My program gets user input and compares it against an array of characters (guessLetters[x]) to decide whether the do/while loop repeats. The whole character array contains underscores yet if i enter any letter it goes into the if statement and repeats the do/while loop.
do {
repeatflag = false;
cin >> UserInput;
UserInput = toupper(UserInput);
[Code] .....
I am writing a program for a class where the user enters their age, how much money they have, and their full name. I know that I have to use the getline method to get the user's full name, and I know that I have to use cin.ignore() before that code, but i'm not sure why I have to use cin.ignore()?
View 1 Replies View RelatedThis is the problem :- Write a program that keeps reading integers until user enters -1, then it prints the maximum and the minimum among all numbers (-1 should be ignored).
View 14 Replies View RelatedI have my Reverse Polish calculator compiling and everything but for the assignment I need to handle a few exceptions that I can't seem to get. First off I'm trying to make the program exit if the user enters only "0" but since the input i'm using is string, I cant figure out how to code
"If the first node is 0 and the next node = NULL, return true"
Here is my code:
#include<iomanip>
#include<iostream>
#include<stdlib.h>
#include<stdio.h>
#include<string>
#include<sstream>
using namespace std;
class Stack {
[Code] .....
How do you find, when you first introduced with say some of the STL container, function or algorithms, what are its requirements? I mean,
1. what operators object should have for specific container?
2. what function args and type it should return for a algo?
3. when extending some container like with custom allocator, char_traits...and what not, what methods should be overridden? What work should they do?
Right now my application database is stored in the AppDataRoamingAppName directory.
The client has requested that the administrator choose the location for the database, and have a choice between a local machine, or an online repository.
The clients are not IT people, they are business people, and I don't think it's a good idea to let a user choose where to keep the central app database. Other users (think admin vs user) will need to download the database for use on their own local machines, which is how the issue even came up, it's kind of a shared database that only the admin can add to.
My compromise was to COPY the main database to the location of the user's choosing, then push updates to it as the main database was written to.
So after working on this today, I have the user choose a directory, I add the file path to the application settings, then I create the file and copy the database as needed to the new location (online repositories are next).
My goal is to create a loop that keeps taking user input over and over until the user doesn't enter anything into 'cin >>', leaves the line blank, and simply presses the ENTER key to move on, at which point the program is supposed to break out of the loop and continue on with the rest of program execution. Something like this:
Code:
do {
cout << "
Enter a name: ";
cin >> input1;
if (input1.empty())
[Code] ....
As you can see, I've already tried using the empty() function, but that didn't work, the program simply stays in the loop and doesn't break out, no matter how many times I press enter. It just keeps prompting me to enter a name. I've also tried using something like
Code: if (input1 == "")
but that doesnt work either. How do I break out of this loop?
So I've run into the following problem. My goal is to create a loop that keeps taking user input over and over until the user doesn't enter anything into 'cin >>', leaves the line blank, and simply presses the ENTER key to move on, at which point the program is supposed to break out of the loop and continue on with the rest of program execution. Something like this:
do {
cout << "
Enter a name: ";
cin >> input1;
if (input1.empty()) {
[Code] .....
As you can see, I've already tried using the empty() function, but that didn't work, the program simply stays in the loop and doesn't break out, no matter how many times I press enter. It just keeps prompting me to enter a name. I've also tried using something like
if (input1 == "")
but that doesn't work either. How do I break out of this loop?
Im still new to this but i dont quite understand whats wrong with this code
Code:
#include <stdio.h>
int num1, num2, num3;
char resp;
int main()
{
printf("Quer os seus numeros em ordem crescente ou decrescente?
[Code] ....
It is in portuguese but the thing is, when i type the C when it asks for the response it still reads as if it was D the response
How can we use switch statement 2 times in a program?
View 2 Replies View RelatedHow to put my all assignment questions that are 6 in number in one program by using switch statement ?
so if a user wants to see any question by choice!
I just started learning C and trying to create a program in C that will have a starting menu for a calculator. The problem is that I could do that with a switch/case but the assignment requires me to use if/else.
Here's what I have so far:
Code:
#include <stdio.h>
int calc();
int menu();
int main() {
printf("Hello. Welcome to the program.
");
printf("Press RETURN key to continue...
[Code]...
How should I go from now using if/else to have those 4 choices?
I'm trying to write a program that has a menu with a switch statement. I'm getting "case label'1' not within a switch statement" and subsequent errors for the other two choices and the default.
int main(){
int choice;
Matrix A,B,C;
cout <<"What would you like to do? "<< endl;
[Code]....
Why is my program outputting zero for the variable pop?
Code:
#include <iostream>
int main(void){
using namespace std;
//capture data
cout << "Enter the world's population: ";
[Code] ....
It's obviously not std::cout, but I'm thinking its the way I'm operating on long?
