tell me what is wrong here ?
#define LOG_MACRO(format,args...) printf(format,args)
#define TEST_MACRO(__arg1, __arg2, __format, args...) LOG_MACRO("ARG1: %s, ARG2 : %s" ## __format, ##args)
char* arg1 = "test";
char* arg2 = "test";
TEST_MACRO(arg1,arg2,"Testing Macro %s","foo");
error: pasting ""ARG1: %s, ARG2 : %s"" and ""Testing Macro %s"" does not give a valid preprocessing token
I have a problem in using ATL 7.0 string conversion macros.
My codes looks like this, which uses ATL 3.0 string conversion macros in the past:
Void Myfunc()
{
USES_CONVERSION;
LPSTR lpszA;
LPWSTR lpszW;
If (...) {
CString strText;
If (...) {
If (bUnicode)
[Code]...
But since 3.0 macros do not support large strings, I want to switch to 7.0 macros, but have problems. Based on the [URL]... samples, I should declare CT2A pszA(strText) or CT2W pszW(strText) within the if and else bodies, as below:
Void Myfunc()
{
USES_CONVERSION;
LPSTR lpszA;
LPWSTR lpszW;
If (...) {
[Code]...
However, in such a case, after running to the codes using lpszA or lpszW, both CT2A and CT2W will be destructed so lpszA and lpszW will be invalid. How to solve this problem?
I'm trying to concatenate two arrays after their multiplied together, and not only can I not figure how to combine the two arrays, but I'm experiencing an error in the add function.
#ifndef _MATRIX_
#define _MATRIX_
#include <string>
class Matrix {
private:
int a, b;
[Code] .....
I have this simple "C" code where a new string is being built in each run of the loop. The string keeps concatenating, however, instead of starting anew.
Output should be:
,
,
,
,
,
,
But it’s coming out to be:
,
,,
,,,
,,,,
,,,,,
,,,,,,
Here’s the code (string is basically a char* type):
Code:
for (i = 0; i < size i++){
char* outputLine = NULL;
outputLine = realloc(outputLine, strlen(",")+1);
strcat(outputLine,",");
printf("
===> Output = %s",outputLine);
free(outputLine);
outputLine = NULL;
}
I am programming a translator, and I have it so that it detects words with spaces both in front of and behind them, so I did "string.append(space);" where space equals " ". That added a space to the end, but I still need a space added to the front.
View 1 Replies View RelatedI have a problem who must print the sentences who have lenght more than 20 characters. I dont know why, but it prints just the first words. Look what i made.
#include<stdio.h>
#include<conio.h>
int main()
[Code]....
For instance :
Give the number of sentences : 3
First sentence : I like the website bytes.com
Second sentence : I like more the website bytes.com
Third sentence : bytes.com
After I compile the program it should print the first two sentences.
I tried to add 2 or more strings together but failed.
eg I would like to add "KK" & "LL" together by adding but it couldn't work.
string string_B = "KK";
string string_C = "LL";
string_A = string_B + string_C;
1. I finished reading a beginning C book, and in the section about arrays, it says that one string can fit in a character array (char arrayname[]) but there cannot be a string array (string arrayname[]) that have multiple strings. Is
Code: string arrayname[4] = {"one", "two", "three"}; not valid?
My compiler lets me run it and it works, but why is the book saying it's wrong?
2. I know you can represent multiple strings in a character array by:
Code: char newarray[10][4] = ("one", "two", "three");
because [10][4] indicates that there should be four newarrays created with a max of 10 characters each, but is
Code: string multiplestrings[10][4] = ("i love you", "hello come to me", "i don't get C"; "hello world", "what are arrays"; "i am happy", "I am learning how to code"); valid?
Does multiplestrings[10][4] basically create 4 string arrays that have a maximum of 10 different strings within each string array?
How join two strings? basic reason is add given filename little text to end. I try do by hobby not school project program which converts files format x to format y.i dont say which formats becouse reading and writing is almost done. (only little amount code is needed).'
View 2 Replies View Relatedjavascript:tx('quote')
void family () {
string father;
string mother;
string kids;
int x;
int y=0;
[Code] .....
How am I allowed to but the 3 strings father, mother and kids in a array?
None of my string is coming out onto my output file..
void OutputHeading (ofstream& fout, string CLASS_EXERCISE,
string PROGRAMMERS_NAME);
void OutputDivider (ofstream& fout, int WIDTH,
char symbol);
void OpenFiles (ofstream& fout, ifstream& fin);
[Code] .....
I've got a very simple but annoying problem.
if (letter3=="
"){
letter3==letter;
PrintCharacterLineEnd();
This is a code. the string "letter3" contains the string "
". What I want to happen is when, letter3 contains the text "
" I want to go to the function PrintCharacterLineEnd.
However, as of right now it's not working.
