I am trying to get my input from user in the same line with certain width between but my output is not in the same line. my third variable which is fruit[i] is shown one line below . How I can fix this ?
#include <iostream>
using namespace std;
int main () {
int staff[3] , fruit[3];
[Code] ....
I am having problems printing "->" on the beginning of each line, im trying to do it as a loop and ending it when the user types "q". also i would like to know how to ignore text from the user when the input begings with a specific character. heres what ive done so far, and not currrently working as expected.
Code:
#include <stdio.h>
int main (void) {
char prompt;
printf("~~~ FRACTION CALCULATOR ~~~
[Code] ....
I want to be able to write a program where I can record user input but combine it with command line arguments. For example I do a simple getline(); and the user types test how to combine it so it could be like test /q and it gives a different output depending on what additional input was added. Can this be done with lots of different inputs?
View 8 Replies View RelatedHow to get this thing to work. All i need to do is ask user to input a name and then it brings out the line from the .txt file containing the information.
For example in my case I'm doing a member search function I'm required to ask user to input the name of the customer and then print out all the details (which consumes 1 text line in the .txt file)
Here is the code, This is the write to text file method (100% working)
Code:
cout << "Customer Name: ";
cin >> name;
// ...
ofstream myfile("customer.txt", ios::app);
[Code] .....
I am making program that allows the user to determine how big the array size will be and then asks the user to make up numbers to fill the array. Every time run the program on Dev C++ it says "program has stopped working"
Heres My Code:
//Assignment 19 Program 2
#include <iostream>
using namespace std;
int main()
[Code].....
int get_command_line (char * sa) {
char * s;
char * l = fgets(s, 300*5, stdin);
int i = 0;
int j;
int n;
[Code] ....
The aim is to have the function return the number of arguments made after assigning each of the arguments to a c string stored in an array of five pointers. This is how I declare this:
int main(void)
int n;
char s0[300];
char s1[300];
char s2[300];
char s3[300];
[Code] ....
My goal is to create a loop that keeps taking user input over and over until the user doesn't enter anything into 'cin >>', leaves the line blank, and simply presses the ENTER key to move on, at which point the program is supposed to break out of the loop and continue on with the rest of program execution. Something like this:
Code:
do {
cout << "
Enter a name: ";
cin >> input1;
if (input1.empty())
[Code] ....
As you can see, I've already tried using the empty() function, but that didn't work, the program simply stays in the loop and doesn't break out, no matter how many times I press enter. It just keeps prompting me to enter a name. I've also tried using something like
Code: if (input1 == "")
but that doesnt work either. How do I break out of this loop?
I have been trying to make a small program that I will be using in a larger program that will make the user press space to see the next line of output.
Not exactly sure what I'm doing wrong, but I'm pretty sure that I need to put the space that the user would enter into an output file, and the read the input file
It runs, but it doesn't allow me press space before showing the next line.
I added a getline(cin, charVar) before, but I got a whole bunch of errors.
#include <iostream>
#include <string>
#include <cctype>
#include <cstdlib>
#include <fstream>
using namespace std;
// function for dialouge
[Code] ....
So I've run into the following problem. My goal is to create a loop that keeps taking user input over and over until the user doesn't enter anything into 'cin >>', leaves the line blank, and simply presses the ENTER key to move on, at which point the program is supposed to break out of the loop and continue on with the rest of program execution. Something like this:
do {
cout << "
Enter a name: ";
cin >> input1;
if (input1.empty()) {
[Code] .....
As you can see, I've already tried using the empty() function, but that didn't work, the program simply stays in the loop and doesn't break out, no matter how many times I press enter. It just keeps prompting me to enter a name. I've also tried using something like
if (input1 == "")
but that doesn't work either. How do I break out of this loop?
I want to be able to read 2 line input, then safe them in separate arrays.
line1 input=array1
line2=array2
How to input two variables in the same line? Like when i type 12 and press enter, 1 must be assigned to a, and 2 must be assigned to b. I want it to be entered on the same line, and press enter only once. How do i do that?
View 5 Replies View RelatedMy program allow user to draw lines and the user should know the length of the line that he draw in centimeter (.cm)
I did use
SetMapMode(MM_LOMETRIC) function to convert the device units into logical units
and it works correctly but I don't know how the line length will appear to the user to let him draw in correct length
I think to make the length appear on the mouse when the user draw but I don't know how I calculate and display it.
I want the phrase "BUY TICKET" to trigger something, i'm thinking an if statement, and then assign the number after the phrase to another variable. There will also be other commands entered from the input file such as "BUY RAFFLE' "TOTAL REVENUE" on the following lines. Sounds like I need to compare a string(?) to a constant phrase, and if they match have it run the specific code?
Code:
//scan in from file
fscanf(ifp, "%c", &input);
if (input == 'BUY TICKET'){
//Run this
}
How to do it using the tools in C.
