How can i assign current date as integer ?
for example:
today's date 26 Sep 2014 on a computer
i try to make as below
int day=26
int moth=9
int year=2014
I also research i think i will use time.h library surely
i need to display the current time and date in my program and use variable to store each of the time values like
a = 10
b = 29
c = 31
printf(``%d : %d : %d``, a,b,c);
which then give the output as - 10:29:31
How to save the time in variables in C....
i am using C in windows 7 and my complier is Bloodshed Dev C++
I need to add the current date to the end of a string but I only need to add the day and not the year or month.
Put the code This is what i have
char date[9];
_strdate(date);
cout << date << endl;
I am doing a school project. The project basically is that it records the in and out time of an employee(of an particular company).The employee while checking in or out should enter a unique key generated specially for him so that no one else can check in and out for him.Then referring to the employees position( A worker or a manager or something like that) his total working time each day , for a week and a month is calculated. The company starts at 8 am and ends at 5 pm for 1st shift and for second shift from 3.30 pm to 2.30 am. Plus Saturday and Sunday off. Then after a month the program refers to the working time date stored in a file and calculates his pay(For workers its per hour salary and for managers it aint).
If an employee is consistently late the details are forwarded to the HR account( so that necessary steps are taken).This will support the company log the details of their employees duty time plus give enough detail to take action if someones always late. I'm doing this as a school project and it needn't be of enterprise class and all.. But i want the coding to perform as it should. Also i'm forced to use the old Turbo C++. Now i'm struck in the place where the time of the employees in and out time is logged. This coding does the work
Code:
void main( ) {
clrscr();
char dateStr [9],timeStr [9];
_strdate( dateStr);
cout<<" The current date is "<<dateStr<<'
[Code] ....
I think the second one is better as it not only gives me date but also gives me the day so i can check easily for the weekends. So, how these time functions work.
I am trying to use to save the current date and time into a char array using this code:
char current_time(char *date){
time_t result = time(NULL);
date = ctime(&result);
return *date;
}
main{
[Code]...
now when I output the date char array into a txt file I only get gibberish.
I have an extra credit project where I'm supposed to calculate an approximate the user's age based on the current date and their birthday. My problem is that I am not getting the proper date and time. C++ keeps giving me some random date. I looked up c++ time format on the internet because this is extra credit and not in my book.
I am currently using dev C++ 4.9.9.2. Here is my current code :
// included libraries
#include <cstdlib>
#include <iostream>
#include <iomanip>
#include <time.h>
#define cls system("cls")
#define pauseOutput system("pause")
void printM(int x);
void age(int m, int d, int y, int &yearAge, int &monthAge, int &dayAge);
[Code] ....
I have an assignment in which i must create a program which prompts for user input of current and birth date, which will compare said dates and output if its your birthday or not. I've completed a large portion of it, but cannot figure out how to get the user input of month as an integer such a 2 into February.
#include <iostream>
using namespace std;
class DayOfYear {
public:
void input();
[code]....
I would like to know how I can convert a string which represents a date to an integer.
#include <iostream>
using namespace std;
#include <string>
int main(){
string actual_date("18/10/2000");
int date = ????????
Here is the code:
#include <iostream>
using namespace std;
int main(int argc, char * argv[])
{
double foo [5][5];
This is the warning:warning: extended initializer lists only available with -std=c++0x or -std=gnu++0x...It's referring to the boldened part.
I have the following C++ code
typedef union UUID {
unsigned char byte[16]; /**< Array of 16 bytes. */
unsigned int ll[2]; /**< Array of two 64-bit words. */
} UUID;
[Code] ......
The compiler complains thus
$ g++ union.cpp
union.cpp: In function "int main()":
union.cpp:15:17: warning: extended initializer lists only available with -std=c++0x or -std=gnu++0x
union.cpp:15:17: warning: extended initializer lists only available with -std=c++0x or -std=gnu++0x
union.cpp:15:17: error: no match for "operator=" in "entry.EntryHeader::uuid = {0, 0, 0, 2}"
union.cpp:1:20: note: candidate is: UUID& UUID:perator=(const UUID&)
How do I go about assigning values to this union in C++.
How do I convert date in integer format to DateTime without using DateTime?
