C++ :: Make Average / Maximum / Minimum Score To Output File?
Nov 3, 2013
i have to make a score average, minimum, maximum as statistics for the out file. here is the code i have done:
Code: #include "stdafx.h"
#include <iostream>
#include <string>
#include <fstream>
[Code].....
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Aug 27, 2014
#include <stdio.h>
float total, avg, max, min;
float judge[4];
int index;
int array[4];
int main() {
total = 0.0;
max = array[0];
min = array[0];
[Code] ....
I dont understand how to make the array when it prints out only print out the final average and the final maximum score with the final minimum score but what its doing at the moment is just giving an average for each individual score taken...
Minimum and maximum scores are displaying 0.0
And it displays these things 4 times in a row i just want it to be displayed once.
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Sep 29, 2013
Program that reads 10 students marks and display the average, the maximum and the minimum marks.
Code] ....
#include <Stdio.h>
main(){
// Local Declarations
int marks[10];
int i; /*loop counter */
int avg;
int sum = 0;
[Code] ....
In this program i am able to get Average Marks and Minimum Marks But i am not able to get the Maximum Marks Output correct.
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Dec 31, 2014
I am given two month's data (Max, Min, Ave) for every day in that month.
The task is to display all 3 of that data for any selected day in that 2 months.
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Oct 24, 2013
How to traverse through this array and output each student and score that falls below the average. I think I may have the method down for traversing through the list to find the "total score" however, before proceeding under a possible wrong presumption, I would like confirmation as to whether or not I'm understanding this or botching this concept.
void dispLowScore(struct payload *arrayStart , //first element of array
struct payload *arrayEnd ) //last element of array {
int studentCount; //total number of students in list/array
int totalScore ; //accumulated value of all scores added together
float averageScore; //totalScore / studentCount
[Code] ...
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Jan 4, 2015
I wrote a program to find the minimum and the maximum values from a vector. It works fine. What I'm trying to do is show the positions of said values and it's not working quite right. When I insert 4 elements: 2 0 1 3 it says:
"The min and max are 0 and 3
The position of the min is: 01
The position of the max is: 03"
What am I doing wrong? Here is the code:
Code:
#include <stdio.h>
#include <conio.h>
int main() {
int A[10], i, j, n, min, max, C[10], k=0, D[10], l=0;
printf("Insert no. of elements in vector A
[code]....
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Oct 29, 2014
A function finds approximate maximum or minimum point of a second degree polynomial function (the point where the derivation will equal to zero ). The input polynomial function will be in the following format:
x2 + bx + c = 0 .
Your C function should take a , b and c as input parameters. Your C function also should take the srch_starting_point and stp_sze from the user. Finally, print the resulting maximum or minimum point (m_x, m_y) and step count (n_step) in your function.
For example, if the input is (a, b, c, srch_starting_point, stp_sze );
1 1 1 -3 1
Output similar to;
Maximum point results ( m_x, m_y, n_step )
-1 1 2
i can find the minimum point at first(Using derivation). After choosing starting point, staating point gets lower step size by step size. I can compare numbers to the minimum number. Afterwards, to find m_y i put m_x in the function. Finally, I put a counter to count steps.
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Dec 6, 2013
I need to write a program that not only calculates the minimum and maximum, but also calculates the average and the difference between the largest and the smallest.
Here's the code:
#include <iostream.h>
#include <conio.h>
#inlcude <math.h>
#include <windows.h>
[Code].....
I know the problem is the "sdt::cin" but I don't know what else to do
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Oct 25, 2014
The question is: Write a program that reads 3 integer numbers, then finds and prints the: Mean - Maximum & Second Minimum.
#include <iostream>
using namespace std;
int main () {
double a, b, c;
cout<< "Please enter three values"<<endl;
[Code] .....
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Jan 22, 2013
I want to finding maximum and minimum values of 10 numbers using for loop and the program work wrong !!
#include <iostream>
using namespace std;
int main() {
int x;
int max = -999999999;
int min= 999999999;
[Code] ....
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Nov 10, 2013
I have to get the average score for each student. And modify my avgmarks function and write the marks to a output txt file.
Code:
#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
int bubble(int*,int);
void filewrite();
void avgmarks();
void fileprint();
void filesort();
void rollin();
[Code] .....
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Oct 9, 2014
Create a 1-D Array to hold a set of exam scores:
55 74 93 84 64 72 69 78 87 84 72 33 83 68 62 51 88 90
Write a program to do the following tasks:
1. Display scores in rows of four(4) scores.
2. Calculate average score and display.
3. Find Lowest score and display.
4. Find Highest score and display.
5. Find the deviation of each score, and display the score and its deviation.
6. Find the Standard Deviation and Display
7. How many scores are within One Standard Deviation
So I have the average down, but I am getting stuck at the part of displaying the highest and lowest score. Every time I run the program I get two giant negative numbers for both of them. I put all the scores into a .txt file and I just opened in through the program.
#include "TCHAR.h"
#include <iostream>
#include <fstream>
#include <iomanip>
[Code]....
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Apr 11, 2013
it compiles and runs, it gives me the average and the highest score but says lowest is 0 even though 0 is never entered.
Write a program which uses an array of 5 scores and calculates the average score, the highest score and the lowest score.
#include <iostream>
using namespace std;
int getHighest(int [], int);
int getSmallest(int [], int);
double getAverage(int [], int);
int count;
int numbers;
[Code] ......
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Dec 11, 2013
[URL] ....
This is my code, but how can I implement this?
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Oct 29, 2014
I need to get Students to input there Name And Score > and for me to output the grade. This works but I want to tidy this up so I can see all the names and grades when the program finishes.
