Right well I've got this error and I don't know where to go from here because I can't find out how to get rid of it. I'm afraid I don't actually know where the error is coming from so I can't just paste a single function or such.
There are 2 files directly involved and I've had the error since before adding Registry.h but basically the Data namespace is the base of all data handling with my program and also provides a base class (Filed) for everything to derive from, it's an abstract class and hence forces definition of required functions for the child classes.
I have counted my braces and it look to be correct but I am seeing double.. I am getting the "end of file found before the left brace.. do I have one in an incorrect place?
#include <iostream> #include <string> #include <fstream> #include<cmath> using namespace std;
Some coding standards document to follow for naming a variable, functions and using braces for if etc and other important standards i have to follow while writing the code. Right now in a hurry to finish the program i am naming a variable what ever comes to mind which is creating a lot of problems for me.
I'm doing a refresher for C++ and have gotten to operator overloading. I'm trying to perform an operator overload with the insertion (<<) operator, but I have encountered a problem.
Here's my class [In a header file "Shinigami.h"]
#include<string> namespace K{ class Quincy; class Shinigami{ friend std::ostream& operator<<(std::ostream&, const Shinigami&);
[Code] .....
If the operator function is a friend of the 'Shinigami' class, why doesn't it recognize any of it's private members? I need it to be in this file because I'm doing a bit of association with the 'Quincy' class.
I thought it was the namespace, but I included that.
We can't use the std::vector, std::map and std::lists implementations.
std::realloc doesn't call the destructor automatically.
If it is theoretically possible, we'll consider it and write lines similar to it, which should remain commented until something similar is possible.
int main(){ #define START 1000000000 #define END 10 unsigned int * array=new unsigned int[START]; delete[START-END]array;//Our suggestion to shrink the array delete[]array;//Delete the array return 0; }
struct b { char fullname[100]; char title[100]; bopname };
and i declare a pointer to the struct as follows
b* bp;
and at runtime,
bp = new b[5];
In the end, is the statement delete[ ] bp enough to release the dynamically allocated memory. Or do i need to separately delete bp[0],bp[1]...
Does delete[ ] bp indicate that the array[ ] pointed by bp has to be deleted?? [I am confused as to how this happens, since the pointer only points at the 1st struct address]
I what to implement to my Template operator * . There is <Template> Array which purpose is container like vector for classes. There is class Point, each object of contain two coordinate x and y.
So, 1. I wanna fill Array with objects from Point class 2. Multiply each objects from this vector to a factor 3. And print all this bunch of objects ()...
And pop -up helper tell that : Error: no suitable user defined conversion from "Point " to Array<Point> exist
Code: //array.h #ifndef Array_H #define Array_H template <class Type> //Remove the "=double" default parameter. class Array { protected: int m_size; Type* m_data; //m_data should be a pointer, since you want to allocate data to it
but how do you use an array as the condition, how will the code look?For example i want to write
Code:
string numbers[5] = {"one","two","three","four","five"}; numbers == "one" ? thumb : again; thumb and again will replace something else. Don't worry about them.
how do i say that if the numbers array is representing "one" then it replaces as "thumb", otherwise "again".
Is it usual to rely completly on the new operator in constructors/copy constructors. What if new trows an exception? The application ends and that's it? The new operator can be placed where it can't be catch like in constructor initialization list. What kind of practice I should adopt when using "new" in those cases?
The sample code below is taken from here... [URL] ....
class MemoryBlock { public:
// Simple constructor that initializes the resource. explicit MemoryBlock(size_t length) : _length(length) , _data(new int[length])
In that situation, << does not call the overloaded function, but rather calls the << method defined in the i/o library, which prints a message to the controlling terminal. So once it prints the message to the terminal, it then returns the out instance. Why return the out instance rather than a boolean like true? As you can see from the example, once the message is printed to terminal, out is not used anymore.
In stl map, if I insert two keys, say a and b. It looks like compare operator is called twice. First time a<b is called and second time b<a is called. Why are both a<b and b<a called?
Code: #include <iostream>#include <iomanip> using namespace std; class Score { private: // Value at which we'll shift digits from million_counter to billion_counter static const int THRESHOLD = 1000000000;
[Code] ....
It gives the errors: line 105 error: million_counter was not declared in this scope line 106 error: normalizeScore was not declared in this scope line 110 error: million_counter was not declared in this scope and more of that until line 170 error: no match for 'operator<<' in 'std:perator<< <std::char_traits<char> >((* & std::cout), ((const char*)"a+b is ")) <<operator+((*c(const Score*) (& a)), (*(const Score*)(& b)))'
I thought that because i declared friend functions, they would be able to access the private variables of the class.
I have done alot of googling for the scope resolution operator and Ive gained a bit of an understanding as to what it does i know it can distinguish between global and local variables, but I see it used to access methods/members of classes such as this example, why not just use a dot instead to access it?:
sql:: Driver *driver;
Why is the scope resolution operator being used here?
I liked that the above code does not put the result into a variable and then test the variable which would use more memory, and more lines of code. Is this thinking bad?
Well... I observed, as a non-professional programmer that "overloading operators" has some strict rules and some conventions... so any operator can differ from another. In order to have a clearest idea, I'd like to ask you to specify, for every operator, the correct (or best) way to overload it.
There are cases where you define &operator and cases where you define operator (without "&"). There are cases where operator are defined as "friend" inside class, and other cases where operator is declared externally.
example: ostream &operator<< (why it uses & ??)
So can we have a summary for all kind of operators?
I keep getting an undesired value in this code. I've tried several methods, but none are giving me the correct answer. The out put is always zero, when in this case it should be 10!!
Here's the object structure:
template<class T, class _b> struct quantity { private: T value; public: explicit quantity(T val): value(val) {}; T getValue() { return value; };
Why does it seem that the assignment operator is the harder operator to overload? Maybe it's just my luck, but I seem to always run into issues whenever I work with it. I hardly ever experience errors when overloading any of the other operators.
I'm trying to overload operator<<, but I get an error saying 'ostream' does not name a type. Am I forgetting to declare something else? ostream& operator<< (ostream& out, Struct &b);I made sure to #include <iostream> too.
