C/C++ :: Difference Between Literal And Symbolic Constants?

Jun 29, 2014

"A constant, like a variable, is a memory location where a value can be stored. Unlike variables, constants never change in value. You must initialize a constant when it is created. C++ has two types of constants: literal and symbolic.

A literal constant is a value typed directly into your program wherever it is needed. For example, consider the following statement:

long width = 5

This statement assigns the integer variable width the value 5. The 5 in the statement is a literal constant. You can't assign a value to 5, and its value can't be changed.

The values true and false, which are stored in bool variables, also are literal constants.

A symbolic constant is a constant represented by a name, just like a variable. The const keyword precedes the type, name, and initialization. Here's a statement that sets the point reward for killing a zombie:

const int KILL_BONUS = 5000;

Whenever a zombie is dispatched, the player's score is increased by the reward:

playerScore = playerScore + KILL_BONUS;

If you decide later to increase the reward to 10,000 points, you can change the constant KILL_BONUS and it will be reflected throughout the program. If you were to use the literal constant 5000 instead, it would be more difficult to find all the places it is used and change the value. This reduces the potential for error."

what's the difference? Here is a program to demonstrate what I'm having trouble conceptualizing.

#include <iostream>
using namespace std;
int main() {
int width = 10, length = 10;
int area = width * length;
cout << "Width: " << width << endl;
cout << "Length: " << length << endl;
cout << "Area: " << area << endl;
return 0;
}

Now, why would it be harder to go in and changed a regularly defined integer than one defined with the 'const' keyword proceeding it? For example, the width and length variables. My confusion comes from the point that they seem to both simply be variables with a value assigned to them. I feel as if the process of having to change a literal constant's value is synonymous to the process of having to change a symbolic constant's.

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Feb 17, 2014

My assignment is to create a simple stock broker program that ask the user how much they are willing to invest and ask what company they would like to invest in. Finally it outputs how many shares the user will have based on their investment amount. My code is below. My professor said to declare symbolic constants and factor out the if else statements. Ive been struggling trying to understand constant variables. How do I use const variables to factor out the if else statements?

#include <iostream>
#include <cstdlib>
using namespace std;
int main() {
//Declare Variables
const double BAC = 16.7;
const double Citigroup = 49.52;

[code]....

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This error keeps coming.

******************************************************************
CSCI 240 Program 5 Part 2 Spring 2013

Programmer:
Section: 1
Date Due: 3/1/13

Purpose: This program uses functions to calculate the surface area of various shapes. It is an exercise in learning to write functions.
******************************************************************/

#include <iostream>
#include <iomanip>
using namespace std;
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int Menu();
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[Code] .....

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What's the problem with the following:

Code:
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Why is it not allowed, and how is it different from:

Code:
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[code].....

With this code i get compile error!

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Code:
struct Node{
char ACNO[15];
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Code:

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[Code]....

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Apr 5, 2012

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May 28, 2013

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Code: /* ... */
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/* or even */
char *pstr = "example";
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This compiles o.k.:

Code:

int main(void){
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I get an error saying "pointer being freed was not allocated". This happens for free(a), free(*a), free(&a), free(&*a).

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template <typename A, typename ...B>
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write(argTail...);
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these function works. but if i concat literal strings with '+', i must use '(string)'. so i'm trying overload the operator + for concat literal strings, but without sucess:(

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Apr 19, 2014

In the following char array, notice the use of a backspace character in a string literal: ''.

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When it is used with cout, cout just treats it like a string and instead of printing the address, it just prints out all characters one by one until it reaches the terminated null character.

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Code:
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char* data;
std::size_t size;
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Code:
const String message;

Is there an elegant way to create a const String like this when data is a string literal?

I tried this:

Code:
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size_t string_size = strlen(string_data) + 1;
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The problem with that is that string.data isn't considered const during the initialization of the String struct so the compiler throws an error. It doesn't feel very elegant to do it like this either way.

Is there an elegant solution to this problem? I would like to avoid making a copy of the string literal.

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Mar 20, 2014

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Code:

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Code:

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}
return;
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I could type in putsXLCD("5.00") in order to display it on the LCD, but how do I implement this automatically for values, e.g. 0.00 to 5.00?It appears I can only pass literal values through the function SendCharacter, meaning that in order to display "0" I have to pass the value 0x30 (the hex value of "0" on the LCD Table).

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Jul 10, 2014

I'm making a .json loader for a project that I'm working on, and to simplify things, I decided to make all the root attributes named in a separate file. Here's my problem: my loading function, Add(const char* id), works just fine when I pass it a string literal.

However, when I use a function that iterates through a vector list, even with the exact same definitions as the literal, it returns the error: std::out_of_range at memory location 0x0026fb30

I've stepped through it with the VS2010 debugger about a hundred times, checked against memory locations, and just have done everything I can think of, all to no avail..

The code, with data-checking omitted:

The std::map I'm adding to:

static std::map<const char*, Item*> *s_mItems;
Initialized as std::map<const char*, Item*> *Item::s_mItems;

Add() Function (Works by itself with a literal):

static bool Add(const char* id) {
...
std::string name = node.Get("name").ToString();
std::string desc = node.Get("description").ToString();
int rarity = StrToRarity(node.Get("rarity").ToString());

[Code] ....

AddList() function, where the program always breaks:

static void AddList(std::vector<std::string> list) {
for(std::vector<std::string>::iterator it = list.begin(); it != list.end(); it++) {
Add(it->c_str());
}
}

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Jan 24, 2014

Background: I'm using SDL and CodeBlocks and trying to make a Graphics class that would simplify some SDL operations such as drawing and loading images.

Issue: The loadImage function in the graphics class fails to load the image correctly and so the program prints out a blank window during run-time. I've tried multiple ways of passing a string literal into the function the surface temp fails to load and so background in Game fails to load. After testing it several times, I'm pretty sure that the issue lies with SDL_LoadBMP not registering the passed variable for whatever reason. I know the image is in the right place as writing SDL_LoadBMP("./Graphics/image.bmp"); brings it up just fine.

Current Code:

Main simply creates a Game object and execute(), so I didn't feel the need to put it on here.

Game.h
#ifndef GAME_H
#define GAME_H
#include "SDL/SDL.h"
#include "SDL/SDL_ttf.h"
#include "Graphics.h"
#include <string>
#include <cstring>
using namespace std;

//GLOBAL CONSTANTS
//game window settings

[Code] ....

Output: A blank window. (It should show the background image but doesn't.)

Note: I originally wrote it as gfx.loadImage(background, "./Graphics/image.bmp") but that gives me a conversion warning and still fails to show the image when the program runs. I've tried looking up examples similar to what I was doing but no one else seems to have this problem.

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Oct 19, 2014

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Jan 26, 2013

#include <functional>
using namespace std;

template<typename...Args>
void on(function<void(Args...)> f) {
function<void(Args...)> fn; // this line causes error C2059: syntax error : '<fake-expression>'
}
int main() {
function<void()> f;
on(f);
}

What's the difference between 'f' and 'fn'?

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