I'm trying to create Minesweeper and with 2D Multidimensional character Arrays, It doesnt appear like in a grid format i want it to.
#include<iostream>
#include<conio.h>
#include<string>
#include<cstdlib>
#include<ctime>
[Code]....
I am trying to use multidimensional arrays. I have made a 9 by 3 array and I am trying to use it in my code. Now I am trying to print the content of a particular subscript on user demand but it is giving me some weird error. Everything seems ok to me. Heres my code
#include <stdio.h>
#include<Windows.h>
int main(void) {
double array1[9][3]={{1000.99, 2000.99, 3000.99}, {950.99, 800.99, 700.99},{850.99, 750.99, 600.99},{725.99, 625.99, 525.99},{650.99, 550.99, 450.99},{655.99,555.99,455.99},{350.99, 250.99,200.99},{325.99,225.99,175.99}, {300.99,150.99,100.99}};
[Code] ......
I have used strcmp before on one dimensional arrays but not 2 dimensional arrays.The problem is that I have one 2d array that has text with some misspelled words and I have to compare it to another 2d array and if the word from the first array (misspelled word) is not in the 2nd array then I print it to the screen instead of correcting the spelling. Here is what I have so far:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int read_dic(char [], char [][20]);
int read_words(char [], char [][20]);
void typo_check(char *, char *);
}
[code]...
I'm trying to get a full understanding of multidimensional arrays. When I try to initialize the array I get an error.
Code:
int Pick2(void) {
int pick = 2;
int limit = 0;
[Code].....
The error I get is "variable-sized object maybe not be initialized" with warnings messages pertaining the that Error message.
Write a program to enter data into a table and display on the screen in tabular form. I want to know where are the errors.
#include<iostream>
using namespace std;
int main() {
int table[3][4];
int r,c,i;
r=c=0;
while(r<=2)
[Code] .....
Here is my program to look up words. How do I use character pointers instead of using arrays?
Code:
#include <stdio.h>
struct entry
{
[Code].....
According to [URL] ....
" char myword[] = { 'H', 'e', 'l', 'l', 'o', ' ' };
char myword[] = "Hello";
In both cases, the array of characters myword is declared with a size of 6 elements of type char: the 5 characters that compose the word "Hello", plus a final null character (' '), which specifies the end of the sequence and that, in the second case, when using double quotes (") it is appended automatically."
However there are examples where word array is declared as :
char myword[] = { 'H', 'e', 'l', 'l', 'o' };
Is syntactically correct?? If yes, what is the size of myword? and does ' ' append by compiler automatically?
And is char myword[] = "abc" same as char myword[] = {'a','b','c',' '} or is it same as char myword[] = {'a','b','c'} ??
I'm trying to write a code that is read character user 'e' or ' ' space also numbers I mean a number 'e' or space 'e' a number 'e' or space so forth.But i get absurd numbers. The program shows me the added number. If '
' entered the taking numbers will stop(scanf will stop).
Example input:
e 1 8 7 2 3 6
or e 1 e 8 e 7 e 2 e 3 e 6
Code: #include <stdio.h>
#define MAX 10
void addq ( int *, int, int *, int * ) ;
void test();
[Code]....
Passing and returning character and integer arrays with functions using simple programs...use pointers if necessary
View 1 Replies View RelatedI keep getting this warning message and I do not know how to fix it. Is it because I'm using char to instead of strings to replace all 't' with 'lp'?
#include<iostream>
#include<string>
#include <stdio.h>
using namespace std;
char * scanf(char * a) {
[code]....
Double values are stored in text file. 23.5 36.8 34.2 ... My teacher told me to read them character by character and then make words, like i have to read "2" "3" "." "5" and now have to make it or treat it as word and then using atoi(). I have to convert it into double. but i dont know how to do this....
View 5 Replies View RelatedI have to optimize a code for below scenario. I am reading stdin (a file redirected to stdin) character by character. How many chars are going to come is not known. After every few chars there is a seaparator. e.g $ as below
rhhrkkj$hghjhdf$ddfkrjt
While reading, if the separator arrives I'm processing the string stored before that separator and then continue reading stdin in same fashion, till EOF. I am using getc(stdin) to read chars.
Using gprof I can see most of the program time is spent inside main() , for this reading logic. Rest of the program is just some insert and search operations. I am getting time of 0.01 secs at the moment, want to reduce further.
How do I write an a program that will read an input file character by character?
View 1 Replies View RelatedIn my program, I'm supposed to read a text file (the name of which is given to me as a command line paramater, as long with an integer), and display the text in a specific format (each line can only be as long as the integer). However, I'm having trouble even reading the text file. I don't know the syntax. I'm only allowed to edit the function that does the formatting, and the code in that is
void typeset (int maxWidth, istream& documentIn)
I don't know how to 'read' the file, as most examples online are ifstream, or openFile or something like that. What I want to do is just read the first character of the file, and continuously keep reading characters until the end of the file.
So I'm trying to create a function that replaces any instance of a character in a string with another. So first I tried the replace() string member function:
In my implementation file
void NewString::ReplaceChar(const char& target,const char& entry)
{
this->replace(this->begin(),this->end(), target, entry);
};
Main program
#include "NewString.h"
using namespace ...;
int main()
[Code].....
Instead of replacing the the l's with y's it outputted a long string of y's. Also, NewString is derived from the string class (it's for the assignment). the header and whole implementation file, already tested.
