I need to ask the user to input a number, and then put the number in a string array. so for example if the size of the number was 4: example 1200
i would make him put the number like that
for (i1=0; i1 < 4; i1++)
cin >> Num1[i1];
where Num1[] is a char array type. yes and it works.
But my question is what if I do not know how many numbers will the user put, how do i extract the size of the total characters existing in a number?
Very new to programming, and I know that there must be another way on inputting a string into each array cells not by just inputting it one by one, but as a whole. My code at the meantime is: [URL]
View 1 Replies View Related/*assume array is already initialized and declared and is of array type string.*/
int i = 2;
int j = 1;
string newvalue;
cout<<"Current value at array[i][j] is "<<array[i][j]<<endl;
cout<<"Enter new value "<<endl;
cin>>newvalue;
array[i][j]= newvalue; //PROBLEM IS IN THIS LINE.
cout<<endl;
cout<<array[i][j]<<endl;
I'm having lots of trouble with storing a cin string text into a string array. It just seem that after I cin newvalue, the program crashes. Is this way of storing it considered illegal? I'm just a beginner with 5 months of coding experience in C++.
If the user puts in a 6. I need the array to display the even number from 0 - 6. Right now what it does is it displays the first six even numbers. Okay as I'm writing this I'm starting to see where my problem might be..
Code:
void sumIntegers () {
int arr[50];
int i = 0;
int num = 0;
int sum = 0;
[Code] .....
I want to ask for a number as an input during runtime and then create an 2-dimensional array of size as specified by user. i.e. if the user inputs 3, the array should be of size 3X3, and likewise...
View 9 Replies View Relatedi was trying to solve a problem in SPOJ and what i wanted to do is to accept an input number from the user and to convert it into a array of integer.
Code:
#include<stdio.h>
int * toarray(int *num);
int main(void)
{
int testCases;
}
[code]....
But whenever i try to print the array in the main function i get only two value and the rest address
Code:
1//number of testCases
23456 //input number
6
2293452
4
2293700
1974439125
Process returned 0 (0x0) execution time : 4.152 s
Press any key to continue. However, if i tried to print the array from within the function, it prints the numbers just fine.
print the array elements from the main program, so that i would be able to go on with the rest of it
I'm trying to code the program that will store item data.And I'm having problems to receive user-input string to array.
#include <iostream>
#include <cstdlib>
#include <cstring>
#include <string>
#include <iomanip>
using namespace std;
[code].....
I have been reading up on arrays and string array. I created a string string text[0] and it is defined by user input. I am trying to sort the input. I want Michael to read Macehil.
When I wasn't using an array and just a string I did this:
return sort(text.begin(), text.end()); a
And it worked fine. Do I need to change my string into a char? If so, would I static cast that?
I want to take string input into a char array.
What is the functionality for the above problem.
I am having a problem printing out the results for my code, It is supposed to print out the largest and smallest value in the array, but keeps giving me a value not entered and I don't know why.
//This program lets the user enter 10 numbers and then display the highest and lowest number.
#include <iostream>
#include<stdio.h>
using namespace std;
int main() {
const int NUM_ENTERED = 9;
int number[NUM_ENTERED], highestValue = number[0], lowestValue = number[0], count=0;
[Code] .....
I need to create A program That makes a 12x10 Array Grid Filled With Random Numbers From 0-99.
Then I need To Allow The User To Input A Number Between 0-99 And Then The program will then search through the array and count how many of the users number there is inside the array.
Code:
#include <iostream>
using namespace std;
int main() {
int input;
int number;
int row=0;
int col=0;
int Array [12][10];
[Code] ....
How would you search in a vector array from a user input string?
ex: user input : "Hello"
output: search vector array and find the line that has the string "Hello" and output the array "Hello" is on?
I have an assignment where I need to read in a phone number into any array and I can't use the string data type. Assuming I need to use the getline function, how do I do this? I'm guessing it's with the cstring or .c_str() functions? I don't know.
View 4 Replies View RelatedI need to write a code in c++ , to input decimal number and the output to be number in Scientific notation with 32 bits .
View 1 Replies View RelatedQ. WAP to find the next palindrome number larger than the input number.
for eg:-
Input=25
Output=33
The program is giving correct output for number with all digits '9';
why is it not giving output.
#include<iostream>
#include<string>
using namespace std;
int main() {
int len,flag=1,count=0,num,ind;
[code]....
I have problem with string compare. I want to compare the string user input with a string in binary. And I don't know how to do it. Problem in function login();Here is the code: And you also can download file in attachment too..
Code:
#include<conio.h>#include<dos.h>
#include<stdio.h>
#include<process.h>
#include<string.h>
char nsb=1;
char ch, password[20], passlogin[20], inputpass[20], checked[20];
FILE *fp;
}
[code]....
