I know how to add a node and delete a node from the beginning and from the end of the List. Now I want to sort the List by Age. I tried everything but there must be a very little mistake that I can't find. Here is my code:
#include <iostream>
using namespace std;
struct Node {
char name[20];
int age;
double height;
[Code] ....
I've been trying to implement a quick sort algorithm for linked list but when i try to run it with 1000000 values my compiler tells me its running too long and ends up not finishing. However when i run it with 10 values it seems to work fine.
Is there anyway to improve this run time?
Code: struct listnode *quicksort( struct listnode *data ) {
size_t length = 0;
struct listnode *pivNode, *temp = NULL, *low = NULL, *high = NULL, *ltail = NULL, *htail = NULL, *prev = NULL, *end = NULL, *next;
// Get length
for( struct listnode *cursor = data; cursor != NULL; cursor = cursor->next ) {
length++;
}
[code].....
This is in response to the bubble sort and selection sorts for linked lists. On my system, (Intel 2600K, 3.4ghz), it sorts a list with 4,194,304 nodes containing 64 bit unsigned integers in about 1.05 seconds.
Code:
#define NUMLISTS 32
/* number of lists */
typedef unsigned long long UI64;
typedef struct NODE_{
struct NODE_ * next;
UI64 data;
[Code]....
I am trying to sort a linked list using quick sort in C. Here is my code--Actually, first I am inserting data in the list from a file. For a small file, it's working fine. But for large file it's just not working.
Code:
struct node {
int data;
struct node *link;
struct node *plink;
[Code] .....
I'm trying to apply a bubble sort on a linked list. It works in the first traversal, but then after the code cPtr = nPtr;, it inputs repeated digits at the end of the (semi-sorted) linked lists.
View 1 Replies View RelatedThis is in-place merge sort, for merge function.
LinkedListNode::LinkedListNode(int value) {
this->next = NULL;
this->value = value;
}
LinkedListNode *mergeSortedLinkedLists(LinkedListNode *firstList, LinkedListNode *secondList)
[Code] ....
I'm having trouble getting my sort function to work,
void Linkedlist::sort(int num)
{
node *q;
node *a;
int input=num;
[Code].....
I get a crash and I've narrowed it down to the last if statement. Also this function is meant to handle new members after 1 member has been added.
I am making a custom linked list (for fun!) and want to implement a sort method that sorts the stored data using the stored types > and < operators (will require the type to have these operators overloaded)
What is the best way to do this? I guess the first thing one might jump to would be to compare the current node with the the node to its "right" see if one is greater than the other. Then keep iterating through the list until you don't swap any more nodes. However I am thinking there is probably a more efficient way to do this. Here is my code so far:
#ifndef LIST_HPP
#define LIST_HPP
#include <string>
[Code].....
Surely there is a way to sort with only one iteration through the list?
At the line number 65 that's my sort method first i sum up all the value in the nodes after that i want to sort the Nodes In ascending order but the method is not working ...
#include <iostream>
#include <conio.h>
using namespace std;
// Node Class
[Code] ....
is this correct? I used this sorting with numbers i don't know if it is the same with strings. When I run it, there are no errors detected, but when i try to view it, the inputs does not appear.
void add(node **h, node **t){
node *temp, *ptr;
char s[20];
temp = (node*) malloc(sizeof(node));
printf ("-INSERT-");
printf("Fruit: ");
scanf("%s", temp->fruit);
[Code] .....
HelI have been tasked with creating a program which (1) takes in integer values from a user (until the user enters -1) and inputs these values into a linked list. This (2)original list is then to be printed out. The program then uses the algorithm "bubble sort" to (3)order the list in descending order before finally printing it out again.
I have managed to do this but I kind of cheated since I do not quite understand how to manipulate a linked list. What did was I took the values in the linked list and transferred them into an array and then did bubble sort on that array.how to do bubble sort on a linked list as well as how to print a linked list.
Code:
#include<stdio.h>#include<stdlib.h>
typedef struct node
{
int info;
struct node *link;
}Node, *NodePointer;
void printList (NodePointer head)
}
[code]...
i am making a program that reads a file from .txt and print them out using linked list. However, i need to sort them from the highest price to lowest price.
Code:
/* my structs */
typedef struct{
Node *head;
Node *tail;
Node *iterator;
int size;
} List;
[Code]...
i know its long but im afraid that i might miss out some things.
i want to make a program that accepts 15 items in a singly linked and sorts the nodes.
View 1 Replies View RelatedI'm trying to write a function that takes two linked lists and creates a third one with only the common elements.
It assumes the first list (the caller) has no dups, but it doesn't seem to be working. The program doesn't crash, it just hangs when it is supposed to display L3 (the third list)..everything else runs and is displayed fine.
template <typename T>
LList <T> LList <T>:: common (LList <T> &B)//common fct
{
Node <T> *hunter1 = Head;
[Code]......
I have a linked list comprised of chars like so...
Code:
node1 - "p"
node2 - "o"
node3 - "p"
I need a function that will take in three perameters...node *replaceChar(node *head, char key, char *str)Stipulations of this function. head is the head of the list, 'key' and 'str' are guaranteed to contain alphanumeric characters only (A-Z, a-z, and 0-9). str can range from 1 to 1023 characters (inclusively). So if I call this function with these perameters..