Here's my code, it's for a poker hand evaluator
input:
'ad 2d 3d 4d 5d...
...4s 5s 6s 7s 8s'
I think it should go through all the 10 crads and disply the name of each card, but it seems to only do it for the second hand
Code:
include <stdio.h>
#include <ctype.h>
int main( void ) {
char inputtedhand[64];
int z=0, counter=0;
int index;
int i=0,m=0,n=0;
[Code].....
We need a program that takes three names ( first middle last ) and print it each one at a different line...
View 5 Replies View RelatedI am trying to use the command line to put a txt file in this code. I do Project->set project arguments in code blocks and nothing happens. How does one set up the arguments and where do i do it in codeblocks?
Code:
int main(int argc, char *argv[]) {
char name[20];
struct artist *ptr;
char lineBuffer[LINEBUFFERSIZE];
artistNodePtr startPtr = NULL; /* initially the artist list is empty */
FILE *musicFile;
char *artistTemp, *discTemp, *yearTemp, *trackTemp, *songTemp;
[Code] ....
I have three questions concerning the below code I have written, which is expected to do basically as the attached diagram illustrates:
Code:
#include <stdio.h>
#include <stdlib.h>
double getAverageGrade(int studentGrades[] , int size);
int* getStudentInfo(int * numCourses);
int main()
[Code] ...
(1) How may I display the averages to 2 decimal places, namely why doesn't %.2lf work? The program gives 89.00 for 89 and 90, for instance.
(2) How may I read the number of courses and the relevant grades in a row for each student?
(3) How may I free (de-allocate) my array of pointers, namely grades? Does it suffice to use free(grades)?
I'm new to C/C++. I am attemping to use fgets and sscanf to read a line of input, and confirm it is a positive number.My code works great, except for the case of a negative number. When I enter a negative number, my while loop seems to run infinitely, with stdin providng the same input over and over again.
Here's the code snippet:
Code:
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#define TEXT_LEN 64
void foo() {
char* inStr = (char*)malloc(sizeof(char)*TEXT_LEN);
memset(inStr, 0, TEXT_LEN);
}
[code]....
I've been stuck on this for hours, and have scoured the internet for any insight on this particular issue with no luck.
I'll simplify the problem here. I have a lines in an input file:
John Smith 1234 Main St New York
Carol Thomas 5678 5th Ave Columbus
...
and I am reading into character arrays using code like this:
infile.getline(name,20);
infile.getline(street,15);
infile.getline(city,10);
but when I print the output using something like this:
outfile << "Owner Name: " << name << endl;
outfile << "Address: " << street << city << endl;
(let's pretend I included spaces between the address components, which I omitted to save space)
I get an output file of:
Owner Name: John Smith
Address:
The output stops after the name variable, which I believe is stored correctly. I don't think anything is storing in the address pieces, this is the problem.
I think it's because I'm not using getline() properly in this case. Can you string together multiple getline()s like that?
If this was my design, I'd read in strings instead, but that is not possible in this case.
I want to input the elements of a two dimensional array in the same line . So while giving input . when i press enter . it should remain on the same line ? HOW to do that ?
View 1 Replies View Relatedoutputting the contents of my stack on the input line.
View 7 Replies View RelatedHow can I create in my C++ program so a user can paste a text and then choose a character on specific line and place?. The above thing isn't that important. I just want to place a character on a specific line and place.
I mean something like this:
Enter a character:
You choosed " / "
On which line do want the character?
You choosed "Line 1 and 2"
Where do you want the the to appear on the line? (left or right)
You choose left.
Results:
Line 1. / hello
Line 2. / hello
I want the numbers to be put into the array until it hits a new line. Maximum number of numbers is 1000. What can I replace that while loop with to stop it from reading further into the input file?
Code:
while (input != '
'){
for(i=0; i<1000; i++)
fscanf(ifp, "%lf", &auctions_prices[i]);
I am having an issue with the statement "Both the input and output files' names should be read from the command line." I don't understand what this means or what I need to do.
View 4 Replies View RelatedI'm trying to create a program that takes an integer input and displays each digit on a new line from right to left.
An example of this would be:
Enter an integer: 657
Digit (1): 7
Digit (2): 5
Digit (3): 6
So far I have this:
#include <stdio.h>
#include <math.h>
int main() {
int i, input, output;
printf("Enter an integer: ");
scanf("%d", &input);
if(input == 0)
printf("Digit (1): 0");
[Code] ....
It works perfectly fine, but I just learned that I am not allowed to use the #include <math.h> so I have to take out floor, log, and pow.
I'm pretty sure I have to do some sort of while or for loop to get the results, but how to do it.
How can a mulitline string be read line by line
ex: str = "PERIOD="week"
DAY="day"
TIME="time"";