C/C++ :: Program To Calculate Stats Based On Snakes And Ladders
Feb 28, 2014
I have a problem with my code while trying to simulate a snakes and ladders program. The objective of the program is to simulate many games (100000+) to gain statistics:
1. The most likely number of rolls.
2. The mean value of the number of rolls.
3. The most common square, C, on which a token may come to rest. i.e. move on to.
4. The probability of coming to rest on square C.
5. The least likely square on which a token may come to rest and what is the probability of this occurring.
6. The distribution in the number of rolls needed per game presented as a normalised graph.
7. The minimum number of rolls of the die - called Nmin.
8. How many different paths (unique sequences of die rolls) take Nmin rolls to complete the game?
However my program (on Tenacious C) doesn't seem to run at all...
I have run it on internet compilers and other compilers but it must work on Tenacious C.
Below is the code I have at the moment, it works fine when stepped through or ran on a different compiler.
How to create code to answer the 8 points above. For instance, to get point number 2. I must find the total rolls divided by the total number of games, but am not sure how to do this.
Code:
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#include <time.h>
#define NUMBEROFGAMES 10
int GetThePositionOfMovement(int CurrentPosition, int dieValue);
I am trying to create a program that will calculate pi based on a user input for accuracy. If the user input .3 then when the leibniz infinite sum value at a particular i becomes less then the input of .3 then the loop will exit.
I have looked at a number of examples on the internet but I feel lost. I have put together working code that will infinitely output sums but I need the loop to stop when the sum value is less then the accuracy value.
My question is what is wrong with my while loop, why will it only give me infinite summations? How do I make it so that the loop will exit when my accuracy input is greater then the sum?
int main () { double accuracy; cout<<"Give an accurate number." << flush;//looks nice cin>>accuracy; int d;//initialize denominator double pi = 0.0; while(accuracy < d){
I am writing a snakes and ladder program and I'm almost finished, but I am struggling with the dice to work in the way I want it to work. I want the dice to work like this :
Before each player throw the dice they must start at 0. Each player must throw a 6 on the dice to move on the board. If a player threw a 6 on the dice, that player can throw again.
But I ended up with two seperate dice, one for each player (game is only for two players).And when I run the program, both players don't start at 0. And when I throw the dice, both players move at the same time but with different values.
If one of my players threw a 6, they just keep on throwing until someone wins the game. I tried to use a switch and if statements but I couldn't get it right. And so I did this :
Code: #include<stdio.h> #include<stdlib.h> #include<windows.h> #define SpaceBar 32// 32 is an ASCII value for a spacebar
I have an extra credit project where I'm supposed to calculate an approximate the user's age based on the current date and their birthday. My problem is that I am not getting the proper date and time. C++ keeps giving me some random date. I looked up c++ time format on the internet because this is extra credit and not in my book.
I am currently using dev C++ 4.9.9.2. Here is my current code :
// included libraries #include <cstdlib> #include <iostream> #include <iomanip> #include <time.h> #define cls system("cls") #define pauseOutput system("pause") void printM(int x); void age(int m, int d, int y, int &yearAge, int &monthAge, int &dayAge);
Write a program in C++ that calculates the amount to be paid to an employee based on the hours worked and rate per hour. A user will enter hours worked and rate per hour for an employee. Your program should have a function payCheck that calculates and returns the amount to be paid. The formula for calculating the salary amount is as follows: for the first 40 hours, the rate is the given rate (the rate that a user has entered); for hours over 40, the rate is 1.5 times the given rate.
I had write my own coding, but it keeps error. it is okay. But i still don't think i could share here? Still running... I will update my coding for you alls to check for any syntax or logic error. The problem is i need to calculate if the employee work for more than 40 hours which 1.5 times.
I need to run some basic statistics on about ~150 tables that are currently in dBase format. Rather than use excel to do them all individually, i was told to use s+ and write a code to loop through them, but I have never written any code and my experience with spotfire s+ is limited (the stat software i have available) ....
