I have to write a program that asks the user to input a positive integer, counts how many primes there are before this integer, then divide the number of primes by the integer. Here's what I have so far:
int n;
int counter = 0;
cout<<"Enter a positive integer n.
";
cin>>n;
[Code]....
the value of the integer counter is supposed to increase whenever a prime number is identified but it's increasing n times
I have a program that gets prime numbers that doesn't work. It looks like it works for all prime numbers except odd non-prime ones. Here is the code:
Code:
#include <iostream>
using namespace std;
bool isPrime(int prime) {
while(true) {
int track = 0;
[Code] ...
I'm a new coder for C++, and I've recently learned java before starting this programming language. I'm attempting to find all prime numbers up to the number a user enters (i.e. User enters 10, System shows "1,2,3,5,7"),
#include <iostream>
#include <cstdlib>
using namespace std;
int main(int argc, char** argv) {
int num;
cout << "Enter a positive number." << endl;
[Code] ....
I've been looking at my forloop, and I can't seem to pinpoint the problem with it.
I need to write a program that will allow the user to enter a number "n" and the program tell you that the nth prime number is .....
EXAMPLE
user enters 55
printf("The 55th prime number is %i", variable");
I am attempting to write code that receives a number from the user and outputs the largest prime number underneath the user's number. There are no errors in my code, but no matter what number is imputed, the program says the largest prime number is 1. I cannot find where the issue is in the code. Here is the code I wrote:
#include <cstdlib>
#include <iostream>
#include <cmath>
using namespace std;
bool isPrime(int num);//function prototype
[Code] ....
I am currently working on an assignment.
#include <iostream>
using namespace std;
int main(int argc, char *argv[]) {
char letter;
int count = 0;
double ppl = 0;
double finalCost = ppl * (count - 1);
[Code] ....
I am trying to create a word counter program that asks for the price per letter and then asks for the sentence they are writing. The app should then calculate the number of letters and give the total cost similar to:
You have 40 letters at $3.45 per letter, and your total is $138.00.
Everything compiles fine but when I run it the inputs don't work and it outputs:
You have -1 per letter, and your total cost is $-0.
#include <iostream>
using namespace std;
int main() {
//input output
[code]....
its supposed to tell whether the inputted number is prime or not
I have to create a program where I need to find the prime factors of a number and express it using exponents.
For example, for the number 1368 should output:
1368 = 2^3 * 3^2 * 19^1
This is my code:
void primeFact (int n){
int i;
int score = 0;
[Code].....
I am trying to factorize semi-prime numbers by using a brute force method and a square root method.The brute force method should start by multiplying all odd numbers between 1 and the semi-prime number. Meaning that 1 should multiply 3 then 5 then 7, etc. Then three should multiply 5 then 7 then 9 and so forth. The first number would never multiply a number equal to or less than itself.
bruteForce(int x){
f1 = 1;
f2 = f1 + 2;
while (f1 < x){
for (f2 = x; f2 <= x; f2-2){
[Code] ....
For my other algorithm, I want it to get the square root of the semi-prime and then start multiplying odd numbers around it. I made it so that the square root would have to be set to the next even number (in case it was a factor). If the product of the two odd numbers (a * b) is greater than the original semi-prime, I would multiply b by the next smaller number than a. Conversely, if the product of a and b is less than the original semi-prime, it will multiply a by the next odd number larger than b. This will repeat until the two correct factors of the original semi-prime are found.
Algorithm:
SquareRootFactorize(int x){
int N = x;
sqrtN = sqrt(N);
if (isOdd(sqrtN) == true)
sqrtN = sqrtN + 1;
f1 = sqrtN - 1;
f2 = sqrtN + 1;
[code].....
I wrote this program to print prime numbers between 2 and 10 but it only prints '3'. here is the code
#include<iostream>
#include<conio.h>
using namespace std;
int prime(int x, int y);
void main(){
int n=2;
[code].....
We are working on building a cluster and needed to create or find a program writen in C that we can run. I was thinking a program that finds prime numbers and insert them into a MySQL database. I have never worked with C so I don't know where to start or anything. I have a week to prove our project is worth keeping and our cluster is almost completely installed we just need to create a program.
View 4 Replies View Relatedcin.ignore (10);
return 0;
}
Its not working
We need it to say if the number is prime or not we need the equation for the if statement or if we have something else wrong to let me know.
#include <iostream>
using namespace std;
int main () {
int number;
bool countr;
for (countr = 0; countr <= 2; countr ++)
[Code] ....
my assignment is to print out the numbers from 2 to 20 stating if they are primes or not using loops and/or a function..once i execute, it throws the program into an infinite loop...
#include <iostream>
#include <cmath>
using namespace std;
bool prime(int n);
int main()
{
int i;
Can I possibly get a better implementation of a prime number detecting algorithm than the one I already have below?
Code:
#include <cstdio>
#include <cstdlib>
int main() {
int no, high, low;
int divisor;
[Code] .....
Basically, I am suppose to compute 10 numbers and find their highest prime number for each of them. I've already have the inputs working, and set up 2 arrays to store inputs and their highest prime number. But I am uncertain on how to find and store their highest prime number. How to start it off?
View 7 Replies View Relatedhow would I write a while() loop that calculates the sum of all prime numbers from 1 - 50.
View 5 Replies View Related#include "stdafx.h"
#include "iostream"
using namespace std;
int main (){
int x;
int i;
int e;
[Code] ....
is the logic good ? and why the program is looping
I am trying to find the prime factors of a number but when i compile and run my code after i enter a number it just closes it doesn't print ....
included library : [URL] ....
#include "std_lib_facilities.h";
void prime(int n) {
int result;
result = 0;
int i;
for (i = 2; i == n*n; ++i)
[Code] .....
This shows any prime number between a and b and also counts them*/
#include <iostream>
using namespace std;
int main(){
int a;
int b;
[Code] .....
What is the minimum range of numbers which we need to go necessarily to check either a number is prime or not?(for all integers) ....
View 6 Replies View Relatedi want to write a program which find the biggest prime factor of a number for example the biggest prime factor of six is three or the biggest prime factor of fifteen is five. What is my program bug
Code:
#include <stdio.h> // main functions
#include <math.h> // for sqrt function
int main()
{
int i, j, k, f; // F = Flag;
printf("Enter K
[Code]...
While finding the primes , I do not know how to make it into one array so that...
View 7 Replies View RelatedWrite a program that prompts the user to enter a number larger than 2. The program should use the Number class to determine the prime numbers between 2 and the number entered, and display them in the console window.I've been stuck for a while now and just lost in implementing classes and contstructors.
#include <iostream>
using namespace std;
int main(int argc, char * argv[])
{
cout << "Enter a number larger than 2: " << endl;
int n;
cin >> n;
What is the largest prime factor of the number 600851475143 ?
This is what I have. If I replace 600851475143 by 1000 (for example), it works fine until 2 divides 1000 to 500, 250, 125...but when it has to find the next divisible prime (ie 5) it cannot do that and the program stops working.
Code:
#include<iostream>
using namespace std;
bool find_prime(int number) {
int factor, num;
factor = 2;
num = number;
[Code] .....
I have to write a code in which the addition of prime number gives the number user input..
for example if user enters 10 then
7+3 = 10
2+3+5 = 10