In my main I have a do/while loop, which is to iterate around the method calculateImportance while i is not equal to the numNodes.
do
{
int i;
int numNodes = Test.count();
for(i=0; i<=numNodes; i++)
[Code]....
I have been messing around with the data type node, hence why it is there are present, but, that doesn't seem to the answer
This is the function declaration in the header file.
node CalculateImportance();
So the task is to find the node with minimum value of a binary tree (not binary search tree). the input is the pointer to the root of the tree. and i cannot make recursion work when i do if conditions. here is what i have Code: /*function 3-takses as input the pointer to the root of the tree and returns a pointer to the node with the minimum value*/
CPPtr minimumvalue(CPPtr SP){
CPPtr min = NULL; //node of minimum value
if(SP== NULL){ // if there is a node, begin comparing
return NULL;
}
else{
if(SP->data<SP->left->data){ //if the node has smaller value than its left child
min = SP; //update node of minimum value
[code].....
no matter where i call my function i get errors like unhandled exception at some memory. how to use recursion in this?
So the task is to find the node with minimum value of a binary tree (not binary search tree). the input is the pointer to the root of the tree. and i cannot make recursion work when i do if conditions. here is what i have
CPPtr minimumvalue(CPPtr SP){
CPPtr min = NULL;//node of minimum value
if(SP== NULL){// if there is a node, begin comparing
return NULL;
[Code] ....
No matter where i call my function i get errors like unhandled exception at some memory. How to use recursion in this?
I'm quite new to C and these days I have been playing around with a linked list. I managed to make a working version using pointers, ad only for the sake of learning I was trying to do the same thing just passing the "Object reference" Here is the method that apparently doesn't work..
Code:
struct Node addNode(struct Node head){
int value;
struct Node *n;
printf("Please enter the value
");
scanf("%d", &value);
[Code]...
when I return the function i have something like: head=addNode(head)
Unfortunately it does not work the way I aspect. I suppose that there is something I have left out..
Code:
like n->next=&head
// passing the address of the head at the next pointer of the struct
head =*n
//copy the values of the new node to the old head..
There must be something wrong with this line.. return head; What have I done wrong?
The following code compiles and runs fine till it reaches line 16 and gets a sigsev violation which I'm not sure about as to why. I have no problem passing the object of type node** into the constructor of base and storing it into the double pointer node** copy;; but when I call the function void pass(node** temp) it crashes.
#include <iostream>
class base;
class node {
private:
node** data;
public:
[Code] .....
What my purpose here is to use a template to append an item of type T to a node of a ptree (boost)
Code:
template<typename T>
ptree& stick(ptree& tree, char *location, T const & t) {
return tree.add(location, t);
}
Here I can't compile
Code:
struct hdr {
WORD weights_per_vertex;
WORD weights_per_face;
WORD num_bones;
[Code] ....
Doesn't the type of T includes the type struct hdr?
Code:
returnType operatorOperatorSymbol (parameterList); // syntax for operator overloading
Class Fraction
public:
Fraction operator-(const Fraction& f1){
Fraction r;
return r;
}
Is this even syntactically correct? It gives me errors. Im just trying to compile it without errors. I think the function makes sense since its returning a type Class
understand the below program.
Why I'm getting output y is 6.000000
Code:
#include <stdio.h>
int square(double a);
int main()
[Code].....
Say I have overloaded functions with different arguments AND return types. Each set of argument has only one corresponding return type.
Code:
Vector grad(Scalar)
Tensor grad(Vector)
Later I have:
Code:
template <class T>
void test(T x) {
... Y = grad(x)
}
Then how do I automatically declare the type of Y. Do I need to make the grad function a template and specialize each of them ?
I am new to c++ and trying to learn. for instance. i have a struct and method.I am trying to learn what i can do with the method if i define the return type as struct type.
struct S {
int age;
string name;
};
S method() {
//what i can do in here. with the Struct. I mean can i reach members of the struct. etc
}
I am wondering why return type for an assignment operator cant be a void or int? Cant I write assignment operator for student class like this as we do nothing with returned value?
Student {
char name[20];
int marks;
public:
student(char*name,int marks)
[code].....
i'm getting a new error is a wrong return type.
WebAPI.cs
namespace DarkAPP___WForm.Libs {
class WebAPI {
System.Net.WebClient wc = new System.Net.WebClient();
public WebAPI() {
[code].....
i heard that it was int but later it is deprecated , so at present what is the default return type of a function ?
View 4 Replies View Related/*
* symboltable.c
*/
#include "symboltable.h"
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "include/utlist.h"
[Code] ....
I want my function to return the type mpz_t, but I'm not sure how?
I've tried: mpz_t MyFunction(mpz_t A, mpz_t B){}
But it didn't work, here is my code so far, I have bolded the parts of the code which are causing errors and added the errors in the comments:
Code:
#include <iostream>
#include <mpir.h>
using namespace std;
???? A(mpz_t m, mpz_t n){
mpz_t mmo; //used to store the value of m, minus one
[Code] .....
Is there a way around this?
I am having problems with my function definition of a function that should return a structure value.
