C++ :: Switching Function Prototype To Another Type

Mar 29, 2014

This is my code:

#include<iostream>
#include<string>
using namespace std;
int bin2dec(const string binarystring); // Declaration of bin2dec prototype with one string parameter
int main() {
cout << "Enter Q to terminate program.

[Code] .....

Right now the code is in the form of a 'const string binarystring' and were supposed to be able to use 'const char binarystring[]' and for some reason whenever i try to switch it i run into problems when referencing the main function to the int bin2dec(...) function.

I wanted to know if theres a simple way to switch the prototype to an array type of function with [] without changing the entire code.

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C++ :: Type Signature For Function Prototype

Mar 30, 2013

The function im having problems with takes an array where each element is an array of unsigned chars i.e. octals representing a bitmap of one of 95 ASCII code characters and searches through this two dimensional array looking for a match for a predetermined of array of unsigned chars i.e. the bitmap of a predetermined char. If we find the char the function outputs the index in the two-dimensional array where each elem. is an array of octals ELSE it return -1 i.e. when the char is not found.

I have 2 files, one .cpp, the other .h. There is a function named find_char. See INPUT and OUTPUT on line 48 in .cpp file.

The exception im getting is: font2.cpp:23:45:error: invalid conversion from unsigned char to unsigned char(*)[5]

The input type specified for my function prototype corresponding to find_char. If I put just unsigned char it doesn't fix the problem because it's an array parameter i.e. like a call by reference. I've lead myself to believe that the array variable contains a pointer to the first value in the array and so I've made function prototypes that work with a T* i.e. a pointer to type T. Making the function prototype argument unsigned char* i.e. a pointer to unsigned char simply gives me the exception: "invalid conversion from unsigned char to unsigned char*". When I have the argument be 'unsigned char' I get undefined reference to find_char(unsigned char). URL.....

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C :: Variably Modified Type - Function Prototype

Mar 24, 2013

Variably modified types are subject to certain restrictions , just as variable-length arrays are. The most important restriction is that the declaration of a variably modified type must be inside the body of a function or in a function prototype.

Code:
void f(int m , int n) {
int a[m][n] , (*p)[n];
p=a;
//....
}

What does it mean? That we can't declare such a pointer as a global variable?

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C++ :: Does Prototype Of Friend Function Has No Value?

Mar 30, 2013

[URL] ..... Prototype is commented.

[URL] ..... Prototype is included.

both give the correct output. Why?

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Aug 25, 2014

#include<stdio.h>
#include<conio.h>
#include<math.h>
void main() {
int i=1,j=2;
float k,l=1.5;

[Code] ...

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C++ :: Class Prototype - Generic Function

Aug 20, 2014

Let's first take the following class prototype:

#include <ctime>
#include <iostream>
#include <sstream>
#include <string>
#include <fstream>
class Debugger;
class Debugger {

[Code] ....

My question is regarding the GetCurrentDebugLevel function above. Ideally I would like to use just one function to get the current debug level of the class, the std::string form would be used to save the "debugging level" in a settings file and the enumerated version would for evaluation purposes throughout the program.

My question is if implementing function prototypes by return value the best way to go or should I do something else?

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C++ ::  How To Initialize Function Prototype Of Array With Zero

Apr 23, 2014

We can initialize normal function prototype's parameters with zero like this:-

void output(float = 0.0, int = 0);

or

void output(int = 0, int = 0, double = 0.0);

But how do you do the same for a pointer array or simply an array?

Assume that second parameter has to be an array.

I have tried the following and it does not work:-

void output(float = 0.0, int = 0);
void output(float = 0.0, *int = 0);
void output(float = 0.0, int* = 0);
void output(float = 0.0, int[] = 0);
void output(float = 0.0, int []);

But if I skip the default declarations altogether, it works.

like:

void output(float, int []);

or

void output(float, int*);

how can I do it by explicitly writing zero, just like the first cases?

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C/C++ :: How To Remove (Function Should Have A Prototype) Error

May 22, 2013

#include<iostream.h>
#include<conio.h>
int main() {
setcolor(BLUE);
setbkcolor(yellow);
cout<<"the text in blue colour with yelow background";
getch();
return 0;
}  

it keeps returning the same error always in my turbo c++ compiler . What is the correct program for changing background colour and text colour ...

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C :: Prototype For A Function Accepting Variable Arguments

Dec 6, 2014

what should be the prototype for the following function.

