I want to know if there is any function that can introduce a value in a certain time.
For example : In the next 3 seconds : cin>>n;
If you don't introduce a value in 3 seconds the program will go further.
make a time-in time-out fuction which extracts the no. of hours and minutes from a string entered by the user.
#include <iostream>
#include <fstream>
#include <string>
[Code].....
I have created this code with the classes for time and message. Basically the point of this code is to give the information of the sender, recipient, time, and message and im having issues with the time part.
#include <iostream>
#include <string>
#include <ctime>
[Code].....
so when you run this you can see i left a spot for the time but I just cant figure out how to figure out the Time part of this.
I am working on a project, where I have to be able to exclude some code fast and dynamicly at compiletime.
I got a scheduler running and actually I just want to remove some of the tasks from it - but at compile time so that the code wont take up space in my microcontroller.
I know that I can use macros like #ifdef #endif etc. But I think that method makes the code unreadable and complicated.
How to archive such functionality a more elegant way?
I want to implement some "debugger like" tool (very limited one, just identify at running time the current stack trace, and print messages from the user) on some code that the user wrote. what I get from the user is a function name (in the beginning of it's declaration), and when the user want to print some message he uses some print macro I should implement.
My target is printing the stack call, and all the messages that the user wrote, in the right place on the running place.
By what c++ feature can know on running time that a specific function code has ended??
Its easy to push a function to some vector when it called (since I get its name from the user), but when it ends and return to the function called it...
I am looking for a function or any example that shows elapsed time in seconds and minutes. I didn't find any solution for both OS Win and Linux. I am looking for example that works for both - win and linux.
View 14 Replies View RelatedHow do i make the srand() function make new numbers every time i call it? Now it seems like it repeats its result over an over again.
Below is a program that should generate random numbers for 3 dices and print these out. But it prints out the same nr over and over.
Code:
#include <stdio.h>
#define MAX 100
int filler(int dice1[MAX], int dice2[MAX], int dice3[MAX]) {
int throws, nr;
printf("Define the number of throws");
scanf("%d", &kast);
[Code] .....
I need to create a function that performs the addition of x days at a time, taking two integer values, the first being a date (yyyymmdd format) and a number of days to add / subtract that date.
How can I perform validation if the entire amount received is a valid date and how can I add x days of that date?
Program should continually have user enter a positive integer, and quits on zero entered. This entered number represents the total number of seconds and after each number is entered a function is called that displays the time in hours, minutes and seconds. Sample output is as follows:
Enter Total Seconds --> 3605 1:00:05
The function needs only one value parameter and should return nothing back to main. If the minutes or seconds are a one digit number then make sure to display a leading zero as the example above shows.
Here is my program. my question is how do i make the numbers appear like this? 1:00:05
#include <iostream>
#include <iomanip>
using namespace std;
[Code].....
My code is given below:
cout<<"1. runtim";
cout<<"2.tims";
cout<<"Your selection will be automatically neglected within (function to be inserted for time ) ";/* insert timer here */
cout<<"What kind of process u need to do";
.
.
.
.
I have 2 questions
1.the timer function has to be such that when any key is pressed in between the specified time its has to stop its counting and go to the nest line and functions . i checked sleep function but if any key is pressed its does not break out of the sleep program and execute the next command
2.and if the timer has completely finished running then it has to skip few lines and execute the program .
This is a round robin execution. with gantt chart. arrival time and burst time. I think there is an error in my formula to get the right answer,i cant resolve it but my program is running. What is the code or the right formula??
#include<stdio.h>
int main(){
int i,j=0,n,time,remain,flag=0,ts;
int sum_wait=0,sum_turnaround=0,at[10],bt[10],rt[10];
int ganttP[50],ganttStartTime[50];
printf("Enter no of Processes : ");
scanf("%d",&n);
remain=n;
[Code] ....
I have this piece of code from the book "Modern C++ Design" that checks for compile-time error. When i tried to compile it, i get the error "invalid application of size of to function type". How to make this compiler-time checker work?
Code:
template<bool> struct CompileTimeChecker{
CompileTimeChecker(...);
};
template<> struct CompileTimeChecker<false> {};
[Code] .....
So I'm trying to learn how to use time for time based movement and what not. I did this only knowing the command time(&variable)
time_t timer;
int I, X;
void main() {
time(&timer);
X=timer;
while(I==5) {
[Code] ......
There's probably some other better way to do it... Obviously but for now I see it as putting current time in X.
start while
take in time constantly until I is 5
constantly asking is time>X(preset time 5 seconds ahead)
if it is
display message and add one to I
Why doesn't this display my message after 5 seconds?
when we would use add items at design time and when we would add them at run time
does it have anything to do with the page load method? if so, can i type this in source code instead?
why nGrade comes out as 0 every time?
