C :: Variadic Macro Function

Sep 12, 2013

I'm doing right now is creating a function that callocs (I prefer this to malloc) and returns a string, and it will work similar to printf, I'm calling the function alloCpy(),I have several values that I need in a malloced string, so I call Code: myAllocedString = alloCpy("Value 1 is %s, value 2 is %s, and value 3 is %d", str1, str2, num); To do this I'm using the Variadic Macro, the reason I'm not just using a Variadic Function such as this: Code: char* alloCpy(char *format, ...) {} is because I need to append NULL to the end for the sake of looping through arguments, and I'm understanding it thusfar, but I have a few issues, first of all, I tried defining the Macro in a header file, but when I try to call it I get the error "Undefined reference to alloCpy". Also, to loop through arguments to get string lengths I'm using va_arg(args, char*) which requires all the arguments to be of type char*. Here is my code:
myheader.h:

Code:

#define alloCpy(format, ...) _alloCpy(format, ##__VA_ARGS__, NULL);
char* _alloCpy(char *format, ...); mycfile.c: Code: char* _alloCpy(char *format, ...) {
va_list args;
va_start(args, format);
int args_len = 0;
}

[code]....

So, how can I do this to, first of all, make my macro function accessible from other files importing myheader.h, and second, how can I make it accept any type of argument like printf, so that my example above would work?

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C++ :: Passing Variadic References To Template Function?

Dec 14, 2014

I'm having some problems in understanding how the code below works and why it produces the output it produces.. What I'd expect is that both functions, namely `add_1' and `add_2', would print the same output; but I've been proven wrong :/ So why does the second one get different memory addresses for the same variable?

Code should be self-explaining:

Code: template<typename... Types>
void add_1(Types&&... values)
{
// by the way: why do i have to use `const int' instead of `int'?
std::vector<std::reference_wrapper<const int>> vector{
std::forward<Types>(values)...};
std::cout << "add_1:" << std::endl;
for (const auto& value:vector) {
std::cout << &value.get() << std::endl;

[code].....

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C++ :: Variadic Function - Parameters Get Passed In Reverse

Nov 17, 2014

I noticed that when using variadic functions, if I pass the va_arg() as parameter to a function, the parameters get passed in reverse. Is that expected?

For example, the following code outputs
Code:
1 2
2 1

Code:
#include <iostream>
#include <stdarg.h>

void foo_func(int v1, int v2)
{
std::cout << v1 << " " << v2 << std::endl;

[Code] .....

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C++ :: Variadic Template Function Parameters And Method Pointers?

Oct 24, 2013

I have been experimenting with variadic templates with the aim of caching a call to a class method by storing away the object pointer, method pointer and parameters. I've actually had some reasonable success but have now hit a stumbling block. I now wish to wrap my parameters in a simple template class when I cache them. My success is as follows:

Using variadic template functions to store these pointers and paremeters;

I'm able to pass a method pointer and unwrapped parametersI'm able to pass wrapped parameters on their own.I'm NOT able to pass a method pointer and wrapped parameters I set up a little prototype project to demonstrate the issue and added comments above the function calls to indicate the compilation results. Here is the code:

Code:
#include "stdafx.h"
//////////////////////////////////////////////////
// Basic class with a simple method
//////////////////////////////////////////////////
class MyClass {
public:
char Method( int i, float f ) {
return 'A';

[code]....

But I'm convinced it should take three arguments, the method pointer and two wrapped parameters. Visual studio even suggested it should as shown below:

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C++ :: Variadic Templates - Enter Unlimited Amount Of Types In Function

Feb 25, 2013

I'm looking for a way to enter an unlimited amount of types in the <> part of a template function, I found Variadic templates but I'm not sure if it can do it, all the examples I've found are similar to the C argument list and don't use the <> part of the template at all.

I tried this, but the overload is ambiguous?

#include <iostream>
#include <typeinfo>
template<typename T>
void stuff() {
std::cout << typeid(T).name() << "

[Code] ....

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C :: Function Macro For Finding Square Root Of A Number

Jul 13, 2014

How to write a function macro in C for finding the sqrt of a number?

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C++ :: Define A Macro Within A Macro?

Feb 26, 2012

Is it possible to define a macro with in a macro? Any trick will do. I am trying to do quick conversion of cuda program to open mp by defining some macros at the top:

Code:
#define __syncthreads() #pragma omp barrier

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C++ :: Inheriting One Variadic Class From Another?

Jan 30, 2014

I have a variadic base class with a pure-virtual function per type:

Code:
template <typename ... Types>
class Base;
template <typename T, typename ... Types>
class Base<T,Types...>: public Base<Types...>
{
public:
using Base<Types...>::doSomething;

[Code] ......

Now, I'd like to inherit from it using another variadic class, which provides implementations of doSomething(), but I run into trouble --- where do I indicate it derives from Base?

Code:
template <typename ... Types>
class Derived;
template <typename T, typename ... Types>
class Derived<T,Types...>: public Derived<Types...>

[code]....

I see two possible approaches:

First, virtual inheritance *might* get me what I want, but I don't know how bad a performance hit that might be.

