For Example, it the entered string is: 0324152397 I want it to get stored in an array like-[0] [3] ...[7]. Secondly the string entered may be of any length that is defined only at run time. So, I also need to calculate string length. How could I do that.
View 2 RepliesComplete the function myitohex so that its converts 8-byte integer to string based hexadecimals.
Ex: printf("0x%s",myitohex(64,hex)); should printout "0x40" on the screen
char *myitohex(uint8_t i, char *result){
???
return result;
}
I wrote:
#include <stdio.h>
#include <stdint.h>
char *myitohex(uint8_t i, char *result){
*result = i + '0';
[Code] ....
0xp gets printed out which is wrong. I think *result = i + '0'; is wrong. What changes should i do on this row ?
I'm trying to convert a string into a integer and when I call stoi(line) it causes the program to crash.
int main() {
vector<int> numbers;
int i;
string line;
ifstream myfile ("example.dat");
[Code] ....
The file being read from looks like:
3
12
23
34
12 34
12 12
34 23
23 23
struct time
{ int t;
int h,m,s;
};
int main() {
time t;
int totalsecond;
char A[10],B[10];
[Code] ....
It gives error at line no 12.
I want to convert the integer into a string.
int x = 693;
char chararr[max];
In my homework, x is unknown. but don't worry, I wont ask for the full code. I just need the part where you change the int into a string/array of char.
I'm thinking in circles from where to start?
I am trying to convert a 1d string array to a 2d but i couldnt do it. Heres my code so far,
for(i=0;str2d[i][j]='';i++)
{
for(j=0;str2d[i][j]=' ';j++)
{
str2d[i][j] = str1d[k];
k++;
}
}
str1d is a paragraph btw.I tried using NULL instead of '' but didnt work either.
In this program, I have to ask the user for an employee, then the program will check to see if the file for that employee exist, if it doesnt then it will automatically create the file.
ReadNew function reads the file....check to see if it exist
CreateNew function creates a new file.
In my code I have no problem with the first part of reading file.. and my createnew function works in other programs where I am asking for input of file name to create the file name. However in this code I cannot figure how to automatically pass the input filename from the ReadNew function to the CreateNew function. I can't ask the user to enter the name a second time, so I have to pass the input filename into both functions. Here is my code.
Code:
//Create a file, append to it, and read it.
#include <iostream>
#include <fstream>
#include <string.h>
#include <stdio.h>
using namespace std;
char filename[256];
string n;
string filelist;
void CreateNew(ofstream & FileNew);
[Code]...
I am having a lot of trouble extracting values from a string into a double array.
I have a string that looks something like this: "asdf 1.320 1 234.43 5.00000 3"
All I want to do is extract the doubles and store them in an array of doubles.
I am new to coding Here is the problem. Have a program prompt the user for a filename to open. Change every alphabetic character in the file to a capital letter. Numbers and special characters should not be changed. Print the output to the screen.
Here is my code so far but i am only returning the last line of text capitalized from the file. I am trying to get the program to display all of the three lines of text from the file capitalized. The program displays the file correctly before i try and convert everything toupper();
Code:
Code: #include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <ctype.h>
int main()
{
char line[81], filename[21];
int i;
FILE *inFile;
[Code]...
I am trying to understand why i keep getting errors in my code. The errors are after the string is converted in my console window. I have to allocate and delete memory via dynamic array to do the problem.
#include<iostream>
#include<string>
#include<cctype>
using namespace std;
int main() {
string sentence;
int size;
[code]....
I just want to know why the extra characters are at the end of my conversion and how to make them stop.
int main () {
string integer1;
string integer2;
cout <<" enter your first number: " << endl;
cin >> integer1;
cout << endl;
cout << integer1 << " is your first number" << endl;
}
Now how do I turn the string integer into an array?
I'm just learning and C. Here is a code snippit from a program that will compile. It's function is to validate credit card numbers. I have an error I can't find though. the last print statement shows the conversion in reverse string (as integers). Here is the code:
int main (void)
{
char cn[17];
char *cardtype;
int n0,n1,n2,n3,n4,n5,n6,n7,n8,n9,n10,n11,n12,n13,n14, n15;
int s1,s2,s3,s4,s5,s6,s7,s8;
int oddsum;
int sum;
int total;
int validate;
}
[code]....
// prompts the user for a non-negative numbers (>= 0)
// reads in the a number and checks
// keeps re-prompting user if the input is invalid (negative)
[Code].....
How do I go about Populating the elements in the array created, I keep getting a compiler error on this vArr[i] = tmp_stream.str.at(i);
Ok so I'm in a programming 1 class working with c++. I have the following assignment:
Write a C++ program that:
asks for and accepts the Percentage earned with as a double (i.e. 75.45)
rounds it to an integer (>= .5 rounds up, <.5 rounds down.)
prints the original Percentage and the corresponding Grade and Points exactly as shown below.
prints an error message for any input that is less than 0 or greater than 100.
For example, if user enters 89.4, the program prints out:
Percentage: 89.4% Grade: B Points: 3.00
You must use an if-else statement to do this in your program.
Use fixed and precision output manipulators (see Ch. 3) to display the values with the exact precision shown above.
