C++ :: Swap Between Two References?

May 28, 2013

I have the following code segment:

Code:

void Swap(Number& num1, Number& num2)
{
cout<<"Before swap:"<<num1<<" "<<num2<<endl;
Number& temp=num1;
num1=num2;
num2=temp;
cout<<"After swap:"<<num1<<" "<<num2<<endl;
}

[code]...

to which the output is:

Code:

Before swap:13 11

After swap:13 11

13 11 that seems confusing.

why doesn't Swap() swap the two Numbers?

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[Code]....

appears that error on line 25 & 30 where swap1 & swap2 is not declared in this scope.

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Did a little Googling on this but couldn't find anything definitive. Is it safe to do something like

Code:
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store_for_later(&foo);
}

Then at some pointer later in execution, another function uses the pointer passed to store_for_later.

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Code:

int main(void) {
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[Code]....

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#include <iostream>
#include <cstdlib>
using namespace std;
const int SIZE = 3;
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[Code] ....

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for (int i=0; i<m; i++) {
for (int j=0; j<n; j++) {
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void f()
{
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[Code].....

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template<class T>
void swap_values(T& variable1, T& variable2)

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#include <conio.h>
using namespace std;
void fillVector(vector<int> &aVector);
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[code].....

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Sep 22, 2014

I simply need to know how I could swap the first and last letters of the input in this program:

int main() {
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    cout << "---------------------------------------------------------" << endl;  
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[Code] ....

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Code:

#include<stdio.h>int main(){char*p[2]={"hello","good morning"};
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}void swap(char*a,char*b){char*t; t=a; a=b; b=t;
}

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I'm using code blocks ....

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wait until an event on a condition variable occur.
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The second wait until an event on a condition variable occur.
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This is the code

thread t1([&p1]()->void{
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[Code] .....

Why it say error "abort() has been called " on the istr ***

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public:
void add(int& value);
void remove(int& value);
...
};
int main()
{
container c;
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// `value' should be accessible as type `int&' instead of being a pointer, `std::reference_wrapper<int>' or something like that
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