See code below:
#include <stdlib.h>
#include <stdio.h>
int main ( int argc, char *argv[] ) {
int P[150] = {}, i, j;
for ( i = 2; i <= 150; i++ ) {
[Code] .....
Using gdb, I noticed that the variable j keep going back to initial value after the interior for loop condition returns false. Why doesn't this for loop terminate right away?
I am writing a program to display a triangular pattern using nested loops and user input for the size of the base and character used to generate the image. 99% of the program runs fine. However I am having trouble with some of my input validation.
When given an integer value for the base I can verify if it is within a certain range (0-80). However, when the user inters a "char" instead of an "int" the program enters an infinite loop.
Here is the piece of code giving me trouble. (I wont bother you with the entire chunk of code, I have commented out everything else to narrow down the problem bit)
// Pattern Displays
// program that asks user for the size of the base of a triangle and then generates it in a character the user chooses
#include <iostream>
#include <istream>
#include <string>
#include <cstdlib>
using namespace std;
int main () {
char escape;
[Code] ....
What I need to do to get rid of the infinite loop?
Code:
do {
printf("Enter the number of tests:");
scanf("%d", &test);
if (test< 0 || test> 4)
printf("Wrong number. Please try again!
");
}
while (test< 0 || test>4);
I have been trying to get this piece of code to work but it seems to be running infinitely. What i'm trying to do is that whenever the iterator points to the map element, I check whether the element is 1 or 0. If it is 0, *do something*. But if it isn't, it should not do anything and proceed to the next element in the map.
//infinite loop - not working!
for (MapType::iterator p = pwCounter.begin(); p != pwCounter.end(); ++p) {
if (p->second.second != 1) {
[Code]....
my code seems to enter an infinite loop should a user mistakenly enter a character other than a digit. The code is about selecting from a preset number of options, numbered 1- 4. If the user mistakenly enters a letter for example, instead of a number, the infinite loop kicks in...
View 1 Replies View RelatedI have made a program that can take an infinite string:
Code:
#include<stdio.h>
int main(void) {
int i = 2, j = 0;;
char *string;
printf("Enter any string:
[Code] .....
But there is some problem in it, like its printing extra characters after string. reading infinite characters in a string
#include <windows.h>
int main() {
int i;
int y=6;
int x=9;
gotoxy(x,y);
//gotoxy(x,y) must be the coordinate that the number lies in.
[Code] ...
How to make this program that the output is a number that counts up to infinite (or we say just like a timer but there's no minute just all whole number counting up ) using for loop ? and when the number changes it also change in color !
and the color of a number is according to the color attribute of console output.
So I have to create a program which will print, among other things, a rectangle made of asterisks. The rectangle has to follow this general format:
*****
* *
*****
but with the width and length of the rectangle being set by the user. I've tried every way I can think of to work this out, but I can't seem to get anything to work. The main errors I'm getting are either an infinite loop of asterisks filling my screen or nothing at all, depending on whether I use an && comparison or ||. A screenshot of my code is included below.
The code below gives me the maximum odd number and the minimum even number of a list of numbers that the user type. However, for the loop to stop the user needs to type 1000. Is there a better way (without having to have a "stopping" number, just in case I need this number to be somewhere on the list) to get the same results?
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
#include <string>
using namespace std;
int main() {
int x, maxi, mini;
[code]...
Code:
// Lab0Inventory.cpp : Starter lab
//Anastasia Glyantseva
#include "stdafx.h"
#include <fstream>
#include <iostream>
#include <iomanip>
#include <sstream>
[Code]....
I can't figure out why my makeString gets called first and the pString its called with contains garbage. I want my allocateMem to get called first, but my program is not going to that. What is wrong with the order of my code?
I have a small loop that gets the user input, as well as acts as input validation to make sure he or she doesn't enter a value that is not within the specified range.
The user is supposed to enter a month number. E.g. if he or she chooses February, then enter 2, or December, 12.
It works correctly if they type a number that is not in the range, but goes into an infinite loop if, say, they type a string such as "month".
Code:
int main() {
// Variable Declaration(s)/Initialization(s)
int month=0;
// Get input
cout<<"Enter a month";
cin>>month;
[Code] ....
How could I go about revising this?
I have the program working but when I check if the input to make sure it is not a char it creates a infinite loop. I used an if statement to check for the issue and solve it but its not working. I even tried throwing an exception but I learned later they are not used for things like this.
