C :: Comparing Part Of Character Array With Scanned Input
Feb 25, 2013
I want to compare the part of the character array with the scanned input. I've initialized the character array (colourCompare).
What I want to do is, if the input colour matches up with one of the elements in the colourCompare array, it will then read the next value(I did not include "read the next value part"). If the input does not match up, then it goes back to the scanning part.
The issue that I'm having is that when I run this part of the code it seems to enter the if statement and set it to 0 when comparing the array to the input.
What I want it to do is to search the array for the grade, set it to zero, and then exit the loop in case there are any repeat grades. It always sets the first number to 0 and then exits.
//Below is the prototyping for the array
int grades[14] = {60,50,50,20,75,90,0,0,0,0,0,0,0,0};
//There is some code between here, but it is probably not relevant so I didn't post it.
printf("Enter the grade that you want to remove. Press Enter after each input."); printf("Enter 0 to exit: ");
[Code] ....
I didn't mean to leave the "prototyping" part in the code. I was initially going to put the function prototypes in there, but decided it wasn't necessary for the question.
I created a function to check whether the first character of a string is a number or not by comparing it to every base 10 digit using a for loop. If it is, the string is valid, if it is not, the string is not valid
Code: //ensure the first character is not a number int ValidFirstChar(char FirstChar) { int IsChar = TRUE, DigitCount = 0; /*boolean value indicating whether the first character is a number or not.*/
//check through all base 10 digits for (DigitCount = 0; DigitCount <= 9; DigitCount++) { if ((int)FirstChar == DigitCount)
[Code] ....
I have checked for the case where the first character is a number but it is displaying the error message for it. I have tried typecasting the char variable but that has not worked.
Question simple like that: Let user enter some words from keyboard, one word per line until a '.' (period) entered then print out result, for example:
Code: Enter a word: word1 Enter a word: word2 Enter a word: . You have entered 2 word(s): word1 word2
Problem is I don't know how to declare the array of character at the beginning since I don't know neither how many word user may enter nor how many letter of each word. So I go ahead and declared like this: char word[20][50] but I know it is not best way.
Code:
int main () { char word[20][50]; //array has maximum 20 words, each word maximum 50 character int i=0, number_of_word; do { printf ("Enter a word: ");
I'm trying to solve the ferry loading problem using two queues. My problem is I can't enter in data after the first set is scanned in, I'm assuming there is a problem with my loop, such that the scan function doesn't get called after one iteration. In the example I marked the data I can't enter. An example correct input would be:
correct input: 1 - can enter data20 4 - can enter data 380 left - can enter data 720 left - can't enter data 1340 right - can't enter data 1040 left - can't enter data
I have a character array that includes configuration bits that are 0x00, thus when I try and do a strcat it adds the appended string into one of those spots instead of the end of the array.
How can I Passe some part of multi-Dimensional Array to a Function; for example only two dimension of three dimension of a an array with 3 dimension. This is because my function is defined for working with 2 dimension arrays.
the real char got 1000 digits this is just example how do i convert chars from numbers[4] to numbers[15] and save them as one number ? in this case i will get int x = 5444546546545643 as u can see char numbers as a example above
I wanted to check whether the input is a character or not, if a character is given then the output suppose to be "ok", but the output is always "oppppssss", where is the problem here?
im working on mine first 2d game and im practicing a lot, how to input my inventory for character ( for items, and others ) So, i just want to let u know that i have :
So, i want to put this in my shop and if i buy it i want to appear in my inventory, or sell sell trought my inventory.Also i have one define
#define WEAPONBEGIN_WOODENSTICK (1)
Which will go instant ( when u create character ) to inventory. And:If i have 1, 2, 3, 4, 5, 6, 7, 8, 9 slots ( example ) and i sell item which was on 3rd slot, what will happen with others ? will they just go back for one slot or ?
i have 3 arrays total, 2 of them i am comparing to see if any of the values match at all, and then i am putting the value that matches into the 3rd array. currently i am trying
int isthere (int match[], int maxmatchLength, const int vec1[], int vec1Length, const int vec2[], int vec2Length) { for (i=0; i<vec1Length; i++) if vec1[i]==vec2[i]; vec1[i] = match[i]; }
But this will just match the same values are in the same spot. how do i fix it so that it compares one value in the first array to the whole second array, before going to the next number.
