Code: Obj<TCHAR>* obj = dynamic_cast<Obj<TCHAR>* >(I->objects[0]);
Which is resulting in this error
Code: A dynamic cast is present, but the correct RTTI option is not specified.
Here is the code,
Code:
class B {
};
class D1:public B {
};
class D2:public D1 {
};
int main() {
B& b = dynamic_cast<B&>(*(new D2));
return 0;
}
D2 is actually grandchild of B, so D2 object reference can still be converted to B reference without any exception. Is it legal?
Is there a difference between having static and dynamic cast in this scenario? The output is the same.
Code:
Base* pb = new Derived();
if(Derived* pd2 = static_cast<Derived*>(pb)) // true {
pd2->get_price(); // calls Base::get_price()
pd2->get_rate(); // calls Derived::get_rate()
[Code] ....
I've a big problem. I'd like to generate of all permutations of objects present on my list and i don't know how to do this. I've found a few examples, but i can't use them in my code...
#include <iostream>
#include <string>
#include <list>
#include <fstream>
#include <cstddef>
#include <cstdlib>
#include <iterator>
using namespace std;
class Item {
private:
[Code]...
Input file with objects:
3
2 0 0 4
5 0 1 5
3 0 2 6
and output should be:
2 0 0 4
5 0 1 5
3 0 2 6
2 0 0 4
3 0 2 6
5 0 1 5
3 0 2 6
2 0 0 4
5 0 1 5
etc... 3! so 6 permutations for this example.
I was 'fighting' with this for few days, and I'm so downcast.
I am having an issue with the below error saying that there is no data present for the second read item (bold and underlined).
But I can see in the data that both fields have data in them. why the approver2 variable is not being populated?
Error : An unhandled exception of type 'System.InvalidOperationException' occurred in System.Data.dll
Additional information: Invalid attempt to read when no data is present.
C#
string approver = null;
string approver2 = null;
con.Open();
string Approve = "Select Approver"+
",Approver2"+
" From dbo.Tbl_Overview"+
" Where RequestID = '" + STAR.Globals.Detail + STAR.Globals.DetailNum + "'";
[Code] ....
SQL
Select Approver,Approver2 From dbo.Tbl_Overview Where RequestID = 'CR4'
Results
ApproverApprover2
User.1 User2
there is a file contains only a numbers ,we dont know how many numbers present in that file.so i want a program to display top n largest number present in that fie.(n may be 5,10,12 like that.)
View 3 Replies View RelatedI am reading a file whick looks like following:
Code:
10 = NAND(1, 3)
11 = NAND(3, 6, 5)
15 = NAND(9, 6, 2, 8)
Problem: I have to find the word "NAND" and then find the numbers inside the brackets because they are the inputs to that NAND gate. I have written a code below but that code can detect the fixed number of inputs. I need a code which can detect any number of inputs (whether 2 inputs or more than two). But i don't understand how do i do that?
My code:
Code:
string input_str ("INPUT"), output_str ("OUTPUT"), nand_str("NAND");
while (getline( input_file, line ))
{
std::size_t guard_found = line.find(guard_str);
[Code].....
I just started on a project on c++ and I was wondering if it is possible to add a select option (where the c++ program requires the user to select an option) . I couldn't find this anywhere.
View 3 Replies View RelatedI'm getting Unhandled exception when try to run option 3.
This my code below.
Code:
#include <iostream>
#include <string>
using namespace std;
struct Vet {
string name;
int numOfAnimals;
string phoneNum;
[code]....
I've been having problems with my loop that asks if the user wishes to continue or not. The required input should either be 'y' or 'Y', or 'n' or 'N'. Anything else should be counted as invalid, and repeat the prompt for input. The first few times I ran my program, the compiler does not read it as a loop. The next few times just won't work properly.
Here is the prompt:
Code:
void question() {
char option;
printf("
Do you want to continue? {Y|N) ");
scanf("%c", &option);
[Code] ......
As it is, it immediately runs the else option, but otherwise runs just fine. I suspect it could be because I have not specified a size for the option variable, but I try doing that, and the prompt relegates everything to the else.
