In Windows, if you open a command prompt, there are a bunch of keywords like, 'chdir', 'copy', ...
What I'm trying to figure out is how to use that COPY command in c++ code. I want to use the COPY command with the options (/a, /b, ...).
this is my C# code
System.IO.Directory.SetCurrentDirectory
("C:/Users/fahime/Documents/Visual Studio 2010/WebSites/MyWebSite/UserFiles/ProblemAnswers/");
Process.Start("cmd.exe", @"/k ""C:Program Files (x86)Microsoft Visual Studio 10.0VCvcvarsall.bat"" x86");
[Code] .....
I want to compile my cpp code file with visual studio cmd
I'm writing a program to turn the two commands "gunzip file.tar.gz" then "tar -xvf file.tar" into "x file.tar.gz", but I've ran into a problem I can't find a solution to, here are the outputs I get depending on if I use a gunzip -f flag in my system() call or not:
if I use: (void)system("gunzip ", store );
> x file.tar.gz
gzip: compressed data not read from a terminal. Use -f to force decompression.
type: gzip -h
store 1: file.tar.gz
tar: option requires an argument -- 'f'
[code]....
I don't know if the problem is something to do with my code or something to do with gunzip and if it is to do with gunzip if I can even solve it with my code? I've tried for a while to find more info and read the gunzip man file, ran "gunzip file.tar.gz" outside of my program and found that it works normally producing file.tar so I suspect the problem is related to system()?
The objective: Open and read a CSV file one line at a time using SQL commands.
The problem: I am getting an error that I have a feeling may not point to the "real" problem.
Where I may have syntax or other errors in code.
stInputConn = "Provider=Microsoft.jet.OLEDB.4.0;Data Source=V:\IT\RE\Exports\;Extended Properties="text;HDR=YES;Format=Delimited(,)"";
OleDbConnection cn = new OleDbConnection(stInputConn);
stInputFileName = ConfigurationManager.AppSettings.Get("InputFile");
// the input file name is CSV_DataExport.CSV
[Code] .....
The last line (ExecuteReader) is where I get the OleDb Exception.
I need to write a ANSI program to print out each command line argument on a separate line using a for-loop. also it need to print the name of the executable .so far I have
Code:
#include <stdio.h>
int main(int argc, char **argv) {
int i;
printf("")
[code]....
l need to write a program which writes out its command line arguments in reverse order one per line. The output from the program should look like this:
% a.out Two roads diverged in a yellow wood
wood
yellow
a
in
diverged
roads
Two
I write a program which now works perfectly well. However, I want to make it run at the right time automatically, instead of waiting for a user to start it when needed.
The basic problem is, that in a WinPE environment an exe is running. Unfortunately it would need critical input, which must be inputted perfectly. So, I wrote a program which gets the data and sends it to the other app, by bringing it to the front and presses the keys needed using SendInput().
However, this program should wait for it's cue, then get on the inputting part. It's cue should be the point where the program waits for the first user input with this displayed on the last line:
Text:
My question is: how to listen and check whether the last line displayed is "Text:"?
I've tried with AttachConsole(), but for some reason it opens a new console window. I checked and the PID I'm using is the console window's, so I don't know why that happens.
The few lines I'm trying with:
HWND hwnd = FindWindow(NULL, "Administrator: Command Prompt");
SetForegroundWindow(hwnd);
SetFocus(hwnd);
DWORD process_id;
GetWindowThreadProcessId(hwnd, &process_id);
[Code] ...
Please don't criticize the first line. I know it can be ambiguous, but I modified it, When actually using it, the exe name will be in the title, so it will be unique.
How to read a file line by line and then later access them by doing something like
Code:
lines[0] //Line number one
...
lines[100] //Line number one hundred and one
lines[100][0] //L
lines[100][1] //i
lines[100][2] //n
lines[100][3] //e
lines[100][4] //
lines[100][5] //n
...
I am studying C How to Program book and want to run GuessNumber Game.
My system command prompt gives C:UsersAcer>_. And GuessNumber path is C:UsersAcercode_examplesGuessNumberWindows.
I am getting below error after pressing enter. How I can run this program.
‘code_examplesch01GuessNumberWindows’ is not recognized as an internal or external command,operable program or batch file.
I am using visual studio 2010 c++ express for C/C++ programming but is novice here to take command line arguments..i did went to project->properties->debugging and specified there the command line arguments but it didnt work..i think i need to know the format to enter the arguments.
View 9 Replies View Relatedint get_command_line (char * sa) {
char * s;
char * l = fgets(s, 300*5, stdin);
int i = 0;
int j;
int n;
[Code] ....
The aim is to have the function return the number of arguments made after assigning each of the arguments to a c string stored in an array of five pointers. This is how I declare this:
int main(void)
int n;
char s0[300];
char s1[300];
char s2[300];
char s3[300];
[Code] ....
I'm trying to read in a file specified in the command line but I'm having some trouble. The command line entry specifies the inputfile preceded by '<' and the output file preceded by '>' like so
./program -v < input_file.cmd > output_file.cmd
This is what I've got so far.
int main(int argc,char* argv[]){
string strv="-v";
string input="<";
string output=">";
string str;
string input_file;
const char* in=input_file.c_str();
[Code] .....
This compiles ok, but when i run it using :
./program -v < test1.cmd
I get a segfault, if i cout argc it returns '2' where i would expect for this command line entry, I 'd get 4.
