i have highlighted the errors in block letters.
#include<fstream.h>
#include<conio.h>
#include<string.h>
#include<stdio.h>
#include<stdlib.h>
void login();
struct date {
int dd,mm,yy;
[code].....
i always get error case bypasses initialization of a local variable
here's my coding
my header files
Code: #include <stdio.h>
#include <conio.h>
#include <iostream.h>
#include <fstream.h>
[Code].....
i'm using borland c++ v5.02
#include <iostream.h>
#include <conio.h>
int main() {
int a;
cout<< "ingrese un numero entre 1 y 4 gracias
";
cin>> a;
switch(a)
[code].....
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace Furniture {
class Program {
static void Main(string[] args)
[Code] ....
I tried changing the type of variable to char but i still get the same result. i also tried using a switch statement which was my first choice but i had the same issue.
In Visual Studios I keep getting this error. cpp(36): error C4700: uninitialized local variable 'Eligible' used
Code:
#include <iostream>
#include <string>
#include <iomanip>
#include <fstream>
#include <cmath>
using namespace std;
void Getinput(int& Loantype, double& Income, double& Totaldebt, double& Loanamount);
[Code] ....
This program was running at first but when I started to change the couts and cins to fouts and fins (in order for them to be save in a file directory), it shows a lot of errors such as:
initialization of 'fin' is skipped by 'case' label
'std::ifstream fin': redefinition
Here is the code of the program:
#include <iostream>
#include <iomanip>
#include <fstream>
using namespace std;
struct file{
int fnum;
char fname[50], lname[50];
[Code] ....
I need to transform a local variable into a global variable so I can use it in one of my functions. I thought about passing the value as a parameter to this function but I can do this since the function is called inside the while loop and this variable counts how many times the while loop does (so the final value is outside the loop). Example to visualize better:
Code:
while(condition) {
function(parameter1, parameter2);
count = count + 1;
}
printf("%d
", count);
So, I need to transform the final value of "count" into a global variable. Can I do this?
I tried to initialize the frames variable but when I go to debug it, it just gives me 30 errors compared to the one error when I don't initialize the frames variable.
#include "Gfx.h" // general gfx lib I made for SDL
#include "Input.h"
#include "General.h"
#include "Sprite.h"
#define screenw 620
#define screenh 480
/** CHARS ARE DONE */
//int mousex; int mousey; int mouseon = 0;
//int red = 0; int green = 0; int blue = 0;
[Code] ....
#include<iostream>
#include<stdlib.h>
using namespace std;
int Name(),Minimum(),Maximum();
int main() {
int name=Name(),minimum= Minimum(),maximum= Maximum();
[Code] ...
There are error to let user to key in minimum and maximum values, i would like to know whats the problem?
Is it possible to initialize class member variables in their definition statement instead of using a constructor?
Is the code bellow correct?
class rectangle
{
float a=0;
float b=0;
public:
string color="Red";
...
};
Which C++ Standard allows it?
Should i never return a pointer to a local variable. i have seen the following code in the standard text book.
Code:
struct node *add_to_list(struct node *list, int n)
{
struct node *new_node;
new_node = malloc(sizeof(struct node));
// some code here
return new_node;
}
new_node is a local pointer then why is he returning the new_node? Is it wrong or am i failing to understand something?
Here is my overloaded operator :
const double & Waz::operator()(int i,int j) const {
return ((WazImpl const)(*p))(i,j);
}
Where in Waz class I have : WazImpl* p; and in the class WazImpl I have an operator () const
The warning is : Warning C4172 returning address of local variable or temporary
As far as I understand I'm returning a temp variable which is destroyed somewhere else what can I do to fix it?
I know that this code is wrong because it returns the address of local variable which no longer exist after function:
int *f1()
{
int x = 2;
return &x;
}
However, why this one does not show problem and runs fine, here the pointer p is also a local variable:
int *f2()
{
int x = 2;
int *p;
p = &x;
return p;
}
I keep getting the "Uninitialized Local Variable" error. But for my code it's says it's the variable 'pay' in my Manager Function. This is the only error that is popping up.
I've tried setting pay to 0 but when I do, I get a bunch of external errors. I've also tried assigning pay to WeeklySalary like this:
double pay = WeeklySalary;
//Calculating pay for a company
#include <iostream>
#include <iomanip>
using namespace std;
//Function prototypes
double managerFunction();
double hourlyWorkerFunction();
double commissionWorkerFunction();
[Code] .....
{
//Declare Variables
decimal hrsWrkd, otPay, grossPay, taxRate=0, taxAmount, netPay,basePay, wage;
string maritalStatus;
const decimal WORKWEEK = 40;
const decimal OTRATE = 1.5m;
const double m = 0.15;
[Code] ....
The error message I am getting is Use of unassigned local variable 'otPay' . I see its been declared and been used in the code so the error is confusing, also when i run the program i noticed that it doesn't take out the taxes.
So I have been working my way through this assignment and I'm just stuck now. I cannot get this work properly It just tells me I'm trying to return a local variable when attempting to return postfix in the to_postfix function. It is line 97 that wont compile. Also I cannot change anything in runner.c.
