C++ :: Write Swap Function To Swap 2 Elements In Vector?
Nov 15, 2013write a swap function to swap 2 elements in the vector?
View 3 Replieswrite a swap function to swap 2 elements in the vector?
View 3 Replieshow to swap the first and 'mid' elements of a vector?
View 2 Replies View Relatedwriting a sorting function that has an argument for a vector of ints rather than an array; it should use a selection sort algorithm.Here is what I have:
#include <iostream>
#include <vector>
#include <conio.h>
using namespace std;
void fillVector(vector<int> &aVector);
// PRECONDITION: number declared size of array a.
// POSTCONDITION: number_used is the number of values stored in a
//a[0] through a[number_used-1] have been filled with nonnegative int.
[code].....
I am reading a book currently on data structures in c++. The questions I have is how I would be able to swap two adjacent elements by adjusting only the links (not the data) using, a) singly linked lists, doubly linked lists.
For the single linked list which I am somewhat familiar with (by the content of the book), I would consider taking the Node A, and copying its data into a new Node temp, then re-routing the pointer from whatever connected to Node A, now to Node temp. now I want to re-route the pointer of Node B to Node temp and Node temp to whatever Node was being connected from Node B. Is this the correct approach?
The idea is to make an array and have it sort the contents inside the array in order from smallest to greatest by using a swap function. I don't know why it needs to be done this way when a sort function makes the most sense, but it is what it is.
For simplicity I want my array to only include three numbers. I was thinking {18,-2,24}. My only problem is that I am not understanding how to translate the swap function in an array. I tried using my previous swap function from another assignment and translate it to work for an array, but it doesn't work and I am completely lost and stuck. What I tried to do was this:
#include <iostream>
#include <cstdlib>
using namespace std;
const int SIZE = 3;
double myList[3] = {18, -2, 24};
void swap(myList[0], myList[1], myList[2]) {
[Code] ....
So I been working on this c++ project and I need to be able to take three seperate strings and send them to function to put them in alphabetical order through a-z and use the swap function to return them in order. I been searching for problems like this but I haven't fame across any. I can copy my code onto here as well as a more detailed description of what I'm needing to do onto here if needed.
View 4 Replies View RelatedI am trying to realize a simple code with thread and lambda function.
My goal is to swap 2 variable . I launch 2 thread,
The first:
Put his value in a shared variable and notify it .
wait until an event on a condition variable occur.
read from shared value .
The second wait until an event on a condition variable occur.
Wake up
read from shared value .
Put his value in a shared variable and notify it.
This is the code
thread t1([&p1]()->void{
m.lock();
nt++;
if(nt==1) {
//first thread
unique_lock<mutex> u1(m); ***
[Code] .....
Why it say error "abort() has been called " on the istr ***
I have the following code segment:
Code:
void Swap(Number& num1, Number& num2)
{
cout<<"Before swap:"<<num1<<" "<<num2<<endl;
Number& temp=num1;
num1=num2;
num2=temp;
cout<<"After swap:"<<num1<<" "<<num2<<endl;
}
[code]...
to which the output is:
Code:
Before swap:13 11
After swap:13 11
13 11 that seems confusing.
why doesn't Swap() swap the two Numbers?
#include <iostream>
#include <conio.h>
using namespace std;
[Code]....
appears that error on line 25 & 30 where swap1 & swap2 is not declared in this scope.
This is for homework . Must use only getchar and putchar
Code:
int main(void) {
int pch; //first
int ch; //second
[Code]....
And it works , but i need to hit ENTER two times when i have 3,5,7... chars to print result.
I want to swap the value of two rows in matrix among themselves, the index of rows are user defined.
void swapRows(int matrix[M][N], int m, int n, unsigned short R1, unsigned short R2) {
for (int i=0; i<m; i++) {
for (int j=0; j<n; j++) {
//dunno what to put in here
[Code] .....
How to swap two strings without using 3rd variable? could it be done using constructors? If yes how?
View 11 Replies View RelatedWrite a function which will take 3 arguments. The function needs to return a new number which is formed by replacing the digit on a given position in the number with a digit which is carried as an argument (the position in the number is counted from right to left, starting with one). Write a main program which will print the newly formed number.
Examples:
A function call of 2376, 3 and 5 should return the number 2576
A function call of 123456, 4 and 9 should return the number 129456
What I succeeded to do so far:
Figure out the logic for swapping the digit and write working code for it (in the main function).
What I failed to do so far:
Write a function which will return the desired result.
What is my problem:
I tried writing a function to do this, but as you see from my calculations, my result is divided in 3 parts. I don't know how to return more variables from a function.
Code:
#include <stdio.h>
int main() {
int inputNumber, swapPosition, swapDigit;
scanf("%d%d%d", &inputNumber, &swapPosition, &swapDigit);
int i, numberPart1 = inputNumber;
for (i = 1; i <= swapPosition; i++)
[Code] ...
Im trying to swap the values of an integer and a character, however Im not sure where to insert the static_cast<type> part that I need for this to happen?
// Program to demonstrate a function template
#include <iostream>
using namespace std;
// Interchanges the values of variable1 and variable2
template<class T>
void swap_values(T& variable1, T& variable2)
[Code] ....
I simply need to know how I could swap the first and last letters of the input in this program:
int main() {
cout << "---------------------------------------------------------" << endl;
cout << " Letter Swapping Program" << endl;
cout << "---------------------------------------------------------" << endl;
string word;
cout << "Please enter a word at least 3 letters long: ";
cin >> word;
[Code] ....
