C/C++ :: Censoring Specific Word Within Array?

What the program does: I am trying to code a program that makes the user enter a phrase, then censor the word "darn" if the user entered it.

The program is working very well; it will censor any "darn" words the user enter, by replacing it with ****.

The problem: I need to enter a phrase just once, before the program prints out the phrase the user had entered, The phrase purpose is to tell: either the phrase was clean, or it had "darn" within it.

I tired:

1-Defining an integer (counter=0;), and adding (counter=counter+1;) in the first while loop, when I am storing char's into my array. Then, adding if statement (if index==counter) for the phrase I need to print before printing the user entry. It should print out the statement only if (counter==index), because counter would still have the count of user entry. -> didn't work, the phrase won't print.

2- Making the previous step within its' own loop. -> It stopped printing the user's phrase.

Tools I can used : If statements, while loops.

Here is my code: (Ignore the phrases within /**/, they are just the statements I want to print)

#include <stdio.h>
int main() {
char phrase[1001]; // Creats 1000 array ( max. number of letter the user could enter is 1000).
int index=1; // Act as counter, which would refer to a character in the array.
char cur; // Identify cur, which will be used to store characters into the array (phrase).
printf ("Please enter a phrase:

[code]....