Code:void addition(int x, ...);

I am getting compilation errors. I have written the prototype as :

Code: void addition(int, va_list);

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Mar 30, 2013

I am trying to computed the time it takes for a projectile to hit the ground. The problem is that i need to square the input of velocity before i do the calculation. the question I have is that if it's possible to have multiple arguments inside the brackets after main.

#include <stdio.h>
#include <math.h>
double distance (double a, double v, double g);
int square(int y);
double height(double v, double a, double g);
double time (double v, double a, double g);
double sqrt(double num);

[Code] ....

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C/C++ :: How To Make A Function Prototype That Uses Variables By Reference

Dec 4, 2014

How to how to make a function prototype that uses variables by reference. I'm making a decision based game where two running totals of two variables (ending and morality from decisions made) will decide the game outcome. I only have a few modules put in so far and most of the "story" parts cut down here to save space. I'm also getting an error saying there is more than one instance of overloaded function for the "whatToDo" module.

// ZombieGame.cpp : Defines the entry point for the console application.
//
#include <stdlib.h> /* srand, rand */
#include <time.h> /* time */
#include <iostream>
using namespace std;
//These are function prototypes to declare the functions being used
void WakeyWakey();
void TwentyMinsLater(int);

[Code] .....

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Visual C++ :: How To Call Sleep Function Prototype

Dec 23, 2012

I have two problems with the code below:

1. I cannot find a header file to #include that has the sleep function prototype.

2. When I add my own sleep function prototype, I get an unresolved external reference error (for _sleep, not sleep).

What must I #include to get the sleep function prototype? What lib must I include in the linker configuration to resolve the external reference? (I suspect that if I #include the correct header file, the second question might become moot.)

The "man page" at [URL] .... says the header file is <WinBase.h>. But #include'g only <WinBase.h> results in compilation errors.

A response marked "answer" at [URL] ..... says <windows.h> [sic]. #Include'g only <Windows.h> does eliminate the compilation errors.

But apparently that does not bring in the sleep function prototype. Neither does also subsequently #include'g <WinBase.h>. (Which seems to be #include'd by <Windows.h> anyway.)

But even with my own function prototype shown below, I get an unresolved external reference for _sleep. Is that a symptom of my problem: my sleep reference is changed to _sleep? If so, how can avoid that?

According to "man page" (see link above), the external should be resolve in kernel32.lib. And kernel32.lib does appear in the "Additional Dependencies" list under Configuration Properties Linker Input.

Since I am not using C++ features, I tried setting "Compile as C" under Configuration Properties C/C++ Advanced, to no avail.

My code....

#include "stdafx.h"
#include <stdlib.h>
#include <time.h>
#include <Windows.h>
void sleep(DWORD msec); // added later
int _tmain(int argc, char* argv[])

[Code] ....

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Apr 9, 2013

I am quite new to C programming. Now facing lots of problem with the code below. I attempt to convert he alphabet sorting into function prototype model but still facing warning during compilation.

Besides, I wish to open multiple file at the same time as well using array looping method, but got no idea to modify it...

[URL] ....

Code:
#include <stdio.h>
#include <string.h>
#define SIZE 255
#define LEN 31

// Function prototype
void alphabetisation (int final, char *webaddress[]);

[Code] .....

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For whatever reason, I get an error meassage about lines 53-57 saying there is no matching function to call to. Yet the header and the prototype are correct (I think anyways).

#include <iostream>
#include <string>
#include <fstream>
#define N 10
using namespace std;
class cust{

[Code] ....

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Consider the class specification below. Write the prototype (i.e. header) of a member function to overload the insertion operator (i.e. <<). The << operator is to output the data members of an instance of class StudentTestScores into an output stream. Your definition should allow for chaining of output operations (e.g. cout << x << y; where x and y are of type StduentTestScires).

#include <string>
using namespace std;
class StudentTestScores{
private:
string studentName;
float *testScores; // used to point to an array of test scores
int numTestScores; // number of test scores

[code]....

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Oct 28, 2013

so in declaring a display function prototype only that displays a student test scores in the format (student name tab number of scores tab test scores )

is this right?

#ifndef STUDENTTESTSCORES_H
#define STUDENTTESTSCORES_H
#include <string>
using namespace std;
class StudentTestScores{
private:

[Code]...

and also how do we call the display function if it is in a class from the header file onto the main cpp file.