Calculator.c
Code:
1 #include <stdio.h>
2 #include <stdlib.h>
3 #include <ctype.h>
4 #include <string.h>
5 #include "stack.h"
[Code] .....
I got the following lines of code from a book. The variable char c is being used here to demonstration local variable declaration.
while(char c = cin.get() != 'q') {
cout << c << " wasn't it" << endl;
if(char x = c == 'a' || c == 'b')
cout << "You typed a or b" << endl;
else
cout << "You typed " << x << endl;
}
It compiles and runs. There are two issues when I try to run it.
1) It seems to loop through two times for every entry. If I insert cin.ignore() just before the closing bracket, it seems to work better.
2) the variable c does not seem to have the character I entered when examined in the if statement.
What is happening with the variable c inside the while loop scope?
Does c actually get initialized?
is it possible to have a global variable pointing to a different address depending on the thread?
Imagine one would like to use threads with the loop:
for (i=0;i<n;i++){
globalPointerVariable=getAddress(i);
DoThingsUsingThe_globalPointerVariable();
}
I am doing a piece of gui code on some embedded system.
I'm trying to find a way of eliminating the local variable kEvent:
Code:
EVENT kEvent;
....
Code:
kEvent = EVENT_UPSTREAM;
xStatus = xQueueSendToBack(getEventProcessorQueue(),&kEvent, 0 );
....
I tried this, it doesn't work:
Code:
xStatus = xQueueSendToBack(getEventProcessorQueue(),(EVENT *)EVENT_UPSTREAM, 0 );
Shouldn't this work?
What does the order of console output from your program tell you about when the static object is initialized?
#include <iostream>
using namespace std;
//class
class Firstclass {
private:
Firstclass(); //constructor
~Firstclass(); //destructor
[Code] ....
Doesn't it allocate the class static variable to the heap, thus executing its algorithm then destroying it when the program ends - or. What exactly does it tell me? When the static variable is initialized, it takes place first before any of my other functions?
Here is the code,
Code:
class A {
};
A& CreateObject() {
static A a;
return a;
} static A aa;
int main() {
return 0;
}
So is there any difference between a defined in CreateObject and aa?
When a declare a string e.g.
Code:
char str[30]; as a global variable, the srting is initialized to NULL.
But if I declare char str1[30] INSIDE main(), then the string has garbage inside.... Why this happens??
E.g. the following code snippet...
Code:
#include <stdio.h>
char str[50];
int main(){
char str1[50];
[Code] ....
Can local variable be passed as the parameter for a new created thread procedure? Here is the example code:
Code:
void CDLG::some_function()
{
CString strFileName="abc.doc";
//local variable, can it be valid for being passed into the following new thread???
//Can strFileName still be accessed from within the stack of thread procedure?
::AfxBeginThread(ProcessContentThread,(LPVOID)&strFileName);
}
[Code]...
There is another method using variable on the heap,
Code:
void CDLG::some_function()
{
CString strFileName="abc.doc";
CString* pstrFN=new CString(strFileName);
::AfxBeginThread(ProcessContentThread,(LPVOID)pstrFN);
}
[Code]...
I test these code, both methods work as expected, but I doubt whether the first method is a good way. OR if only the second method is the correct way to pass a parameter to a thread.
I created a class (let call it X) which contains the structure to store the data from my data base. Them I have a class (call Y) which will contain a list for each row in my data base. Third, I have a class with thousands variables (Z). What I am trying to do is to take the list of objects (Y) that contains the data to initialize Z. What I want to now if I can do something like that.
Imaging that one of my rows contain the following data:
Type Nameofvariable etc...
"static const double; MNFAIL ; 0; 0; 0,25"
In my list I have a node with contain this data
I want to use the field Nameofvariable to initialize the variable called MNFAIL contained in my class Z.
Is it possible in C++
Ran into something today that does not make sense:
This compiles: Code: int x = 5;
switch(x) {
case 0:
{
int value = 5;
}
break;
[Code] ....
Ok so it doesn't like int value = 6 b/c of int value = 5 for case 0. However since the value in case 0 is declared within the brackets one would think it has case scope.
So I tried this:
Code: int x = 5;
switch(x) {
case 0:
{
int value = 5;
}
break;
[Code] ....
Now it doesn't like it b/c value has not been declared in case 1:. These two conditions cannot possibly be both true at the same time. You cannot disallow the declaration of value in case 1 b/c it interferes with value in case 0 and at the same time disallow me to use value from case 0 b/c it is not in scope. If it was not in scope then theoretically I should be able to declare value in case 1.
Both MSVS 2012 and 2013 exhibit the same behavior. I checked the standard and it is unclear on the matter.
Well, I thought I had this program working but now I'm getting the above referenced compiler error. The program is just a basic user interface. It is for a classwork assignment.
The program is to accept user information as a string, convert it (if needed) to either the int or double variable, and then display the result. I'm using stringstream convert to make the change between types, but I'm not sure if I'm using it right (that might be what's causing the error, I'm not sure). Line 36-37 generates the error.
Code:
#include <iostream>
#include <iomanip>
#include <sstream>
using namespace std;
[Code] ....