Community Hospital needs a program to compute and print a billing statement for each patient. Charges for each day are as follows:
a. room charges: private (P) room = $125.00; semi-private (S) room = $95.00; or ward (W) = $75.00
b. telephone charge = $1.75
c. television charge = $3.50
Write a program to get data from the keyboard, compute the patient’s bill, and print an appropriate statement. Typical input (nut yours do not have to be identical to this) is the following:
How many days was the room occupied? 5
What type of room? P
Telephone used during the stay? N
Television used during the stay? Y
Keep in mind that the user needs to know that the input can be any integer number of days for the length of stay, either (P, S, or W) for the room type, and either (Y or N) for both telephone and television options.
A statement (which yours MUST be identical to) for the data given follows:
Community Hospital Patient Billing Statement
Number of days in hospital: 5
Type of room: Private
Room charge:$ 625.00
Telephone charge:$ 0.00
Television charge:$ 17.50
TOTAL DUE = $642.50
a program that allows the user to enter a statement and outputs statistics; number of vowels, number of constants, percentage of vowels and constants, number of words, number of punctuation characters
View 2 Replies View RelatedFor my C programming module, I've been asked to create a program which is basically a ten question mathematics quiz or test if you like. Below is a copy and paste of my current, working program.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main () {
[Code]....
I am also trying to include into my program; If the user achieves 4 or less marks in the test, they are asked if they would like to repeat the test (have a second chance).
I have been asked by my Lecturer to ask the Question; "Would you like to try again" and the response is 'Y' for yes, 'N' for no. Would this be shown by:
char Y = Y;
char N = N;
printf("Would you like another go?");
scanf(%d%, &Y, &N);
And finally; If the user would like another go, then I am trying to include the code that clears the screen and then reloads the program?
What code is used to clear the screen and no clue what code is written to refresh or reload the program. I assume it's a loop statement or some sort.
Is there a way to tell the program to continue reading the next line of code within a nested IF statement?
The reason I want to do this is because the two "else" statements in the following sample (the main and the nested else) will contain the same exact code and I don't want to repeat it twice. I know I can do this by creating a function and calling it from each else statement but I was just wondering if what I'm asking is even possible without using a function.
if(1 < 2) {
// yes 1 is less than 2
if(5 > 10) {
// do something
} else {
// no, 5 in not greater than 10
// here is where I want to tell the program to continue reading the next else statement
[Code] ....
I am creating a pizza program for ordering a pizza and I have removed all the errors except for two. I have tried everything I can think of to fix this problem so it will compile, but to no avail. The only errors left are:
1>------ Rebuild All started: Project: Pizza Order App Midterm, Configuration: Debug Win32 ------
1> stdafx.cpp
1> Pizza Order Midterm.cpp
1> Pizza Order App Midterm.cpp
1>c:usersindia-n-jerrydocumentsvisual studio 2010projectspizza order app midtermpizza order app midtermpizza order app midterm.cpp(57): warning C4390: ';' : empty controlled statement found; is this the intent?
[Code] ....
The entire code is listed below seperated into 1 header and 2 cpp files.
// OrderPizzaApp.cpp : Defines the entry point for the console application.//
#include "stdafx.h"
#include "Pizza_Order.h"
#include <iostream>
#include <string>
using namespace std;
// prototypes
Pizza_Order createPizza_Order();
[Code] .....
If a user enters a string of boolean algebra it will ouput the table.
I have input parsing, cycling through the combinations, and outputing working. However once i parse the input I am not sure what to do with it. I have thought of having it write the parsed input to a new file as a function and then use that function, but that seems bad.
How to dynamically create the function, how to implement it.
BTW This is a console function, if that changes anything.
I want to autogenerate employee id when user enters details of employee
Conditions:
User Selects Department which should be used as prefix.
A new Sequence of numbers must be generated for each department
Example:
DeptA0001
DeptA0002
Again DeptB new seuquence must be started
DeptB0001
DeptB0002...
How to make if else code below into SWITCH STATEMENT?
cout << "Enter the temperature: ";
cin >> temp;
cout << "Enter the pressure: ";
cin >> pressure;
cout <<endl;
[Code]....
This while statement is not cooperating and I am not really sure why. I tried to say while not equal to true and later false, but both produce a never ending loop. I know I posted this before and I got several comments back about different issues with this program. However this question is specific about the while statement.
Code:
#include <iostream>
#include <vector>
#include <string>
using namespace std;
[Code] ....
I'm having a really dumb moment and I cant seem to remember how an if statement works, with only the variable name as the condition..
Code:
if(var){
//then do something
}
Well for some reason this doesn't work.
Code:
#include <stdio.h>#include <ctype.h>
int main(void)
{
int lottoNums[150];
int num;
[Code]....
how would i got about making an if statement for an array so it prints what u enter
Code:
example:
struct input{
float peopleseen;
float creditrate;
char insurprov[12];
[Code] ....
