C :: Pointer - How To Accept 50 Names
Mar 24, 2013char *name[50]
How to accept 50 names using above definition...
char *name[50]
How to accept 50 names using above definition...
i have a vector of stores. i would like to delete the specified choice(store) from the list. Here is what i have but my erase statement is wrong and wont compile.
void Store::deleteSpecifiedStoreFromList(string choice) {
for (int i = 0; i < this->stores.size(); i++) {
if(this->stores[i].getStoreNames() == choice) {
this->stores.erase( std::remove_if( this->stores.begin(), this->stores.end(), choice ), this->stores.end() );
}
}
}
For a program I am required to use a cin that accepts 4 variables. The first describes a function such as add(), remove(), print(), or quit(). The problem is that to use add() I need to input all 4 variables but for remove(), only 2 variable input is needed.
I want the input to be "add 9 James Bond"
or be "remove 341"
Here is my current code.
int command(string command, int Id, string first, string last){
while (command != "quit"){
cout << "customers> ";
cin >> command >> Id >> first >> last;
if (command == "add")
[Code] .....
My program is a dictionary vector with a cin at the end that will read your input and check if it's in the dictionary.
#include "std_lib_facilities_3.h"
#include <algorithm>
#include <string>
#include <iostream>
string translate_to_lower(string s){
transform(s.begi[/code]n(), s[/code].end(), s.begin(), (int (*)(int)) tolower);
[Code] ...
How do I make the program accept inputs such as "hello?", "hello!", and "hello,"?
I want to accept numbers from the user into an array and convert into corresponding alphabets. E.g 1 into A, 2 into B, and so on.
This is simple, but the problem is the user is supposed to enter the character # also which I want to display as it is in the output. How can I do this ? What type of array should be used - int or char?
Basically I do not want to use a menu, instead just accept either an float or a single character. Then send the data to the appropriate spot based on the user input. I have been unable to convert the char to a float, and even if I did the char would probably only accept the first digit, say user enters '15' it would only read the '1'. I've tried strings instead of char but then unable to use the isalpha function. Do I need a char[] and then iterate through to get the numeric data? Then how do i make '1' and '5' become 15. There is probably a solution. I've also tried to use a loop waiting for the correct data while(!(cin >> letter)) which works but how do I get out if the user enters number.
#include <iostream>
#include <cctype>
#include <string>
#include <cstdlib>
using namespace std;
[code].....
how can I create a program that will accept 2 two integers. the user will also choose among the different operations:
1 for addition
2 for subtraction
3 for multiplication
4 for division
I need a program to run that will accept an input for user id. It will take the customer input and capitalize the letters, and return invalid id with the user inputted values. Then if it's valid it will add a counter counting the number of letters and numbers. It will keep track until the user puts in !. It seems when I try to pass values from the array to my toUpper function to capitalize it it doesn't seem to work right.
View 3 Replies View RelatedWhat I want to do with my program is I want my length, width,volume and price to accept number values only. This is what I have so far.
// This program calculates and displays the pool's volume
// the amount of water needed and the cost.
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
// the double type accepts numbers including fractions for the following inputs.
double length, width, depth, poolvolume, watervolume, price;
[Code] .....
I was trying to look up solution for this for quite a while already but found nothing. I am writing a simple console based turn based RPG game for my class project. I was trying to have a member function attack() in class of the player character, which affects the component called health of the class Enemy. both this classes are inherited from the base class Unit. I tried to pass the object of type enemy as an argument to the function attack, but the function call gives me Error: too many arguments in function call. Here's the code for classes:
#include <iostream>
#include <cstdlib>
#include <ctime>
#include <string>
using namespace std;
class Unit {
protected: int power, intellect;
[Code] ....
class Program {
//Accept two input parameter and returns two out value
public static void rect(int len, int width, out int area, out int perimeter) {
area = len * width;
perimeter = 2 * (len + width);
[Code] .....
why is the static keyword required in the method signature for the rect() method. It will not compile if it is absent. why?
the same is true for this example:
class Program {
static void printvalues(params int[] passedin) {
foreach (var printthis in passedin) {
Console.WriteLine(printthis);
[Code] ....
This code won't compile without the static keyword in the printvalues() method signature. why?
string answer;
cout<<"5.Newton's which law states that F=ma?";
cin>>answer;
if (answer == "newton's second law")
[Code].....
Create Binary Search Tree that will accept integers in this order: 35, 18, 48, 72, 60, 25.
It needs to prompt the user for input and then return either "True" or "False" if the number exists in the array.
