32 bits .
View 1 Replies View RelatedWrite a program to convert the time from 24-hour notation to 12-hour notation and vice versa. Your program must be menu driven, giving the user the choice of converting the time between the two notations. Furthermore, your program must contain at least the following function: a function to convert the time from 24-hour notation to 12-hour notation, a function to convert the time from 12-hour notation to 24-hour notation, a function to display the choices, function(s) to get the input, and function(s) to display the results. (For 12-hour time notation, your program must display AM or PM.)
Answer:
#include <iostream>
#include <iomanip>
#include <cmath>
[Code]....
It is showing error because may be I was not able to put that if statement inside any function. find out the error sand complete the program with corrected code.
Can we change the floating point number format from scientific format to below example format ?
FROM TO
==========================
2.06374E-03 ---> 206370-8
-4.30311E-01 ---> -.430310
-4.28146E-04 ---> -42815-8
==========================
Is there a simple notation to check if a value is within a plus or minus range?
E.g.
//I read a value A. delay(50); //Read value again -calling this value B delay(50);
//Read value again -calling this value C delay(50); //Read value again -calling this value D delay(50);
//Read value again -calling this value E
Check IF first value A is within 5 of the value B and within 5 of value C, etc.
I can think of a few round about ways of doing this but is there any simple "equals to plus or minus" notation? (what I actually want to do is to check a lot more values than this and it will get very complicated with any of my solutions)....
My program suppose calculate postfix expression.
Ex. 5 4 + 3 10 * + the answer is 39 because if I change it to infix, it's (5 + 4) + (3 * 10)
I need to use vector to compute the value. Here is what I think. First, I save leftmost from the string. If it is a number, I push. If that is a operation, I pop twice and push the result. By doing it until the string is emptied, the vector will only contain the final answer. And here is my code
#include <iostream>
#include <vector>
#include <string>
using namespace std;
int main(){
vector<int> stack;
string input;
[Code] .....
When I put 1 1 + or 2 2 +, it showing me a correct answer, but when I put the above example which is 5 4 + 3 10 * +, it shows 30 instead of 39.
I'm trying to make an infix to postfix notation calculator. The difficult thing is th stack class is custom. It's not to hard to understand, I don't know if the fact that it is that way will not allow me to receive support. The difference is that the pop functions is as such:
stack<char> conversion;
char temp;
conversion.pop(temp);//It receives a parameter and puts the popped element in there.
conversion.peek(temp);//Places the top element in said parameter
not only that... but these are boolean functions. they return true if the operation was completed. So they can be used as conditions.
#include<iostream>
#include<string>
#include<stdio.h>
#include"stack.h"
using namespace std;
int main(void) {
Stack<char> conversion;
string infix,inter,temps;
[Code] .....
The error is that i am mismanaging parenthesis handling and i can't seem to grasp where and how.
An example input is:(35+7)-(9-2)
that input gives me:35 7 + 9 2 ) -
but another input such as :(35+7)/7
outputs as: 35 7 + 7 /. Totally fine.
I have to develop script in C to print the alphabets in given notation.
Please check the attachment.
been working on this code til my eyes bled, can not get second operand to work, if i enter 1 2 3 + - it will only return 5 from the addition operand.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
[Code].....
I was trying 2 write a program that would calculate the sum notation of 1/(i^2) with the starting number to be 1 and goes up to the nth term. For instance if the user inputed 3 then the sum would look like 1+1/4+1/9. I somehow made a code but it gets weird numbers which some include negative numbers... when I input a number that is above 5.
#include <stdio.h>
#include <math.h>
int main(int argc, const char * argv[]) {
int n;
register int i=1;
float b;//For part 1
[Code] ....
For some reason I can't edit printf("%f",/>/>; when I post it as the topic so ignore that part cuz Ik its supposed to be written as printf("%f",/>;
My code compiled well(After long Messing up with my head). But, i still not satisfied of my output as i expected. My code ought to sort the object of person comparing their salary. But, its not.
Code:
#include <iostream>
#include <string>
using namespace std;
class person {
protected :
string name;
float salary;
[Code] ....
It doesn't sort the object of class person rather than it prints out the stored value as it is.
I have this code in order to make a RPN calculator,but im trying to read from the console entering the expression in reverse polish notation,Also I think it will be better to use fgets() instead of scanf since the person can entere something like this 3 2 1 + x
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <ctype.h>
[Code].....
