C++ :: Turning Arabic Numerals To Roman Numerals?
Nov 11, 2013
this program is supposed to turn Arabic Numbers into Roman Numerals, but after making the program shown below I only am able to get some alt codes to show up (I got a green lantern symbol to show up)
How would I fix this program to show Roman numerals?
#include <iostream>
#include <climits>
#include <cctype>
using namespace std;
int main(void)//makes all values void until entered {
system("color 0C");
while(true)
[code]....
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Dec 5, 2013
About exercise 7 of chapter 10 of PPP (page 372): changing the calculator to gives us the result of the roman numerals, like XXI + CIV = CXXV.
At *first* time there are two solutions for solving it in my mind.
First is, giving each roman number to a function like the one existing in exercise 6 and then get their integer numbers and then calculate them by the calculator of chapter 7 and finally make a function to convert the result to roman mode. (simpler)
Second is to change the calculator from chapter 7 to calculate roman numbers inside itself and gives the result again in roman mode. (harder)
As an important step of ‘solving the problems’/’programming’, how can I make decision to choose a solution for solving a problem.
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Nov 19, 2014
how to convert integers -> Roman Numerals using both if & switch statement.
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Feb 26, 2014
Program to convert a date entered into roman numerals. I can only use one output prompt to get the date, so that makes it more difficult. Here is what i have, but how to go about the rest of it.
#include <cstdlib>
#include <iostream>
#include <string>
using namespace std;
int array_date[20];
char I; // one
[Code] .....
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Mar 23, 2015
I've Been working on a program that acts as a form of Roman numeral calculator, I input Roman Numeral Characters, and the program (is suppose to) output the corresponding digits. *Not allowed to use for loops or arrays.
Input:
MCCXXVI
LXVIIII
+
Output:
The First number is 1226
The second number is 69
Arithmetic operation is +
the sum of 1226 and 69 is MCCLXXXXV (1295)
However, when I run the program:
input:
MCCXXVI
LXVIIII
+
Output:
The first number is 77
The second number is 76
Arithmetic Operation is +
The sum of 77 and 76 is (infinite loop of I's) (153)
I noticed that when I input MCCXXVI, it only takes the first character (I thought cin.get() was suppose to stop this?), and returns the ASCII decimal value of that, instead of the integer value that I assigned to each letter. Why i get an infinite loop, and how to fix it.
#include <iostream>
#include <iomanip>
#include <string>
#include <cmath>
using namespace std;
const int I_Value = 1;
const int V_Value = 5;
[Code] ....
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Oct 11, 2013
So I am trying to write a program that converts roman numerals into decimal numbers. I so far have come up with:
Code:
#include <stdio.h>
#include <ctype.h> // importing the tolowerfunction
//variables
int decimal, total;
char numeral[];
[Code] .....
But each time I compile it, it times out as if it were hitting an infinite loop. I have a feeling that I am not passing an individual character to the roman_to_decimal function but am unsure why.
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Dec 10, 2014
I have a problem with transforming a string, for example
"13 + 19"
and store this in a list as seperate integers,
list = {13, 19};
and another list with the +, -, /:
list2 = {+};
this is my function:
int evaluate(char* formula, int* result) {
struct List *listofintegers = list_create(); //creates a list, this is the structure:
/*
struct ListNode {
int value;
struct ListNode* next;
[Code] ....
This is how i execute my function in my main.c:
int value;
evaluate("19 + 16", value);
This is what i get in my prompt:
I will also have to seperate the +, - and / in another list,
I don't even know how i can get my string when char* formula is given as an argument...
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May 14, 2013
I don't know how to start with it, first thing that came up to my mind was "loop through an array of bits" in bitmap (monochromatic), but I can't get the bits. Here's code I have:
#include <iostream>
#include <fstream>
using namespace std;
unsigned char* readBMP(char* filename) {
[Code] .....
No errors, it's working fine but I just can't get the bits of picture. I've tried to "cout" values form header (width, height) and they're ok, but I wonder how to get representation of picture itself. I thought that this code will give me something like array of 1 and 0.
I have to convert black and white (monochromatic) bmp image to min. finite automata.
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Jul 21, 2013
So I have a code like this one below :
void get_sum( INNER_ID id, vector<INNER_ID>& dont_check ) {
vector<INNER_ID> below = get_below( id );
vector<INNER_ID>::iterator second;
[Code]....
I use this algorithm for my "crappy" physic engine, so the point of this algorithm is to get the sum of mass below an object. get_below( id ) function can get the ids of what object is below them.
But before I need ids of the object below them to apply impulse, force, and some other physic stuff.
One object doesn't neccesarrly rest on top of one object, it can rest on 2 object or more.
when I look at it, it resemble a tree, maybe it's not. I just don't really know very much about tree algorithm
I cannot optimize a recursive code so I think, I better turn this into an iterative but I cannot seem to find a way to do that
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May 28, 2014
Im programming a roguelike game using visual c++ Microsoft express 2010 and i made a multidimensional array for my first map. I have the walls as # and was wondering how i could turn those into ascii symbol 219. Also i need to know how to turn specific text certain colors.
