C++ :: Scope Of Inline Function Definition

Dec 11, 2013

I have observed that inline functions can not be prototyped. example:

.cpp file:

inline void whatever() {
cout<< "this is inline"<< endl;
}

.h file, prototype
inline void whatever(); //would ask for a definition

Because of this, I have have just made functions that are used in only 1 .cpp file (ever) inlined, to make it more efficient (and it has demonstrated that it is more efficient). It's worked out fine so far, but what about the scope of the definition??

Since an inline function is like a templated function, in that it can't be prototyped, how are name conflicts resolved, and what is the best practice for writing inline functions??

Example of a conflict:

//in some arbitrary header...
void do_somthing();
//in .cpp file that inlcudes the header...
inline void do_somthing() {
cout<< "I'm doing somthing!!"<< endl;
} int main() {
do_somthing(); //which one?? it compiles fine though!!
return 0;
}

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C++ :: Compiler Not Always Be Able To Insert Code For A Function Inline

Apr 14, 2013

This: "The compiler may not always be able to insert the code for a function inline (such as with recursive functions or functions for which you have obtained an address), but generally, it will work."

For a function inline why wont it work for a recursive function or a function for which you have obtained an address?

Why cant the compiler still insert the inline?

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C++ :: Inline Function Prefix - External Call And GCC?

Jan 17, 2014

I have some functions inlined using the inline function prefix. If the function is called from outside the file (so a seperate psp-gcc -O3 ... filename.c filename.o compile command, when only the function is changed), will the other files be updated too? (I'm using the pspsdk toolchain).

Example:

max.c
inline byte max(byte a, byte b) {
return a>b?a:b;
} use1.c
void use1() {
if (max(1,2)==0)

[Code] ....

If I compile this, next change the max function and recompile using make (the compiler only takes the changed max.c->max.o file, next links them together) will use1.c&use2.c be updated with the new max.c function?

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C++ :: Template Function Don't Work As Inline Function?

Mar 8, 2014

I have this:

string input;
unsigned short choice;
...
istringstream valid(input);
...
if(!(valid >> choice))
{
//some error
}

Ok. My code is almost 1000 lines, and I have splited some functions in headers. But the same function doesn't work:

template <typename T> bool valid_input(const string& input, T var)
{
istringstream valid(input);
return (valid >> var);
}

You can check it here: [URL] The output is correct, but in my machine with C++11, MinGW 4.8 (64 bit in a 64bit-Windows8), the output is incorrect. Why?

If you want more specific info, the problem is that I use input, I think. I use std::getline(std::cin, some_string).

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C++ :: Global Scope And Scope Resolution Operator

Jun 14, 2013

Are there any situations to explicitly use the scope resolution operator with global scope? I can imagine a situation like:

#include <cmath>
class IntWrapper{
public:
IntWrapper& pow(char);
IntWrapper(char);
private:
int m_int;

[Code] ....

But then I would think that the writer should have used a different name, and that using the scope resolution operator in the constructor body is still pointless...

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Visual C++ :: Cannot Use Global Scope Max Function

Jan 30, 2013

The compiler "forces" me to use the std::max method, I cannot override it even when writing ::max in my code.

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C++ :: Stack Function Is Supposed To Represent Scope Of Program

Dec 5, 2014

I am trying to make an interpreter. This stack function is supposed to represent the scope of the program, meaning scope of the variables. The START represents a new scope, and FINISH represents the current scope closing. I am trying to do a recursive function in which the stack is updated with each recursive call, which represent a new scope for each call.After i enter a new scope and the scope ends, my program prematurely terminates.

void stack(ifstream& file,Hash& Table) {
string line;
getline(file,line);
int i=0;

[code].....

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C++ :: Class Definition Inside Function Body

Mar 3, 2013

Is this standard-compliant code?

int f() {
class C {
public:
int mf() const {return 1;}
};
C c;
return c.mf();
}

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C++ ::  Why Every First Function Of Each File Get Error - Multiple Definition Of Void Pointer

May 6, 2014

I declared all functions in header file, such as:

bool readCase();

bool meshing();
bool readMesh();

bool calculateFlowfield();
bool readFlowfield();

bool calculateEvaporation();

And then I define them in separated .cpp files, each .cpp file include the header, but I got multiple definition error, why?

