I am trying to solve a MIP problem using C with Cplex linker. I need to find min value of two decision variables, as far as i know, i should write as a constraint because they are decision variables. "if" statement does not work for decision variables. here is some part of my model in C.
Code:
void TSPMIP(int Scenario, int Agency)
{
int i,j;
double tmpDouble;
[Code]....
I want to finding maximum and minimum values of 10 numbers using for loop and the program work wrong !!
#include <iostream>
using namespace std;
int main() {
int x;
int max = -999999999;
int min= 999999999;
[Code] ....
I am trying to make my program read a bunch of numbers in an array to find its maximum and minimum. the program will ask the user to enter in as much number as possible until they enter a non number/letter. i got my program to find the maximum value but the program couldn't read the minimum value. it always says zero. also everytime i enter the number 0, the program will just finish its loop statement. If i typed in a negative number, it'll read the negative number as its minimum.
Code:
#include <stdio.h>
int main()
{
//-------variables------------------
double list[1000]; // can hold 1000 items
int i;
char letter;
int max = list[0];
int min = list[0];
[Code] ....
I am having a little trouble finding the minimum value in my two dimensional array. I feel like my code is right, but it could be returning the wrong value. Below is my code, this is just my "minimum" function!
Code:
int minimum( int array[][MAX], int size ) {
int i,j,min;
for( i = 0; i < size; i++ ) {
for( j = 0; j < size; i++ ) {
if( array[i][j] < min ) {
min = array[i][j];
[Code] .....
A function finds approximate maximum or minimum point of a second degree polynomial function (the point where the derivation will equal to zero ). The input polynomial function will be in the following format:
x2 + bx + c = 0 .
Your C function should take a , b and c as input parameters. Your C function also should take the srch_starting_point and stp_sze from the user. Finally, print the resulting maximum or minimum point (m_x, m_y) and step count (n_step) in your function.
For example, if the input is (a, b, c, srch_starting_point, stp_sze );
1 1 1 -3 1
Output similar to;
Maximum point results ( m_x, m_y, n_step )
-1 1 2
i can find the minimum point at first(Using derivation). After choosing starting point, staating point gets lower step size by step size. I can compare numbers to the minimum number. Afterwards, to find m_y i put m_x in the function. Finally, I put a counter to count steps.
Is there any way to find the variables declared or defined in a c program and print those variables?? E.g. this is the code
#include<stdio.h>
int main() {
int a, b, c;
printf("Enter two numbers to add");
scanf("%d%d",&a,&B)/>;
c = a + b;
printf("Sum of entered numbers = %d",c);
return 0;
}
I want to print all the variables been used. I used (gdb) info locals but its not giving the proper ouput.
i am trying to find the max value from a list of 10 values. here i have stored the double values for prices of items in numVal.There are 10 values in numVal i would like to find the max and min value of these numbers. getPrice(1) returns the ten double values.
for(int i = 0; i < store.size(); i++) {
double numVal = this->store[i].getPrice(1);
}
I'm trying to implement a decision tree that gets doubles as input (in this sample code just random numbers) and returns a boolean value. At the nodes, I'd like to use various operators that can have different input and return types. I've implemented an abstract base class for the nodes and I'm deriving the specific nodes from it. In the code below, I've included only a few derived classes. Building the tree (randomly) is no problem. However, I'm looking for a clever way to evaluate the tree. I think that uncommenting the lines in bold print would in principle do it. However, this is not possible because "value" is not a member of the base class. The type of "value" is different in the derived classes, so I cannot simply declare it in the base class.
"Node.h"
#pragma once
class NodeBase{
public:
NodeBase* Child_1;
NodeBase* Child_2;
virtual void evaluate() = 0;
[Code] ....
I recently wrote a "Tic Tac Toe" console game, and i seem to have a problem in my winning conditions, as when it checks if the player won (should have won) it doesn't take the appropriate action.
The winning conditions are in CoreLogic.cpp
here's the code, might not be the most pretty and clean code ever but it works for me.
there are more files i just didn't feel the need to include them all since the problem is only within CoreLogic.cpp and possibly in main.cpp
pos1-pos9 have been declared in the UserInterface.cpp and are being used to determine the correct decision to do within CoreLogic.cpp
Nothing happens when you win at this point it just exits the program.
How i can find two equal int in array with O(n) time complexityand O(1) place complexity?
View 8 Replies View RelatedKeep track of the sum of values entered (as well as the smallest and the largest) and the number of values entered. When the loop ends, print the smallest, the largest, the number of values,and the sum of values. Note that to keep the sum, you have to decide on a unit to use for that sum; use cm.
View 9 Replies View RelatedIn the following code I want to iterate through "Win32_OperatingSystem" to find all variables and their values. Using GetNames() I can get the names of all the variables but the subsequent Get() call fails to return a value.
Code:
//connect to WMI
std::wstring wmiClass = L"Win32_OperatingSystem";
CComPtr< IWbemLocator > pLocator;
HRESULT hResult = pLocator.CoCreateInstance( CLSID_WbemAdministrativeLocator, nullptr, CLSCTX_INPROC_SERVER );
if ( SUCCEEDED( hResult ) )
[Code] ....
Question: State the values of each of these int variables after the calculation is performed. Assumed that, when each statement begins executing, all variables have the integer value 5.
a) product *= x++;
b) quotient /= ++x;
What is the answer for a and b?
I have the main() - which has entries like
Code:
main() {
int ss, ret, z;
float yy;
ret = function1(&yy, &ss, &z);
//int function1(flat *cc, int *dd, int *k) - is it correct?
[Code]...
So I have this text file that I am trying to read from and store the values of each line in multiple variables. Let's say my text file contains
AXSYZ3482 Tom 100 112 and my code below here works fine when the lines in the text file is separated by spaces.