Write a program that will ask the user to enter some words followed by the word END.
Input the words into an array and then output the following statics:
the list of and the count of how many words were typed (not counting END) -- Test 2 the list of and the count of how many unique words were typed -- Test 3 the list of sorted unique words (in alphabetical order) -- Test 4 the list of sorted unique words along with frequency counts for each word -- Test 5 See the sample run below:
Please type in some words. Type END and return when you are finished. red green blue RED red blue green blue orange red reg apple banana banana END
You typed the following 14 words: red, green, blue, RED, red, blue, green, blue, orange, red, reg, apple, banana, banana
You typed the following 7 unique words: red, green, blue, orange, reg, apple, banana
Here are those same unique words sorted: apple, banana, blue, green, orange, red, reg
Here are those same unique words sorted with a count of how many times each was used: apple: 1 banana: 2 blue: 3 green: 2 orange: 1 red: 4 reg: 1
I'm trying to make a Quiz program based on C++'s Data File Handling capablities. I've attached the code in .txt file and I wonder why I'm getting the error identifier bScience cannot have a type qualifier?
I am making a very basic parent/child class based program that shows polymorphism. It does not compile due to a few syntax errors reading "function call missing argument list. Lines 76 and 77, 81 and 82, and 86 and 87.
#include<iostream> using namespace std; class people { public: virtual void height(double h) = 0; virtual void weight(double w) = 0;
I need to create a program that prints a certain number of asterisks based on user input. The user inputs 5 and I want my program to output "*****". How would I do this in C? I've tried printf("%#**", myvariable) but this does not work it only prints "*".
I'm trying to successfully run a program that calculates your BMI but, although it runs, it is not giving the the correct math. Instead, it gives me the number i've submitted as my weight as an answer. I'm using Visual Studio 2008 and the formula: weight / (height/100)*2
Here is my code
#include <iostream> #include <cmath> using namespace std; int main() { int weight; int height; double BMI;
So my midterm exam for programming is done. My program didn't run. Tried rewriting it once I got home. I am still getting an error that the program could not be run. Also, we weren't allowed to use the internet. So I didn't know how to calculate for the discounted rate.
I am using Microsoft Visual Studio 2010.
Given problem:
ABC Hotel offers 5-10% discounts depending on how much money has the user spent. If item purchase is lesser than 1000php (1USD is 43.19PHP) 5% discount is availed. Greater than 1000php then 10% discount is availed. Total price and discounted price should be displayed.
#include<iostream> using namespace std; main() { float a,b,c,d,e,f,g,h,i,j,total,discounted_price; cout<<"Please input price of first 1st item: ";
void input (int array[20]); //Used when user inputs the numbers. void calculate(int array[20], int *pairs); //Used to calculate the matches. void output(int *pairs); //Used to output the number of pairs.
Writing a program to calculate grades... My algorithm is long, so I only posted the part that gives me trouble. When classes== 1,2,4, or 5, the program runs fine. but it terminates when classes == 3.
if (classes==3) { do { cout<<"Enter the Letter grade for 1st class. (USE CAPS)"<<endl; cin>>grade1;
I write this code for Inverse of matrix in C language . But there is error in determinant function that say "can not convert 'float' to 'float(*)[20]' for argument '1' to 'float determinant(float(*)[20])' " ....
/* a program to calculate inverse of matrix (n*n)*/ //actually one of the way to calculate inverse of matrix is : A^(-1) = 1/|A| * C(t) that A is matrix and c(t) is taranahade A
#include <stdio.h>; #include <conio.h>; #include <string.h>; #include <stdlib.h>; const int max=20; int i , j , n , k , size=0 , row , column ; float num , det=0 , inverse_matrix[max][max] , matrix[max][max] , new_mat[max][max] , m_minor[max][max] , m_Transpose[max][max];