I need to make a small program with a function with this prototype: void f(char *a,char *b) that adds two numbers represented as strings without using conversion operators or other tricks.
View 17 Replies View Relatedwhy all strings are always constant?
View 2 Replies View RelatedI have a vector I want to add book titles to, then i want to print my updated vector. This is best I have come up with but the program fails at the getline line. why?
string book;
cout << "Enter book to add: "<< endl;
getline(cin, book);
books.push_back(book);
for(int i = 0; i < books.size(); ++i) {
cout << i+1 << ". " << books[i] << endl;
}
The problem with this code is that there are no errors showing, but when i compile the program, the if else statements do not carry out as they should do. Both if statements show the same answer, for example the second if statement. If I type Y or N then I get the same thing, 'You will now choose an event'. How do i get rid of this problem? Is char supposed to be used or string?
#include <iostream>
#include <iomanip>
#include<stdlib.h>
[Code].....
How would I alphabetize this with the different strings? Would I just need to use a bubble sort?
Code:
#include <iostream>
#include <string>
#include <fstream>
[Code]....
Code:
#include <iostream>
#include <string>
using namespace std;
int main()
[Code] ......
How do I link the strings to the integers?
I am trying to figure out how to go about comparing two strings of numbers. I have two files that both contain numbers 1-50, one file has multiple repeating numbers while the other one just has 1-50.
I want to compare the files and count how many of each number a occurred and make a chart with * next to the number. First I figured I would use the strings like an array and compare them using nested loops. Then I noticed I have single and double digit numbers. The numbers in the files are printed as:
1 44 5 34 4
2 22 7 55 4
...... etc
Compared too:
1
2
3
4
5
......
50
I thought about using string stream and converting the string to int but wouldn't it just be a huge number when set to the int variable? Then I thought about a array initialized with 1-50 and compared to the file but I still have the issue with single and double digit numbers.
My question is how can I just read one number at a time, either double or single digit?
I am having trouble converting strings in my application.
This is the code that is eventually getting called, the first parameter takes a LPCWSTR
Code:
hr = m_pGraph->RenderFile(m_filePath, NULL); // takes LPCWSTR This is where the trouble begins.
The compiler shows that sResult is proper but after I try to convert a std::string to a wchar it prints garbage
Code: const wchar_t* m_filePath = (wchar_t *) oDb->GetNext().c_str();
Code:
std::string CSqlLiteDatabase::GetNext() {
sqlite3_stmt *oStmt = nullptr;
std::string sql = "SELECT path || filename FROM table WHERE id = 1";
char message[255];
[Code] ....
I have to read data from a text file, load it into an array and then bubble sort it! Here is my code:
Code:
#include <iostream>
#include <string>
#include <fstream>
[Code]....
Basically what i am trying to do is that sort the names of 10,000 movies and then write those names to a text file. It gives an error in the nested loop by underlining arr and tells that no suitable conversion function from std::string to const char* exists.
I currently have a structure that contains strings.
What I would like to do is randomize these strings so that for example the user picks an input, one of these strings will display.
Is it possible to do with the rand function or do I have to go about creating my own functing, assigning values to these strings somehow etc. etc.
I tried reading up on it but as far as I could realize you could only use rand () with numbers, set values etc.
Code:
struct sample_a
{
string mot1 = "heej";
string mot2 = "haj";
};
[Code] ....
I'm trying to sort strings as alphabetical but somewhere i have error.
Code:
#include <stdio.h>
#include <string.h>
int main(){
char s[100][20];
int num;
char temp[20];
int i,j;
[Code]....
I have a huge xml file from which the key and value attributes are selected among other things.
Code:
foreach (
XmlNode node in
configProductCode.SelectNodes("/configuration/appSettings/add"))
{
ConfigProductCode cpc = new ConfigProductCode();
XmlAttribute keyAttr = node.Attributes["key"];
XmlAttribute valAttr = node.Attributes["value"];
// etc
}
How does C# handle the instantiation of literal strings? does it make a new object with allocating heap memory on every iteration or just once?
It appears that when you enter command line arguments or use fgets() to input a string you can assign that string to another string variable using the assignment operator. But when you read from a file, you can't do that, you get a segfault. It seems the only way to get around that is to malloc the string and use the strcpy function.
Code:
#include <stdio.h>
struct person {
char *names[2];
};
void readFile(struct person p){
FILE *file = fopen("names", "r");
[Code]....
I'm wondering how to access Buffer 1 and 2 via the pointer array;
Code:
char *BufPtrs[3];
char Buffer1[64];
char Buffer2[64];
BufPtrs[0] = Buffer1;
BufPtrs[1] = Buffer2;
BufPtrs[2] = NULL;
I thought that if I were to access Buffer1 via BufPtrs[0], I would simply just put an * to it before printf()-ing or store it in a char[] (equivalent to a string).
