I want to find out the time difference,say i start walking from my home at 23 hr 10 min 25 seconds and I reach destination at 1 hr 10 min 25 seconds.. I know here the time difference is 1 hr 55 min 55 seconds. But how am I gonna calculate this?
View 3 RepliesI have a problem with calculating the CPUtime. I am using CPLEX to solve linear programming with 3 diferent algorithms.
1-primal Simplex
2-Dual Simplex
3-Barrier Method.
When I am trying to use Barrier method, my clock does not give me a right processing time. I don't have any problem with the other two methods. The value I am getting from ticks2 is 0 when I am using Barrier solver unlike the two other methods that I am getting some small values (ticks1 is fine). Using time_t ticks1 , ticks2 and time(&ticks1) and finally difftime(ticks1,ticks2) also gives me an integer number which is not precise enough. I need a way to compute cputime with accuracy of at least 2 decimals.
clock_t ticks1,ticks2;
double solvingtime
if (solver.primopt==1){
ticks1=clock();
status=CPXprimopt(myEnv, myLP);
ticks2=clock();
[code]....
I have a question. I would like to actually have some measure of roughly how long it takes to do a fwrite to a drive. When I do the following:
clock_t begin = clock();
unsigned long long size_t = fwrite(send, 1, transfer_size*sizeof(unsigned long long), wpFile);
clock_t end = clock();
double long elapsed_secs = double long(end - begin) / CLOCKS_PER_SEC;
Unfortunately, I don't get any different result for different transfer size!!!
My guess is that the clock_t , once it issues a fwrite command, some how stops its measurement, and it comes back again, when I am already done with fwrite. I do get the almost same measure, whether my transfer size is 32KB Byte or 16MB ! Which I was indeed expecting to see a huge difference. I wouldn't really want the exact real timing measure (well off course it will be nice to know); and all I care about is to see some difference in time whether I am doing KB transfer vs MB transfer.
Some rough measurement required of the actual time being elapsed for fwrite function?
I would like to actually have some measure of roughly how long it takes to do a fwrite to a drive. When I do the following:
clock_t begin = clock();
unsigned long long size_t = fwrite(send, 1, transfer_size*sizeof(unsigned long long), wpFile);
clock_t end = clock();
double long elapsed_secs = double long(end - begin) / CLOCKS_PER_SEC;
Unfortunately, I don't get any different result for different transfer size!!!
My guess is that the clock_t , once it issues a fwrite command, some how stops its measurement, and it comes back again, when I am already done with fwrite. I do get the almost same measure, whether my transfer size is 32KB Byte or 16MB ! Which I was indeed expecting to see a huge difference.
I wouldn't really want the exact real timing measure (well off course it will be nice to know); and all I care about is to see some difference in time whether I am doing KB transfer vs MB transfer. Any other function that will give me some rough measurement of the actual time being elapsed for fwrite function?
i writing a code which will calculate the difference between time_in and time out. Can i use a 2 dimensional array for example
int time_in[hours][minutes]
int time_out[hours[minutes]
I have accomplished this but it looks hacky if you ask me
time_t timeToNextFeed()
{
Leaf::Record* r = records->getRecord(0);
if (r != NULL)
[Code].....
I need to get the current time, have the system sleep for a period of time, then return the difference in seconds.
#include <iostream>
#include <string>
#include <ctime>
#include <time.h>
#define _CRT_SECURE_NO_WARNINGS
using namespace::std;
// in the <ctime> library is a function time(0)
[Code] ....
I'm not receiving an errors but the return value is not correct. It's returning 1.4259 no matter how long it sleeps for.
I have to write a program for class in which users will be inputting:
start time = startTime
number of minutes = callDuration
so first off, teacher wants us to input time as a floating point number such as 09.00
How do I validate the time so that users cant input i.e. 09.61 for every hour? In other words, so the user cant input minutes 60-99 for every hour.
then, when calculating:
endTime = startTime + callDuration
how would I make endTime display a correct time in such a situation: endTime = 09.45 + 00.30
so that it displays 10.15 not 09.75
I'm challenged to write a program which calculates the time difference between two daytime.
compiler doesn't give an error, yet the warning: "format '%d' expects argument of type 'int *', but argument 3 has type 'int' [- Wformat]" for lines 24 and 26
However, by entering the first time the program crashes anyway. so I assume I do really need some pointer to make it read from the console can you see where my problem is?
Code:
#include <stdio.h>
#include <stdlib.h>
typedef struct {
int Second;
int Minute;
int Hour;
}Time;
[Code]...
This is a round robin execution. with gantt chart. arrival time and burst time. I think there is an error in my formula to get the right answer,i cant resolve it but my program is running. What is the code or the right formula??
#include<stdio.h>
int main(){
int i,j=0,n,time,remain,flag=0,ts;
int sum_wait=0,sum_turnaround=0,at[10],bt[10],rt[10];
int ganttP[50],ganttStartTime[50];
printf("Enter no of Processes : ");
scanf("%d",&n);
remain=n;
[Code] ....
So I'm trying to learn how to use time for time based movement and what not. I did this only knowing the command time(&variable)
time_t timer;
int I, X;
void main() {
time(&timer);
X=timer;
while(I==5) {
[Code] ......
There's probably some other better way to do it... Obviously but for now I see it as putting current time in X.
start while
take in time constantly until I is 5
constantly asking is time>X(preset time 5 seconds ahead)
if it is
display message and add one to I
Why doesn't this display my message after 5 seconds?
Finally got a programme partially working, why the values are not showing? Is this down to incorrect formula or i havent declared the values etc?
Code:
#include <stdio.h>
#include <math.h>
float timeconstant(float R, float C);
float R;
float C;
float time_c;
[Code] ....