By all means, I know this is a messy program and is not the most concise way to write it....
I have the following code. According to this the values of pointers p[0] and p[1] remains unchanged since the swap is made to local variables in swap function.Now my doubt is how can I swap the pointers p[0] and p[1] inside the function swap??
Code:
#include<stdio.h>int main(){char*p[2]={"hello","good morning"};
swap(p[0],p[1]);
printf("%s %s",p[0],p[1]);return0;
}void swap(char*a,char*b){char*t; t=a; a=b; b=t;
}
I'm using code blocks ....
1.Write a program to swap positions of digits of a user entered three-digit integer N, where N is equal or between 101 and 999. (i.e. if user enters 389 your program should print 983. If user enters 300 program should print 003). Repeatedly ask user for correct N, if he/she enters an integer N which is not in the range.
2. Given that y= 4*( 1- 1/3 + 1/5- 1/7+ 1/9-...plus or minus 1/N) Write a program using a for-loop or a while-loop to compute and print the sum of first 50 terms of y.
3. a) Write a user-defined function funGx to compute G(x), where
5 if x<-10
x^2 +(5/x) if -10 <=x<-5
x^2 - (5/x-5) if -5<=x<5
x^2 -(5/x) if 5<=x<10
-5 if x>=10
b) Call the user-defined function funGx in main function to compute and print G(x)values for x= -15.5 , x=5, and x= 0.5 in an informative sentence.
While executing this code i was getting a error Invalid lvalue in assignment. Can any one tell how to correct this.
dataItem* d=(dataItam*)malloc(10*sizeof(dataItem));
dataItem* temp;
temp=(d+6);
(d+6)=(d+8);//error line
(d+8)=temp;//error line
I am having problems with my game of fifteen. I have implemented the swap> I know the swap takes place[using GDB] but the swap does not show on the screen even if GDB says it has taken place. I am getting no errors from the move function so I know that something is taking place. I was thinking that the problem may be in the draw function but it looks okay to me. I have looked at this over and over but I don't know why the draw is not printing the move to the screen.
#define _XOPEN_SOURCE 500
#include <cs50.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
// board's minimal dimension
#define MIN 3
// board's maximal dimension
#define MAX 9
[Code] ....
I have been trying to swap two adjacent nodes for my linked list sort. Its not meant to be optimal, just meant to work. My problem is I either lose nodes or get Access Violation errors.
PHP Code:
void List::sortList() {
Node *current = _head;
Node *rightNode = NULL;
if (_head->_data > _head->_next->_data) {
current = _head;
rightNode = _head->_next;
[Code] .....
"Write a declaration for a function that takes two int parameters and returns an int, and declare a vector whose elements have this function pointer type."
View 9 Replies View RelatedWrite a function that takes an array and returns true if all the elements in the array are positive, otherwise, it returns false.
View 6 Replies View RelatedI'm writing a program with a class containing a private std::vector<bool>. I chose bool because the vector represents a 2D array (think grid) and I only need 2 states per cell. I kept it one-dimensional as this hardly complicates things.
My problem is that I don't know how to initialize the vector, i.e. fill it with 0's.
The grid's resolution is not known at compile time, so I imagine I have to set the size (and content) of the vector in the class constructor.
Here's what I have tried among several things:
Code: World::World(const u_short worldsize)
{
grid.reserve(worldsize * worldsize); // grid is the private vector; square dimensions.
std::fill(grid.begin(), grid.end(), 0);
std::cout << grid.size();
} The output is 0. Only std::vector::push_back seems to have an effect on size(), but judging by its description, it doesn't look like the right candidate to populate a vector with zeros. Correct me if I'm wrong.
Frankly I expected line 3 to set the vector's size.
I have an integer vector of size "n".
e.g.
std::vector<int> vec;
vec.pushback(0);
vec.pushback(1);
vec.pushback(2);
vec.pushback(3);
Now I want to generate all possible combinations of size = {0, 1, 2, ... , n}.
{0, 1, 3} is not equal to {3, 1, 0} or {1, 0, 3} or {3, 0, 1}
I had a question about memory allocation/how iterators work for a std::vector<foo> of a user defined class 'foo'. Say foo contains variables of variable size, so that each member of the std::vector<foo> does not require the same amount of memory space.
Does c++ allocate the same amount of memory for each element, equal to the amount of memory required for the largest element? Or does it use some sort of array of pointers pointing to the location of each element in the vector to make the iterator work? Or does it use some other method? I am wondering because I wrote a code which reads data from a binary files and stores most of it in std::vectors.
The code seems to be using significantly more memory than the sum of the size of all the binary files, and I am using vectors made up of the datatype within the binary files (float). So I was wondering if internally the code was allocating space for each vector element which is the size of the largest element as a way to handle indexing/iterators. I ran my code through a memory leak checker and it found no errors.
I am currently trying to implement a 2d vector to store x and y of type int.
I have successfully passed it to the function, however i am unable to store the values in it. It always returns with a segmentation fault and my program terminates from there. May i know how do i store them properly and call them out?
Below is my code snippet
int reconstructSecret(int x, int y, vector< vector<int> > &inVec ,int constructSecret) {
int getX,getY,formula,accum,count,getSecret,startPosition,nextPosition,numerator,denominator;
getX=x;
getY=y;
int result;
[Code] .....
The main method
vector< vector<int> > inVec;
for(int i=0;i<constructSecret;i++) {
cout<<"please key in the "<<i<< "share of x value:";
cin>>x;
[Code] ...