I have tried:
Regex regex = new Regex(@"^(0[1-9]|1[012])(0[0-9]|1[0-9]|2[0-9]|3[01])(1[789]|[2-9][0-9])dd+$");
if (regex.IsMatch(txt_fromdate.Text) == true)
{
DateTime dt = DateTime.ParseExact(txt_fromdate.Text, "MMddyyyy", null);
}
I am trying to assign the integer value to unsigned char array. But it is not storing the integer values. It prints the ascii values. Here the code snippet
Code: uchar uc[100];
for(i=0;i<100;i++)
{
uc[i] = i;
}
The values which are stored in uc[] is ascii values.I need the integer values to be stored in uc[]. I tried to do it with sprintf. but the output is not as expected. if I print the uc[i] it should diplay the value as 0,1,2....99.
I'm trying to write a very simple program that takes values in through variables, and stores those values in a two dimensional array. The values are already passed into the void function, I need to have those values write to their corresponding locations in the array.
void planeSeats(int seats[13][6], int ticket, int ticketRow, int ticketColumn) {
if (ticket = 1) {
if (ticketRow >= 1 && ticketRow <= 2) {
[Code] ....
For example, lets say that ticketrow is 2 and ticket Column is 4 .
What I need is for ticketRow and ticketColumn to assign that data to seat[ticketRow][ticketColumn], turning it into seat[2][4]. How to do that.
I am trying to assign a list of values to a vector:
vector<string> words;
words[] = {"one", "two", "three"};
This does not work. How can I accomplish it?
The problem may only apply to VC++ compiler - ??.
Cannot do this:
const unsigned int Port = 0x900E0000;
unsigned int *pData = Port; //Error - can't convert from int to int*.
Solution:
const unsigned int PORT = 0x900E0000;
const unsigned int PORT_PTR = ((unsigned int *)0x900E0000);
unsigned int *pData = PORT_PTR; //No Error.
I found no way to do it but the above.
Ex., you cannot do:
pData = (unsigned int *)0x900E0000;
I'm okay with 2-dimensional arrays, but when I get to 3 or more, I can't seem to wrap my head around how to assign and/or pull values from specific parts.
To give an example, let's take the following example:
We know that a player can take up to 5 total quests, and each quest can have a max of 5 tasks.
Let's assume I have the following multi-dimensional array holding all of a players quest data:
quests[0] = 78;// Store the questID
quests[0][0] = 3945;// Store the 1st creature ID
quests[0][1] = 2230;// Store the 2nd creature ID
quests[0][2] = 3045;// Store the 3rd creature ID
quests[0][0][0] = 2;// Store how many needed of the 1st creature
quests[0][1][0] = 5;// Store how many needed of the 2nd creature
quests[0][2][0] = 13;// Store how many needed of the 3rd creature
As we know, the above code can't be done. How do I assign certain values to each specific dimension?
I am writing a program to play rock paper scissors, and I am trying to get a vector to store the result of a given round of play, and output it as a declaration as to who won. I can't figure out how to store the values in the vector properly, and how to use the vector as an argument to output the result of play.
Code:
#include <iostream>
#include <iomanip>
#include <ctime>
#include <vector>
#include <cstdlib>
#include <string>
using namespace std;
const string name[4] = {" ", "rock", "paper", "scissors"};
const string roundResult[3] = {"computer win", "player win", "tie"};
[Code]....
write a c++ program that reads an unknown number of integer values and then print count, sum and average of odd values, even values, positive values, negative values!!
View 1 Replies View RelatedI'm attempting to save values from a char buffer into integer values of a struct.
This is what resides in the buffer "STD 2 2 2 2 2 2 2 " and this is my sscanf call
Code:
sscanf(buffer, "STD %d %d %d %d %d %d %d
", &dt_struct.date,
&dt_struct.mth,
&dt_struct.year,
&dt_struct.dow,
&dt_struct.hr,
&dt_struct.min,
&dt_struct.sec);
I then print the values back out in a string using sprintf.
Code:
sprintf(t_string, "STD %d %d %d %d %d %d %d
", dt_struct.date,
dt_struct.mth,
dt_struct.year,
dt_struct.dow,
dt_struct.hr,
dt_struct.min,
dt_struct.sec);
But this is what I get:
STD 0 0 2 0 0 0 2
Instead of what I want:
STD 2 2 2 2 2 2 2
I've been working on a homework assignment that randomly generates integers and populates them into an array (array1). The program is then supposed to:
1.) copy those values to a second empty array (array2)
2.) sort the values already in array1 (using an inline function)
3.) enqueue the unsorted integers from array2 into a heap vector
4.) a third empty array (array3) is supposed to be populated with those unsorted integers (by dequeuing them from the heap), sorted in reverse order.
