This code snippet just won't compile in a conforming compiler:
Code:
template<> struct series<0.0, 0, 0>
Because of the floating point template parameter.... If this "specialization" is useful, how come MS would have discarded it?
I have a generic template class with another template in one of its types. Now I want to specialize one of its methods for a particular (template) class, which leads to a compile error, however.
Here is the example:
#include <stdio.h>
template<typename Type>
class Obj1 {
public:
void ID() { printf("Object 1, size = %zu
[Code] .....
GCC ends with:
:35:27: error: type/value mismatch at argument 2 in template parameter list for ‘template<class Type, template<class> class O> class Foo’
:35:27: error: expected a class template, got ‘Obj2<Type>’
What is wrong with the specialization? Can it even be achieved and how (if so)?
[URL]
#include <iostream>
struct Outer {
template<typename T>
void go() {
std::cout << Test<T>::f() << std::endl;
[Code] .....
I have tried several variants on this code to no avail. Outer is in a header, along with the extern template statements, and the specializations after main are in their own cpp file. Main is in a different cpp file.
What do have to do to make this work? I cannot bring the definitions of f() into the header, and they will be different for different template parameters. Ideally, I want Test to remain a private member of Outer, though this can change if it's the only option.
I'm trying to write some naive binary serialization code and wanted to cut down on repetition of logic for serializing/deserializing nested vectors or other STL containers to reduce the chance of typos etc, and thought templates might hold a solution for me.
Code:
template <typename T> void serializeField(IWriter& writer, const T& val) {
writer.write((char*)&val, sizeof(T));
}
template<typename U, typename V>
template <> void serializeField(IWriter& writer, const U<V>& collection)
[Code] ....
Is there a way to do something like this? It isn't a big deal for me to just manually write code to serialize my vectors to the needed depth, but it sure would be nice to get this working.
I've been trying to create a templated class that takes a template as a parameter. I'd like to specialise this class for certain partial specializations of the template parameter but can't seem to figure out how to do it nor find anything online, (although I may be searching for the wrong thing).
As an example, say I have a class A that takes a template class with two parameters as its parameter:
template< template<class X, class Y> class Z > class A {};
I'd like to have a general version of A, for a general version of Z, but a specialisation of A for a specialisation of Z, e.g. where X is int but Y is still any type.
[URL]
#include <iostream>
#include <type_traits>
template<typename T, typename = void>
struct Test {
static int constexpr value = 1;
[Code] .....
Why does it output 1 instead of 2? How can I make it output 2 and still output 1 for e.g. Test<double>::value?
I'm trying to get template specializations working for char * as well as for char[]. I.e. in the following code the last test does not use the specialization and fails:
Code:
#include <string>
#include <iostream>
#include <cstring>
template<typename T1, typename T2>
bool compare(const T1& lhs, const T2& rhs) {
[Code] ....
I want to write a template that combines two type of resources:
class someClasses {
typedef someType ElementType;
} template<class T1,class T2>
class combo {
...
}
And I want to specify my T1 and T2 has the same ElementType, how can I write my combo class to partial specialize the general case so the ElementType check is at compile time?
I want to specialize a particular function for Integer datatype inside a class template. My XX.h will be
namespace ZZ {
template <class T>
class XX {
void doSomething(T x);
};
}
provide me XX.cpp which has template specialization for the function doSomething on Integer datatype.
I tried the following in XX.cpp
#include "XX.h"
using namespace ZZ;
template <class T>
void XX<T>::doSomething(T x) {
[Code] ...
But this code is not working.
Can you take a look why I am getting compile error.
Code:
// clang++ main.cpp -g -std=c++11 -o main
#include <iostream>
class QuoteClass {
public:
QuoteClass() = default;
QuoteClass(std::string param) {symbol = param;}
std::string get_symbol() {return symbol;}
[Code] ....
Code:
#include<stdio.h>
#include<conio.h>
void main()
{
float i;
i=0.7;
[Code] ....
If i do run the above program in turbo C/C++ complier, it outputs "h". But,if i change the code as i=0.6 and if (i<0.6), it outputs "w". Even if i change it to i=0.8 and if(i<0.8), then also it outputs "w".
Code:
#include<stdio.h>
#include<conio.h>
float square(float);
void main() { clrscr();
float a,b;
printf("ENter a Number");
scanf("%f",&a);
[Code] ....
In the above program, I am calculating the square of float number. But sometimes the number is entered as NAN and sometimes Output is NAN. What is NAN? I am entering floating point number, then y NAN is entered?