#include <iostream>
#include <string>
#include <cstdlib>
[Code].....
I am creating a WinForm registration application and my program accepts user input information and stores it but I am struggling to use my login function. I believe there is an error in the area of cmd.Parameters.AddWithValue section, I dont think addwithvalue is correct ? I get a fatal crash has occurred when I click Login
string constring = "datasource=127.0.0.1;port=3306;username=root;password=welcome";
string Query = "SELECT * FROM 'userinfo'.'users' where 'username' = @userid and 'password' = @password)";
MySqlConnection conDatabase = new MySqlConnection(constring);
MySqlCommand cmd = new MySqlCommand(Query, conDatabase);
cmd.Parameters.AddWithValue("@userid", this.userid_txt.Text);
cmd.Parameters.AddWithValue("@passone", this.passone_txt.Text);
[code]....
Fixed the crash error, simple typo but now I am getting SQL Syntax errors which I originally believed I fixed.
i'm wondering if this will work
string user;
remove(user+".txt");
Can I create 1 variable that accept any type? And can I give it the NULL value too?
View 14 Replies View RelatedI've been experimenting a bit and can't find a decent way to make a brute forcing script that accepts a password from standard input, and goes through all possible combinations until it is matched. How to structure the code?
View 1 Replies View Related#include <iostream>
#include <iomanip>
using namespace std;
// Function Prototype
void sortArray(int array[], int size);
[Code] ....
This program was made to allow students to enter as many test scores as they want and the program will show them in ascending order and then will calculate the average of all test scores. It works wonderful until you enter a negative test score and then it throws the averaging process off. I can't seem to be able to make the program not accept the negative numbers.
#include<iostream>
using namespace std;
int main() {
int a[9],x,f=1;
cout<<"Please enter an integer [0-10 only] : ";
[Code] ....
So this is the activity (LOOPING) :
Write a program that accepts a positive integer. The program should be the same from the given output. Use do while to allow the user to continue or not.
OUTPUT must be:
n = 5
0
1==0
2==1==0
3==2==1==0
4==3==2==1==0
5==4==3==2==1==0
if n = 6
0
1==0
2==1==0
3==2==1==0
4==3==2==1==0
5==4==3==2==1==0
6==5==4==3==2==1==0
I want to fix this code. The program must accept 7 values or stop it when you type s. The code not only couts the element, but also some other random numbers.
Code:
#include<iostream>
using namespace std;
int main() {
int numb[7];
int i;
char s;
for (i=0;i<=6;i++)
[Code] .....
i was trying to solve a problem in SPOJ and what i wanted to do is to accept an input number from the user and to convert it into a array of integer.
Code:
#include<stdio.h>
int * toarray(int *num);
int main(void)
{
int testCases;
}
[code]....
But whenever i try to print the array in the main function i get only two value and the rest address
Code:
1//number of testCases
23456 //input number
6
2293452
4
2293700
1974439125
Process returned 0 (0x0) execution time : 4.152 s
Press any key to continue. However, if i tried to print the array from within the function, it prints the numbers just fine.
print the array elements from the main program, so that i would be able to go on with the rest of it
Write a function named replaceSubstring. The function should accept three C-string or string object arguments.
Let's call them string1, string2, and string3. It should search string1 for all occurrences of string2. When it finds an occurrence of string2, it should replace it with string3.
For example, suppose the three arguments have the following values:
string1: "the dog jumped over the fence"
string2: "the"
string3: "that"
With these three arguments, the function would return a string object with the value "that dog jumped over that fence." Demonstrate the function in a complete program.
Write a C++ application program to accept a signed decimal integer as input and output the equivalent 2s complement version in 16-bit binary. Include a space between every four bits in the output string. The input will only be processed by the application if it falls in the valid range that can be represented in 2s complement format with 16 bits. The range of a decimal number from - to + is -32768 to 32767.
View 3 Replies View Relatedi want to make a program that accepts 15 items in a singly linked and sorts the nodes.
View 1 Replies View RelatedI am making a program which is going to print out a head image according to the input values entered by the user. Here is the code:
Code:
#include <iostream>
#include <string>
using namespace std;
void Sides()
// draws the sides to take proportion
[Code] .....
At first i tried to work program like:
Code:
cout << "plase enter which way you want to print out the head, with parted hair or bald." << endl;
cin >> headstyle;
if (headstyle != "bald" || headstyle != "parted hair" )
But it also had given the same mistake. The program compiles BUT; even if I put in the values bald or parted hair the program prints out "wrong input" then exits.