I am working on a program to find uppercase, lowercase and digits in a 2D char array. When I try to use an if statement to increase the counter, I get an error "no conversion from 'int' to 'char*'". This is the if statement I am using.
What I am doing is using fgetc to take a char input from the user, and then directly after that calling a function which will clear the buffer and remove the character. But for some odd reason all my inputs are being assigned before taking the char input by the user. Here is my code for the relative problem:
Code: char playAgain; Code: playAgain = fgetc(stdin); readRestOfLine(); Code: void readRestOfLine(void) { int ch; /* remove all characters from the buffer */ while(ch = getc(stdin), ch!=' ' && ch!=EOF) ; /* clear the error status of the input pointer */ clearerr(stdin); }
And en example through terminal of the issue, with print statements debugging the value of play Again:
So in both instances here I have entered 'y', one returning it as ASCII 10 which is ' ' and ASCII 121 which is 'y'.
Code: #include <stdio.h> int main(void) { char c; int i=1; while (scanf("%c", &c)==1) printf("loop sequence %i: %c(%i)
[Code] ......
Done it seems a "carriage return" serves two purposes here, one is to signal the program to read in the character typed in before the "carriage return", another serves as a second character typed, how can i do this cleanly, that is without having to use a "carriage return" as the second character to signal "I've typed in the first character already".
I am having problems printing "->" on the beginning of each line, im trying to do it as a loop and ending it when the user types "q". also i would like to know how to ignore text from the user when the input begings with a specific character. heres what ive done so far, and not currrently working as expected.
Code: #include <stdio.h> int main (void) { char prompt; printf("~~~ FRACTION CALCULATOR ~~~
I'm very new to c programming and I have some background in C# and java. I am supposed to read a string from input then determine in that string, which character is the largest, i.e. I think b>e and e>z, e.t.c. If the string is empty I should return ' '.
I haven't done any programming in C before and I don't know how to handle strings and characters in C.
I have function that looks like this myfoo(char* Name) Now i want to compare this name to another one . But the another name is a pointer . This my code :
I wrote a program that reads a list from a file and stores it in a string type vector. Now, I want the user to input a word so that the program can search the vector to see if that word already exists. I have used every possible way of reading input from the console and storing it in order to compare with the vector but it never results in a match. When I print the input string and the vector string they are exactly the same thing (or at least print to the console as if they were). I've tried using getline; using cin direct to a string var; using cin to a char array and then casting to string using string str(arr); I even added a newline at the end just in case and STILL I cannot get a match.
vector <string> currentSet; //read a list in from a file and has 9 items in it cin.ignore(); string line; getline(cin, line); if(line == vector[0]){//if printed to console line is HEAT and vector[0] is HEAT cout<<"match"<<endl; }
I am stuck in this program, Be given a string of chars, where each single char belongs to the following alphabet: a..zA..Z0..9 (So, in the string there are only lowercases, uppercases and digits. No blank, no comma, ...). For every char of the given alphabet, count how many times in the string
1-- the char belong to a sequence of identical chars whose length is at least three (i.e.: in the string cc74uyrpfccc348fhsjcccc3848djccccc484jd for three times the character 'c' satisfies this condition)
I'm new in programming, and trying to write a code in C. The requirement is following - to write a text, and to find frequency of 1 chosen character in it. The main thing is that program should check user input (for example, I want to check if user entered "char" --> then correct, or if entered "int" --> not correct). But the program still doesn't check. So I have:
Code: #include <stdio.h> int main(){ char c[1000], ch; char i, count=0; printf("Enter a text: "); gets(c);