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C/C++ :: Function Prototype Using In Function

Oct 24, 2014

My instructor mentioned using function in other function.

int test(double abc(double)){
// ... .....
double abc(double n){
// function main
}
as parameter

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Jul 6, 2014

error says "cannot convert 'int*' to 'int' in function main()
and also
type mismatch in parameter in function sort(int,int)

Heres the code:
#include<iostream.h>
#include<conio.h>
void main() {
void sort(int,int);
clrscr();

[Code] .....

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Apr 12, 2014

I have written this bit of code for the Fibonacci sequence.

Code:

9 int size=0;
10 int fib[DWORD];
11
}

[code].....

I have tried quite few things and I am trying to change the prototype for generate Fibonacci to... int* generateFibonacci(size). I have been trying to use calloc inside generateFibonacci and then declare a pointer in main that points at the address of the pointer that generateFibonacci returns.

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Oct 25, 2013

So i have to use these prototype functions to run loops and to pause the program, the only problem is after i select a loop option and enter a number of dots to print in the loop it goes into an infinite loop and why, also when i try using the 4 option to exit it still asks me how many dots i want to print.

Code:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int pause(char *);
int getInt(char *);
void whileFunction(int);
void doWhileFunction(int);
void forFunction(int);

[Code] .....

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Dec 30, 2013

The compiler says my Rotor's cctor's definition doesn't match it's prototype.

Also, how can I convert my for loops into foreach loops?

Attached is the project.

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Jan 10, 2015

My g++ compiler is telling me that said printTest() is not part of the class. I have presented it in header class and implemented it in .cpp class but still keep getting the error. Compile and compile error -

blackjack > g++ -Wextra -pedantic -std=c++11 Deck.h Deck.cpp test.cpp ;
test.cpp: In function ‘int main()’:
test.cpp:6:6: error: request for member ‘printTest’ in ‘test’, which is of non-class type ‘Deck()’
test.printTest();

My Code -

//Deck.h
#include <iostream>
#include <string>
class Deck{
public:
Deck();
void printTest();

[code].....

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Nov 21, 2012

Say I have overloaded functions with different arguments AND return types. Each set of argument has only one corresponding return type.

Code:
Vector grad(Scalar)
Tensor grad(Vector)

Later I have:

Code:
template <class T>
void test(T x) {
... Y = grad(x)
}

Then how do I automatically declare the type of Y. Do I need to make the grad function a template and specialize each of them ?

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Feb 17, 2013

I'm really brand new to C++ and I'm currently learning it for fun. I'm working on prototype functions, and I got an error.

I get an error saying “warning : '<' : signed/unsigned incompatibility” but I haven't defined an unsigned int anywhere. Actually, I don't even really know much about them except that they allow bytes from -127 to 127 instead of 0 to 256 for signed int's if I understood correctly...

The function itself is supposed to make a pointer go to the end of a string and add the Null Byte at the end. There's probably an already-existing way to do so, but I don't know it. Plus it is fun making this.

In the below code I'll be making comments for most lines so you may correct me if I'm not doing what I think I am. Any way, here's the code of my "my_fct.h" header file :

#include <stdio.h> //Includes basic functions necessary in C as 'scanf' or 'printf'.
#include <string.h> //Includes string functions such as 'strcpy' or 'strcmp'.
#include <iostream> //Not sure about what this does.
int strend(char[]); /* Specifies the existence of a function 'strend' that uses a char
* string as argument and that returns a value of integer type. */

[Code] ....

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May 21, 2014

So I am writing an assignment to Detect prime numbers and it works by Asking for how many values you are going to enter, and then saying "Enter value 1: "

Then you would input and it would calculate via for loop, and that part is working. However to make my program more foolproof, I devised a way for the user to be unable to "Break" the program by inputting characters or float values. Here is the code for that:

while(!(cin >> num)){ //num is some type (char, float, int etc.)
cout << "That is not at valid input, please try again" << endl; //"Error Message"
cin.clear();
cin.ignore(10000, '
'); //Clear and reset cin
cout << "Enter value " << n << ": "; //Re-Prompt User for input
//n is whatever value the for loop is on
}

and this code works fine, I was just curious about how i would turn it into a function. Preferably wiht the name: ValidateInput(Param1, Param2);

The Parameters of the function preferably would be the variable youre inputting and the message you want to prompt. So somehow i wish to have it so for the above example it would look like:

ValidateInput(num, "Enter Value " << n << ": ");

But I don't know exactly how to label either parameter part because I want it to work for chars, ints, floats etc. And I don't know what I want it to return if anything either.

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