C++ :: Solving Linear System Of Equations Using Threads
Dec 14, 2014
I am trying to write a code that solves a system of linear equations such as A*B=C. My system has a dimension equal to 1600. The matrix A cab be separated into 4 sub matrices and each can be handled by a different thread. I tried to solve this using the following code:
int main() {
int count = 0;
//Inputing matrix A
ifstream matrix;
matrix.open("example.txt");
[Code] ....
Although the above code gives the correct answer, the time needs to find the solution is bigger than that needed without using threads.
I have a problem: solve the system of equations by the Gauss-Jordan methods with pthreads. I have a big matrix A (for example 2000x2000), so i must solve Ax = b. Before I devide matrix to number of threads and each thread must work only with his peace of matrix.
Code: #include <iostream> #include "synchronize.h" #include <pthread.h> using namespace std; typedef struct _ARGS { int thread_count; int thread_number;
[Code] .....
I write it on Ubuntu, and when I compile [g++ main.cpp -o main -lpthread -lm] the it works good(for example, if in 1 thread I get time_of_working = 10 sec, on 2 threads time_of_working = 5.4, i.e. about 2 times faster ), if I compile like this [g++ main.cpp -o main -lpthread -lm -O3] it is only 1.2-1.3 times faster.
I am using the gnu glpk library to calculate a linear program for my matrices. Why I get the error message exit code 3 which apparently means "The system cannot find the path specified"?
If i m writing a code for a program to solve factorials, what is the best approach if i have large numbers in mind?
If i use int, i can only go upto 4bytes and if i use double i can go upto 8bytes. so should i create new type or is there any other way to get this done.
I am writing a program to solve a triangle. Given any three pieces of information, find the other three. I am having trouble with SSA. I use the cosine law to find the unknown side. Then I use the sine law to find the other two angles. The sine law will give me each of the other angles. If one of the unknown angles is over 90 degrees, my program gives an angle as under 90 degrees. Not surprisingly, the correct angle and my wrong angle add up to 180 degrees. If you draw out the triangle you can deduce the right answer. How to have my program find out when the angle needs to be over 90 degrees.
I need to find out all the possible equations which are same of a given equation. For eg. a+b+c-d and b+c+a-d are same. So if the user inputs a+b+c-d then the output will be all the possible equations that can be formed from the given equation, viz:
a+c+b-d c+a+b-d -d+a+c+b
etc
i.e the program should rearrange the operands and operators in such a way that it should give the same result.
Program which accepts two lines and and determines their intersection point and whether they lie within a circle, also given interactively. I'm racing against time and I've racked my skull to no avail
/* Check numbers of arguments, and read input */ validInput = (argc = 4);
[Code] ....
Is a section of the code (the first section). And as you can probably guess, it goes on to calculate for a > 0 etc...
I dont really understand what the validinput section is saying? And a, b and c are never defined so Xcode is just saying a,b,c,root1,root2 are uninitialized and I also dont know what means. Do I need to define these values?
Code: int main(int argc, char *argv[]) { int validInput, solution_type; double a, b, c, root_1, root_2, q;
The main point of the program is to calculate equations just like a standard calculator but I wanted to do it myself. I don't understand what the problem is right now but I've managed to create a program that asks for both values but somehow it doesn't want to ask for an operator (*, /, + etc). What's wrong with my code that the terminal skips the scanning part for the operator?
Code:
#include <stdio.h> int main() { int value1, value2, answer; char operator;
I wrote a program that solves an equation of two numbers, but in addition to that, I want it to be able to continue to solve longer equations. Ex: ( solves 2 * 4, or 2 * 4 - 5).I want to put this part of the program's result into a variable and go from there. How do I place the result of the calculation into a variable, and where would it go?
Code:
#include <stdio.h> #include <string.h> int main(void) { int a; scanf("%d", &a); char s[2]; scanf("%s", s); int b; scanf("%d", &b); }
I have to make a numerical integration program, how I can write my code so that the user is able to write their own function that they want to integrate?