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Nov 19, 2013
I have an integer that the user enters. I need each digit of the integer to be set as an element of an array. the integer could also be entered as an array, but I need the user not to have to enter each element and press ENTER.
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Mar 2, 2014
In my program, I am fed a string that contains integers such as Code: *str = "45678" and my program is simply supposed to read the number in and store each given number in a separate spot in an integer array. So basically, when my program has finished running it should be stored like:
Code:
arr[0] = 4
arr[1] = 5
arr[2] = 6
arr[3] = 7
arr[4] = 8
The way I have been attempting to do this was just copying it to the array like so:
Code:
arr = malloc(sizeof(int) *(strlen(str));
for (i=0; i<strlen(str); i++) {
a->digits[i] = str[i];
}
however, this just seems to return an impossibly high garbage value when I do. I'm assuming the way I'm trying to store it is 'illegal', but I cant seem to find online a proper way to do it.
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Dec 20, 2013
Basically i am really close (i think) and the numbers im getting when i run it are weird like for instance i should get back a one if i enter in I or i but instead im getting like 178976087.
MAIN:
#include "stdafx.h"
#include "iostream"
#include <iomanip>
#include "romanType.h"
using namespace std;
int main() {
romanType r;
[Code] .....
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Dec 23, 2013
I am writing a program that converts arabic numbers into roman numerals.
Quote Write a program that asks the user to enter a number within the range of 1 through 10. Use a switch statement to display the Roman numeral version of that number.
Input Validation: Do not accept a number less than 1 or greater than 10.
Prompts And Output Labels. Use the following prompt for input: "Enter a number (1 - 10): ". The output of the program should be of the form "The Roman numeral version of A is R" where A is the Arabic numeral entered (1,2,3,...) and R is the all-capitals form of a Roman numeral, such as VII.
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Aug 31, 2014
Here is the problem:"Write a program that converts a number entered in Roman numerals to a positive integer. Your program should consist of a class, say, romanType. An object of type romanType should do the following:
a. Store the number as a positive integer.
b. Convert and store the number as a positive integer.
c. Print the number as a Roman numeral or positive integer as requested by the user.
The integer values of the Roman numerals are:
M 1000
D 500
C 100
L 50
X 10
V 5
I 1
d. Test your program using the following Roman numerals: MCXIV, CCCLIX, MDCLXVI."I'm doing the best I can to understand the concept of the class. Here is what I have (which is not much thus far, and nowhere near correct I'm sure).
#include<iostream>
#include<iomanip>
using namespace std;
class romanType {
public:
void getRoman();
[code]....
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Sep 17, 2014
#include "stdio.h"
#include <stdarg.h>
#include <math.h>
// Main Function
int main(void){
int number;
printf(" Please enter a number from 1-10? ");
scanf("%d", &number);
[Code] ....
I took the while statement out didn't want that in there.
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May 4, 2014
I have a fascination with Roman numerals and would like to create a C program that converts Roman numeral inputs to normal numbers.
I want to keep everything simple and only use the C library for the coding.
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Jun 27, 2013
This program compiles, but has a bunch of logical errors. I know my problem is somewhere in the while loop that I have, but I can't figure out where. Here are some of the issues I am experiencing:
1. At the beginning of the program it asks you to enter a number, and when you do it does nothing while proceeding to the while loop where I have it asking the same question
Code:
"Please enter a number between 1 and 20 (Enter 0 to stop)
";
cin >> num;
cout << endl;
I want to be able to eliminate that first statement but if I only run this in the loop without the above statement the program will display nothing on the screen and proceeds to stop.
2. This code runs fine, except that if you make a mistake, it will prompt you to enter a valid number, however; it ignores your first response if the number you enter is valid and asks you to enter a valid number anyway. Once you enter it a second time, it will accept it and the program will continue on.
Code:
while(num != SENTINEL) {
cout << "Please enter a number between 1 and 20 (Enter 0 to stop) ";
cin >> num;
cout << endl;
Also if you type in 0 on your first response, it will prompt you that it is not a valid number and ask you to try again, instead of stopping the program like it is supposed to do. On your second response the program will accept your 0 and stop the program correctly.
//Write a program that displays the roman numeral equivalent of any decimal number between 1 and 20 that the user enters. The roman numerals should be stored in an array of strings and the decimal number that the user enters should be used to locate the array element holding the roman numeral equivalent. The program should have a loop that allows the user to continue entering numbers until an end sentinel of 0 is entered.
Input validation: Do not accept scores less than 0 or greater than 20
#include <iostream>
#include <string>
using namespace std;
int main() {
// Declare constants and variables
const int romanNum = 21; // Size of the elements in the array
[Code] ....
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Nov 20, 2013
I can do the folowing:
float var1 ;
var1 = 9.12345 ;
printf("%.2f",var1) ;
the output will be 9.12. What if I wanted to save that as another separate float with displaying it on screen?
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