#include "stdafx.h"
#include "stdafx.h"
#include <conio.h>
#include <iostream>
#include <stdlib.h>
#include <string>
using namespace std;
int _tmain(int argc, _TCHAR* argv[])
[Code] ....
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Oct 21, 2013
I was tasked with creating a program that asks for the scores of three gamers then takes these scores and outputs the highest. I THINK I have the other parts down but I don't know how to get the program to compare the scores and output the highest without having to write a long list of commands comparing playerone to playertwo, then player one to playerthree, then player two to playerone, etc.
#include <iostream>
using namespace std;
int main () {
int playerOne, playerTwo, playerThree;
cout << "Please enter score for Player One: ";
cin >> playerOne;
[Code] .....
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May 3, 2015
Now this issue is about calculating the average of numbers and displaying it in the out put.
The following numbers is what I have read in from a file. There are 7 lines all the same format, just different values of course.
132475.889.392.3
435686.383.498.3
The output will need to look like:
Student #Test1Test2Test3Average
132475.889.392.385.8
435686.383.498.389.3
My program thus far is: (omitted code to shorten post and remove irrelevant information.
I don't know if it is because I have been working on other things and forgot how to proceed with the calculations and display, but I am just stuck. I'm not sure how to have the program read the numbers from columns 2 through 5 and then divide by 3. As you can see in my DisplayAverages() method I should have the ConsoleWrite and WriteLines done properly.
static void Main()
{
double[,] scoresArray = new double[7,4];
LoadFile();
ReadData(scoresArray);
[Code]....
Should read columns 2-4 and then display the average in column 5.
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Jan 24, 2014
I have this code that im stuck on what i need to do is Extend the code such that when it starts the user is asked to input values to specify each of the three ranges before moving on to accept and tally the main values how do i do that Using a for loop to input and output array values Also calculate the average
*/
#include <stdio.h>
int main(void)
{
/* Declare an array of integers */
int Grades[5];
int nCount;
int nTotal = 0; /* Declare and initialise the value */
float fAverage;
[Code]...
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Feb 17, 2014
#include <windows.h>
void gotoxy(int x,int y);
int main(int argc, char *argv[]) {
char urname[15],surname[15],fullname[30],nput;
int cntr;
[Code] ....
example
Please Enter your name : Ron
Please Enter your Surname : Smash
Your name is : r.Smash
// just an example that i input my name Ron and a surname Smash
My question is how to make the output in Your name is : is only r.Smash
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May 3, 2014
I want to convert energy from joules(J) to gigajoules(GJ)
1 joules = 0.000000001 GJ
and i use this--->
printf("
Enter the value of length to be converted: ");
scanf("%f",&value);
[Code] .....
when I try to print the "ans", it turns out to be like this-->
1.000000 J is equal to 0.000000 GJ
what I want is-->
1.000000 J is equal to 0.000000001 GJ
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Apr 8, 2015
I have this code down except I'm very confused how to make the output come out in 3 columns.
#include<iostream>
#include<fstream>
using namespace std;
int main()
{
int i, j, n, flag = 0, prime_number = 0, temp;
cout << "Enter first prime numbers that will be used or -1 to end:" << endl;
cin >> n;
[Code]...
My output right now is:
Enter first prime numbers that will be used or -1 to end: 20
Twin Prime Number : (3,5)
Twin Prime Number : (5,7)
Twin Prime Number : (11,13)
Twin Prime Number : (17,19)
But what I want is: 1. {3;5} 2.{5,7} 3.{11,13} 4. {17,19}
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Jul 28, 2014
I have problem with finding the maximum value in a column. This is my code
Code:
#include <stdio.h>
#include <stdlib.h>
int main() {
FILE *fp;
fp = fopen ("C:
ocket1.txt", "r");
float time, altitude, velocity, acceleration, amax, bmax;
[Code] ....
The first loop will print out all of numbers in the velocity column. The second while loop is looking for the maximum value in that column. It is supposed to print out the max velocity in the end of the second loop. However, when I build and run the program, it's crashed. I run debugger and received "Segmentation fault" error. When I eliminate the second loop, it run just fine I use Code::Block for text editor.
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May 26, 2013
How can I make the output print out to the screen in reverse?
Code: #include <iostream>
#include <iomanip>
using namespace std;
int getnum();
void Fibonacci(int n);
[Code].....
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Jul 29, 2014
Write a program to ask a user to input a symbol from the keyboard and to output that symbol in a n X n/2 sized V where n = the width of the V. You must use a loop to process the data
I am stuck at trying to figure out how to do the actual output formatting. This is where I am sitting currently.
string character = "";
int vheight = 0;
Console.WriteLine("Enter the character you wish to use for your V: ");
[Code]....
so Im really just a bit stumped on how to get the actual V shape to be formatted..
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Jul 11, 2014
I am making a multiple quiz program. So everything is working fine, except for the part where i'm trying to add a highscore for each user which is being stored in a binary file. I have added a sample of the program containing the error. This isn't the actual program, which is very long.
class user { //The collection of all info pertaining to the users
char user_id[50];
public:
int hscore1;
user() {
strcpy(user_id,"NULL");
hscore=0;
[Code] ....
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Nov 14, 2013
I must write a function that has a one dimensional double array and the number of values in the array as its arguments. Normalize the values. I must also print the maximum, minimum, average and numbers of values above the average in the array.
The equation that computes the normalized value from a value x is:
Normalized x= (x-min(array))/(max(array)-min(array))
My code does not print the correct normalized value, average and values above average.
Code:
#include <stdio.h>
int findMax( double array1[], int num_elements) // This function computes the maximum value of the array
{
int i, max=-32000;
for (i=0; i<num_elements; i++)
[Code] .....
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