E.g. they would see the message: 'please enter your function' and would be able to write whatever they wanted e.g. 'x +5' then this would then be integrated by the program.
I have already written a program that can integrate a known function but would prefer that the user could choose their own.
Calculated by the explicit scheme. Produces some very large numbers.
task:
[math] U_t = 3 (1,1-0,5 x) U_ {xx} + e ^ t-1 [/ math] [math] U (0, t) = 0 [/ math] [math] U (1, t) = 0 [/ math] [math] U (x, 0) = 0.01 (1-x) x [/ math]
Need to find a solution with accuracy [math] 0.0001 [/ math] on the interval [math] T = 1 / a ^ *, where a ^ * = max a (x, t) [/ math] Plot graphs of functions [math] u (x ^ *, t), u (x, jt ^ *) [/ math] where [math] x ^ * = 0.6, t ^ * = T/10, j = 1,2,4 [/ math]
I found this program in a forum and it creates 1 to t threads with each thread pointing to the next and the last thread pointing to the first thread and it allows each thread to sequentially take a turn until all threads have taken n turns. That is when the program ends.
My doubt is if we see in void *tFunc(void *arg) function, first thread locks the mutex and then wait there forever till it's turn comes.Lets say if I spwan 1000 threads and they have take 10 turns each sequentially and what if a 550th thread locks the mutex as soon as the program starts and waiting for its turn which will never happen because still (turn=1) which means it's first thread's turn and first 549 threads have to complete their 1st turn before this 550 threda's turn comes.Doesnt this result in deadlock?
The problem is i don't want to use local vars , is ther anyway do end the loop safely(removing all the vars used in function and etc) without using a local var ?
I had a requirement where i needed to create a thread and if the execution of thread is not completed in 5 minutes i needed to terminate its execution and continue with other part of the code.
I used the below code to create the thread
_beginthread(FuncnCall,0,NULL);
HANDLE hThread = GetCurrentThread();
Then after this code, I used the below code to check for 5 minutes
for (int i=1;i<=0;i++) { printf("Value of i=%d ",i); if(threadFinished) { break; } else { Sleep(1000); } }
After this if the value of "threadFinished" is false then i am terminating the thread like below
The Problem here is, after terminating the thread, the program abruptly closes by giving fatal error. Looks like memory leakage is happening after terminating the thread. Is it not the right way to safely exit the thread?
I am trying to do single axis solar tracker with linear actuator /rtc/ UNO. I have already done with feedback sensor.
Now Here I am trying to without feedback. Linear actuator specification: 24v , 3.2mm/sec as speed , 600mm stoke.
Desired angle calculation: tracking start from 7am to 18PM, 11hours Assumed degree: 7AM as -45 deg , 12.30 as 0 degree and 18 pm as 45 degree. static float slope= 0.00227272727273; static float intercept=- 102.272727273;
[Code] ....
How can i put time here. Coding for calculating Ton time and solve above equation. below i posted my code . I need it has to be modified little bit. i need to implement ton time actuator here.
I need function takes desired and actual angle , where actuator try to move to its actual desired position.
Code below in arduino version
Code: double Desire_Degree; unsigned int TS; static float slope= 0.00227272727273; static float intercept=- 102.272727273; static int length; double Actual_Degree;
I'm trying to write a continuous linear linked list. But whenever I run my program and enter an option from my list, my switch statement gets highlighted in green and says "Thread 1: breakpoint 3.1. And then my program just stops. I'm wondering what part of the switch statement I've gotten wrong.
Here's my code. #include <iostream> using namespace std; struct node { int key; node *next; }; node *l; void print(node*list)
How to return a message saying that the value searched for is not found. We had to pull the data in from a .dat, i won't let me attach it as a .dat so I attached it as .txt. I know my it's sloppy. I usually clean up what I can once it is working properly.
#include <iostream> #include <iomanip> #include <fstream> #include <string> using namespace std; int ccnt; int size = 10;