Second, I could do some magic where the full set of types is captured in a tuple at the lowest level and continually passed up, then re-expanded in the base case to indicate Base inheritance. However, I'm not sure if that can be done in an unambigious manner; I can't have two variadic packs at once (Types... and the tuple contents), and I'm not sure if there's a way to use enable_if to check if an arbitrary template type is any kind of tuple.

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C++ :: Variadic Template Basic Syntax

Jul 31, 2014

I had to learn how to use variadic templates recently, and had trouble finding simple examples that just showed the basic syntax.

So I decided to write one myself. Admittedly, it's a bit on the long side, but that is mostly because it includes five specializations.

insert Code:
// Variadic.C
// Compile command: g++ Variadic.C -std=c++0x
// I used GCC version 4.6.3 on Ubuntu.

// This file contains a basic variadic template with five specializations.
// It is intended for non-software engineers who are looking for a simple
// example of variadic template syntax.

[Code] ....

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C++ :: How To Remove Last Argument In Variadic Template

Nov 1, 2013

I wonder if it is possible to remove the last argument in an argument pack? Below is an example on what I want to accomplish:

template<template<int...> class A,int... Ints>
A<remove_last_int<Ints...>::list> func(const A<Ints...> & a0)
{
A<remove_last_int<Ints...>::list> a;
...
//Here a set the members of a based on a0.
...
return a;
}

For example, I want the return a A<1,2> value from (const A<1,2,3> & a0)

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C++ :: Enable If With Variadic Template Arguments

Sep 17, 2014

template <typename FIRST, typename... REST, typename std::enable_if<std::is_convertible<FIRST, Base*>::value>::type* = nullptr>
void foo (FIRST first, REST... rest) {}

that successfully allows me to enable the function foo() only if FIRST is convertible to Base*, but I also only want foo() enabled if each type in REST... meets the same condition. What is the syntax for that? If no such syntax exists, how to achieve that effect?

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C++ :: Variadic Templates And Type Composition?

Jan 28, 2014

Let's say I have a variadic type A and a non-variadic type B:

Code:
template <typename ... Args>
class A
{};
template <typename T>
class B
{};

Now, I'd like to do the following (pseudocode since I don't know how to do this yet):

Code:
template <typename ... Args>
class C: public A<B<Args1>,B<Args2>,B<Args3>....>
{};

Essentially, I'd like to take the parameter pack used for C and compose B around each element individually, then pass the result to A.

how I can do this?

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C++ :: Variadic Templates And Overload Resolution

Jan 2, 2014

I'm trying to learn how to use variadic templates, and I decided a great example would be serializing a series of types into a stringstream:

Code:
// Send a fully constructed message.
virtual void send(ostringstream &msg) = 0;
// Construct a message from the arguments and send it.
// This is the usual entry point.
template <typename ...Args>
void send(Args ...args {

[Code] ....

This works fine, so far as I can tell. However, I decided to see if I could specialize the way certain types are serialized. I tried using a Google Protocol Buffer object as an example, and added this:

Code:
// Handle a protocol buffer type while constructing a message.
template <typename ...Args>
void send(ostringstream &msg,
const google::protobuf::MessageLite &protobuf, Args ...args) {
std::string msg_str = protobuf.SerializeAsString();
msg << msg_str;
send(msg,args...);
}

I would expect this overload to be preferred over the generic T overload when a protobuf object (which always inherits from MessageLite) is passed into send() anywhere in the list. However, this is not happening. I am getting an error message to the effect that << doesn't know how to deal with my concrete type, pointing at the T overload.

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C++ :: Expanding Variadic Template Arguments In Lambda

Feb 1, 2013

I'm trying to expand a template + argument parameter list inside a lambda function like this:

template <typename Class, typename ...Args>
static void create(Args ...args) {
// Perform pre-thread creation work.
std::thread([=]()

[Code] ....

But this does not work:

The compiler error is "error: parameter packs not expanded with ‘...’:|"

However, when I do the following:

template <typename Class, typename ...Args>
static void create(Args ...args) {
// Pre-thread work.
auto tthr = [](Args ...ar) -> void {

[Code] ....

It works just fine. That shows that lambda threads are able to take variadic arguments...

So here is my question; what is the correct capture clause for capturing the variadic object correctly?

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C++ :: Ambiguous Call On Overloaded Variadic Template Operators

Oct 30, 2013

When compiling the code

#include "tensor.h"
int main() {
Tensor<2,-2> m = {{1,2},{1,3}};
Tensor<2> v = {1,5};
std::cout<<m*v<<"

[Code] ....

Why do I get an ambiguity and why is not the wanted operator*-overload (the last one in the tensor.h file) not even mentioned as one of the candidates? Is it clear what I want to do? And if so, what can I do to make the call unambiguous?

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C :: Defining And Using A Macro

Jan 4, 2015

I am trying to create a small set of filepath functions that I intend to compile across linux and windows (I prefer not to use a big library). I want to have a global constant PATH_SEPARATOR that depends on the OS environment. This is what I set at the top of header file.