I've been trying to calculate the Second standard deviation but the average in the second loop isn't calculating correctly which is causing the standard deviation (method 2) to not calculate correctly. I can't find anything wrong.
Code:
#include <iostream>#include <iomanip>
#include <string>
#include <fstream>
#include <cmath>
usingnamespacestd;
int main ()
[Code]...
Currently I am working on a program where you enter in a date 14 03 2013 (Day, Month, Year) and you get the next day. I seem to be coming stuck with months with less than 31 days, and the whole leap year thing. Here is my code so far.
Code:
#include <stdio.h>
int day, month, year, next_day, next_month, next_year, calculation;
int main() {
printf("Enter a date in the form day/month/year: ");
scanf("%d %d %d", &day, &month, &year);
[Code] .....
As part of a project i want to display the speed of a small wheel on a 7 segment display. I am using a hall effect sensor to pick up the pulses of the rotation. I am not sure how to write a programe on C to calculate the RPM from this....
View 4 Replies View RelatedI am having trouble with my C++ program. My program asks the user to enter any number greater than 0 and less than 20, and if the user enters any number(s) outside the acceptable range, the output should display:
input outside of exceptable range > 0 and < 20
length: 1 width: 1 area: 1 perimeter: 1
But in my program, this output displays no matter what the user types (even if the numbers are in the acceptable range, when it should be displaying the length and width the user enters and also displaying the calculated perimeter and area whenever the user enters number(s) in the acceptable range. Here is my code:
#include <iostream>
using namespace std;
float class_rectangle_area();
float class_rectangle_perimeter();
float class_rectangle_length();
float class_rectangle_width();
[Code] .....
I am just learning arrays, I modified my program to use arrays but now it wont calculate the gross pay well it seems it does but not correctly. The gross pay is coming back as "-9.25596e+061" it worked fine before I added arrays. I do have a text file with the following input :
John Doe 1404 45 20 H
Bobby Jill 1404 45 20 S
#include <iostream>//including library (directive header file)
#include <windows.h>//makes console look pretty
#include <fstream>//Library to read files
#include <iomanip>
using namespace std;
int main() {
SetConsoleTitleW(L"Payroll System");//Set Console Title
[Code] .....
Write a program to compute average grades for a course. The course records are in a single file and are organized according to the following format: Each line contains a student's first name, then one space, then the student's last name, then one space, then some number of quiz scores that, if they exist, are separated by one space. Each student will have zero to ten scores, and each score is an integer not greater than 100. Your program will read data from this file and write its output to a second file. The data in the output file will be nearly the same as the data in the input file except that you will print the names as last_name, first_name and there will be one additional number at the end of each line: the average of the student's ten quiz scores.
The output file must be formatted such that first and last names appear together in a left justified column that is 20 characters wide where the last name comes first, then a comma and a space and then the first name. Use your read string function to read each name separately and then put them together into a larger correctly formatted string before trying to output them. Each quiz score should be listed in a right justified column that is 4 characters wide, and the average should appear in its own right justified column that is 10 characters wide.
Note that if a student has fewer than 10 scores, the average is still the sum of the quiz scores divided by 10; these students are assumed to have missed one or more of the quizzes. The output file should contain a line (or lines) at the beginning of the file providing appropriate column headings.
This is how much I have so far:
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
char* read_string(char* buffer, int max_size, FILE* fp);
int main(int argc, char *argv[]) {
FILE *fp_input, *fp_output;
[code]....
my code is working as expected except a slight error, i have to find min max and median values of an inputed array terminated by 0, the problem im having is with calculating the minimum, where when i enter 0 to terminate the program it uses 0 as the minimum value. my code is as follows
public static void FindAverages()
{
try
{
[Code]....
I wrote a function to calculate the hypotenuse of a triangle. My code looks fine but when i enter the two sides it does not give out the right answer. I really don't know what to do.
#include <stdio.h>
#include<Windows.h>
#include<math.h>
double hypotenuse(double side1, double side2);
int main(void){
double side1, side2, hyp;
[Code] .....
When I compile my code with g++ I get the error: constructor, destructure or type conversion missing before sum.
int sum(int,int);
void sum(int,int,int&);
main()
sum (v) // This is the line that the compiler is reporting the error occurs.
answer sum()
int main(){
int a=1;
int b=2;
int sum;
[Code] ....
I'm trying to determine the first Tuesday of any month in a given year.. I'd prefer to use my own functions to arrive at a solution, but logically I could sorting these things out.
View 6 Replies View RelatedAs homework we were assigned to enter the following code to calculate the distance between two points on the x and y plane. The program should ask the user to enter two points then should calculate the distance between two points and print the distance on the screen.
My program will compile correctly but when attempting to run the actual program it doesnt do anything and some how completely skips over my main function...
Code:
#include <stdio.h>
#include <math.h>
struct point {
float x;
float y;
[Code] ....
How do to calculate the following equation"5+((56+8)/2)" using expression builder
Note: the equation may change "50+((26+8)/12)"
Here's my attempt:
input.open(name);
if (input.fail()){
cout <<"Error opening file"<<endl;
}
while (input>>numbers)
{
counter++;
total += numbers;
[Code]...
Copy of the output:
Error opening file
The Standard Deviation of all the numbers is: -9.25596e+061
Press any key to continue . . .
Its not giving me the right answer.
I have two doubts in the following code,the doubts are marked..PLs note that the following code is correct .This is a program to read 2d array using pointer ()i.e Dynamic array ,to calculate its rowsum and column sum and display this array along row sum and column sum.
#include<iostream.h>
#include<conio.h>
void main() {
clrscr();
int *Val,*Rsum,*Csum;
int MaxR,MaxC,i,j;
[Code] .....