IMPORTANT:
Each if statement condition should contain only one comparison! read this again
This means code that is similar to this is NOT okay: if (Percentage >= 80.00 && Percentage <90.00)
This code is not acceptable because the if statement condition above has two comparisons.
(Hint: If you order your if-else chain statements correctly, you will only need one comparison in each.)
I have the program working, but I'm pretty sure I'm not rounding how my professor would like it to. This is my code:
#include <iostream>
#include <cmath>
#include <iomanip>
[Code].....
So my issue here is the rounding, and then theres the converting the double percetnage to an integer. In my next assignment I have to write the program with a switch statement.
I'm able to convert an integer to a vector<unsigned char> and back. However, when I try to use a nearly identical function designed for the long long data type, the last byte or two is broken.
Program code:
long long num = 9223372036854775551LL;
cout << "Before: " << num << endl;
vector<unsigned char> data = getBytes(num);
num = getLongLong(data);
cout << "After: " << num << endl;
Code for converting between vector<unsigned char> and long long:
Code:
vector<unsigned char> getBytes(long long value) {
int bytes = sizeof(value);
vector<unsigned char> data(bytes);
for (int i = 0; i < bytes; i++)
data.at(i) = (unsigned char)( value >> ((bytes-i)*8) );
[Code] ....
Output:
Code:
Before: 9223372036854775807
After: 9223372036854775552
Is there something special about long long that would prevent this from working? This problem doesn't happen with int.
I am working on an assignment about converting an integer number to its 2's complement presentation. The binary representation is consisting of a single linked list.
As we all know, the steps of this converting is to taking the reminder of the absolute value, then flipping the 1 to be 0, and the 0 to be 1 in the binary number. And the last step will be to add 1 to the binary number invers.
I wrote a code that implements every thin correctly. However, when I reached the part of adding 1, the program was hanged.
int Absolute; //the first step is to convert the number to the binry reprezentation
Absolute = abs (value);// by take the Absolute value of the negative number, then find the
while (Absolute !=0) //the binary reprezentation {
int res;
res= (Absolute % 2);
pushFront (res);
Absolute /=2 ;
[Code] .....
I am trying to assign the integer value to unsigned char array. But it is not storing the integer values. It prints the ascii values. Here the code snippet
Code: uchar uc[100];
for(i=0;i<100;i++)
{
uc[i] = i;
}
The values which are stored in uc[] is ascii values.I need the integer values to be stored in uc[]. I tried to do it with sprintf. but the output is not as expected. if I print the uc[i] it should diplay the value as 0,1,2....99.
Code:
void convertNetPay(float netPay, char *netPayString){
int numHuns, numTens, numOnes;
char OnesTable[9][8]={"One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};
char ResultString[10+1];
char TensTable[9][8] = {"Ten","Twenty","Thirty","Forty","Fifty","Sixty","Seventy","Eighty","Ninety"};
char TeensTable[9][10] {"Eleven","Twelve","Thirteen","fourteen","fifteen","Sixteen","Seventeen","Eighteen","Nineteen"};
float cents;
[Code] ....
I have to convert my netpay which is a float to a string So if I input a value of say, 356.26 it should output "the sum of three hundred fifty-six and 26/100 dollars" . My program function works for the sum of three hundred but after that it spits out garbage.
How will I add the existing content of the text file to the newly inputed date(hoursworked & minsWorked) to compute the total number of hours works. I'm just a beginner in using Visual basic C++.
Code:
#include <iostream>
#include <fstream>
#include<string>
#include <cstdlib>
using namespace std;
bool parseTime(char* _timeStr, int& _hour, int& _min) {
[Code] ....
I'm trying to find a way to accuratley convert a double in the form of a bank account number stored in a file into a string representing the number returned by a file.
View 1 Replies View Relatedvoid convertNetPay(float netPay, char *netPayString) {
int numHuns, numTens, numOnes;
char OnesTable[9][8]={"One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};
char ResultString[10+1];
[Code] ....
BASICALLY, I have to convert netpay (float to string). Theoretically if I have 666.66, my program here should output the sum of "six hundred sixty-six and 66/100 dollars".
i think i need to convert a double to a string, we are working in visual studio doing a program. when i run the calculator i'm not getting the answer i need instead its giving me 0.0 when it should be reading 0.5, here is the code i'm using
{int width;
int height;
int area;
double gop;
String ^strWidth;
String ^strHeight;
String ^strArea;
String ^strGop;
strWidth=width1->Text;
[Code]....
In my project i have to take the string valve and convert it into float
For example
100 will be 100.00
100.0012 will be invalid
100.00 will stay as it is
99 will be 99.00
I am thinking of using stof but i m stuck on how to set the precision of 2 ....
Quick code for converting strings to Dates in C++.
Example: What is the date:
User response: 12/05/14
Any way I can code this to recognize it as a date, and make it so that the date is sortable? Not referring to the system date, but a user input date.
how to convert from string to date in c++? Example: 17 mar 2012 to 17/03/2012
View 1 Replies View RelatedHere's the code I'm working on:
string* arrayPush(string *array, char **toks){
if(array[sizeofHistory -1].empty()){
//find the next available element
for(int i=0; i < sizeofHistory; i++ ){
[Code] ....
toks is an array of pointers to strings. I need to assign a toks to array[i].