C++ :: Subtract In A String With Decrementation

Nov 24, 2013

Here's my code :

>>>>>
std::vector<std::string> x = split("3 5", ' ');
int total = 0;
// then we loop over the elements
for(size_t i = 0; i < x.size(); ++i) {
// convert the string to an integer
int n = atoi(x[i].c_str());
total = total + n;
}
std::cout << "total = " << total << std::endl;
}
<<<<<

So, as you can see, this will add 3 to 5. However, I would like it to do the inverse (3 - 5). How I can do that?

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I have a code for subtract of two char arrays(size of each is 50).but i want to write this program with string and i should be consider that size of each string may be not equals.for example we have s1=4777 and s2=55.and we should be subtract them. This is my code.

char* sub(char x[50],char y[50]) {
int i,j,temp=0;
char z[50]={'0'};
for(i=0;i<50;i++)

[Code] .....

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I know how to do it and can do it in real life. It's like, "Oh, I need to pay $93. So I use four $20 bills, which brings me to $80. Using one more would bring it to $100, which is too much. So now, I need to use a $10 bill, which brings it to $90. Oh, so now, I need to use three $1 bills, which brings me to $93."But how do I tell that to a computer? It seems like I would have to put some kind of limits on it, or string code lines together,Here is the code so far:

Code:

#include <stdio.h>int main(void)
{
int amount, twenty, ten, five, one;
printf ("Enter a dollar amount:
");
scanf ("%d", &amount);
}

[code]....

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Code:
main() {
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int minute=5;
int second=13;
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[Code] ....

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the prototype is: void subtracting(char array[], int size, int value)

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#include <iostream>
#include "SafeArray.h"
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[Code].....

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Code:

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#include <math.h>
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[Code]...

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Oct 7, 2012

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And here is the test data. I am posting the results from my desk-check table.

operation first integer second integer answer
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S 65 50 15
s 7 13 6
G -1
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d 45 15 3
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Then, I transferred my program into a source file. Here it is:

//Exercise16.cpp - display answer of two integers

#include <iostream>
using namespace std;
int main() {
//declare variables
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[Code] ....

After putting in the data, everything worked fine, except the last two operations, which are M (multiplication) and D (division). All the answers for the last two operations essentially give me a 0.

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[Code] ....

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Code:
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[Code] ....

Now I understand that it returns the count in "int" so my question is:

Let's say i declared

Code: int count = 0;
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[Code] ....

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k

but I want
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K

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Code:

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[Code] ....

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[Code]...

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