Code:
while (fscanf(fp, "%s %s %d %d
", userID, name, &startLoc, &endLoc) != EOF) {
printf("%s %s %d %d
", userID, name, startLoc, endLoc);
}
But let's say my file was to look like this instead.
AXSYZ3482:Tom:100:112
But if i try this below...
Code:
while (fscanf(fp, "%s:%s:%d:%d
", userID, name, &startLoc, &endLoc) != EOF) {
printf("%s %s %d %d
", userID, name, startLoc, endLoc);
}
It seem to store the entire line in userID including the ":". I want to ignore the ":"'s and store everything in between in respective varibles in the order specified above.
So first string in userID, then ignore the :, then second string in name, and ignore the next :, and so forth.
Here's a bit of code:
CvClimateInfo::CvClimateInfo() :
m_iDesertPercentChange(0),
m_iJungleLatitude(0),
m_iHillRange(0),
m_iPeakPercent(0),
[Code] ....
does this means that these variables are initialized with the values between parentheses?
I know that returning to main() is not a good idea but how will I loop the program to go back to the position selection when the voter is done voting for the last position.
when I run the program it seems fine. getting the votes from President to PRO Position is fine. The problem is how will the next voter vote without losing the vote (tally) of the previous voter?
FLOW:
SELECT POSITION (a-e) ---> SELECT A CANDIDATE (a-c) ---> (this goes on until the position of PRO) ---> ( then go back to the POSITION SELECTION)
After every vote there is a case statement for which I can choose to vote for the next position, quit, or show results (and after showing the results it will go to the next position to vote)....
#include<iostream>
#include<string>
#include <conio.h>
using namespace std;
int pca=0,pcb=0,pcc=0,ptv=0;
[Code] .....
The code below is suppose to output all the prime numbers between the values of startNum and endNum variables. but its not working correctly instead it display all the numbers between startnum and endNumber including non-prime numbers.
void PrimeFinder::run(){
bool isPrime = false;
for(int i = startNum; i <= endNum; i++) {
for(int j = 2; j < i; j++){
if((i % j) == 0)
[Code] ....
So I have this text file that I am trying to read from and store the values of each line in multiple variables.
Let's say my text file contains
AXSYZ3482 Tom 100 112
and my code below here works fine when the lines in the text file is separated by spaces.
while (fscanf(fp, "%s %s %d %d
", userID, name, &startLoc, &endLoc) != EOF) {
printf("%s %s %d %d
", userID, name, startLoc, endLoc);
}
But let's say my file was to look like this instead.
AXSYZ3482:Tom:100:112
But if i try this below...
while (fscanf(fp, "%s:%s:%d:%d
", userID, name, &startLoc, &endLoc) != EOF) {
printf("%s %s %d %d
", userID, name, startLoc, endLoc);
}
It seem to store the entire line in userID including the ":". I want to ignore the ":"'s and store everything in between in respective varibles in the order specified above.
So first string in userID, then ignore the :, then second string in name, and ignore the next :, and so forth. How I can accomplish this?
Which is more efficient in functions? Returning values or using pointers to redefine variables passed as arguments?
I mean either using:
void ptr_Func(int *x)
{
*x = *x+1
}
or
int ptr_Func(int x)
{
return x + 1;
}
In terms of speed, memory use etc.I want to know general efficiency, I know it will obviously vary with different uses and circumstances.
I am trying to create a simple interface on console to allow to input some values to some variables. For ex:
int main() {
double a = 1.5;
double b = 2.5;
double c = 3.5;
string x;
[Code] ....
However, I want these three to display at the same time (now they display one by one), and in the console window I can move the cursor between input place of a, b and c with "arrow key" of keyboard.
if(rand() % 200 == 0)
{
switch(rand()%8)
[Code]....
How can i introduce a minimum gap sort of thing between these cases?
I wrote a program to find the minimum and the maximum values from a vector. It works fine. What I'm trying to do is show the positions of said values and it's not working quite right. When I insert 4 elements: 2 0 1 3 it says:
"The min and max are 0 and 3
The position of the min is: 01
The position of the max is: 03"
What am I doing wrong? Here is the code:
Code:
#include <stdio.h>
#include <conio.h>
int main() {
int A[10], i, j, n, min, max, C[10], k=0, D[10], l=0;
printf("Insert no. of elements in vector A
[code]....
The method doesn't work properly, the point of the code is to tell the minimum value in the given matrix "m", it's supposed to take the first value of the matrix store it in min_ and then compare it to every value of the matrix, if the value stored in min_ is bigger than the current value in the loop then it's stored as the new min_ and at the end it's supposed to print that minimum...
Code:
#include <stdio.h>
#include <stdlib.h>
#define SIZE 3
void minimum (int mat[SIZE][SIZE]){
int r,c;
int min_;
printf("
[Code] ......
Here is my code
//input:
4
0 -3 5 2
-3 0 1 0
5 1 0 1
2 0 1 0
#include<iostream>
#include<fstream>
#define fin "d:input.txt"
#define fon "d:output.txt"
using namespace std;
ifstream fi;
ofstream fo;
void OpenFileRead(){
[Code] .....
the result should be:
1-2
2-3
3-4
-1
but it is
1 - 2
2 - 3
2 - 4
-2
You are given an integer, perhaps a very long long integer, composed of only the digits 1 and/or 2. You have the ability to change a 1 digit into a 2 and a 2 digit into a 1 and must determine the min. number of changes that you can make resulting in no 2 digits remaining in the number that are in a position(in terms of powers of ten) higher than any 1 digit.
example:
2222212 number of changes:1
1111121 1
2211221 3
1122112 2
no negative numbers.
how to get started. Also I'm not allowed to use anything related to arrays or sorting.