This is the error I get compute.cpp(9): error C2146: syntax error : missing ';' before identifier 's_advertisebus'
The error is on the line where I start my function definition typing my function type as a structure. A long time ago in c the keyword struct is used with the structure type like struct s_advertisebus s_readadbus(). I tried it both ways but I got errors.
// struct.h
#ifndef STRUCT_H
#define STRUCT_H
struct s_advertisebus {
int nnumberofads;
float fpercentused;
[Code] ....
I always have confusions while using pointers with functions both as arguments and as return type.
View 1 Replies View RelatedIf we are using strcpy() for copying the string. As we are passing pointers to it It will copy the string & no need to return the string .This function will finely work with return type as void then why Ritchie has used it as char* strcpy()?
View 4 Replies View RelatedIs this really the preferred way to get the return type, for use in a derived class, of a function defined in the template parameter?
template<class PARAMETER> class C {
protected:
typedef typeof (reinterpret_cast<PARAMETER*>(0))->function() returntype;
};
This works just fine for me, but seems inelegant.
I have this code:
#include <iostream>
#include <vector>
#include <map>
#include <string>
using namespace std;
[Code]...
and it does not compile.
The error is:
test.cpp: In function ‘int main()’:
test.cpp:20:30: error: no matching function for call to ‘func1(std::vector<int>&)’
test.cpp:20:30: note: candidate is:
test.cpp:8:45: note: template<class T, class U> std::map<T, T> func1(U)
test.cpp:8:45: note: template argument deduction/substitution failed:
test.cpp:20:30: note: couldn't deduce template parameter ‘T’
I am trying out a technique for a singleton class:
// access controlled singleton, accessed through function "instance()"
// singleton is constructed in this function
// so that constructor and destructor will be used
class single {
// private constructor/destructor
[Code] .....
Playing around with the code in main(), I am having trouble with auto:
single& s = single::instance(); // works fine
auto a = single::instance(); // error ~single() is private
When I make the destructor public, the output of the program is:
ctor
dtor
dtor
So I fixed this by typing auto&. I'm still confused though, why wouldn't auto know I am returning a reference?
I have a class where a method based on the type passed I should return a value.
prototype declared in the header file:
template <typename T>int getNum() const;
Code of the cpp file:
template <typename T> int class::getNum() const{
int c = 0;
for(int i=0;i<v.size();i++)
if(typeid(*(Pro*)v.at(i)) == typeid(T)) c++;
return c;
}
To invoke the method as I do:
ostream & operator << (ostream & os, Pro & obj) {
return os << obj.getNum();
}
I sew lot of sample for ASP WEB API. In althose link the post method is using
HttpResponseMessage as return tyope
Is it possible to use return type bool in WEB API post method?
I am writing a class Player which has several char arrays as private fields. I am trying to write a method which returns an array as a pointer, but doesn't alter the array in any way, thus the const.
Here is a snippet:
Code: class Player
{
private:
char state[MAX_STATE_CHAR + ONE_VALUE];
int rating;
char last[MAX_NAME_CHAR + ONE_VALUE];
char first[MAX_NAME_CHAR + ONE_VALUE];
int groupNumber = NEG_ONE;
public:
char * GetFirst() const
{
return first;
}
Visual studio is saying that the return type doesn't match.
I am trying to create a flexible interface for my CL application. And what i have is this :
Code:
using namespace std;
// iplcp -i queryFile -d databaseFile
template <typename INT, typename CHARA>
class API {
vector<string> files;
vector<INT> flags;
[Code] ....
and in main :
int main(int argc, char **argv){
//set variables
API<int, char**>args(argc,argv);
cout << "In file: "<< args.GetOpt("i") << " Db file: " << args.GetOpt("h") << endl;
}
// first thing to be printed should be string and the second int
I know this is not probably the best way to but i am laying around and was curious if something like this could work . Are there any good C++ templates for CLI applications from which i could learn?
I am working on C# Project [Windows Form Application], to update treeview nodes from excelsheet [xls] Cell [row i, Column 3] Values, while on selecting treenode, it should update corresponding Column 4 Value [row i, Column 4]. For me, Treenode are populated successfully, but on selecting the treenode, it always display first Element of treenode [Not selected one].
Populated Treenode from Excel as: [ Update Child Nodes from Column 3 elements [Column 2 Contain Parent node name and Column 3 have Child Node name], if Column 2 Value is same as Parent node name [My Module], update the child nodeunder same Parent node.]
for (int i = 0; i < worksheet.UsedRange.Rows.Count; i++) {
string mynode = ((Excel.Range)worksheet.Cells[i + 1, 3]).Value2.ToString();
string mynode2 = ((Excel.Range)worksheet.Cells[i + 1, 2]).Value2.ToString();
[Code] ....
On selecting the Child Node, it always give 1st Parent node. Instead of Selected Node.
for (int i = 0; i < worksheet.UsedRange.Rows.Count - 2; i++) {
string mynodetext = ((Excel.Range)worksheet.Cells[i + 2, 3]).Value2.ToString();
string mynodetext1 = ((Excel.Range)worksheet.Cells[i + 2, 4]).Value2.ToString();
if (treeView1.SelectedNode.FirstNode.Text == mynodetext) {
this.richTextBox1.SelectedText += Environment.NewLine + mynodetext1 + Environment.NewLine;
}
}
How to get correct selected Node.
