C++ :: To Form Counter Of N Element

How can i form a counter of say 30 elements so that to meet following requirement,

I need to access 5 elements out of 30 elements and out of these 5 elements once the one value is printed (i.e now access for remaining 4 element will be left) other one should get added immediately to this 5 element set, from remaining total 25 elements. In this way 5 element count will be there always.

I am trying this as follows, by forming vector of 30 elements accessing its 5 elements as :

for (iter = vector1.begin(); it < vector1.end();it++) {
for(int count = 5; count >= 1 ; count--) {
cout << "Print value<" <<count<<"> : "<< *it <<endl;
it++;
}
}

This displays 5 elements at a time but counter "count" waits for to finish off its remaining 4 elements however i want to maintain this counter to 5 elements always.