Code:
#include <iostream>
#include <limits>
#include "contacts.h"
using namespace std;
int main()
[Code].....
So I learned how to make a basic for loop and I decided to try my best to make an infinite one. Every time I run it, it doesn't say anything and just closes. Visual Studio doesn't say there's anything wrong with my code.
Here's the code
#include <iostream>
#include <conio.h>
using namespace std;
int main () {
int d = 9;
for(int k = 10; k < d; k = k +1) {
cout << "For loop value = " << k << endl;
getch();
} }
Why I have an infinite loop when reading from a pipe?
i = 0;
while(i < 10) {
test_value = read(pipe3[READING], &message, sizeof(struct MESSAGE));
printf("test_value is %d
", test_value);
//printf("Entering infinite loop
[code]....
I have more programming before this, but everything else works fine. My else loop has an infinite output. i also want it to output an error message if the value is not an integer and return to the input
cout << "Select number corresponding material for fencing:" << endl;
cout << "wood = 1" << endl;
cout << "stone = 2" << endl;
cout << "aluminium = 3" << endl;
cin >> material;
if (material == 2){
cost = 100 * perimeter;
[code]....
How exactly did u accept it as a string? i mean did u use ascii values or anything? and what was your code for keeping track of carry?
View 1 Replies View RelatedI currently have a hangman game in the making. Which is giving me debugging issues when I go to pick a letter, it will keep asking for a letter, if I place a break; within the loop it asks for a letter and says you've won. I know all I should need is a couple extra lines somewhere within the code.
/// Play game
public static string playGame() {
Words words = new Words();
[Code].....
This function is apparently causing infinite recursion, but I have no clue what's causing it:
Code:
int pow( int base, int exp ) { int somevariable = pow(base,exp-1);
if (exp == 0) {
return 1;
}
else {
return base * pow(base,exp-1);
}
}
From the example given below, I would like to Generate a matrix who stores a generated array for each iteration. I have an understanding of inputting single elements to a matrix but how can I input an array to a matrix. let's say I would like to input and array of 4 elements that should be stored as a single row of the generated matrix and do this for an infinite while{true} loop.
#include <iostream>
#include <unistd.h>
#include <cstdio>
#include <cmath>
#include <ctime>
#include <stdlib.h>
#include <stdio.h>
#include <vector>
void printArray(int arr[], int size) {
[Code] ....
I wondering how to stop a infinite loop. The program clears a file then opens it and refreshes it over and over(the file is going to be modified by another program). I want it to start from the beginning anytime i press enter or escape, it doesn't really matter as long as you can restart it.
Here is the complete code:
#include <cstdlib>
#include <iostream>
#include <fstream>
#include <conio.h>
#include <windows.h>
using namespace std;
void x() {Sleep(1000);}
[Code] .....
I am getting an infinite loop when my program generates a new bracket
#include <iostream>
#include <string>
#include <stdlib.h>
#include <numeric>
#include <fstream>
#include <vector>
using namespace std;
const int MAXTEAMS = 20;
const char* c;
[Code] ....
it will produce the answer above..when user enter a nonnumerical character it will force the user to reenter again
do {
cout<<"Min of the secret number : ";
cin>>min;
}while(cin>>min);
cout<<"Max of the secret number : ";
cin>>max;
this is my coding but it will auto jump out when i enter non-numeric character
it will produce the answer above..when user enter a nonnumberic character it will force the user to reenter again
do
{
cout<<"Min of the secret number : ";
cin>>min;
}while(cin>>min);
cout<<"Max of the secret number : ";
cin>>max;
this is my coding but it will auto jump out when i enter non-numberic character
I am unable to find why my code is going into infinite loop as below. This works perfectly fine if I keep entering just the integer values but if I enter a float number it ends up in an infinite loop
int main() {
int x;
while(1){
cin>>x;
cout <<x;
}
return 0;
}
I'm having trouble getting my loop to work correctly. If I iterate the for loop once it works as expected and displays proper output. When I try to iterate two times or more the program gets stuck in an infinite loop.
testData8.dat:
Code:
12 9
13 756
I am trying to code a partition quicksort but the problem here is at the output is in an infinite loop:
The input : 4 3 5 7 2
The expected output : 2 3 4 5 7
But my output is infinite :
2 3 4 5 7
2 3 4 5 7
2 3 4 5 7
.
.
and so on
[Code:
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
/* Head ends here */
void partition(vector <int> ar) {
[Code] .....