Assume input is char array holding a C-string. Write code that counts the number of elements in the array that contain an alphabetic character.
counter = 0
for (i = 0; i < SIZE; i++) //size being whatever input's size is
{
if (isalpha(input[i]))
{
counter++;
}
}
Is there anything wrong with this method?
I have
#define LessSymbol -1
#define MoreSymbol 1
#define NeitherSymbol 0
#define MAX_COLS 20
#define MAX_ROWS 20
#define MAX_CHAR 3
char averageMap[MAX_ROWS][MAX_COLS];
char rowCount[MAX_ROWS][MAX_CHAR];
char colCount[MAX_COLS][MAX_CHAR];
I have other stuff in the code, but basicly, at this stage i have a map of 1's,-1's and 0's in a 20 x 20 map. I just want to count the occurrences of each and basicly tally them in the 3 colums/rows at the end of the bloc. so far ive tried many different if statements, here is what i tried last.
for(row = 0; row < MAX_ROWS; row++){
rowCount[row][0]=0;
rowCount[row][1]=0;
rowCount[row][2]=0;
} for(col = 0; col < MAX_COLS; col++){
[Code] ....
Its outputting 20 as a result for each row. Its like its counting the symbol no matter what it is.
How I can go back to an alphabet letter I want that letter to land on? Adding capital letters. Lower case letters not needed.
For example;
- User enters "XYZ"
- Program comes up with the next 10 letters which would be something like 'HIJ' (Since X+10 = H, Y+10 = I, Z+10=J)
My problem is with the last few letters. The program goes to the next 10 characters ahead of those characters rather then the alphabet.
Program example: (What I want shown)
"What are your three favorite letters?" XYZ
"The next ten letters are: HIJ"
Error example: {It goes to the next 10 characters instead of the next 10 alphabet letters.)
"What are your three favorite letters?" XYZ
"The next ten letters are: ^[a"
Code example: (I've tried other ways as well.)
char a, b, c;
cout << "What are your three favorite letters?";
cin >> a >> b >> c;
cout << "The next ten letters are: " << a+10 << b+10 << c+10 << endl;
I have a function that is suppose to swap positions of 2 letters but It doesn't seem to work. Im passing in the array of char into the function.
void swapletter(char word[]) {
char temp1;
int swap1;
int swap2;
cout<<"What is the first location: ";
cin>>swap1;
[Code] ....
I now know how to count integers with while loop but I'm not sure how to count the integers with array.
So the question is:
1. program should keep reading integers as long as the integers are within [0,9999]
2. when user typed the integer not between 0 to 9999, the program print out the numbers of integers that were typed.
Sample
3
3
3
9999
9999
-1
You entered 3 3 times.
You entered 9999 2 times.
#include <iostream>
using namespace std;
int main() {
int i=-1;
int x;
int numbers[10000];
[Code] ....
I cannot use "do" ....
I have to count the letters from a text file into an array so the first spot is the number of A's second spot number of B's and so on then take the array and sort it in decending order how could i do this without loosing track of where the numbers go so if there are more b's than a's they switch but how will i know where each letter has moved in the array after it has been sorted?
View 1 Replies View RelatedI've made a code to check whether or not a save file has been created correctly, but for some reason it always returns this line: readdata[qa]=='1' as true. in which qa is the counter I use in a for loop and readdata is a character array consisting of 50 characters that are either 0, 1 or 2.
this is the entire code:
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
[Code]....
at first is also went wrong at line 22 and also returned that as true, but then I added brackets and it worked.
I am trying to concatenate two words from a file together. ex: "joe" "bob" into "joe bob". I have provided my function(s) below. I am somehow obtaining the terminal readout below. I have initialized my memory (I have to use dynamic, dont suggest fixing that). I have set up my char arrays (I HAVE TO USE CHAR ARRAYS (c-style string) DONT SUGGEST STRINGS) I know this is a weird way to do this, but it is academic. I am currently stuck. My file will read in to my tempfName and templName and will concatenate correctly into my tempName, but I am unable to correctly get into my (*playerPtr).name.
/* this is my terminal readout
joe bob
<- nothing is put into (*playerPtr).name, why not?
joe bob joe bob
seg fault*/
/****************************************************************/
//This is here to show my struct/playerInit
[Code]....
This is going to seem like a stupid question but how can I count the elements of a const array. Surely c++ compilers provide a count for const arrays?
const wchar_t* ItemHandler::itemNames[] = {L"Coins", L"Matches"};
const wchar_t* ItemHandler::itemIconLocations[] = {L"./media/Items/coins.png" , L"./media/Items/matches.png"};
const bool ItemHandler::itemStackable[] = {1, 1};
I want to count the elements so if the server sends a bad item id it won't crash every client in range lol. I heard that the sizeof keyword returns the size of the array in bytes. I used to think the size of keyword would return the element count but found out it isn't.
I am new to coding Here is the problem. Have a program prompt the user for a filename to open. Change every alphabetic character in the file to a capital letter. Numbers and special characters should not be changed. Print the output to the screen.
Here is my code so far but i am only returning the last line of text capitalized from the file. I am trying to get the program to display all of the three lines of text from the file capitalized. The program displays the file correctly before i try and convert everything toupper();
Code:
Code: #include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <ctype.h>
int main()
{
char line[81], filename[21];
int i;
FILE *inFile;
[Code]...
I need to do a function that copy every word from a text to a char word. How can i do it?
View 5 Replies View RelatedThis for loop replaces the stars ******** in an array that contains a word to be guessed with the correct letter (c) that the user inputs if the word contains that letter.