(And also, here's the rest of the code. Basically, it just assigns a value to the letters of the word (a/A = 1, b/B = 2, etc.), adds these values, and determines if a word is prime or not based on the sum.)
Code:
#include <stdio.h>
#include <string.h>
#define size 30
int main() {
char letter, word[size], lower, upper, option;
int i, value, ans = 0, a, choice = 1;
[Code] .....
I have a menu for a project that takes a string input and does whatever option you specify. It works perfectly EXCEPT when it goes through the while-loop (while you didn't say quit the menu reloads). It will spew out all the text in the menu like a bulimic teenager. Then it reloads properly and asks you for an input like nothing happened. While this is not a fatal error (code still functions)...
Code:
#include <stdio.h>
#include <math.h>
#include <string.h>
double aa=0, ab=0, ac=0, sa=0, sb=0, sc=0;
char a1[13], o1[]="AAS
[Code] .....
i need one more option which it can display all the items i have entered in alphabetic order in my program..this is my coding......
#include<stdio.h>
#include<string.h>
#include<ctype.h>
#define capacity 1000
void cal_item(struct item[capacity]);
void input(struct item[capacity]);
}
[code]....
So , i had to make an rock paper scissors game . After lot of hard work and struggle ,I completed it but my professor rejected it since I didnot add option where it says "Would you like to play again .Y/N " . The code has too many brackets ! Here is my code
#include <iostream>
#include <ctime>
#include <cstdlib>
using namespace std;
// for displaying the outputs to the user; passing string to functions
void user_win() {
[Code] ....
Remove the break statements from each of the cases. What is the effect on the execution of the program?
Add an additional switch statement that allows for a Passing option for a grade of D or better. Use the sample run given below to model your output.
Sample Run: What grade did you earn in Programming I ? A YOU PASSED! an A - excellent work!
Rewrite the program LastFirst_lab44.cpp using if and else if statements rather than a switch statement. Did you use a trailing else in your new version? If so, what did it correspond to in the original program with the switch statement?
// This program illustrates the use of the Switch statement.
// The break statement causes all subsequent expressions to be executed as well, also known as "falling through".
// The trailing else statement acts just like the default section if none of the options from before work it gets "defaulted" to it.
#include <iostream>
using namespace std;
int main() {
char grade;
cout << "What grade did you earn in Programming I ?" << endl;
[code]....
how do you add an additional switch statement? i tried multiple times and i'm not sure if i don't understand braces enough but it didnt seem doable. also, I'm not sure what the teacher wants me to submit.
I need to do a code that gave me Original string, uppercase string, lowercase string, reverse string (if letter is upper then convert to lower, and if lower then convert it to upper) and uppercase first (first character of each word in uppercase).
I need to do it in functions but i dont know hot to use strings. The program should provide the option to save the outputs in a file.
I'm writing a program that stores records into a file and then these records can be printed out. A last name, first name, and score is stored to be exactly 36 characters long (using leading spaces to pad) making it easier to retrieve specific records. For example, three records stored in the file would like like this: (the underscores are simply to illustrate the distance, they are not in the file itself)
_______lastname_______firstname__90__________lname __________fname_100___________last___________first __60
When printed out, the names are formatted as follows:
lastname, firstname: 90
lname, fname: 100
last, first: 60
However, when I print them out this is what I get:
lastname, firstname: 90
lname, fname: 100$
last, first: 60H
For some reason, for any record after the first, an extra character is added to the end. These characters are not in the file, so I was thinking that the array for some reason wasn't being filled completely, (the array is initialized to size 36 and 36 characters are read from the file using fread) so it was printing out a random character assigned to the 36th array position. Except the character never changes, (always a $ for record 2, H for record 3, l for record 4 if i remember) and I've tried reducing the array size or the number of character read and it's the string that gets altered, the random character always remains. I figure the problem must be in the print_records function (appending seems to work no problem). Anyway here is my print records and appending records code.