But no matter what I do, I always get garbage values like these:
I've tried using both a standard random number generator:
array1[i] = rand()%100+1;
And the d_random.h file my instructor gave us, but nothing works.
Here's the code from all 3 files:
HeapTester.cpp
Code:
#include <iostream> // Provides cin, cout
#include <cstdlib> // Provides EXIT_SUCCESS, rand, srand
#include "d_random.h"//Provides random number generator
#include "Heap.h"
using namespace std; // Use C++ Standard namespace
//Elements in each array.
const int arrayLength = 15;//100;
[Code] ....
Why I'm getting those garbage values?
I am attempting to read values from a file into a 2d array temp[31][2] (31 rows, 3 columns).I only want the values from the file to be read into the first two columns.I believe I am accomplishing that but when I go to print the array, I expect the first two columns to have the file data and the third column to have all zeros. The third column, however is printing such that the value is the next row/first column.
I'm not sure for instance why on the bottom loop for line 1 it doesn't print:
temp[0][0] temp[0][1] temp[0][2] 20 49 0 It instead prints: 20 49 1
Code:
#include <stdio.h> Code: #include <math.h>
FILE *inptr;
int main() {
int temp[31][2] = {0}, tempavg[31][2] = {0};
int i, j, k, sum;
inptr = fopen("ProgrammingProject14.txt", "r");
[code]....
I'm having a pretty weird problem. I've created an unsigned char array for an image buffer:
buffer_rgb = new unsigned char[_w * _h * 3];
memset(buffer_rgb, 0x0, sizeof(unsigned char)* _w * _h * 3);
And I add pixel color values to it like so:
buffer_rgb[i] = ((unsigned char)(col[0] * 255));
buffer_rgb[i + 1] = ((unsigned char)(col[1] * 255));
buffer_rgb[i + 2] = ((unsigned char)(col[2] * 255));
Where col is a 'vec4' struct with a double[4] with values between 0 and 1 (this is checked and clamped elsewhere, and the output is safely within bounds). This is basically used to store rgb and intensity values.
Now, when I add a constant integer as a pixel value, i.e.:
buffer_rgb[i] = ((unsigned char)255;
Everything works as it should. However, when I use the above code, where col is different for every sample sent to the buffer, the resulting image becomes skewed in a weird way, as if the buffer writing is becoming offset as it goes.
These two images illustrate the problem:
tomsvilans.com/temp/140803_render_skew.png
tomsvilans.com/temp/140803_render_noskew.png
You can see in the 'noskew' image all pixels are the same value, from just using an unchanging int to set them. It seems to work with any value between 0-255 but fails only when this value is pulled from my changing col array.
Whole function is here:
// adds sample to pixel. coordinates must be between (-1,1)
void Frame::addSample(vec4 col, double contrib, double x, double y) {
if (x < -1 || x >= 1 || y < -_aaspect || y >= _aaspect) {
[Code] .....
I am having problem in writing the code for the problem "To assign the elements of 1-D integer array into 2-D array of integers such as if the array is 1,2,3,4,5,6 The resultant 2-D array should be like :
1 0 0 0 0 0
1 2 0 0 0 0
1 2 3 0 0 0
1 2 3 4 0 0
1 2 3 4 5 0
1 2 3 4 5 6
"
i'm making a program that, given a person's birthdate or any other date, will display the day of the week of the person was born.
There is this part where it says "use a switch statement to make this calculation, If desired month is 12, add the number of days for November, if desired month is 11 add the number of days for october....
So it's suppose to start with "case 12 :...
I can't figure out what to write for the statement....
Using a for loop, construct two 100 element arrays, x and y, such that element i of x stores the value sin(2*pi*i/100)) and the corresponding element of y stores cos((2*pi*i/100)). Print the values stored in the elements of x and y as you calculate them.
I have attempted to solve it but I'm not sure why the value 0 is only being printed, maybe I haven't assigned sin(2i/100)) and cos((2i/100)) to the arrays properly?
Code:
#include<stdio.h>
#include<stdlib.h>
#include<math.h>
int main () {
[Code] .....
i am having trouble finding a way to detect integers from an external text file. i currently have this code:
while(inputfile.get(wc))
{
char character = inputfile.get(wc);
if (character + 1 != NULL)
{
cout << character << endl;
}
}
this does not work as if (character + 1 != NULL) comes up with errors.
is there a way to detect ints?
