#include <stdio.h>
#include <stdlib.h>
int main(int argc, int * argv) {
char buffer[16];
FILE *fp;
unsigned long long test;
unsigned char key[16];
fp = fopen("D:key.txt","r");
[code].....
i searched for a code for reading bytes from a file and i found this one but when i run the program, it doesn't return the bytes written in the file, it returns another bytes / what is the problem?
I need to read repeatedly data from a MPEG2 file to the buffer of 188 bytes and analyse data bit by bit.
I have the problem with correct bytes reading from file. In my code listed below I have two methods for that.
First one is lossing this bytes which in hex_base mode have 0 at the begining, eg: 03, 0F, etc.
The second method based on read function which need to have buffer as a char (lenght > 1 byte). Because of that I receive different values from that from file in some cases.
How can I properly read such file?
Code:
#include <iostream>
#include <fstream>
#include <stdlib.h>
#include <windows.h>
using namespace std;
int main() {
fstream plik_in;
[Code] .....
I have used the following code to write and read wchar_t bytes from a disk file:
Code:
int WriteBytesW(wchar_t * wcp, int nsz, wchar_t * wcfilepath) {
wfstream wf;
codecvt_utf16<wchar_t, 0x10ffff, little_endian> ccvt(1);
locale wloc(wf.getloc(), &ccvt);
wf.imbue(wloc);
[Code] ....
Output:
save bytes succeeded
1234 5678 9ABC EF12 ABCD FE21 DCBA 1F2A EFFF 02FF
read bytes succeeded
nsz =: 20
Now, if wbuf[8] = 0xefff; is replaced by wbuf[8] = 0xffff;
Output:
save bytes succeeded
1234 5678 9ABC EF12 ABCD FE21 DCBA 1F2A 02FF
read bytes succeeded
nsz =: 18
Obviously, the 0xffff wbyte is not read. WHY ?
This presents a significant problem when attempting to read ALL wbytes from a file.
how to accommodate double-size:8 bytes in 4 bytes pointer in 32bit system.
View 1 Replies View RelatedCode:
int i12 = 1001;
cout << i12 << " " << &i12 << endl;
gives the result: 0x7fff0d065098
It's 6 bytes, but I'd expect the address to be 8 bytes on my 64 bit machine. I am using Ubuntu 12.04, GNU compiler.
So, why the address is 6 bytes and not 8 bytes?
I am encoding some information in a binary file, and I want to check what I am doing by printing out all the bytes that represent the file.
This is being done by opening a pointer to the file with fopen, reading in each byte of data as a char, and then writing this char to the screen.
I have some image files (e.g. "image.jpg"), whose structure I know, so that I can test my program.
When I print out the chars, they are initially correct, and follow the structure of the file as expected.
However, after about 40 bytes, I find that every subsequent character is ' ' i.e. a blank character.
I then created a CharToBin function, which allows me to print out the actual bits in the char. When doing this, it shows that all the bits are 1 for the characters. i.e. most of the file is represented by 1's, which is clearly not correct.
This happens on all the image files I have tested, and furthermore, on several other non-image files. They all start printing out ' ' after a while. However, all these files are fine and not corrupted, e.g. the image files display correctly.
Code:
#include <fstream>
#include <iostream>
#include <sstring>
#include <string>
#include <stdio.h>
using namespace std;
string CharToBin(char ch) {
bool bits[8];
for (int i = 0; i < 8; i++)
[Code] ....
while bytesremaining >=8 do something;
if bytesremaing <8 then something else .
I am new and don't know how to code for this.
How to delete certain bytes from middle of a binary file?
Those bytes are in fact of a struct.
One approach I found was to re-write the whole data except the struct I want to delete. But may be its not good one if file size is in gb and I will have to write complete data again.
I am a member of a group still developing the Microprose European Air War game. We have the source code and permission to do this. As the code dates back to 1998 I use Visual Studio 2006.
I have written many programs in Visual basic, and have the following one to read the airbase value in the "targets.dat" file. The file has a four byte header containing the number of tatgets, and a 32 byte data block containing the data for each target.
Private Sub Command1_Click()
List1.Clear
Dim nt As Long
Dim a4() As Long
Open App.Path & " argets.dat" For Binary Access Read As 1
'read and display the number of targets
[Code] ....
Despite many attempts I cannot write the C equivalent of this code into the eaw.exe source. All I really need to know is how to open the 'targets.dat' file and how to get the value of a byte (or integer, or long) at a given position as in the "Get #1, k, a4(n)" line.
How to read a line with maximum of 8 bytes from a line in a file.
Let say line has 10248 bytes in one single line and same repeats for remaining lines in the file.
I need to read the first 8 bytes of a line and go on read the last 2 bytes of the line and repeat the till end of file.
How I write a 0s or 1s to binary file in bits not in bytes how can i do that ???
View 2 Replies View Relatedhow to split a file in equal size and when clicking on split button it split the files as well as encrypt split parts and the size information are automatically stored in groupbox and save all splitted files in folder.
View 1 Replies View RelatedI'm trying to write a program that takes input from the user (thats a char) and outputs it to the monitor in hex form.The program is meant to continuously take input from the user then output to the monitor in hex form until an EOF is detected this triggers the program to close.The following code does this except that I get a lower case 'a' at the end of each output.
example:
input from user: ABC
output to monitor: 41 42 43 a
#include <stdio.h>
int main(void) {
char myChar;
[Code]....