Code: /*
- Prints a single record stored in the file pointed to by ifp.
*/
void print_record(FILE *ifp, int record) {
[Code]......
I am running ubuntu and have tried adding -1GL to the end of my gcc compiling commands but the error says "unrecognized commandline option: 1GL". do i have to install any packages to get this to work?
Its supposed to be an l not a 1.
Basically i have a 'HomeWindow' with a button 'OptionWindow'. My idea is that the 'OptionWindow' button will open up the 'OptionWindow'. Which will give the user three options 'Option1', 'Option2' and 'Option3'. If they pick 'Option1' then in the 'HomeWindow' in a stackpanel i want it to display 'UserControl1'. Where as if they pick 'Option2' then in the 'HomeWindow' in a stackpanel i want it to display 'UserControl2'.
If you need some of my code that i have already then let me know what you need as i have a lot of it so can't paste it all in one go. But the new thing i need is the way of making the user-controls in the 'HomeWindow' change depending on what is selected in the 'OptionWindow'.
today I've been working on a rock, paper and scissors game. It compiles OK, except:
It doesn't use a random number from 1 -3, or goes out of scope.2. It doesn't COUT and it doesn't flush the buffer.3.
My code is as follows:
#include <windows.h>
#include <iostream>
#include <cstdlib>
#include <ctime>
std::string randomPC(int &);
void PCSelect(int &);
[code]....
I'm writing a program in which I have to use a matrix to represent a file in code. because it's a file, the size of the matrix is undefined, and therefore the matrix has to be dynamic. I found out that my compiler doesn't like dynamic multidimensional arrays, so I was thinking of this matrix as a dynamic (monodimensional) array of other dynamic (monodimensional) arrays. My program (and thus this example) uses unsigned chars.
unsigned char variable=something;
unsigned char**matrix=new unsigned char*[lenghtOfMainArray];
for(int rowNumber=0;rowNumber<lenghtOfArray;rowNumber++)
{
[Code].....
i'm implementing a playerclass for a game.. in the game there are multiple player types, weapons ect.. i just wanted to turn my players weapons into a dynamically allocated c_str. once i added my: Destructor, Copy Constructor and Overloaded Assignment Operator. My initial values became corrupted and i cannot fix them.
Player2.cpp
#include <string.h>
#include <iostream>
#include <cstdlib>
#include <iostream>
#include "player2.h"
#include "dice.h"
#include "gamespace.h"
[code]....
Is it possible to get the string representation of an int. So I mean if i have: 5, I want to get '5'.
I was searching in the internet and I found this solution:
Code:
int number = 5;
char c = number + '0'; which works fine for small numbers, but if I do:
Code: int i;
char c;
for(i =0; i < 10000; i++) {
c = i + '0';
printf("%c
", c);
}
At some point some strange sings like %&/)/)$%&) are appearing, But i really need this huge numbers as well .. Is there any other way to do this??
How to cast an int to a string I came across this code:
#include <iostream>
#include <string>
int main(){
double f = 23.43;
std::string f_str = std::to_string(f);
std::cout << f_str << '
';
}
Unfortunately, using Dev C++ Version 5.4.2, I'm getting an error:
[Error] 'to_string is not a member of 'std'
In my refference book I have got a example with a part saying to access the a[4][0] element of the array (named a) with pointer this can be written:
*((int*)a+4)
I wonder if the cast is really required. The book says it is required so that the pointer arithmetic can be done properly. However I am not sure about it. When I work with pointers defined by myself I don't use casts similar to this one. Is there a difference between a self defined pointer and array name?
I have this program.
Code:
int test_variable;
int main() {
test_variable = (int)0x12;
}
Now my doubt is what is the advantage of type casting 0x12 to int. suppose if the test_variable data type is "char" then should i type cast to "char"?
Code:
namespace ConsoleApplication1 {
class ImplicitlyConvertibleFromFoo {
public ImplicitlyConvertibleFromFoo(Foo foo) {
this.foo = foo;
}
Foo foo;
[code]....
Any way to easily convert arrays of user-defined types?