I was having problems changing the value of my head node I passed it as an argument as head which would be the address. The parameter was defined as struct node *head. like this
bool deleteNode(struct node *head, struct node *delptr)
I tried manipultaing pointer values to change head node value but it did not work. I saw some code online which used pointer to pointers(in code below) to change head node value it worked I dont fully understand why. Would like better understanding of why.
Would also like to know why the argument call needed &head instead of just head.
remove = deleteNode(&head,found); opposed to remove = deleteNode(head,found);
#include "stdafx.h"
#include<iostream>
struct node{
[Code].....
I'm trying to create a connect four game, but I've ran into a problem while trying to read valid user input.
Code:
// 4 in a row game
#include <stdio.h>
#include <stdlib.h>
#define NUM_ROWS 6
#define NUM_COLS 7
}
[code]...
If the user enters an invalid number, then it works fine, but if a character is entered, the while loop in main never breaks.
I'm new to C programming and am quiet lost, create a program that takes a start and stop time and prints the passed, or show me where I can find the information needed?
View 6 Replies View RelatedI found a for loop in an example that I don't understund fully.
Code:
for (i=64; i; i/=2)
printf("i: %d
",i);
Now this is dividing by 2 until it reach '1' and stops. But why does this stops?
I'm trying to get the user to input their 5 digit zip code but my problem is how can I stop the program after the five characters have been inputted. Also how can I only get numbers to be inputted cause so far letters can be inputted as well.
View 2 Replies View RelatedJust a quick newbie question: I'm doing a console application and whenever I open a .exe using system(), the console pauses and does not run the next instruction until I close this exe. For example when I do this:
...
system("mspaint.exe");
printf("Hello");
It opens ms paint and does not print the next message until Paint is closed. How do I work around this?
I am trying to display a messagebox, but instead of just displaying the message box, there is also a console the pops up. How do I prevent the console from popping up? I'm using Visual Studio 2012. I'm creating an empty project, but I still get the console.
View 1 Replies View RelatedMy program is designed to take a reading from a glucometer and light an LED if the reading is too high or too low. I used this code:
#include <eHealth.h>
void setup(){
pinMode(13, OUTPUT); //first alert
pinMode(12, OUTPUT); //green LED
[Code]....
The glucometer stores the tests and the code just pulls the most recent one, however even if I unplug the glucometer the first if statement keeps repeating and the LED in pin 12 keeps shining. Is it the if statement itself malfunctioning, or is the Arduino storing the data it pulled and just repeatedly plugging that into the if loop?
Having multiple issue trying to get a while loop to stop after the third entry.
#include <iostream>
#include <fstream>
#include <string>
#include <stdlib.h>
using namespace std;
int mySequentialSearch() {
int value;
string line;
[Code] .....
I am just working on the while loop right now. Then the function after I get the loop working.
Code:
#include <stdio.h>
#include <stdlib.h>
/*
You are to write a program that will allow a user to enter infinite numbers (greater than zero)(One number at a time). You must have a way for the user to stop entering values.Once the user stops, you will immediately display the following:
The lowest number entered is:
The highest number entered is:
The number of values entered is:
The average of the numbers entered is:
*/
main() {
int userNumber=0, sum=0, count=0, highNum=0, lowNum=0, lastNum = 0;
double average;
printf("Enter a number greater than 0: (Enter -1 to stop)
");
scanf_s("%i", &userNumber);
[Code]....
My program outputs everything I need except the lowest number entered. I have been spending a considerable amount of time on this problem to no avail.
If I wanted to add an emergency stop to an elevator programme should I use an if statement? Eg
Code:
If (emergency stop) {
Void main();
}
Or something along those lines?
This is a problem I have been having with every program I write since I started using SDL 2. Whenever I compile my code and run my program, everything works perfectly fine until at some point (usually after 3-8 minutes of running), the program will stop responding completely and I will have to exit out of the console to close it. The code I believe is relevant is:
void MainLoop()
{
InitLoop();
while ( !QuitMain )
[Code].....
If I change SDL_PollEvent(&Event) to SDL_WaitEventTimeout(&Event,100), then the problem goes away (I did that and had the program running for about an hour without it stop responding before I decided that it solved the problem), so I believe that the problem has something to do with event handling. Also, it might be noteworthy to mention that when I use SDL_WaitEventTimeout with the second parameter being a small number (because 100 milliseconds is a long time to wait and makes the program run at like 8 FPS), the problem returns.
