I would like my program to display other functions in the int main function. For example, this is what my program looks like:
int Function1(int &var1, int &var2, int &var3) {
cout << "blah blah blah" ;
cin >> var1 ;
var2 = var1 * 3 ; //example
var3 = var1 * var2 ; //example
if(blah blah blah)
[Code]...
How to ADD a call to the FindMostExpensive function AFTER the main display loop, and use the index returned to display the information about the most expensive car?
// Session7.cpp : Defines the entry point for the console application.
//using struct
// reading from file
// using functions
#include "stdafx.h"
#include <iostream>
#include <iomanip> // only used to tidy up the console output here
#include <fstream> // added file handling
[Code] .....
Write a program with two functions both called from main(). The first function just prints "Hello". In the second function ask the user to enter a number. Calculate the square root of the number and return the result to main(). In main() print the square root value.
Code:
#include<stdio.h>
#include<math.h>
float fun3 (float );
main()
}
[code]...
I need making my main function to run while not having any if or for statements. It can only declare variables and functions. Since my main function has command line arguments, how to so.
// This program counts all the words in a given file.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, char* argv[]) {
FILE* txtFile = NULL; // File Pointer
char str[1000000];
[Code] ....
So I need to make a main function have no if/for/etc. statements so I need to move it to another function and call it in main. The problem is that it's a command line argument function so I'm confused on how it works. Here's an example:
Code:
#include <stdio.h>
int main(int argc, char* argv[])
{
printf("The program name %s", argv[0]);
if (argc == 2) {
printf("Argument supplied is %s", argv[1]); }
else if (argc > 2) {
printf("Too many arguments");}
else {
printf("One argument");}
}
How can i make this into two functions with main only declaring variables and calling other functions?
I have seen functions that declare arrays in the function input even thou the arrays is already declared in main. Why do you do this?
For example:
int ova(int antal, char glosorSv[][MAX], char glosorEn[][MAX])
int main(void)
char glosorSv[][MAX]
char glosorEn[][MAX]
I have i want to call a function with two results for example x = 1 and y = 2.How do i return this function in c and how do i call such a function in the main program.
View 9 Replies View Relatedi have this program I am working on and it seems to crash after the function call getdata()
here is the code
#include<iostream>
#include<string>
#include<cstdlib>
[Code].....
I am trying to construct a program without a main function that outputs stars but at the same time outputs the number and a colon after the number but before the number of star. This is the coding i have so far.
void output_stars(int num){
if (num > 0){
cout << "*";
output_stars(num-1)
[Code] ....
The program is working the way it should i just can't figure out how to output the number and a colon. The main function is written as such:
output_stars(1);
output_stars(2);
output_stars(5);
output_stars(3);
output_stars(4);
output_stars(7);
How to get the numbers of the main function to show up with the stars of the previous function.
I just wanted to know what's the difference between these two types of main functions:
Code: int main (int argc, char** argv){ ... }
Code: int main (int argc, char* argv[]){ ... }
How to pass arguments from other functions to main. i want to write a program like nano well not exactly like nano editor. I have a function f_read(char* filename[]), and fopen() get filename[1] as file name and *filename[2] as "r" read mode and rest of the code will read from a file.
I want is this char filename[] to main(int argc , char argv[])
how can i do that??
How to implement the main queue functions Enque() and Deque() using two stacks S1 & S2. You allowed only to call push () and pop() functions of the two stacks to implement Enque()and Deque() functions.
#include<iostream>
using namespace std;
const int size=5;
int arr[size];
int front=-1,rear=-1;
bool isfull() {
if(rear==size-1)
[Code] .....
We are coding a Blackjack/21 game. I have a Deck.cpp class, Deck.h, Play.cpp (holds Main), and Card.h (holds card struct). I also have a Hand class/header, but I'm not using it yet. This is what is required per instructor.I am having issues accessing the functions that are in my Deck class. I have tried a few other means to access the class's function, but I've already gotten rid of those. These three are my latest attempts with the specific errors in the comment on the line the error was happening.
ve.
Here is my Deck.h
#pragma once
#include <iostream>
#include <fstream>
#include <string>
#include <cstdlib>
#include <ctime>
#include <iomanip>
#include "Card.h"
#include "Hand.h"
using namespace std;
class Deck
[Code]...
I'm trying to pass the value of an object created from a class file to a function outside of the "Int Main" function in the main.cpp file. I've successfully created the object, I just want to pass it to a void function but I'm getting the scope error below. I'm not sure how to correct. I'm not having much luck with research either (static variables?).
error: 'TicTacToe' was not declared in this scope
main.cpp
#include <iostream>
#include <cstdlib>
#include "Signature.h"
#include "Gameplay.h"
using namespace std;
// Initialize array
char square[10] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'};
[code]....