Problem: After every guess the same hidden string of stars ******* is displayed instead of ex: ***W**** (assuming W was entered by the user)
How can I update the old ******** string in the Stars array with the new string that includes the correct letters chosen, so after every correct guess at a letter in the word a new string is displayed including the correct letters chosen?
I'm pretty sure I have to use strcpy but not sure how to implement it using a loop.
Code:
for(i = 0; i < strlen(unscrambledWord); i++) {
if(unscrambledWord [i] == c) {
Stars[i] = c;
} }
I was writing generic class Array (based on counting access to elements)and i got compiling error I cannot even understand (in vs2012).
Code: [URL] ....
Error: [URL] ....
I wrote this simplified version of a program i am writing that parses data in UDP packets. In the process of doing so i pretty much answered all my questions and fix all the problems i was having.
decodeSystemMap function will be in loop, and will proccess packets that have mostly the same data, only a few items will be added or changed or deleted.
whats the best way to check if there are any new, deleted, or removed items in the packet and only modify those?
Is there anything unsafe / dangrous about the way the code is now?
Code:
/* * File: main.c
* Author: david
*
* Created on May 23, 2013, 11:57 AM
*/
#include <stdio.h>
#include <stdlib.h>
[Code] ....
I have the following code which attempts to assign a u_int8 array of 256 to an unsigned char[256]:
Code:
unsigned char testData[256]=pSample->data;
I get the compilation error:
error C2440: 'initializing' : cannot convert from 'const uint8_t [256]' to 'unsigned char [256]'
What is the safe way to cast or convert here?
I am writing code to multiply two int arrays and in my one function i am trying to convert the char array into an int array. I have tested many parts however i can not find the problem.
Code:
struct integer* convert_integer(char* stringInt){
struct integer *converted = malloc(sizeof(struct integer));
int length, i, *ints;
ints = (int *)malloc(10001 * sizeof(int));
length = strlen(stringInt);
printf("stringInt: %s with length of %d
", stringInt, length);
converted->size = length;
[Code]...
Let's say i have some text in char array Code: char text[] = "Hello my friend"; How can i get a seperate words from it? It should be like
Code:
char a[] = "Hello";
char b[] = "my";
char c[] = "friend";
Is it possible to do?
I have an int array with the binary value of a char. How to to turn it into a char? I can transform it to an int but then I'm stuck.
Code:
#include <stdio.h>
int main() {
int a[260] = {0,1,1,0,0,0,0,1};
char buf[260];
int b=0;
for(int i=0; i<8; i++) {
b=10*b+a[i];
}
itoa(b, buf, 10);
Code:
#include <stdio.h>
char * strcpy(char *restrict s1, const char *restrict s2);
struct item {
char title[20];
struct item *next;
} firstCard;
int main (){
strcpy(firstCard.next->title, "whatever");
}
I am unable to set firstCard.next->title
I have some code:
char cHomeTeamFaceOffsPercentageWon[100];
memcpy(cHomeTeamFaceOffsPercentageWon,cSqlHomeTeamFaceOffsPercentageWon,100);
After this, for example, cHomeTeamFaceOffsPercentageWon is, "29%".
Then, I use
std::string szwPercentageWon = std::string(cHomeTeamFaceOffsPercentageWon);
szwPercentageWon is then, "2". Shouldn't this convert correctly, to "29%" as well.
Or is there something I'm missing? Maybe the termination character, or something.
I like to use a Pointer to char array. And then I would like to do a Pointer Arithmetic by incrementing the Pointer. Finally I would like to see the Addresses of the Pointer to each of the char Array Elements. I had created a program below, but I am not getting any Addresses from my Pointer.
#include <iostream>
using namespace std;
int main () {
int ArraySize;
char ch[]= "This is a Char Pointer";
char* iPtr = ch;
[Code] ....
I have this code:
#include <iostream>
#include <string.h>
#include <fstream>
using namespace std;
ifstream f("input.txt");
ofstream g("output.txt");
[Code] .....
This program make a copy of the source array, then it removes each character and shows the obtained array.
And when i insert "abcdefghijkl"
it should show this: "
#include <iostream>
#include <string.h>
#include <fstream>
using namespace std;
ifstream f("input.txt");
ofstream g("output.txt");
[Code] .....
I am working on a program to find uppercase, lowercase and digits in a 2D char array. When I try to use an if statement to increase the counter, I get an error "no conversion from 'int' to 'char*'". This is the if statement I am using.
if(myArray[j] <='9' || myArray[j] >='0')
I want to assign a char to an array inside an if statement after the user has input the grade as an integer, but it has to fill an array with characters, such as:
char grades[5];
int grade;
char A, B, C, D, F;
cout << "Enter da grade" << endl;
cin >> grade;
if (grade < 59) {
grade[0] = F;
[code]....
A, B, C, D, and F won't transfer to the array, thus giving me the uninitialized variable error in microsoft visual studio 2010.
I want to convert int to char array for get the total of digits like this..
Code:
int total;
char charnum[2] = (char)total; //this is the problem
int num = 0;
for (int i = 0; i <2; i++)
{ num += charNum[i] -48;}
cout << num;
If total was 42 i want to get output as 6. for this purpose i want to convert int to char.
The following is something I am not clear about. Multi dimensional char arrays and the displaying of them.
Code:
#include <iostream>
using namespace std;
main() {
//char test[5][5]
[Code] .....
The commented out expression didn't run at all but the double quotation mark one did, unfortunately, it gives me a hexadecimal display. How can I get it to display like this:
*****
*****
*****
*****
*****