C++ :: Returning QSharedPointer Or Raw Pointer

I have a class which looks like the following:

Code:

class Gadgets {
public:
Data* GetData() const {
return _data.data();
}
const Data * GetDataConst() const {
return _data.data();
}

private:
QSharedPointer<Data> _data;
}

You may ask why i have the second GetData() method that return a pointer to my private member, which will then expose my private member externally. I provide this function just for the case where user can do the following

Code:
Gadgets * myGadgets = new Gadgets();
myGadgets->GetData()->ModifyData(.....);

My question pertains to the use of QSharedPointer of data(), where in the doc, it says

T * QSharedPointer::data () const

Returns the value of the pointer referenced by this object.

Note: do not delete the pointer returned by this function or pass it to another function that could delete it, including creating QSharedPointer or QWeakPointer objects.

Whereas, if i were to use

Code:
Data* data as my private member class instead of QSharedPointer;

I will not need to worry if the caller do as follow

Code:
Data * data = new Data();
Data *data2 = myGadgets.GetData();
data2 = data;
delete data;