I'm not yet outputting to file, just to the screen so im not specifying an output file yet.
I am writing a c++ program in Linux.. I am reading a line from commandline at run time using "getline(std::cin,str);". now, what i want is if i left the commandline as idle (terminal as idle), then i want to know that the commandline is empty... is it possible ???
View 4 Replies View RelatedI'm working on a project that's got a lot of moving parts, from feedback from a position sensor to real-time video editing. The script that runs the sensor is in C++, and the API for the video editing software (vMIX) is executed with HTTP protocol. I'm hoping to use that C++ script to control the video software (as some of the editing is dependent on particular feedback from the sensor), and wanted to see how to execute a HTTP command from a C++ script.
View 3 Replies View RelatedI have found this C++ online compiler (to use when I am at work): Compile and Execute C++ online
When you write and compile a program, on the right side (the "output" side), you can read this command line arguments:
$ g++ main.cpp -o demo -lm -pthread -lgmpxx -lreadline 2>&1
What is the meaning of the following arguments? -lm [link the math header file, right?]
-pthread
-lgmpxx
-lreadline
Any book (ebook, tutorial, printed book, whatever) where I can find all (absolutely all) these and other possible arguments?
I'm currently working on making a program that is run through a GUI run through the command line. The program basically takes an app file and a boot file and runs it through a bunch of functions and generates a new outfile. Anyway I'm new to C and can't figure out how to code it so I can type the two file paths into the command line and read them into the function. Is it possible to do this within the "if else" statement?
Code:
int main(int argc, char *argv[]){
const char * const SrcFilePath;
const char * const SRecordPath;
const char * const FopIspFilePath;
[Code] ....
I tried the exercise 5 on page 312 of King's Book C programming A modern approach second edition. Write a program named sum.c that adds up its command line arguments which are assumed to be integers . Running the program by typing :
sum 8 24 62 should produce the following input
Total : 94
Use the atoi function to convert each command line argument from string form to integer form
My solution is :
Code:
#include<stdio.h>
#include<stdlib.h>
int main(int argc , char *argv[])
{
int i , sum=0;
}
[code]...
It is running good without problems but I am wondering because it is very small solution with few lines of code.
I want to see how the command line arguments work. However I don't know how to enter this input. show me a method to see if my code works?
View 9 Replies View RelatedI have to make a c++ program, in which with an algorithm I have to code a text from a file and write it to another file. The input should like this: "code forCoding.txt toBeWritten.txt" ; or like this: "decode toBeReadFor.txt toBeWrittenIn". I have done everything except one thig: It is says I have to be able to input parameter.
How should i write this? I read [URL] ....., but still dont get. The input of my program has to have 3 strings, so I guess argc should be 3, but I dont really get it. What should I have in my main about this parsing command line parameters?
I am not sure how to enter command line arguments when I run the executable of the file below. I want check an make sure that only two arguments get into the main() before running the rest of the code. I'm using bash on linux.
An example that I have tried to test for 2 arguments in command line -arg1 arg2 > ./a.out This of course does not work
#include <stdio.h>
#include <stdlib.h>
#include <errno.h>
[Code].....
I know you go the the debugger and pass them in. I just need to know the syntax. I know &(ProjectDir) goes first because the text file is in the project directory but how do I pass the text file in as well. The file's name is "tester.txt".
View 2 Replies View RelatedI know this works as expected if your command line arguments are strings.
#include <stdio.h>
int main( int argc, char *argv[] ) {
printf("Program name %s
", argv[0]);
if( argc == 2 ) {
printf("The argument supplied is %s
", argv[1]);
[code]...
Would you be able to do something similar to this if you have integers or would you need to use the first method then convert it with atoi?
#include <stdio.h>
int main( int argc, int *argv[] ) {
printf("Program name %s
", argv[0]);
if( argc == 2 ) {
[code]...
I have "hello world" set for command line args.
int main(int argc, char **argv) {
printf("%s %s", argv[1],argv[2]);
}
That code produces
w
r
d
Why would it do that.
In the following program I have one input .txt file of random words.
Example:
DOOR FLAG APPLE
CAR
I need to create output .txt file which will invert and print every word in the next row.
Example:
ROOD
GALF
ELPPA
RAC
When I run the program with command line arguments:
program.exe FILEINPUT.TXT FILEOUTPUT.TXT
I get the output same as input.
Here is the program:
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
void form(char **a,char **b,int n,char* (*t)(char *));
void invert_words(char *);
void form(char **a,char **b,int n,char* (*t)(char *)) {
[code].....
I'm making a command line program for Maemo but have got a problem reading the args.
main.cpp
Code:
#include <cstdlib>
#include <string>
#include <sys/stat.h>
#include <sys/param.h>
#include <iostream>
#include "exceptions.h"
using namespace std;
struct settings {
//settings() : force(false), deps(false), repo(false) {}
[Code] ....
exceptions.cpp contains bodies of these functions.
Unfortunately the program doesn't seem to recognize the arguments
Code:
marcin@marcin:~/proj/meeinstall$ ./meeinstall -h
-h
Filename not provided.
Exiting...
How can I fix it?
I want to run the following code from the command line:
Code:
#include <iostream>
using namespace std;
#ifdef ABC
const int num = 105;
[Code] ....
But I can not activate the ABC macro from the command line.
I'm trying to use the -d ABC option following the .exe file name, but I could not run the ABC macro.
How can I activate the ABC macro when I run the .exe file from the Windows 7 command line?