Code:

#include <stdio.h>
const char PATH_SEPARATOR =
#ifdef _WIN32
'';
#else
'/';
#endif I was hoping to test this while compiling this in a linux environment using gcc, thusly:

Code:

int main (int argc, char const* argv[])
}

[code]....

where apparently, I seem not to be able to "set" a part of the code to have "_WIN32" defined. I don't know if I explained this clearly.

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C++ :: Macro To Template?

Mar 22, 2013

I have this macro, that expands to some methods of my class:

Code:
#define POPULAR_COMBO_FILTRO_COM_BASE(classeTabela)
void VisualizadorLogsFrame::PopularComboFiltroCom ## classeTabela (bool limparTexto) {
long from, to;
m_cbxDetalhe->GetSelection(&from, &to);

[Code]...

but I get a compile error on this line:

Code:
for (list< CLASSE_TABELA *>::iterator linha = lista->begin(); linha != lista->end(); linha++) {

what am I doing wrong ? the error is:

VisualizadorLogsMain.h:174: error: expected ';' before 'linha'
VisualizadorLogsMain.h:174: error: 'linha' was not declared in this scope

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C :: Testing If A Macro Is Defined To A Value?

Jan 16, 2015

Say I have something lke

Code:
#define FOO BAR
#if FOO == BAR
doX();
#else
doY();
#endif

This causes doX(); to be executed. But the intent is to have doY(); be run. I'm guessing this is because BAR is undefined and therefore blank, so blank equals blank. Is there some way to compare the symbol FOO was set to instead of its value, BAR?

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C++ :: Replacing Macro With Constant

Apr 4, 2013

I heard that const shall be preferred over #define . So I start to change my program accordingly.

But then below error message occurs during compilation:

#include "common.h"
#include "definition.h"
#include "particle.h"
int main() {
Particle *p = new Particle();

[Code] .....

I guess the error occurs because, when the line 9 of particle.h (File 4) is compiled, value of const int dimension is not seen by the compiler.

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C/C++ :: Migration Of Serialization Macro

Jun 12, 2014

I have to migrate C++ source which is compiled with MinGW-gcc to be compiled with VS2013, and have one issue with one macro used for serialization.

Here is macro:

#define IMPLEMENT_SERIALIZE(statements)
unsigned int GetSerializeSize(int nType, int nVersion) const
{
CSerActionGetSerializeSize ser_action;
const bool fGetSize = true;

[Code] ....

Here is place in code were it is call (in class declaration):

IMPLEMENT_SERIALIZE(({
if (!fRead) {
uint64 nVal = CompressAmount(txout.nValue);
READWRITE(VARINT(nVal));

[Code] .....

When compile received errors:

main.h(555): error C2059: syntax error : '{'
main.h(555): error C2143: syntax error : missing ';' before '{'
line 555 is end of macro call ( "})").

How should look using of this macro in order to avoid that errors?

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C++ :: Pitfalls Of Macro Substitution?

Dec 29, 2013

"If you examine the expansion of max, you will notice some pitfalls. The expressions are evaluated twice; this is bad if they involve side effects like increment operators or input and output. For instance, the below example will increment the larger twice."

#define max(A, B) ((A) > (B) ? (A) : (B))

max(i++, j++)/* WRONG */

I don't see what the problem is with the code above. i is incremented and j is incremented and then it performs a ternary operation to see which is greater. Am I missing something?

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C++ :: Two Projects - Defining Value Of Macro

Jun 27, 2012

Say I have two projects A and B. A depends on B. If project A defines a macro to be 100 and project B defines the same macro to be 200. In project A, if I use this macro, what value would this macro be? Let's just forget macro is evil for the time being. Let's also forget that it is not good to define the same macro twice for the time being.

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C :: How Macro Works To Concatenate Three Integers

Nov 15, 2014

when i was finding a way to concatenate three integers in C, I came across a snippet like this

Code:

#include<stdio.h>
#define cat(a,b,c) a##b##c
int main()
{
int d;
d=cat(1,2,3);
return 0;
}

How the macro works here? I am unable to understand the function '#' plays in the macro.

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C :: Writing A Macro That Returns A Boolean Value

Apr 24, 2014

I need writing a macro that would return true/false (1/0) )value. I want to check if a certain element exists in the array. The macro will accept array, its size, and the value to be compared, and must return yes or no. Here is the code that I have written:

Code:
#define EXISTS(T, a, n, val) do {
char ret=0;
T *a_ = (a);
size_t n_ = (n);
for (; n_ > 0; --n_, ++a_){
ret = (*a_ == val);
}
}
while(0)

How can I get the result from this macro.

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C++ :: Macro For Changing Array Size

Nov 22, 2013

I'm trying building a new macro for change the array size:

#define redim(varname,x) ((sizeof(varname)*) realloc (varname, x * sizeof(varname)));
int b;
redim(b,3);

error message:
"error: expected primary-expression before ')' token"

what isn't right with these macro?

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C++ :: Linking To Static Library That Contains A Macro

Jul 16, 2014

I have built a static library that contains a macro. From a separate exe, I am calling this macro, but it doesn't work.

The compilation of the static library and that of the exe went okay.

Static lib contains just the macro definition.

Exe contains call to this macro.

Is there anything else that I need to do for this to work?

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