I wrote a program that reads a list from a file and stores it in a string type vector. Now, I want the user to input a word so that the program can search the vector to see if that word already exists. I have used every possible way of reading input from the console and storing it in order to compare with the vector but it never results in a match. When I print the input string and the vector string they are exactly the same thing (or at least print to the console as if they were). I've tried using getline; using cin direct to a string var; using cin to a char array and then casting to string using string str(arr); I even added a newline at the end just in case and STILL I cannot get a match.
vector <string> currentSet; //read a list in from a file and has 9 items in it
cin.ignore();
string line;
getline(cin, line);
if(line == vector[0]){//if printed to console line is HEAT and vector[0] is HEAT
cout<<"match"<<endl;
}
write a program that prompts the user to input a string and outputs the string in uppercase letters. (Use a character array to store the string.) Does this follow the criteria? This program is very similar to one I found on these forums but I have one problem, it outputs everything backwards! EX: dogs will output to SGOD. What I need to do to make it output correctly, I think it may have to do with getline?
#include <iostream>
#include <cctype>
#include <cstring>
using namespace std;
int main() {
char let[100];
cout << "Enter what you would like to be UPPERCASE: ";
[Code] ....
I am stuck in this program, Be given a string of chars, where each single char belongs to the following alphabet: a..zA..Z0..9 (So, in the string there are only lowercases, uppercases and digits. No blank, no comma, ...). For every char of the given alphabet, count how many times in the string
1-- the char belong to a sequence of identical chars whose length is at least three (i.e.: in the string cc74uyrpfccc348fhsjcccc3848djccccc484jd for three times the character 'c' satisfies this condition)
Code:
#include<stdio.h>
#include<conio.h>
#include<string.h>
[Code]...
2-what is the longest substring of characters strictly rising interm of ASCII code(the following is greater (>) of the previous)
3- what is the longest substring of successive characters interm of given string rannge (i.e.: fhkjshdfruytyzABCDEfglsj => 7)
This could be non contiguous. As an example
string1: "Hello"
string2: "Heelblloo"
occurrences of string 1 in string2 is 2*3c2*2=12
among 2 e's in string 2, we can select only one and thus 2 possible ways.similarly for l and o.
I have to write a program that will ask you to put in a number between 0 and 9 and multiply it by pi. If the number put in is between 0 and 9 then pi is multiplied but if it isnt between 0 or 9, it will say the number is not between 0 and 9 and asks you to put it in again and will repeat until a number between 0 and 9 is put in.
I have got the program working to the extent that it the number is between 0 and 9 it will multiply it by pi but if its not between 0 and 9 it will say the number is not between 0 and 9 and ask to put in a new number.
I can't work out how to get the program to repeat itself if the number entered isnt between 0 and 9.
I have enclosed the code below .....
There's this program I'm trying to code where the user gives input of 2 values.
Sample :-
Value of X: 1234
Value of Y: 234567
Reversed value X: 4321
Reversed value of Y: 765432
New value as Z: 1223344567 (each number was taken in both X and Y)
Now the thing is I could do the reverse, and I've been trying to find out how.
Here's my code,
#include <iostream>
using namespace std;
int main(){
int x=0, y=0;
int reverse_x=0;
int reverse_y=0;
int z = 0;
int l;
[Code]....
What I thought about that area where I've put a comment on, I was wondering if I code a loop for the amount of times x gets divided by 10 until it becomes 0 and store it in the value, same thing for Y, and add the value together to get Z. But if that's how it is then how I could use that concept here.
how to take binary number as an input, generate partial products by bit-wise multiplication and in last step to add all the partial products to generate final products".
View 5 Replies View RelatedThere's this program I'm trying to code where the user gives input of 2 values.
Sample :-
Value of X: 1234
Value of Y: 234567
Reversed value X: 4321
Reversed value of Y: 765432
New value as Z: 1223344567 (each number was taken in both X and Y)
Now the thing is I could do the reverse, and I've been trying to find out how.
Here's my code,
#include <iostream>
using namespace std;
int main(){
int x=0, y=0;
int reverse_x=0;
int reverse_y=0;
int z = 0;
int l;
[Code]...
What I thought about that area where I've put a comment on, I was wondering if I code a loop for the amount of times x gets divided by 10 until it becomes 0 and store it in the value, same thing for Y, and add the value together to get Z. But if that's how it is I can't seem to really get that idea how I could use that concept here. I'm not really good with programming, fairly new at this.
"Every number has at most 500 digits" under input. 500? How am I supposed to store that? And what if someone multiplies 999 ...(500 times) * 999 ... (500 times) ? I seriously doubt that my computer can store that! Is that just some huge value used to scare people off or is there some sneaky trick that I am unaware of?
I am done with the program, but won't post it, Lets not ruin the fum for ohers...Does that 500 limit also applies to result of operation?So max length of an input number is ~22 digits ? But still, how do I store 500 digits? Array would be a lot of wastage of memory (though I do have 256MB available).
In my calculator, I am trying to make it so that you put enter 1 to add, 2 to subtract, 3 to multiply, and 4 to divide. I am facing the issue of making it so that you must enter a number, however instead of it being any number, it must be 1, 2, 3, or 4, and if it is not any of those numbers, you must re-enter the number. Here is a little snippet of my code:
Code:
printf("Please enter 1 to add, 2 to subtract, 3 to multiply, or 4 to multiply: ");
while (scanf("%d", &input) != 1) {
while (getchar() != '
');
printf("Invalid option. Please try again: ");
[Code] ....
how I can make the loop affect specific numbers.