Its as if im not inputting the values into the dynamic arrays in int main.
#include <iostream>
using namespace std;
void Calc(int a_anScores[], int a_anPerc[], int a_nTotal){
for( int iii = 0; iii < a_nTotal; ++iii){
a_anScores[iii] = (a_anScores[iii] * (a_anPerc[iii]/100));
}
int nGrade=0;
[Code]...
I am trying to make this while loop cut out / self break after 3 seconds. It is part of a simple game I am creating that gives the users 3 seconds to react otherwise it moves on to the next part.
while(1) {
key=getch();
if(key=='a'||key=='k'||key=='g') {
break;
}
}
All I need is it to end after 3 seconds, the rest of the code is working fine.
This sort of thing:
long startTime = System.currentTimeMillis(); //fetch starting time
while(false||(System.currentTimeMillis()-startTime)<10000)
If it IS for C, then I implemented it wrong or something.
I want to convert time from est to utc. Is there any function for this.
View 3 Replies View RelatedI just spent 3 hours writing and debugging 37 lines of code. Is this normal or am I "below average" in coding abilities. I come from a C background and decided to write C++ code that I finally got right as shown below for the specific example:
Code: #include <iostream>
#include <fstream>
#include <string>
#define SPACE_SEARCH 10
using namespace std;
[code].....
I think it was more the learning along the way that consumed atleast 75% of my time for this specific case. But then again, I read that programming always entails learning along the way and so its somehow no excuse for the long time taken in this specific case.
So as a matter of interest, what pace do all of you operate on, on average? i.e. LOC/day, Debugs per day or any other indicator of productivity?
I tried to write a simple program to calculate monthly yield, APR, and principle in various directions. Anyway, here's some code to get the APR from the principle and monthly yield. When I run it though, it spits 0 at me every time! What the problem is; the other functions work just fine and the code line for the APR calculation is just what it ought to be - I see neither a math nor tech problem here.
Here is the offending function:
Code:
void calculateAPR() {
int principle, monthlyYield, apr;
cout<<"
Please input the principle:";
cin>>principle;
cin.ignore();
[code]....
I am looking for simple code that subtract two time interval. I have time t1=5hour 30 minute and other time in 24 hour format. This code i written but it not working as expected. it not printing 5:30 minute subtract
Code:
main() {
intTime1;
intTime2;
int hour=10;
int minute=5;
int second=13;
int h;int m;
doubleNtime;
[Code] ....
The issue is that I am trying to run a code which can trigger different timers at the same time. That is, when 3 is typed by the user, the firstimer is triggered. If before expiration another 3 is introduced, the second timer will be launched, and the difference between both triggers will be shown. Under this circumstance, timer_gettime only works once. I tried all the things I could imagine but still, it_value_tv_sec and _nsec return zero after the first expiration.
-Theoretically, and following the manuals, once the timer is restarted the gettime function should work as it does the first time.
-I have also tried to removed the timer and start it again, but in this case the timers are still being triggered, but the gettime outputs(even the first time) are nonsense.
Here is the code I am testing: [CODE]#include<stdio.h>
Code:
#include<signal.h>
#include<time.h>
timer_t firstTimerID;
timer_t secondTimerID;
timer_t thirdTimerID;
[Code] ......
I created a program to display time continuously so it auto updates every sec but the issue is i cant integrate the code in the main program because to make time update continuously it needs a loop a infinite loop so none of the rest program gets to work. My q is : is it possible to display time continuously and make the rest of program continue normally? like a multi thread program because i want to display time every sec in the bottom of program. By the way this is console app not gui
View 8 Replies View RelatedWrite a program to convert the time from 24-hour notation and vice versa. Your program must be menu driven, giving the user the choice of converting the time between the two notations. Furthermore your program must contain at least the following function : a function to convert the time from 24-hour notation to 12-h notation, a function to convert the time from 12-hour notation to 24-hour notation, a function to display the choices, function(s) to get the input, and function(s) to display the results.
View 2 Replies View RelatedI have a code to check the last time modification of a file using "gmtime". Is it possible to remove the seconds in the result?
Here is my code:
struct tm* clock;// create a time structure
struct stat attrib;// create a file attribute structure
stat("test.txt", &attrib);// get the attributes of afile.txt
clock = gmtime(&(attrib.st_mtime));// Get the last modified time and put it into the time structure
Why in this code the destructor is called 2 time? How can i avoid it?
int _tmain(int argc, _TCHAR* argv[]) {
Elenco e1;
std::cout << "Test 2" <<std::endl;
std::cout<<e1.size()<<std::endl;
[Code] ....
why does this happen that if i use
string ans;
for(int i=1; i<3; i++)
{
cout << "enter an option" << endl;
getline(cin,ans)
}
in a loop it always skips the first time but in the next times it asks?