C/C++ :: Calculator That Uses Only Getchar / Putchar
Mar 24, 2014
I basically just have to make a calculator that only uses getchar/putchar (printf is Ok for displaying errors) - Also, negatives must be error-checked. As of right now, my program will only work if there is exactly one space between the number, operand, and other number. No spaces, or more than one space, will give me some very weird digits. I also need to display the numbers with putchar, and not printf (as I did below), but I just really wanted a working program.
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#include <math.h>
int add(int input1,char operand, int input2);
int subtract(int input1,char operand, int input2);
I have to make a calculator program that has 5 different functions (this is obviously the easy part, once all the input is assigned to their respective variables), which are addition, subtraction, mod, multiplication and division (negatives are not allowed, and must be error-checked; spaces must be ignored). I need to take the equation from the user, echo it back and then solve the problem.
I want the user to be able to enter a command then a character, like for example: push r....I want the command to be stored in the array command, and the character to be stored in the variable c.
Now I wonder what the best way to get rid of the space is, using scanf or getchar (see below for code, only thing that I changed between the 2 versions is the statement before the comment "get rid of space")? Or maybe it doesnt matter?
Code:
include <stdio.h> #define MAX 200 void push(char c); // Puts a new element last in queue char pop(void); // Gets the first element in queue static char s[MAX]; }
I need to get an integer number with only using getchar() and without pre knowing the number of digits in the integer. And I cannot use strings or arrays.
Once again i hit a very simple problem i am unable to resolve. I using Visual Studio 2010, but am compiling for C.
This:
Code: char i=45; while(i=getchar() != EOF) {
should imo work perfectly (yes, no real code, just to demonstrate the issue), but it doesnt. Getchar() always returns 0x01. Why is that? This, in contrast, works perfectly fine:
Code: char i=45; while(i!= EOF) { i=getchar();
Shouldnt an assignment always return the assigned value?
I just started by defining a stack class (stackDouble). I need to write a program that accepts an infix calculator expression, with the following operators (**, exponentiation, /, division, and, -, subtraction. The operator precedence is exponent, division, and subtraction.I need to use a stack of doubles and a stack of strings, of which I can write two classes, or write a single stack template. The user will input the expression just via cin, and there will be a # before every number, a ! before each operator, and a . at the end of the expression. '#', '!', or '.' can be input into a char variable, numbers into a double variable and operators into a string variable.
For example, the following would output 6:
# 3 ! / # 2 ! / # .5 ! ** # 2 .
As stated above, I already made up a stackDouble class. What would I need to do to create the other class (I don't think I want to do it with a template)?
Code: #include <iostream> #include <string> using namespace std; class stackDouble{
I have an assignment to do a calculator in C, wich will work by clicking the numbers with the mouse, however i have a bug that when i hold the mouse and dragg it, it assumes that I'm clicking multiple times, also, when I click in an empty space the program creates a blank space on the calculator screen.
Code:
#include <stdio.h> #include <conio.h> #include <math.h> #include "..MouseHandler.h" // ajustar o caminho ao seu projecto #include "..calcSkinLib.h" // ajustar o caminho ao seu projecto #define PI = 3.1415;
I'm trying to create a program that will calculate the gpa of several different students, whose data are in a text file. The file looks something like this, with possibly more lines.
Mark 3 4 A 3 D 2 C 1 A Tom 2 3 A 2 C
The very first number tells us how many credit hour/grades will follow. I have a couple of problems though: From the code I've written I don't seem to get any data other than the first line. Also the gpa that does print out after the file runs is just a 0.00, rather than the actual gpa.
'm trying to program a BMI calculator in C for my assignment where the weight must be in KG and an int , and the height must be in m and a double value. The program should allow the user to input his weight(kg) and height(m) separated by a space and be able to calculate and display the BMI. My code is shown below :
However , after running the program , I constantly get a 1.#INF00 value for my result.The compiler did not show any errors so why I'm getting this value.I input my weight and height in this format "45 1.65" 45 being the weight and 1.65 being the height.
I am making a calculator where I will input 5 array of numbers and calculate those numbers with pointers or whatever you call it. I am getting an error like
I have to enhance my BMI program to tell whether the person is at optimal weight, under weight, or overweight and I cannot find the correct calculation. Here is the code I have so far that works for calculating the BMI.
namespace Body_Mass_Index { public partial class BMI_HW : Form { public BMI_HW() { InitializeComponent();
ive been learning from the book for 4 days and decided to make a different type of calculator out of boredom but im really having problems when i try to make it a loop? ive been scratching my head trying to work it out rewriting deleting etc but cant work it out
Code: #include <iostream> #include <string> using namespace std; int main()
In my calculator, I am trying to make it so that you put enter 1 to add, 2 to subtract, 3 to multiply, and 4 to divide. I am facing the issue of making it so that you must enter a number, however instead of it being any number, it must be 1, 2, 3, or 4, and if it is not any of those numbers, you must re-enter the number. Here is a little snippet of my code:
Code:
printf("Please enter 1 to add, 2 to subtract, 3 to multiply, or 4 to multiply: "); while (scanf("%d", &input) != 1) { while (getchar() != ' '); printf("Invalid option. Please try again: ");
The main point of the program is to calculate equations just like a standard calculator but I wanted to do it myself. I don't understand what the problem is right now but I've managed to create a program that asks for both values but somehow it doesn't want to ask for an operator (*, /, + etc). What's wrong with my code that the terminal skips the scanning part for the operator?
Code:
#include <stdio.h> int main() { int value1, value2, answer; char operator;
error C2660: 'Add' : function does not take 0 arguments error C2660: 'Subtract' : function does not take 0 arguments error C2660: 'Multiply' : function does not take 0 arguments error C2660: 'Divide' : function does not take 0 arguments
I'm building a pretty basic calculator program that calculates the area of generic shapes (triangles, rectangles, and squares); for some reason though, my program is having troubles as soon as it hits the if/else code in the int main section. When I enter triangle, rectangle, or square, it just spits back out the "That's not one of the options. Please re-enter and try again." error line I created. When I isolate and run just the stuff inside the if/else statements it works great, but why it won't just understand my if (shape == triangle).... .
Code:
#include <iostream> using namespace std; class figure { protected: double x, y;
I'm working on below program and I want the program to do the same thing, but with not one main() function, but instead one main() function PLUS one user defined function called computeConeVolume that contains the calculation. In other words I want to remove the one line calculation and replace it with a function call, then write and add the function below main with the calculation, surrounded any other syntax that I need to complete it.
The function should contain local variables and a constant declared and must have the calculation, it may not do anything else such as input or output. Should be able to declare "global" variables anywhere but no variables above or outside of main() and the function are allowed. A value-returning function should be used because it's a little simpler to understand, but you can employ a void function. Need to have a function prototype at the top of the code, then main, then your function.
//Cone Volume Calculator Program #include <iostream> using namespace std; int main( ) { //Declare variables and constants double coneRadius = 0.0; double coneHeight = 0.0;
I'm making a simple calculator and have done it all right where you can input everything, all the functions are there, but when i run the program it will come to displaying the result and it will always equal zero, I just need it to say 8+8 = 16 rather than 8+8 = 0, i don't know whether its just displaying the results as 0, or not displaying it at all, the code will follow below:
I am basically trying to make a program for a calculator. I am struggling with how to do the sine calculation. this calculation will take place at line 158.
#include <iostream> #include <cmath> using namespace std; int main() {
