int main () {
string integer1;
string integer2;
cout <<" enter your first number: " << endl;
cin >> integer1;
cout << endl;
cout << integer1 << " is your first number" << endl;
}
Now how do I turn the string integer into an array?
I know strings are essentially just arrays of characters, so what would be the easiest way to take each individual digit and put it into a separate space in an array?
ex.) *str = "90210"
array[0] = 9
array[1] = 0
array[2] = 2
array[3] = 1
array[4] = 0
All my attempts at achieving this just result in an array full of garbage numbers. What I've done is
Code:
int *array;
array = malloc(sizeof(int)*(strlen(str));
for(i=0; i<strlen(str); i++) {
array[i] = str[i]
}
also, I should mention that the string will be defined in main, and its converted into an array in a separate function.
How would one cycle through a turn order in a turn-based game? I was thinking an array of every creature (including the player) and have a pointer to the array++ after the turn, but I couldn't put all the objects into an array.
View 2 Replies View RelatedI'm having trouble trying to turn a word into letters. I've seen other posts but they deal with a sentence and it only outputs the words only. What I want to know is how do they take a word (Ex: "word") and break it into individual letters, where I want to store them in a vector of string?
If it's not too much trouble, I would prefer without using pointers or "std:: " marks, since I am trying to avoid pointers and I'm using "using namespace std" all the time.
Ex:
In the example "word", it should output into:
"w"
"o"
"r"
"d"
and I will push them back into a vector of string where each vector element contains a letter.
Say you the user inputs x number of names and then is to put in x amount of values for each name. How would you display these values in a 2d array and be able to add the values for each row which will represent each name?
View 5 Replies View RelatedFor Example, it the entered string is: 0324152397 I want it to get stored in an array like-[0] [3] ...[7]. Secondly the string entered may be of any length that is defined only at run time. So, I also need to calculate string length. How could I do that.
View 2 Replies View Related I'm just learning and C. Here is a code snippit from a program that will compile. It's function is to validate credit card numbers. I have an error I can't find though. the last print statement shows the conversion in reverse string (as integers). Here is the code:
int main (void)
{
char cn[17];
char *cardtype;
int n0,n1,n2,n3,n4,n5,n6,n7,n8,n9,n10,n11,n12,n13,n14, n15;
int s1,s2,s3,s4,s5,s6,s7,s8;
int oddsum;
int sum;
int total;
int validate;
}
[code]....
// prompts the user for a non-negative numbers (>= 0)
// reads in the a number and checks
// keeps re-prompting user if the input is invalid (negative)
[Code].....
How do I go about Populating the elements in the array created, I keep getting a compiler error on this vArr[i] = tmp_stream.str.at(i);
So I wrote a program to turn a binary file's data into an unsigned character array for inclusion in an executable. It works just super.
I'm wondering how I can write a program that will perform this operation on every file in a directory and all it's sub-directories so that I can I can include everything I need all at ounce.
Complete the function myitohex so that its converts 8-byte integer to string based hexadecimals.
Ex: printf("0x%s",myitohex(64,hex)); should printout "0x40" on the screen
char *myitohex(uint8_t i, char *result){
???
return result;
}
I wrote:
#include <stdio.h>
#include <stdint.h>
char *myitohex(uint8_t i, char *result){
*result = i + '0';
[Code] ....
0xp gets printed out which is wrong. I think *result = i + '0'; is wrong. What changes should i do on this row ?
I am trying to assign the integer value to unsigned char array. But it is not storing the integer values. It prints the ascii values. Here the code snippet
Code: uchar uc[100];
for(i=0;i<100;i++)
{
uc[i] = i;
}
The values which are stored in uc[] is ascii values.I need the integer values to be stored in uc[]. I tried to do it with sprintf. but the output is not as expected. if I print the uc[i] it should diplay the value as 0,1,2....99.
The reason being is that it says that my program is right
Code:
#include <string.h>
#include <stdio.h>
#include <stdlib.h>
#define NFlights 10
struct date {
int month;
int day;
int year;
int hour;
int minute;
[Code] ....
map< int, int > cache;
int count( int n ){
if( cache[n] != 0 ){
return cache[n];
[Code] ....
I don't know how to turn this recursive function into an iterative...
I am trying to include all repetitions for just one turn but I keep getting
00.0 but I want (the one in red)
170.3 0 0.3
180.0 17 0.0
190.3 18 0.0
200.3 19 0.3
210.0 20 0.3
220.0 21 0.0
22 0.0
so basically I call a function that represents just one turn of getting a random number, and then when the player decides he wants to get a random number that is at least 17 and wants to repeat this 3x I have to print out this chart that shows the chances of the player rolling the numbers between 17-22 [how many times does he get 0,17,18,19,20,21,22] this is what I have
cout << "your score: " << (' ') << "chances for that score:" << endl;
/* score is the player's total score for the one turn */
int score = 0;
int score0 = 0; // 0
[Code]....
i wanna put an integer into a string for example:
Code:
string name;
int num=8;
name= "George"
//
I want in the end of George to pas the num variable i ve seen some examples but ive not yet come up with a solution like str.insert();
I'm trying to convert a string into a integer and when I call stoi(line) it causes the program to crash.
int main() {
vector<int> numbers;
int i;
string line;
ifstream myfile ("example.dat");
[Code] ....
The file being read from looks like:
3
12
23
34
12 34
12 12
34 23
23 23
How do I read integers to a string and store then into a vector array?
I need to add two input digits i.e. "1234567878887777" and "123344543543543"
I need to convert below value char *time="00.00.05".
I need to convert this to hh/mm/ss ....
struct time
{ int t;
int h,m,s;
};
int main() {
time t;
int totalsecond;
char A[10],B[10];
[Code] ....
It gives error at line no 12.
[URL] ....
This is my code, but how can I implement this?
Code:
Prompt the user to input a string,
and then output the sum of all the digits in the string.
Sample Run 1:
Input -> A111B222C
output -> 9
Sample Run 2:
Input -> ABC123XYZ32100000005555555555zzzzzz
output -> 62
I have this code:
Code:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
[code]....
What I want is basically to assign to the *p the pointer of the string so that i could do the following printf(" print string %s",*p); so i dont know how to do that.
I'm having a problem converting part of a string to an integer.I used strtok to seperate my string and I have also a function for atoi but how to apply it to my strtok function.What i need is to change the char *years to an int.Have a look of what I got:
Code:
int main() {
char sentence[]="trade_#_2009_#_invest_#_DEALING";
char *word=strtok(sentence, "_#_");
char *year=strtok(NULL, "_#_");; // assigning NULL for previousely where it left off
char *definition=strtok(NULL,"_#_");
char *synonyms=strtok(NULL,"_#_");
[code]...
wrote this program to check if a string is an integer. It checks for + or - sign at the front of it, but it spat out some errors.I think I broke it.Here is the code:
Code:
#include<stdio.h>
#include<ctype.h>
#include<stdlib.h>
int getInteger(char*);
int main(void) {
char str[99];
int x;
}
[code].....
I have been trying to write a function which can convert a number from an unsigned long integer to a readable ASCII character string. this is what I have come up with, but I am receiving some very strange characters in return. Could the problem be that I am telling a char to = an unsigned long int, (cString[i] = product[i])?
void convertToString(unsigned long con) {
unsigned long product[10];
char cString[10];
const unsigned long begConvert = 10 ^ 10;
[Code] ....
string str = "sfsdfsd"
and i want to add like str[3]+str[4]
but it return some integer value