I'm trying to print the full value (in hexadecimal) of a pointer.This is my best attempt so far:
Code:
char *text = "x10x11x12x13x14x15x16x17";printf("%x", &text);
And it obviously doesn't work, best I've gotten is a single byte, but I want the whole lot of bytes.
i m trying to write a code that would convert a each letter from a text to their decimal images . while i was able to write the part of entering the text , i cant do the converting part , i searched all day on the internet and found nothing.
View 3 Replies View RelatedI have an array:
Code: int array1[]={0,1,1,0}
I need to convert the entire array to Hexadecimal.
My first thoughts to the approach was to convert the array to a string then strcmp but i cant seem to find how to convert an array to a string either.
How to convert the array to hexadecimal directly? or, How to convert the array to a string to be strcmp'ed?
Write the function itob(n,s,b) that converts the integer n into a base b character representation in the string s . In particular, itob(n,s,16) formats n as a hexadecimal integer in s .
Note that it says the result is formatted into a hexadecimal integer in the string s. Here is the example provided:
Code:
void itob(int n, char s[], int b) {
static char digits[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
int i, sign;
if ( b < 2 || b > 36 ) {
fprintf(stderr, "EX3_5: Cannot support base %d
[Code] ....
Why does digits array hold the full alphabet when the maximum digit for a hex number is f?
#include <iostream>
#include <iomanip>
#include <string>
#include <sstream>
[Code]...
1)What should be the best variable for adding two 6-digit hexadecimal,such as 0034AD,0057EA? I would like to use array of character but it seems hard to handle.
I have to write a code that converts a hexadecimal value to a decimal value.So far I have
#include <iostream>
#include <cmath>
#include <string>
using namespace std;
int num;
char g;
int rem;
int main(){
cout << " input num: "; cin >> num;
[code]....
I think i need to put the g and rem value into a string... which I'm not sure how to do since g will be a char value and rem will be a int value... and after I believe i need to then flip the numbers in the string.. oh it has to be in the format of 0000
I'm taking a university course and one of our first projects dealing with C is to write a hash table (with chaining as a collision solution) that will hash loads of hexadecimal values into the table. I'm just brain storming right now but how practical is it to hash the values by converting them to decimal and working with that value in another function to organize the values? I'm thinking this might take a lot of time and memory because our code will be tested with text files that could have a few lines of hexadecimal addresses or millions of them.
View 2 Replies View RelatedI am new at programming and I have some questions about converting decimal to hexadecimal WITHOUT using .net library. The problem is, that I don't know how to do vice versa. (if you type 1254, program returns 6,14,4. I want programm to return 4,14,6- this is almost hexadecimal number (14 is not converted to "E")). Also the task is, that program has to return value in string form.
static void Main(string[] args) {
int a = 0;
int result = 0;
int n=1000000;
int[] array = new int[n];
Console.WriteLine("Insert numbers");
a = int.Parse(Console.ReadLine());
[Code] ....
How to search in C or C++ a hexadecimal patterns within a binary file.
For example:
String1:
Code: 0x44 0x65 0x07
Then, once found, extract those 3 bytes and the next 11 bytes (14 bytes in total).
Finally, from those 14 bytes, print without spaces "bytes 1 to 6", "bytes 6 to 12", and byte "13 to 14".
Then I would like to print last 2 bytes (13 to 14) joined in decimal format.
The output without any conversion would be:
Code:
446507c90688 888000800005 0015
4465072ec918 059173495269 002C
44650700cc01 01811bc90b00 00AB
But the output converting to decimal the last 2 bytes would be:
Code:
446507c90688 888000800005 21
4465072ec918 059173495269 44
44650700cc01 01811bc90b00 171
The sample file is attached, and looks like this:
Code:
06 00 00 80 00 00 00 80 09 3c c9 06 88 88 80 00
80 00 44 65 07 c9 06 88 88 80 00 80 00 05 00 15
37 06 01 00 00 01 00 65 00 00 00 02 00 00 02 00
18 00 00 00 03 00 00 03 00 17 00 00 00 04 00 00
[Code] .....
I'm trying to convert 4 hex register into floating point value using IEEE 754 floating point format. My device will reply 4 register value. The problem is that it always reply for example 0x10 as 10 when i use getc() hence using char variable to store it is not ideal.
Code:
union {
char c[4];
float f;
} conv;
i need to code a function that converts an array of 64 bits into a hexadecimal value, the one is tested gives me correct value except for the last hexadecimal letter.
Code:
#include <iostream>
#include <stdio.h>
#include <conio.h>
#include <fstream>
#include <cstdlib>
#include <string>
typedef unsigned __int64 Ebyte;
#define length 64
[Code] .....
I need to write a program in which you do the following:
Define three named constants using the appropriate data types:
DEC_NUM = 65;
HEX_NUM = 0x7a;
LETTER = 'f';
Then display each of these constants in decimal, in hexadecimal, and as a character using cout. Your program will have a total of nine cout statements.
I currently am stuck at getting the needed outcome data from my RFID card. I got it decoded but now I need to do a few more things in order to get the final card number off the back of the card.
The cryptic value was E********B**0**E** (covered to protect card)
Decrypting it turned into 0000003048D1263B
Now I have 3 more steps to take in order to get to my wanted card number.
Quote
Step 1) Mask off the lower 20-bits (which should give me 0x1263B) I am unsure of how to go about doing that using C++.