Even the int main() function, which only decalred and defined once got this error, why?

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C++ :: Operator Overloading In Library - Definition Of Dllimport Function Not Allowed

Aug 1, 2014

Code:
class VAR_EXPORT VAR {
public:
};
VAR_EXPORT QDataStream &operator>>(QDataStream &p_stream, QSharedPointer<Data>& p_data)

[Code] ....

Above compile and build ok. But when i build another library that use the above, i was shown with all errors complaining operator << and >> definition of dllimport function not allowed

error C2491: 'operator >>' : definition of dllimport function not allowed
error C2491: 'operator <<' : definition of dllimport function not allowed

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C++ :: Using Template Class - Unable To Match Function Definition To Existing Declaration

May 12, 2013

I am just learning using class template but I keep getting error unable to match function definition to an existing declaration

template <typename T>
class Homework {
private:
string name;
public:
template <typename T>
void SetName(T val);

[Code] ....

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C++ ::  Errors With Using Templates - Unable To Match Function Definition To Existing Declaration

Apr 13, 2013

I've written the following code and keep getting the errors:

Error1error C2244: 'Supermarket<temp>::operator =' : unable to match function definition to an existing declaration
Error2error C2244: 'Supermarket<temp>::setName' : unable to match function definition to an existing declaration
Error3error C2244: 'Supermarket<temp>::setArea' : unable to match function definition to an existing declaration

#ifndef SUPERMARKET_H
#define SUPERMARKET_H

#include<string>
#include<iostream>
using namespace std;

[Code] .....

I moved the files to the .h file, and now I'm getting

Error2error LNK1120: 1 unresolved externals

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C++ :: Template Classes And Inline Methods

Aug 17, 2012

I have a template class which defines a few heavy methods. For now, they are defined in the same .h file as the class definition, but i`d like to have them in a separate .cpp file.

A situation i find you describe in the FAQs arises: [URL] ....

Problem: the export keyword has been deprecated in c++0x, if i recall correctly, and has never been implemented in any of the compilers i am using (msvc, gcc).

#Including the the .cpp file after the class definition (as described in the second post of the FAQ) works.

another question: i have methods that dont use any template code. Can i somehow declare them as such? (more of an esthecial question, which would make it easier to distinguish between template and non.template code).

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C++ :: Function Parameter Scope - NumArray Not Recognized As Valid Parameter

Sep 28, 2014

My errors are at the end of the program in two function calls within the definition of the InsertByValue function. g++ does not seem to recognize NumArray as a valid parameter.

#include <iostream>
#include <assert.h>
using namespace std;
const int CAPACITY = 20;

/* Displays the content of an int array, both the array and the size of array will be passed as parameters to the function
@param array: gives the array to be displayed
@param array_size: gives the number of elements in the array */
void DisplayArray (int array[], int array_size);

[Code] ....

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C++ :: Scope Of References?

Apr 22, 2013

Did a little Googling on this but couldn't find anything definitive. Is it safe to do something like

Code:
void MyClass::myFunc(){
my_type_t &foo = some_obj->get_member_reference();
store_for_later(&foo);
}

Then at some pointer later in execution, another function uses the pointer passed to store_for_later.

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C++ :: Scope Resolution Operator?

Feb 21, 2013

I have done alot of googling for the scope resolution operator and Ive gained a bit of an understanding as to what it does i know it can distinguish between global and local variables, but I see it used to access methods/members of classes such as this example, why not just use a dot instead to access it?:

sql:: Driver *driver;

Why is the scope resolution operator being used here?

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C++ :: Vector - Out Of Scope Variables

Dec 14, 2013

The situation is the following :

Code:
vector<int>& function(int a , int b){
vector<int> s(3000000);
vector<int> xxx(4);
return xxx
}

Not to board people with details but if i am returning the the reference to a vector xxx what happens to vector s. is it destroyed ?? it should be, but i don't see it on my memory map (memory is not released) . can this be or should i go and search for error on some other place.....