Code:
node *head == /*the head of the list to be examined*/
char key == "p"char *str == "dog"The new list will look like this...
node1 - 'd'
node2 - 'o'
node3 - 'g'
node4 - 'o'
node5 - 'd'
node6 - 'o'
node7 - 'g'
All instances of 'p' were replaced with 'dog' I have a toString function which takes in a string and converts it to a linked list and returns the head. So assume that you can call the function on str = "dog" so...
Code:
toString(str) == /*this will return the head to the list made from the str*/
If it's unclear what my question is...I am stumped on how to write the replaceChar function the one that takes in three perameters..
i write code that's merge two linked list without sort ....
node * merage (node * list1, node * list2) {
// check witch list is empty
if (list1 == NULL) return list2;
if (list2 == NULL) return list1;
if ( list1 == NULL && list2 == NULL ) return NULL;
[Code].....
I am getting an error trying to convert from nodeType<Type> to nodeType<Type>* in my recursiveSort function and why this is happening.
#ifndef H_linkedListIterator
#define H_linkedListIterator
#include <iostream>
template <class Type>
struct nodeType {
Type info;
[Code] ....
Code:
// Write a function called insertEntry() to insert a new entry into a linked list.
Have the procedure take as arguments a pointer to the list entry to be inserted (of type struct entry as defined in this chapter), and a pointer to an element in the list after which the new entry is to be inserted.
// The function dveloped in exercise 2 only inserts an element after an existing element in the list, thereby prenting you from inserting a new entry at the front of the list.
(Hint: Think about setting up a special structure to point to the beginning of the list.)
#include <stdio.h
struct entry1 {
int value;
struct entry1 *next;
};
[code]...
This is a working version of the exercise, but I don't think I'm doing what's asked. I was able to add an element to the beginning of the list using an if statement, not creating a special structure that points to the beginning of the list. How would I go about creating a special structure that points to the beginning of the list to add a new element at the beginning of the list?
I've written code for a selection sort algorithm to sort through a singly linked list, However, it only brings the smallest node to the front, but doesnt swap positions of any of the remaining nodes, even though they are not in order.
Input list: 3 6 17 15 13 15 6 12 9 1 2 7 10 19 3 6 0 6 12 16
Sorted list: 0 6 17 15 13 15 6 12 9 1 2 7 10 19 3 6 3 6 12 16
Code:
#include<stdio.h>
#include<stdlib.h>
struct node{
int val;
struct node *next;
[Code] ......
What I want to create is a program that sorts through a huge list (millions of lines).
I want it to get rid of any line that contains a word that isn't in an English dictionary.
Example list:
00sdfdsf
ahdadsg
angel
ksjflsjdf
green
green000
carrot
and it would go through millions like that, giving me only:
angel
green
carrot
as my new list.
How could I go about this? What extra programs would I need?
I am looking for a function or algorithm to best merge and sort similar content between two lists of unordered strings each in individual files (very large files ~200mb each).
For example, these files have a common first string and are merged based on them:
File 1:
red, apple
green, truck
blue, car
yellow, ball
orange, candy
File 2:
gold, necklace
green, tree
yellow, sticker
blue, water
red, bag
I am looking for the following output:
Output:
red, apple, bag
green, truck, tree
blue, car, water
yellow, ball, sticker
orange, candy
gold, necklace
When I call stl sort with a vector in the following,
Code:
int main() {
vector<int> items;
sort(items.begin(), items.end(), greater<int>());
return 0;
}
It works. But if I call stl sort the same way with a list, there is compiler errors.
Code:
int main() {
list<int> items;
sort(items.begin(), items.end(), greater<int>());
return 0;
}
Why?
I'm working on a linked list and was wondering how this looks to everybody else for a deleteList function.
void deleteList(Node* head)
{
Node* iterator = head;
while (iterator != 0)
[code].....
I am supposed to make a program that take a list of integers from the user and to delete the smallest part of it in order to make it sorted in non decreasing order ..
example : input : 1 2 3 4 5 8 7 6 7 8 9
output : 1 2 3 4 5 6 7 8 9 ( delete : 8 7 )
I need a code that use a technique similar to the merge function to achieve linear time ..
this code works but it is in quadratic time :
int main () {
cout<<"Enter a list of numnbers ending with the sentinel -999:"<<endl;
int A[1000];
int n = 0;
int x;
cin>>x;
while(x!=-999)
[Code] ....
I need to make the functions using these function prototypes. I am mainly having problems with GetFirst() and SwapData() but how to do it..
Header File with Prototypes
Code:
#ifndef LINKEDLIST_H
#define LINKEDLIST_H
/**
* @file
* This file provided a doubly-linked list implementation capable of storing any arbitrary data.
* The list implementation relies on a chain metaphor: a list is merely a sequence of links
* (ListItems) and there is no separate construct to represent the entire list, each ListItem in it
[Code]....
I read an article on linked list here: C Linked List Data Structure Explained with an Example C Program
Code:
struct test_struct* search_in_list(int val, struct test_struct **prev)
{
struct test_struct *ptr = head;
struct test_struct *tmp = NULL;
bool found = false;
}
[code].....
What is "if(prev)"? Wouldn't "prev" always have the same value? Secondly, if tmp is NULL (which will be the case when the loop if(ptr->val == val) finds a match the first time it is run), is *prev assigned a NULL?