I currently have a hangman game in the making. Which is giving me debugging issues when I go to pick a letter, it will keep asking for a letter, if I place a break; within the loop it asks for a letter and says you've won. I know all I should need is a couple extra lines somewhere within the code.
/// Play game
public static string playGame() {
Words words = new Words();
my code seems to enter an infinite loop should a user mistakenly enter a character other than a digit. The code is about selecting from a preset number of options, numbered 1- 4. If the user mistakenly enters a letter for example, instead of a number, the infinite loop kicks in...
I'm having trouble getting my loop to work correctly. If I iterate the for loop once it works as expected and displays proper output. When I try to iterate two times or more the program gets stuck in an infinite loop.
how to ask for the input (className) without getting stuck in the loop. When I remove
char className; cout << "Enter the class name: " << endl; cin >> className;
it works fine. When I leave it how it's displayed below it goes in an infinite loop. By the way I think "char" is not the appropriate way to declare className. If I want to output it later, should I changed it to "string"?
#include <iostream> using namespace std; int main() {
I want to create a loop that that generates a random number set and gives the user the option to run the loop again for a new number. I have that working but when the loop ends the variable value does not leave the loop. I tried a posttest and pretest loop.
Is it possible to declare/create/alter a variable in a loop and have that value exit the loop to use in the code later? I am still learning about global variables.
#include <iostream> #include <cstdlib> #include <ctime> #include <string> int oneDiceSix() // Roll 1d6 {int oneDiceSix = 1+(rand()%6); return oneDiceSix;} //end function
Code: #include<stdlib.h>#include<stdio.h> #include<unistd.h> #include<math.h> int main(void) { double N, NG, LG, epsilon, root; // setting all variables to type double
[Code] .....
The goal is to create a program to calculate the square root of a number provided by the user to an error tolerance 0.005
Looking around i fond the Code: fabs(NG - LG) < epsilon); section that was very similar to what i was using, but if this is better im down for that.
My issue, from what i can see, is the updating of the values of LG. if the test for error tolerance fails then LG needs to take on the value of the results of NG.
Now I am not 100% that is the point of failure due to the fact the script does calculate the root properly, but it never exits the program once it reaches the tolerance level.
Code: imac:ENG-3211 user$ ./hw_4_1
Please enter the number you wish to find the square root: 4
What I need to do to get rid of the infinite loop?
Code: do { printf("Enter the number of tests:"); scanf("%d", &test); if (test< 0 || test> 4) printf("Wrong number. Please try again! "); } while (test< 0 || test>4);
So I have to create a program which will print, among other things, a rectangle made of asterisks. The rectangle has to follow this general format:
*****
* *
***** but with the width and length of the rectangle being set by the user. I've tried every way I can think of to work this out, but I can't seem to get anything to work. The main errors I'm getting are either an infinite loop of asterisks filling my screen or nothing at all, depending on whether I use an && comparison or ||. A screenshot of my code is included below.
The code below gives me the maximum odd number and the minimum even number of a list of numbers that the user type. However, for the loop to stop the user needs to type 1000. Is there a better way (without having to have a "stopping" number, just in case I need this number to be somewhere on the list) to get the same results?
Code: #include <iostream> #include <iomanip> #include <cmath> #include <string> using namespace std; int main() { int x, maxi, mini;
I am trying to get this code eventually to read in a maze file to move the smiley face around in. But right now my current snag is the yes or no to enter the for loop.
#include <iostream> #include <windows.h> #include <conio.h> #include <time.h> using namespace std; int main() { int name; char ans;
I have a small loop that gets the user input, as well as acts as input validation to make sure he or she doesn't enter a value that is not within the specified range.
The user is supposed to enter a month number. E.g. if he or she chooses February, then enter 2, or December, 12.
It works correctly if they type a number that is not in the range, but goes into an infinite loop if, say, they type a string such as "month".
Code: int main() { // Variable Declaration(s)/Initialization(s) int month=0;
I have the program working but when I check if the input to make sure it is not a char it creates a infinite loop. I used an if statement to check for the issue and solve it but its not working. I even tried throwing an exception but I learned later they are not used for things like this.
Code: #include <iostream> #include <limits> #include "contacts.h" using namespace std; int main()
So I learned how to make a basic for loop and I decided to try my best to make an infinite one. Every time I run it, it doesn't say anything and just closes. Visual Studio doesn't say there's anything wrong with my code.
Here's the code
#include <iostream> #include <conio.h> using namespace std; int main () { int d = 9; for(int k = 10; k < d; k = k +1) { cout << "For loop value = " << k << endl; getch(); } }
I have more programming before this, but everything else works fine. My else loop has an infinite output. i also want it to output an error message if the value is not an integer and return to the input
From the example given below, I would like to Generate a matrix who stores a generated array for each iteration. I have an understanding of inputting single elements to a matrix but how can I input an array to a matrix. let's say I would like to input and array of 4 elements that should be stored as a single row of the generated matrix and do this for an infinite while{true} loop.
I wondering how to stop a infinite loop. The program clears a file then opens it and refreshes it over and over(the file is going to be modified by another program). I want it to start from the beginning anytime i press enter or escape, it doesn't really matter as long as you can restart it.
I am unable to find why my code is going into infinite loop as below. This works perfectly fine if I keep entering just the integer values but if I enter a float number it ends up in an infinite loop
int main() { int x; while(1){ cin>>x; cout <<x; } return 0; }
I am writing a program for grading a multiple choice test. The test data is pulled in from another file. My problem is that its only pulling in the first line of data and running an infinite loop without reading the next line of the data file.
I am getting and infinite loop for loop pointer variable current which points to head and is incremented by current->next in while loop. I use the pointer variable the same way in my display routine and it works. Here is listing of code.
#include "stdafx.h" #include<iostream> struct node{ int data; node *next;