C :: Byte Ordering In Binary Buffer

Basically it has to do with the byte ordering in a binary buffer vs the typing of a variable used to hold it.

To give you an example, if I have a buffer (say of indefinite length), and a ptr "ptr" pointing to a byte in the buffer (say, C0), such that if I open the buffer in a binary viewer it reads like this: Code: C0 DD FE 1F Such that this is true:

Code:
/*ptr is uint8_t*/
*ptr == 0xC0

Then I do this:

Code:
uint16_t var;
var = *(ptr+1);

I would expect the result to be:

Code: DD FE /*56830*/

Though if I print that out with:

Code:
printf("%u
", var);

It'll print:

Code: 65245 /*(FE DD)*/

Now obviously it's byte swapped, but what is causing that? I'm assuming if I just stream that out to a file byte by byte it'll be fine, so it's something with the 16 bit data type (also have seen this issue with a 32 bit data type, where all 4 are in reverse order). Is there any way to 'fix' it except bit shifts & masks?