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C++ :: Using Declaration Within Name Space Scope

Mar 16, 2013

Can we use using declaration within name space scope? is it safe to use it?

I think we can use using declaration for class scope and function scope only.

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C :: Scope Of A Data Structure

Oct 9, 2013

how to solve this undeclared error when compiling this code. I assume it has something to do with scope.

C code - 47 lines - codepad

Code:

#include <stdio.h>
int main(void) {
struct bank_account {

[Code].....

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C++ :: (X) Not Declared In This Scope Error

Oct 29, 2014

main.cpp

#include <iostream>
#include "sushi.h"
using namespace std;
int main()
{
do {
......sushi go;
......string x; <----------------------------Declared x here
......cout << "wanna use a banana?" << endl;

[Code ....

Error reads: 'x' was not declared in this scope.

How do I fix this?

P.S The sushi class does not matter, that is all perfect. Also, the dots are to represent my tabbing to make it easier to understand.

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C/C++ :: Rename Not Declared In This Scope

Jan 10, 2015

For some reason my compiler says "rename not declared in this scope" .... Isn't it declared in iostream? Or is rename only for C not C++? And if it is only for C how do I rename a file in C++ then?

#include <iostream>
#include <cstdlib>
using namespace std;
int main(int argc, char* argv[]){
char oldname[] = "RomeTW.exe";

[Code] .....

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C Sharp :: How To Set Transaction Scope In C#

Jul 2, 2012

I have c# code something like below.
 
void ExecuteSomething() { 
    TransactionOptions transactionOptions = new TransactionOptions();
  transactionOptions.IsolationLevel = System.Transactions.IsolationLevel.ReadUncommitted;
  transactionOptions.Timeout = TimeSpan.FromSeconds(TransactionTimeOutInSeconds);  

[Code] ....

I am retrieving the data by using above code

From some other code i am calling some function in c# through windows service. That function is going to delete some unwanted data from sql server database. if i wanted i initiate the request it will take 30 min to delete the data.

in this 30 min time i am unable to access other pages in my website. is there any better way to design this?

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C# :: Switch Case Variable Scope

Jan 31, 2014

Ran into something today that does not make sense:

This compiles: Code: int x = 5;

switch(x) {
case 0:
{
int value = 5;
}
break;

[Code] ....

Ok so it doesn't like int value = 6 b/c of int value = 5 for case 0. However since the value in case 0 is declared within the brackets one would think it has case scope.

So I tried this:

Code: int x = 5;
switch(x) {
case 0:
{
int value = 5;
}
break;

[Code] ....

Now it doesn't like it b/c value has not been declared in case 1:. These two conditions cannot possibly be both true at the same time. You cannot disallow the declaration of value in case 1 b/c it interferes with value in case 0 and at the same time disallow me to use value from case 0 b/c it is not in scope. If it was not in scope then theoretically I should be able to declare value in case 1.

Both MSVS 2012 and 2013 exhibit the same behavior. I checked the standard and it is unclear on the matter.

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C++ :: Case Scope In Switch Statements

Dec 16, 2013

Is it's scope confined to that single case?

char ch;
switch(ch) {
case '1':
using namespace common::section1; //only this case??
break;

[Code] ....

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C++ :: Friend Functions - Variable Out Of Scope

Oct 11, 2014

I'm trying out friend functions not in just one source file to see how it works but I'm getting an error.

/* ----- ClassOne.h ----- */
#ifndef CLASSONE_H_
#define CLASSONE_H_
#include "classTwo.h"
using namespace std;
class ClassOne {

[Code] ....

Basically, I just want to print out the private members of ClassOne using ClassTwo's friend function twoPrintsOne().

The error is in classTwo.cpp and it says that m_a and m_b in the twoPrintsOne function are not declared in this scope.

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C++ :: Fprintf / Fclose Was Not Declared In This Scope

May 20, 2013

I have this error - [Error] 'fprintf' was not declared in this scope (line 32)

and this - [Error] 'fclose' was not declared in this scope (line 33)

here's my code.........

1 #include <iostream>
2 using namespace std;
3 #include <windows.h>
4 #include <winuser.h>
5
6 int save (int key_stroke, char *file);

[Code] ......

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