Visual C++ :: Finding Temperature At The End Of Interval But Can't Seem To Get Answer?
Oct 30, 2013
I've been trying to get the numbers for hours now but i can seem to get it right. Here's the problem below:
During the initial period, when the heater is not yet functioning at peak efficiency the heating will increase the temperature inside the building at a rate given by the following equations. During the initial period when the air conditioner is not yet functioning at peak efficacy the air conditioner will decrease the temperature inside the building at a rate given by the same equations.
Interval = (Time since turning on / 2.0 ) - 3.0
Factor multiplying Temperature change per minute = exp( Interval) / ( 1 + exp(Interval) )
These equations can also be used after the heating or air conditioner reaches peak efficiency. These equations converge to 1, so after the heating or air conditioner reach peak efficiency these equations will always give a value of 1.
the value of these equations needs to be multiplied by the RATE TEMPERATURE CHANGES. The RATE TEMPERATURE CHANGES is EITHER the change in temperature inside the building in degrees Celsius per minute caused by heat being extracted by the air conditioning OR the change in temperature inside the building in degrees Celsius per minute caused by the heat being generated by the heating .Temperature change in degrees per minute = Factor multiplying Temperature change per minute * RATE TEMPERATURE CHANGES
Temperature at end of this interval = Temperature at the start of the interval + temperature change due to heat escaping during the this interval + temperature change due to heat generated by the heating system during this interval + temperature change due to heat removed by the cooling system during this interval
i have a:
...rate of -.05 for heat escape w/o cooling or heating
...rate of 0.10 for heat escape w/ cooling
...rate of 0.125 for heat increase w/ heating
...Starting temp=38.00
...Time interval 3.50
I can't seem to find the temp at the ending interval? What i tried doing:
Code:
#include<iostream>
#include<cmath>
using namespace std;
int main () {
double intervals=0.00;
double tempPerMin=0.00;
[Code] ....
The temperature at the end of the interval is suppose to be 37.81 but i can't get the answer. I'm pretty sure this is a logical error from the equations i used but i can't seem to find it.
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#include <iostream> #include <iomanip> using namespace std;
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Big picture atm:
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#include <iostream> using namespace std; //prototypes void getData(double arr[]);
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#include <iostream> #include <iomanip> using namespace std; //function prototypes int getFahrenheit(); double calcCelsius(int tempF)
[Code] ....
for some reason it keeps giving me a Error C2144: syntax error: 'int' should be preceded by ';' on line 16 column 1 Error C2143: syntax error: missing ';' before 'return' on line 34 column 1 IntelliSence: expected a ';' on Line 34 Column 2
I have tried to fix both of these problems and no matter what I do I either get more errors or they wont go away...
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#include "stdafx.h" #include <iostream> #include <iomanip> #include <fstream> #include <string> #include <stdlib.h> using namespace std; int progfiles() {
[Code] ....
This is the code, most likely the section that is surrounded with "///" contains the problematic "functions." This is the command Line output...investigate why they're dieing or continue on your journey?(i-investigate/c-continue) got input and answer
i c i Press any key to continue . . .
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"1 Do you want to go investigate why they're dieing or continue on your journey?(i-investigate/c-continue) 2 8 i 7 3 4 You continue on picking up speed to get to the egg first.. and.. Oh No, You accidentally bumped into the walls! 2 12 5 1 You go over, and as you realize the walls are acidic and that's why the other sperm are dieing.. 2 6"
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#include <iostream> using namespace std; int main() { int celsius; int fahrenheit;
Note: Windchill Temperature is only defined for temperatures at or below 50 degrees F and wind speeds above 3 mph. Bright sunshine may increase the wind chill temperature by 10 to 18 degrees F.
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My Code is :
#include <iostream> using namespace std; int main() { double fahrenheit, centigrade; cout << "Enter the temperature in Fahrenheit: "; cin >> fahrenheit; centigrade = (5/9)(fahrenheit-32); cout << "The Temperature in Centigrade is " << centigrade << endl; return 0; }
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