SEE the Image attached for the OUTPUT.
if we have a decimal number like c=3.46
And i want to set two number, a and b
now a= static_type<int>(c); so a=3;
and i want b= 46
which is the two numbers after the decimal how can I do that ? how can I set b = 46 ?
P.S: i do not know what c equals to. now it's two number after the floating point but it might be more or less
Is there anyway we can return 2 values from a called function. Example
Code:
float xxxx(float a, float b, float c, float d)
{///
///
///
}
void xxx() {
int e,f,g,h;
////
////
xxx(e,f,g,h);
}
So if I want for example a+b and c+d, can i return those 2 answer? I don't think its possible since I am new into C programming.
I am having trouble understanding the mantissa of a floating point number. I have divided up the floating point number into the sign bit, the exponent and the mantissa, I have found the exponent, but I am not sure what to do with the mantissa? From what I have gathered so far i divide the mantissa by ten until I get a number between 1 and 10. after that i convert the number into a decimal with everything after the decimal point (or radix) being a fractional number. But when I do that on paper I dont get my intended number. How do i put the exponent and mantissa together to make a decimal from my floating point?
ex. input is 00111010000111111111011000001000
sign is 0
exponent is 01110100 which is 64+32+16+4-127=-11
mantissa is 00111111111011000001000 which would be 1.11111111011000001
When i convert that i get 1.99756622314 i dont know what to do with the -11 exponent and the answer i want is 6.1e-4
I'm trying to convert 4 hex register into floating point value using IEEE 754 floating point format. My device will reply 4 register value. The problem is that it always reply for example 0x10 as 10 when i use getc() hence using char variable to store it is not ideal.
Code:
union {
char c[4];
float f;
} conv;
Write a function named "sum" that takes as its arguments the following:
(1) an array of floating point values.
(2) an integer that tells how many floating point values are in the array.
The function should return as its value the sum of the floating point values. For example, if the array that's passed to the function looks like this:
0 1 2 3 4
5.8|2.6|9.0|3.4|7.1
The function should return the value as 27.9 as its value...I know I need to declare and intialize the array in the main function. I don't how to write the sum function.
I'm currently trying to learn about floating point representation in depth, so I played around a bit. While doing so, I stumbled on some strange behaviour; I can't really work out what's happening...
#include <iostream>
#include <cmath>
using namespace std;
int main(){
float minVal = pow(2,-149); // set to smallest float possible
float nextCheck = ((float)((minVal/2.0f))); // divide by two
[Code] ....
Essentially what's happening is:
- I set minVal to be the smallest float that can be represented using single precision
- Dividing by 2 should yield 0 -- we're at the minimum
- Indeed, isZero2 does return true, but isZero returns false.
What's going on -- I would have thought them to be identical? Is the compiler trying to be clever, saying that dividing any number cannot possibly yield zero?
Suppose I wanted to check if a given floating point value is within a certain range. What would be Your recommended approach when considering simplicity, speed, portability, etc.?
View 7 Replies View RelatedFunction is not returning a decimal point value. Here is my function
int meanValueFunction(vector<int> arrayValues){
int sum = 0;
sum = sumFunction(arrayValues);
float meanValue = sum/arrayValues.size();
cout<< meanValue << endl;
return meanValue;
I want result in decimal point i.e 27.2 for the values (2 4 20 10 100) but it returns 27 instead.
I need to implement a C++ program that asks the user for four floating-point numbers. The program should then calculate the average using two different functions, one value returning and one void. The program should output the average of the four numbers. For this program I need to use float instead of int for the types of variables. Below is a proto-type code that I am able to use to do this program.
#include <iostream>
using namespace std;
int sum(int,int);
[Code].....
I'm displaying a table of floating point numbers with setprecision(5). If the number is "1.25" it will display "1.2500" which is what I want. However, if the number is "0.25" it will display "0.25000"
How can I make numbers with a base number of zero display properly?
And it is not running successfully... abnormal termination
View 3 Replies View RelatedI can't seem to make this printf line work
printf("THE NUMBER PI
To six decimal places, pi is equal to \%f" ,3.141593 " which is roughly \%i", 3 "
");
I'm not sure what the correct syntax is to start and end a new write.
Can we change the floating point number format from scientific format to below example format ?
FROM TO
==========================
2.06374E-03 ---> 206370-8
-4.30311E-01 ---> -.430310
-4.28146E-04 ---> -42815-8
==========================
I have written this regex to match a floating point literal:
(^[[:space:]]*)(([0-9]+.?[0-9]*([eE][+-]?[0-9]+)?)|"
"(.[0-9]+([eE][+-]?[0-9]+)?))([fFdD]?[[:space:]]*)$
and when I match it with string like "123e" or "e2" it works while it shouldn't and I can't find the reason why.