C/C++ :: How To Use Result Of If Statement Later On In The Code
Nov 19, 2014
how to use the result of an if statement in my program. I'm writing a program for a knockout tournament, so i want to extract the winner of each match to carry forward in the code for use in the next round. I've tried assigning another variable (#define r1w1) and saying that the variable = cName[0] or cName[1] in the if statements like this: (i did this because i thought i could then use r1w1 later in the code)
if(scorea1 > scoreb1) {
printf("
");
printf("WINNER OF ROUND 1 MATCH 1 IS %s
", cName[0]);
cName[0] = r1w1
I'm working on a CGI application. I'm trying to test my input with a switch statement and output the result with html tags to populate a web page. From within the switch, I've coded as follows:
HTML Code: switch(mFunc) { case 0: cout << "<p><b>YOU ENTERED THE FOLLOWING TO BE CALCULATED:</b></p>" "<h2>"<< number1 <<"+" << number2 << "</h2>" << endl; break; case 1: cout << "You've entered" << number1 <<"-" << number2 << "to be evaluated" << endl; break;
I know that I'll need to put this in an html body with a content type as such:
Each time I run it I get in correct result. I even tried running with code from from my book and it failed aswell. The code from the tutorial worked some how. BTW I use DevC++ as my compiler.
Is there a way to tell the program to continue reading the next line of code within a nested IF statement?
The reason I want to do this is because the two "else" statements in the following sample (the main and the nested else) will contain the same exact code and I don't want to repeat it twice. I know I can do this by creating a function and calling it from each else statement but I was just wondering if what I'm asking is even possible without using a function.
if(1 < 2) { // yes 1 is less than 2 if(5 > 10) { // do something } else { // no, 5 in not greater than 10 // here is where I want to tell the program to continue reading the next else statement
I am writing for loop with a switch so that scores can be inputted in by a judge. The issue that I am running into is that I will put out an the text then the test happens and the code puts out the switch statement 5 times with random number. Here is what I have written.
Code: int main() { int diver; int option; int Judge; cout << "Enter Divers Name:";
Info:Program that stores information about reports .the above function searches the report according to its title. list is the name of the structure that stores the records.
Why i'm using strstr:
for eg. there is a report titled 'report on tigers'
I want the report information to be output if someone searches for 'tiger'
Output:displays all the entries i have made till now
I'm trying to understand the pass by value-result. The code I have came up with so far only does by value and by reference, which I understand. The value-result is what has me stumped, and honestly I am unsure how to write the function for it. Here's my code so far...
#include <iostream> using namespace std; // Function prototypes. void swapByValue(int, int, int); void swapByRef(int&, int&, int&);
I keep getting an undesired value in this code. I've tried several methods, but none are giving me the correct answer. The out put is always zero, when in this case it should be 10!!
Here's the object structure:
template<class T, class _b> struct quantity { private: T value; public: explicit quantity(T val): value(val) {}; T getValue() { return value; };
Why does it seem that the assignment operator is the harder operator to overload? Maybe it's just my luck, but I seem to always run into issues whenever I work with it. I hardly ever experience errors when overloading any of the other operators.
I am trying to make the code below display the result with decimals. I tried using setprecision, but I am not too sure where to put it. I placed it in cout section where the answer is but it still doesn't come out correctly.
#include <iostream> using namespace std; //*Delcare function prototype* int ConvertToCentimeters (double, double ); //declare exception class* class NegativeNumber
I am creating a program that allows the user to enter the number of days worked and calculates the amount of money gained by doubling the amount from the previous day, starting with .01 cents. The program works fine except for in day 3, the program adds .01 along with doubling the amount from day 2. Also I must use a List Box.
using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing;
I am trying to compare 2 strings of characters The users input containing 5 chars is compared to a table If the input is already be existent in the table the index of those chars in the table is printed Quest: how to copy the result of a printf() into an array ? The last printf() gives a sequence of numbers and I am trying to save that sequence to another array for further operation ! I have not been able to do that so far even with tmp[]=i ;
Code: #include <stdio.h> #include <string.h> #define N 30 #define n 100 int main (void) [code]....
I am having a problem using fprintf. I have a function which flips a coin. Heads prints a text to the screen. Tails prints a different text to the screen. My problem is getting the result to print to a text file.
Code:
#include <stdio.h> #include <stdlib.h> #include<time.h> void seedrnd(void); int coinflip(int small, int large); }
I'm making a simple calculator and have done it all right where you can input everything, all the functions are there, but when i run the program it will come to displaying the result and it will always equal zero, I just need it to say 8+8 = 16 rather than 8+8 = 0, i don't know whether its just displaying the results as 0, or not displaying it at all, the code will follow below:
So I want to go from having 0 or 1 to having words like false or true. I did it with an if statement earlier today, but I had to get rid of the whole bool thing. I made the variable just a float. But he requires we use bool. Here is my code:
Car y; cout << "Initial value for the Car: " << endl; cout << "Age= " << y.getAge() << " years old. The Price= $" << y.getPrice() << endl; y.setAge(8); y.setPrice(12000); y.setRaceCarStatus(true); cout << "Modified value for the Car: " << endl;
[Code]...
I commented (//) the if statement that I had earlier. If I set RacecarStatus to True, is cout's 1. The starred (*) line right above the comments is the line that I was required to add. I want to cout the actual word true. The one I had this morning won't work anymore.
I do not have code - I am just wondering if I have a method which gets input from the keyboard and returns it, how would I store that information in a new method after calling it and put the result of it into an array.
The results of my code is supposed to be very simple: return the 2 integers and then their sum. However, it's doing returning the first value, then an address in memory(rather than the 2nd value), and then the 2nd value(rather than the sum). Here is the code:
I'm doing a bitwise operations on 2 bytes in a buffer, then storing the result in a variable. However, I sometimes get a non-zero value for the variable even though I'm expecting a zero value.
The relevant portion of the code is as follows.
unsigned int result = 0; long j = 0, length; unsigned char *data; data = (unsigned char *)malloc(sizeof(unsigned char)*800000);
[Code] ......
I'm expecting result to be zero when my data[j] and data[j+1] are 0xb6 and 0xab respectively, which is the case for most of the time. However, for certain values of j, my result is strangely not zero.
j = 62910, result = 64 j = 78670, result = 64 j = 100594, result = 64 j = 165658, result = 512 j = 247990, result = 128 j = 268330, result = 512 j = 326754, result = 1 j = 415874, result = 256 j = 456654, result = 1024 j = 477366, result = 512
It appears that these strange result values are all powers of 2, with a 1 bit appearing somewhere in the unsigned int.
I'm not changing the value of result anywhere else in the code, and when I print out (unsigned int)(((data[j]^0xb6)<<8)|(data[j+1]^0xab)), I get 0, but somehow when it gets stored in result, it's no longer zero.