I was required to write a program that takes a baseball players statistics and displays there averages. I was required to make 3 function in the file to perform this tasks. my problem I am having a division problem in the SLG function. My compiler does not require the system ("PAUSE"); command.
OUTPUT
The player's batting average is: 0.347
The player's on-base percentage is: 0.375
The player's slugging percentage is:
(test)AB = 101
(test)Tot Base = 58
0.000
Code:
/* Batting Average Program
file: batavg1CPP.cpp
Glossary of abbreviations:
BA = batting average
PA = plate appearances
H = hits
BB = bases on balls (walks)
[Code] ....
I created class called students which suppose to store students names of in array but when I call the display function it display only the first name. but I want it to display names depending on the array size.
#include <iostream>
#include <sstream>
using namespace std;
const int SIZE=5;
[Code]....
I want to write a code that gets three values from the user and puts them into three arrays. When the user enters -999, I want to print out a chart showing all the values they put in. This is what I have so far but it wont build. It tells me std::string is requested, but I'm not sure where to put it, and printArrays is declared void. How can I fix this?
#include <iostream>
#include <string>
using namespace std;
const int ARSIZE = 400;
void printArrays (string reportTitle, int levelsArray[], int scoresArray[], int starsArray[], int i);
[Code] ....
Ok so I am working on a game and I'm in the process of developing my Player class. Anyways, what I have is a keyboard function that is called in my main function to make a shape move.
void myKeyboardFunction(unsigned char key, int x, int y) {
switch ( key ) {
[Code].....
But when I try to call it, trying to copy my previous method,
glutKeyboardFunc(Player1.playerControls);
I get an error
error C3867: 'Player::playerControls': function call missing argument list; use '&Player::playerControls' to create a pointer to member
I get an error saying it can't convert parameters. I would just like to understand why the arguments become a problem when I make the function a member of my class, when the first method I used is so easy.
The function is supposed to return value from the file in my main, but I am getting empty value. I am trying to get better with pointer. Right now just teaching myself.
right now the only way for this code to show value is when in put the putchar(*ps) inside my readfile function. I would like to readfile to return value and print in the main function.
Code:
#include <stdio.h>
char *readfile(char filename[]);
int main(int argc, char *argv[] ) {
[Code].....
I am writing a program in which a Fucntion has to be wriiten to parse the Command Line . When I include Code for parsing in main fuction iteslf ,its run ok . But I want to make a fucntion of that code and call it from main ,than it show Segmentation error .
By using Debugging I found Some thing is mess with " -m" Parameter of Command line , But Cant Rectify it ..
Code:
int main (int argc, char *argv[]){
//get_parameter_value(argc,argv);
// buffer[packet_size+1]= char ("'");
while (argc > 1) {
if (argv[h][0] == '-')
[Code] .....
int example (int [], int, *int,*int,*int,*int);
int main () {
My code will be here
example (int array[], int size, &a,&b,&c,&d); // Like this??? I try it didnt work
[Code] ....
I need to split my main() function into two separate functions.Where would the best place be to split it up?
* Read a text file whose name is given on the command line, and for each word:
* if it is an integer, insert it into an array in sorted order
* if it is not an integer, insert it into an array of words.
* Notes: converted to use C++ strings, because C strings are messier.
* Need to grow arrays, need to insert in sorted order.
* Growing arrays might be done the way we grew a C string:
* bigger = new <type> [size+1]
* for(i=0; i<size; i++) {
* bigger[i] = oldarray[i];
[code]....
Why the value does not return; Here is code
#include <iostream>
#include <string>
#include <ctime> // to use the time function
#include <cstdlib>
using namespace std;
int getUserChoose (int);
[Code] ....
here is the output
Welcome to the program of Rock, Paper, Scissors
The computer is ready to play the game
Are you ready to play the game
Y for yes and N for no
Y
R = Rock; P = Paper; S = Scissors
R
You have choose Rock
1TN
1RM
0U
0C
If so what is the reason, and the returning int value indicates wat?
View 4 Replies View RelatedI am getting call of nonfunction in function main <> error and 's' is assigned a value that is never used in the function warning...
#include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;
int main() {
float a,b,c,s,area;
[Code] ....
I'm currently writing a poker game and am trying my best to avoid using global variables. I have a few variables in int main() which i was hoping to use to store the value of each players hand. I then created a function which calculates the value of the hand but cannot get this value back into the main function.
For example:
Code:
#include <iostream>
using namespace std;
void getValue(int value) {
value = 4;
[Code] ....
Is there any way i can get the value of value using this function? If not what can I do?