C/C++ :: Fraction Calculator - Converting From Fraction To String
May 27, 2014
I'm having a problem when i convert from fraction to string. When I run my program it runs fine I'm supposed to get an output of the fraction ex (2/5) and the decimal 0.4 the problem is that it does not output the fraction all I get it / and 0.4
the code for converting from fraction to string is the following
std::string string;
char numerator[100]/* = {0}*/;
char denominator[100]/* = {0}*/;
_itoa_s(numerator_, numerator, 10);
_itoa_s(denominator_, denominator, 10);
i am having issues converting a fraction to a decimal, i think the code would go in the istream because it is working with input data but i just cant figure it out.
#include <cstdio> #include <string> #include <iostream> using namespace std;
I am trying to write a Fraction class and getting the following warning when compiling my code :
Fraction.cpp: In constructor 'Fraction::Fraction(double)': Fraction.cpp:8: warning :converting to 'int' from 'double'
My Fraction.cpp class looks like :
#include "Fraction.h" Fraction::Fraction(int n, int d):num(n),den(d) { cout << This is double param constructor <<endl; } Fraction::Fraction(double d):num(d),den(0)
I'm writing a function that compares two fraction. if the fractions are equal it returns 0. If the fraction in the first parameter is less than the fraction in the second parameter it returns a negative number. Otherwise it returns a positive number. in doing so convert the fraction to a floating point number.
completing the function to run
typedef struct fracion { int numo; int denom; }fraction;
I am trying to create a program that calculates fraction of time remaining when a student leaves during the middle of the semester. I have to use function files here. I am having trouble with the division in function long double tuitionfrac(int, int, int). No matter what numbers are entered, fractime gives an output of 0. I don't understand that.
long double tuitionfrac(int opening, int leaving, int semend) { int lefttime = semend - leaving; cout << "Left time " << lefttime << endl; //for error checking int tottime = semend - opening + 1; cout << "Total time " << tottime << endl; long double fractime = lefttime/tottime; cout << "fractional time " << fractime << endl; //always returns as 0. return fractime; }
I'm writing a function that compares two fraction. if the fractions are equal it returns 0. If the fraction in the first parameter is less than the fraction in the second parameter it returns a negative number. Otherwise it returns a positive number. in doing so convert the fraction to a floating point number.
typedef struct fracion { int numo; int denom; }fraction; int compareFractions (fracion, fraction);
We're assigned a project working with classes and fractions. My goal is to display a fraction in proper from based on 2 arguments passed to a class member function proper();
My strategy was to utilize the greatest common factor between the 2 arguements, then divide both the numerator and denominator by that number and then it would display.
The program actually runs, but only seems to divide the numerator and not the denominator. This in return makes my other class member functions have incorrect comparisons and sums.
Code: #include<iostream> #include<conio.h> class Fraction { friend void compare(Fraction a, Fraction b); friend void sum(Fraction a, Fraction b);
Write a class definition for a Fraction class. Its member fields are num and den, both of type int. The constructor builds the default fraction 1/1. It has the following operations:
void plusEquals(Fraction second); //Adds the second fraction to this fraction like the operator += void minusEquals (Fraction second); //Subtracts the second fraction from this fraction void timesEquals (Fraction second); //Divides this fraction by the second fraction void dividesEquals (Fraction second); // Divides this fraction by the second fraction void reduce(); // Reduces this fraction to lowest terms double todecimal(); //returns the decimal value of this fraction void scan(istream&); //scans a fraction written with a slash as in ¾ void print(ostream&); //prints a fraction using a slash Fraction(); //constructs a default fraction with denominator 1, numerator 0 Fraction(int n, int d); //constructs a fraction given value for num and den
2. Write a menu-driven driver program designed to allow thorough testing of your Fraction class.
I am working on a project which is a fairly simply BAC calculator. I am attempting to grab data from a text file, which contains state abbreviation, maximum BAC before aggravated, and minimum license suspension. The text file looks like
I am working on an assignment to create a Complex number calculator. In this assignment I am to ask the user for input to the calculator. We are given a sample run output that looks like this.
Enter operand1: 3 4 operand1: (3, 4) Enter operation : + Enter operand2: 1 2 (3, 4) + (1, 2) = (4, 6)
My question is how would I take from the user: an integer followed by a space followed by another integer and convert that into two seperate accessible int values that I can save as real and imaginary values.
I have a calculator with buttons, and when I click the numbers or operators, it goes to a string array. So;
Press 3 Press + Press 2 Press =
and my array is str[0]='3' str[1]=.... so on...
And also I have a C code which calculates the string you entered with some algorhytms and gives a double value as a result. So the question is;
How can I send my STR array in C# to my C program? I mean I want to use my C program as a source code. and How to return that double value to my C# program?
For now, I don't want to change my C codes into C# codes. I want it to keep as is. Just use it as a source code. Is that possible?
I have to convert my netpay which is a float to a string So if I input a value of say, 356.26 it should output "the sum of three hundred fifty-six and 26/100 dollars" . My program function works for the sum of three hundred but after that it spits out garbage.
How will I add the existing content of the text file to the newly inputed date(hoursworked & minsWorked) to compute the total number of hours works. I'm just a beginner in using Visual basic C++.
I'm trying to find a way to accuratley convert a double in the form of a bank account number stored in a file into a string representing the number returned by a file.
BASICALLY, I have to convert netpay (float to string). Theoretically if I have 666.66, my program here should output the sum of "six hundred sixty-six and 66/100 dollars".
i think i need to convert a double to a string, we are working in visual studio doing a program. when i run the calculator i'm not getting the answer i need instead its giving me 0.0 when it should be reading 0.5, here is the code i'm using
{int width; int height; int area; double gop; String ^strWidth; String ^strHeight; String ^strArea; String ^strGop; strWidth=width1->Text;