I've also tried, instead, to use a for loop in ReplaceChar() but I need to overload the == operator and I don't know how I should exactly:
bool NewString::operator ==(const char& target)const {
if(*this == target)
return true;
[Code]....
I want the == operator to test if the value in the char array is equal to target but I'm not sure how to pass in the position. I'm guessing the this pointer in ReplaceChar() is not the same as the one dereferenced in ==() because target is never replaced by entry in the string.
Problems :
1) Is there any way so that i can use "X" and "O" char instead of 9 and 0 int.?? I also tried to use enum but was only able to print out -1 for 'X' and 0 for 'O'...
2) if player - 1 choose field 2 . and player - 2 chooses field 2 .. how can i show error and ask for another input ?
3) is there any short coding trick for int check_result(); ?
Code:
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
[Code] ....
What is the correct method of declaring pointer to multidimensional array
Code:
int array[3][4];
int *p = array;
The above code works but it shows warning. Is it an invalid way of using the pointer? the array is an address then why am i getting warning?
I'm trying to pass a two-dimensional array to a function. The function is defined as: long foobar(char foo[][CONST]); I have to create that array dynamically. Currently I do that this way: char* bar = new char[count * CONST];
But when I'm trying to pass the array I get a type conversion error. I tried a lot of different ways to pass the pointer and/or to allocate the memory, but apparently I didn't find the right way or combination of definition, allocation, casting and calling.I cannot change the definition of the function, which (IMHO) is pretty stupid. :(
I am having trouble accessing a one-dimensional vector as a multi-dimensional one.I have a MultiArray template class, and it is accessed using the function operator. It accesses elements through the expression row * m_columns + col. The row and col are the two inputs to the operator while the m_columns is the width/number of columns in the array. There is also a version that accesses the array with one number. Its underlying representation is a one-dimensional vector.The problem is when I try to load a level:
void Map::LoadFromFile(const std::string& filename) {
std::ifstream map_file(filename);
std::cout << m_map.GetHeight() << ", " << m_map.GetWidth() << std::endl;
std::cout << m_map_dimensions.y << ", " << m_map_dimensions.x << std::endl;
if(map_file.is_open())
[code].....
I've seen code examples for assigning 2 dimensional vectors, but I haven't seen code for assigning more than that. I tried to create a 3 dimensional vector, and the only code the IDE didn't complain about was
int x = 2;
int y = 2;
int z = 2;
vector < vector < vector <string> > >stringvec;
stringvec.assign(x, vector <string>(y), vector <string>(z));
Would this be the correct way of producting a vector[2][2][2]?
I have a doubt about how to go through a multidimensional matrix generically.
Examples of how to go through in particular cases:
-> 1 dimension:
unsigned int d0 = 3;
double m[d0];
[Code].....
How you can see, it is necesary so many for loops as matrix's dimensions.
I want to do an algorithm that go through a multidimensional matrix generically, that is, knowing the number of dimensions and the dimensions of one multidimensional matrix, go through all its elements. For example, it would be to implement this function:
/**
* Go through the multidimensional matrix given, assigning zero to all its elements
* @param dimensionsNumber The number of dimensions of the multidimensional matrix
* @param dimensions A pointer to the first element of one array of unsigned ints who size is the same as the number of dimensions given, so the ith element is the ith dimension of the multidimensional matrix
* @param multidimensionalMatrix A pointer to the first element of the multidimensional matrix
*/
void assignZeros(unsigned int dimensionsNumber,
unsigned int* dimensions,
[Code].....
I have put aside C++ for a while. And I am back to it.
I forgot how to return a 2 dimensional arrays from a method?
Code:
Node** GetNodeMap() const { return m_Nodes; }
private:
Node m_Nodes[60][60];
How can I achieve that?
Working on this one from the Jumping into c++ book. The book asks that I create a multidimensional array at run time based on user input and fill it with a multiplication table
My code compiles fine but throws an uninitiated error for p when I try and run it.
Code:
void multiDimentionalMultiplication(int x, int y, int z){
int ***p;
**p = new int[x];
std::cout << "Allocating array.
[code]....
How to get the number of elements of a multi-dimensional wstring?
The usual char array way not working.
Code:
int main()
{
wstring wstr[][255] =
{
L"bbbb",
L"bbbb",
L"aaa",
L"ccccccc"
};
int Size = wstr.size() / wstr[0].length();
}
I have initialized a multidimensional array eg char fruit[5][10]...Then I would need to read in 3 words with spaces in between from user and store in fruit[5][10] e.g "pear apple orange"
The thing is that after typing orange, when I press Enter it still prompts me to enter more characters. How can I end the scanning of characters after orange ?
I have a 3-dimensional matrix(3,3,3) and want to write it to a file. I have the code for parsing it in a compatible for matlab format. But at this point i want to use a pointer to do the same thing.
Code:
#include <stdio.h>
#include <stdlib.h>
int main() {
const int dimx = 3, dimy = 3;
int i, j;
unsigned char a[3][3][3] = {
[Code]...
If it is a 1-dimensional array i can understand the logic.
Code:
int val[7] = { 11, 22, 33, 44, 55, 66, 77 } ;
int *p;
p = val[0];
for ( int i = 0 ; i <= 6 ; i++ )
[Code]...